INSTITUTO TECNOLÓGICO TECNOLÓGICO DE PIEDRAS NEGRAS
INGENIERÍA INDUSTRIAL ADMINISTRACIÓN DE OPERACONES EJERCICIOS UNIDAD 3 ING. GONZALO GARCÍA LUNA MARI MARIA A DE JES JESUS US TUR TURRU RUBI BIA ATE ZAV ZAVALA
N.C. N.C. 10/ 10/32 320 0
PIEDRAS NEGRAS, COAH. A 27 DE OCTUBRE DE 201
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√(
2 ( D ) ( S )
P ) (C )
=
√(
2 (520 ) ( 10 ) 0.30 ) ( 80 )
b) P ( S )= 520 ( 10 )=249.87 20.81 Q
N =
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D 520 = = 24.98 Q 20.81
=20.81
C =
Q ( H )= 20.81 ( 24 ) =249.72 2 2
%> A5+-" "'")F- $- "4 $-"4 %$ " $*#'$4" +- -)'$*$-( %$ 0; 0 +- %$)'$*$-( %$ 0;. CT =
D ( S ) + Q ( H )= 520 ( 10 ) + 20.81 ( 24 )=499.59 2 20.81 2 Q
D ( S ) + Q ( H )= 520 ( 10 )+ 10.40 ( 24 )=624.80 Q 2 10.40 2
0;
CT =
!
CT =
0;
D ( S ) + Q ( H )= 520 ( 10 ) + 41.60 ( 24 )=624.20 2 41.60 2 Q
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D"(4 D8 200/"<( S 8 : 1200.00 H 8 PC 8 20 ;>:2.00> 8 :.00> S(+)F- "> Q∗¿
√
2 ( D ) ( S )
( H )
=
√
2 ( 200 ) ( 1200 )
( 15 )
=178.88
@> N =
Q 200 = =1.11 D 178.88
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EOQ=Q∗¿
√(
2 ( D ) ( S )
P ) (C )
=
√(
=
√
2 ( 780 ) ( 10 ) 0.30 ) ( 80 )
=50.99
@> D"(4 #"'" @ D820 H 83K S810
EOQ=Q∗¿
√(
2 ( D ) ( S )
P ) (C )
2 ( 520 ) ( 10 )
(36 )
=29.43
)> C+"-%( 4$ -)'$*$-" $ "*"<( %$ ($ 4+@$ $ )(4( %$ -$-"'(.
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D"(4 D8 100000 S81000 H 8 PC 8 30 "> EOQ=Q∗¿
√(
2 ( D ) ( S )
P ) (C )
=
√
2 ( 100000 ) ( 1000 )
( 0.30 ) (100 )
=2581.98
@> N =
D 100000 = =38.72 Q 2581.98
)> CT =
D ( S ) + Q ( H )= 100000 (1000 )+ 2581.98 ( 30 )=42602.78 2 2581.98 2 Q
%> U- -)'$*$-( $- " %$*"-%".
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EOQ=Q∗¿
√
2 ( D ) ( S )
H
=
√
2 ( 12000 ) ( 25 )
( 6.25 )
=309.83
@> E- "*"<(4 %$ 20 #(' 4$*"-" $-%'6" +- )(4( %$ .72 D820 4$*"-" S82 H8K.2
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√
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H
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√
2 ( 250 ) ( 25 )
( 6.25 )
= 44.72
S$*"-" C =
Q ( H )= 44.72 ( 6.25 ) =139.75 2 2
)> D 8 7=0000 EOQ=Q∗¿
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2 ( 780000 ) ( 25 )
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=789.93
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"> E #+-( %$ '$('%$- $4 %$ 2 D"(4 * 8 00 +%4 8 1.7
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Q 8 20 R= m+ ( ᵶ∗ ṓ )=500∗( 1.7∗250 )=925
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inventario medio= s +
Q 2
Q
309.83
2
2
= zxT + = 850 +
=1004.91
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2 ( S )
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2 ( 25 ) .25) ( 400 ) ( 200)
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Q 8 0.1 R= m + ( ᵶ∗ṓ )=5∗( 3∗0.1 )=5.3
C"*@( %$ %$4")F- $4-%"' * 8 200/0>>83.2 8 3
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Q 8 0.1 R= m + ( ᵶ∗ṓ )=3.2∗( 2.6∗.5 )=4.45
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Q 10 = =.05 D 200
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Q ( Z ṓ )= 10 (1.900∗.95 )= 9.025 2 2
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P"'" #8
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S(+)F- "> EO D"(4 D 8 00 S 8 0.00 H 8 PC 8 0.00 .2 8 10 2 ( D ) ( S ) 2 ( 500 ) ( 40 ) EOQ= = =63.24 H ( 10 )
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√
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R= m + z∗T =¿
R1 8 =0 1.03 2 8 =2.07 -$+*)(4, #"'" +- -$ %$ 4$')( %$ =;. R2 8 =0 1.30 2 8 =2.K0 -$+*)(4, #"'" +- -$ %$ 4$')( %$ 0 ;. R3 8 =0 1.K 2 8 =3.30 -$+*)(4, #"'" +- -$ %$ 4$')( %$ ;. R 8 =0 1.0 2 8 =3.0 -$+*)(4, #"'" +- -$ %$ 4$')( %$ 7 ;. R 8 =0 2.37 2 8 =.7 -$+*)(4, #"'" +- -$ %$ 4$')( %$ ; )> + -$ %$ 4$')( $4"@$)$'6" +4$% )(- @"4$ $- " 5')" %$ " #"'$ @ )(*$-$ N.S. I-$-"'( *$%( V"(' %$ -$-"'( 0.= 8 1.03 2 K3.2/2 8 33.K +-%"%$4 33.K : =0 8 : 2K.20 0.0 81.300 2 K3.2/2 8 3.22 +-%"%$4 3.22 : =0 8 : 2737.K0 0. 81.K0 2 K3.2/2 8 3.2 +-%"%$4 3.2 : =0 8 : 273.K0 0.7 81.00 2 K3.2/2 8 3.2 +-%"%$4 3.2 : =0 8 :2=33.K0 0. 82.370 2 K3.2/2 8 3K.3K +-%"%$4 3K.3K : =0 8 : 20=.=0
Valor del Inventario Medio VS Nivel de Servicio %
nivel de servicio %
100 98 96 94 92 90 88 86 84
$2,800.00 $2,600.00 $3,000.00 Valor deInventario Medio
nivel de servicio %
E -$ **( %$ 4$')( &" +$ -( $4 "- 45-)"-$ " %$'$-)" $- )(4(4 $" )(*#"'")F-. 10.! P"'" (4 %"(4 %$ #'(@$*" . "> A )")+$ " '(")F- "-+" )(*( +-" +-)F- %$ -$ %$ 4$')( @> S "4 $-"4 4$ -)'$*$-"'"- +- 0;. +$ ()+'''6" )(- " '(")F- $- +-$ %$ 4$')( %$ ; "> R(")F- "-+" Í-%)$ %$ '(")F-8 $-"4$4 %$)' %$*"-%">/-$-"'( *$%( IR =
Demanda inventario medio
Ir ( 85 ) =
Ir ( 90 ) =
Ir ( 95 ) =
5000 33.69 5000 34.22 5000 34.92 5000
Ir ( 97 ) =
Ir ( 99 ) =
35.42 5000 36.36
=148.41 =141.11 =143.18 =141.16 =137.51
@> I-)'$*$-( $- " $-"4 %$ 0; " -$ %$ 4$')( %$ ; EO -)'$*$-( %$ 0; D"(4 D 8 700 S 8 0.00 H 8 PC 8 0.00 .2 8 10 2 ( D ) ( S ) 2 ( 7500 ) ( 40 ) EOQ= = =244.94 H ( 10 )
√
√
N.S. I-$-"'( *$%( V"(' %$ -$-"'( 0. 81.K0 2 2./2 8 12.77 +-%"%$4 12.77 : =0 8 : 100K1.K0
Ir ( 95 ) =
7500 125.77
=59.63
E 6-%)$ %$ '(")F- "+*$-" )(- '$4#$)( " " $-" %$ 000 +-%"%$4 $- $ 45+$-$ #(')$-"9$
I . r . ( 95 ) para 7500 unidades − I . r . ( 95 ) para 5000 unidades I . r . ( 95 ) para 5000 unidades
59.63 −143.18 56.63
8
=−1.48∗100 =148
C(-)+4(-$4 P"'" +- -$ %$ 4$')( %$ ;, +- -)'$*$-( %$ 0; $- "4 $-"4, #'(%+)$ +- %$)'$*$-( #(')$-+" *"&(' $- " '(")F- %$ -$-"'(4, $- $ ('%$- %$ 1=;.
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D$*. A-+", &"'%"4 300 200 100
C(4( "'. P(' &"'%" 10 = K
S+#(-5" +$ (4 "'6)+(4 4$ ('%$-"- 9+-(4 " *4*( #'($$%(' )(- +- )(4( %$ ('%$-"' #$%%(4 %$ :20 #(' ('%$- & +- )(4( "-+" #(' $"' $ -$-"'( %$ 20;. T"*@- 4+#(-5" +$ 4$ "@('"- 300 %6"4 " "<(. "> U"-%( +- 44$*" P, ?)+" $4 $ -$'"( F#*( %$ ('%$- $- %6"4 @> ?C+-( %$ )"%" #( %$ "(*@'" 4$ ('%$-"'" $- $ )"4( %$ )(()"' +-" ('%$- )(*@-"%" )> ?C+ $4 $ $$)( 4(@'$ $ -$'"( %$ ('%$- " )"*@"' $ )(4( %$ -$-"'( 2, 30 & 3; "> I-$-"'( F#*( %$ ('%$- $- %6"4.
D"(4 P8 D8 300 C8:= S8 :20 2 DS
C
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2 S
CD
Q 1 P = = √ ¿ D D
2 ( 300)( 20 ) 8
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2 ( 20 ) 8 ( 300 )
Q 1 P = = √ ¿ D 300
P=3.33 = 38.72+ .13
P=38.85
@> ?C+-( %$ )"%" #( %$ "(*@'" 4$ ('%$-"'6" $- )"4( %$ )(()"' +-" ('%$- )(*@-"%" A 300 K> 81=00 B 200 10>8 2000 C 100 => 8 =00 )> ?C+ $4 $ $$)( 4(@'$ $ -$'"( %$ ('%$- " )"*@"' $ )(4( %$ -$-"'( " 2, 30 & 3; 1=00 2; 8 0 2000 30; 8 K00 =00 3; 8 2=0 %> ?P(' + -( 4$ #+$%$- ('%$-"' $4"4 "(*@'"4 *$%"-$ +- 44$*" P('+$ )(- $ 44$*" de P se obtiene un resultado fjo
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13.! S+#(-5" +$ +4$% $4 $ #'($$%(' %$ " )(*#"<6" E"4&(( %$4)'( $- $ #'(@$*" 12. C+$4" :2000 )"%" $ +$ +4$% )"*@" %$ *"+-" #'(%+)('" %$ "(*@'"4 %$ +- #( " ('( A, B, C>. S+#(-5" +$ $ )(4( %$ -$-"'( $4 %$ 30; & (4 ('(4 %"(4 4(- (4 +$ 4$ %"- $- $ #'(@$*" 12. )> +$ "*"<(4 %$ ($ #'$$''6" $ #'($$%(' %$ "(*@'"4 "@')"' %$ (4 #(4 A, B, C %> C(*( )(-4"'" +4$% (4 "*"<(4 %$ ($ +$ $ #'($$%(' #'$$'$ "@')"' %$ (4 #(4 )(- "+$(4 +$ " )(*#"<6" E"4&(( $ 5+4"'6" )(*#'"'.
1. S+#(-5" +$, #"'" $ #'(@$*" 1, " " $-%" S#$$%& G'()$'& 4$ $ ('$)$ +%$4)+$-( 4 4$ ('%$-"- *4 %$ 0 )"9"4 " " $. L(4 )(4(4 +-"'(4 %$ "')+( 4(- :=0 +-" )"9" #"'" ('%$-$4 %$ 0 " )"9"4 & %$ :7K #"'" 0 )"9"4 ( *4. E4$ #'$)( %$ :7K 4$ "#)" " " ('%$- $-$'". "> ?D$@$ ")$#"' " $-%" $ %$4)+$-( ('$)%( @> ?+ %$4)+$-( 4$ '$+$'$ "-$4 %$ +$ " $-%" 4$" -%$'$-$ " (*"' $ %$4)+$-( ( " ('%$-"' " EO "> C"-%"% %$ #$%%( 0! :=0.00 0 :7K.00 D8 20 )"9"4 #(' "<( S8 :10.00 #(' ('%$P8 30; 2 ( 520 ) ( 10 ) 2 DS Q∗¿ = = H ( 0.30 ) ( 80 )
√
√
P'$)( #(' +-%"%
√
10,400 24
= √ 433.33=20.81
D Q 10 ( 10 ) + 20.81 ( 24 )+10 ( .30 ) =4.8 + 249.6 + 3=257.4 TC = ( S )+ ( H ) + PD = Q 2 20.81 2
@>
Q∗¿
√
2 D S
H
=
√(
2 ( 520 ) ( 10 ) 0.30 ) ( 76 )
=
√
10400 22.8
=√ 456.14 =21.35
D Q 10 TC = ( S )+ ( H ) + PD = ( 10 )+ 21.35 ( 22.8 )+ 10 ( .30 ) Q 2 21.35 2
TC = 4.68 + 243.39 + 3 =293.19
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TC =46.6 + 46.6 + 1.5 =94.7
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TC = 47.4 + 47.4 + 1.5=96.3
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