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Analisis Struktur Statis Tak Tentu
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Analisis Struktur Statis Tak Tentu
Portal Bergoyang Teknik Sipil Analisis struktur statis tak tentuDeskripsi lengkap...
Author:
Syeni Hastorini
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TUG AS ANALISIS STRUKTUR STATIS TAK TENTU Dosen
: Ir. Soetoyo
Suatu portal bergoyang dengan ukuran/dimensi seperti gambar dibawah ini :
Pertanyaan : a. Gambar bidang momen portal b. Gambar bidang geser c. Gambar bidang normal
1 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
Inersia IAB
Faktor Kekakuan =
KBA
=
= m4
= IBC
KBC (
)(
= =
= =
= KCB =
)
m4
= ICD
=
= =
=
(
)(
)
KCD
=
m4
=
= KDC
= ICE
= = =
(
)( m4
=
) KCE
= =
IDF
= = = =
m4
KDF
= = =
2 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
Faktor Distribusi µBA
µBC
=
µCB
=
=
=
= 0.12
= 0.37
=
µCD
= =
=
= 0.49
= 0.88 µCE
= = = 0.14
µDC
= = = 0.81
µDF
= = = 0.19
3 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
Momen Primer MBA
==-
(
)(
)
= -2.29 tm = -2290 kgm MBC
= =
( )( )(
)
= 0.72 tm = 720 kgm MCB
= ( )( )(
=
)
= -0.48 tm = -480 kgm MCD
= =
(
)(
)
= 4.4 tm = 4400 kgm MDC
= -4400 kgm
MDF
= =
(
)( )
= 1.125 tm = 1125 kgm MFD
= -1125 kgm
4 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
5 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
Perhitungan gaya dorong balok BCD
Gaya geser kolom AB
A
RB
RB
= (1500)(3.5) + MBA/L = 5250+555.14 = 5805.14 kg
B Gaya geser kolom CE MCE C
Rc RC
= MCE/LCE = 1008/5 = 201.6 kg
E
Gaya geser kolom DF RD RD
RF
∑D
D
= -(1/2P+(MDF-MFD)/LDF) = -(750+238) = -988 kg
F
= RB+RC+RD = 5018.74 kg
6 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
Portal diberi simpangan sebesar ∆, sehingga timbul momen primer pada kolom BA sebesar : MBA= + 1.000 kgm MBA = ∆
= 1000 kgm
= =
(
)
=
m
MCE karena ∆ : MCE
= =
(
)
= 5794.65 kgm MDF karena ∆ : MDF
= =
(
)
= 5925.925 kgm
7 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
8 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
Gaya dorong balok BCD akibat pergeseran
Kolom AB MBA A
RB
RB
= MBA/LAB = 962/3.5 = 274.86 kg
RB
= -MCE/LCE = -5293/5 = -1058.6 kg
B Kolom CE MCE RC
C
E Kolom DF MDF RD RD
D
RF
= -(MDF+MFD)/LDF = -(4971+5444)/6 = -1735.83 kg
F MFD
∑D’
= 274.86-1058.6-1735.83 = -2519.57
9 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
∑D + β∑D’
=0
5018.74 + β(-2519.57)
=0
Β
= 1.99
10 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
11 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
Diagram Normal
Diagram Geser +600
+16250 +400 +750
+274.86 -16250
-5250
+750
12 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
Diagram Momen -4833.18
-4689.9
+28.62 +9525.07
+7813.29
-28.62
+10182.56
13 Tugas Analisis Struktur Tak Tentu Syeni Hastorini
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