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Tabel Momen Primer Cross
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Tabel Momen Primer Cross
Momen Primer CrossDeskripsi lengkap...
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TABEL MOMEN PRIMER Cross (soemono) dan Slope Deflection (c! "ia #an$)
∑ N o
1
Pembebanan
3
MBA =
5
1 qL2 12 = MBA
MBA = MAB =
1 5 qL qL2 192 11 qL2 192
MBA =
1 qa2 (3L2a) 6L
MAB
4
= # = # = #
Momen Primer
MAB
2
M $ %
MBA = MAB =
MBA = MAB MBA =
= MBA qaLα2 (4 - α ) 12 1 qaL qa Lα (3α2 - 8α +6) 12 α = a/L 1 qb (3L2b2) 24L = MBA - (q/L2)
1 3
L(a23-
a13) 1
-
6 MAB =
4
(a24 ! a14)"
2
(q/L ) a12)
1 2
L2(a22-
2
-
L(a23 ! a13)
3 1
+
4
(a24 ! a14)"
&
MBA = MAB =
1 qL2 3# qL2 2#
8
MBA = MAB =
1 qa3 (5L ! 3a) 6#L2 qa2 (3a2 + 1#bL ) 6#L2
MBA = MAB =
1 qa3 (5L ! 4a ) 2#L2 qa2(1#L2- 5aL+ 8a2) 3#L2
MBA =
1 qa (5L2 +4aL - 4a2) 96L
9
1 #
1 1
1 2
MAB
MBA =
= MBA
1 5qL2 96
MAB
= MBA
MBA =
1 qL2 32
MAB
= MBA
1 MBA 3 MAB =
1 4
1 5
=
1 L2 ( 2q1 + 3q2 ) 6# L2 ( 3q1 + 2q2 ) 6#
MBA
=
1 qa2 (2La) 24L
MAB
=
MBA
MBA =
1 qa2 (4L3a) 12L
MAB =
MBA
MAB =
1 qL2 (1 - α2 (2-α )" 12
MBA =
MAB
α = a/L
1 6
1 qL2 (1 + α + α21'5α3) 3#
MBA = 1 &
1 8
1 9
MAB =
qL2(1 + + 21'53) 3# α = a/L = b/L
MBA = MAB
1 qL2 15 = MBA
MBA =
1 qL2 15
MAB =
qL2 2#
2 #
2 1
2 2
MBA =
1 PL 8
MAB
= MBA
1 Pba2 L2
MBA = MAB =
Pab2 L2
MBA =
1 Pa (L ! a) L
MAB
= MBA
1 PL (n2 + #'5) 12n
MBA = 2 3
MAB
= MBA n = L/a
MBA 2 4
=
Ma(3α - 2) L MAB = Mb(3 - 2) L α = a/L = b/L
TABEL MOMEN PRIMER Cross (soemono) dan Slope Deflection (c! "ia #an$) Pa*a e,ea.an ei 0en*i *a,am ab,e ini .ami ana menambar.an e,ea.an 0en*i ei 0eeri
an mana ara M AB 0en*iri a*a,a 0eara *enan ara arm am 0eina beran*a o0ii7 eina 0e,r ni,ai *i ab,e ini berni,ai o0ii7' n. i i.a an*a menem.an ba,o. *enan e,ea.an an 0eeri
an mana ara MBA 0en*iri a*a,a ber,a:anan *enan ara arm am 0eina beran*a neai7 ma.a na.an ni,ai ab,e *i ba:a ini *enan 2 ni,ai neai7 ;ono momen rimer no 1 a*a,a momen rimer - 9qL no 2 a*a,a '*0 128 qL2 No Pembebanan Momen Primer 1
MAB =
qL2 16 2
MAB =
9 qL2 128
3
MAB =
& qL2 128
4
MAB =
qa2 (3L ! 2a ) 4L 5
MAB =
qa2 (2α)2 8
α a/L 6
MAB =
qb2 (22) 8
b/L &
MAB =
qb (*2- ;2)(2L2;2- *2) 3# 8
MAB =
2qL2 3#
9
MAB =
&qL2 12#
1#
MAB =
qa2 (3a2- 15aL + 2#L2) 12#L2
11
MAB =
qa2 (α2/5- 3α/4 + 2/3) 2
α a/L 12
MAB =
qb2 (1#L23b2) 12#L2
13
MAB =
qb2 (5L2+ 4aL 4a2) 2 14
2 MAB = qa qL qL22 (1 ( (14L 2L !+α -) ) 2 MAB 5qL(2 a 3a (&)!!) α) 32) 64 = 8 8L 12# α a/L
15
3qL2 64
MAB =
16
1&
18
19
MAB
=
L2 (8q1 + &q2) 12#
2#
21
qL2 1#
MAB =
22
qL2 12
MAB =
23
MAB =
α
M (2 - 6α + 3α2) 2
=a/L 24
MAB =
3PL 16
25
MAB
= Pb (L2 - b2) 2L2 26
MAB
= 3Pa (L - a) 2L 2&
MAB
= PL (n2 - 1) 8n L
n=
a
28
MAB
= PL (n2 - 1) 8n L
n=
a
29
MAB
= PL (n2 + #'5) 8n L
n=
a
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