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APU 2014Full description
RESOLUCION DE ECUACION DE 2° GRADO
〖 〗
+ b +
c ==0
X1= X1=
3
X2 =
-7
a
b
3
12
c -63
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RESOLUCION DE ECUACION DE 4° GRADO
〖 〗 b
+ + c = 0
a
b
-3
5
c 2
Discriminate Raiz Discrim. 1ªSolucion
=
2ªSolucion
X1= X1 =
Err:502
La ecuación n !ene s"ucines rea"es
X2 =
Err:502
La ecuación n !ene s"ucines rea"es
X3= X3=
1.#1#213562#
La ecuación !ene s"ucines s"ucines rea"es
X# =
-1.#1#213562#
La ecuación !ene s"ucines s"ucines rea"es
〖 〗
-
#ac = =
-0.3333333 2
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#$
El discriminante es posivo
7 333
La ecuación posee dos soluciones reales y disntas
SI(-D2-I14<00D2!I14"#(2$%2"
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Ecuación cua%ra!ca
X² + 2X + 1 = 0
=
X1 = X1 =
-0.1055728 -1.8944272
5 10 1
Coloca esta foó foó rmula en la celda D5 & (-$E$6(!"#(($E$6%&2-4'$E$5'$E$7%%%(2'$E$5%
,os datos deen r en las celdas /1 /2 /... estos datos son los nuó nuó mero 3ue multlcan a )* ) una constante es decr decr eemlcando Coloca esta formula formula en la celda D6
& (-'E'-()*I+(('E'",2-4$'E'$'E'."""#(2$'E'"
)* 2) 1 + 0 E5 + 1 E6 + 2 E7 + 1 en forma automatca D5 + -1 D6 + -1 or lo tanto tene solucoó solucoó n uóuó nca de ) + -1
SI(-D2-I14<0
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