PROBLEMAS DE VECTORES

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PROBLEMAS DE VECTORES Uploaded by Maria Bonilla Morales

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Solucionario Capitulo 3 - Paul

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1.- Tres sogas están atadas a una estaca, sobre de ella actúan tres t res fuerzas: A 20 N, E; B= 30N, 30 grados, N del O y C= 40N, 52 grados, S del O. Determine la fuerza resultante usando el método de las componentes.

VECTOR A= 20N B= 30N

ANGULO 0° 30°

C= 40N

40°

COMPONENTE EN X Ax= 20N Bx= -Bcos30° -Bco s30° = -(30N)(.866) = -25.9N Cx= -Ccos52° -Cco s52° = -(40N)(.6156) = -24.6N

Rx= Ax Ax + (-Bx) + (-Cx) = 20N - 25.9N - 24.6N = 30.5 N

COMPONENTE EN Y Ay= 0 By= Bsen30° = (30N)(.5) = 15N Cy= -Csen52° = -(40N)(.7880) = -31.52N

Ry= Ay + By + (-Cy) Sign up to vote on this title = 0N + 15N – 31.52N  Useful  Not useful = -16.52N

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2.-Halle la resultante de las siguientes fuerzas perpendiculares: a) 400N, O; b) 820N, 270 grados y c) 500N, 90 grados.

VECTOR

ANGULO

A= 400N B= 820N C=500N

0° 270° 90° Rx= 400N

                      

COMPONENTE X Ax= 400 400N N Bx= 0N Cx= 0N

COMPONENTE Ay= 0N By= -820N Cy= 500N

Ry= -320N

         

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VECTOR A= 40N B= 80N C= 70N D= 20N

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ANGULO 0° 90° 180° 270°



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COMPONENTE X Ax= 40N Bx= 0N Cx=-70N Dx= 0N

COMPONENTE 0N 80N 0 -20N

You're Reading a Preview

Rx= -30N

Ry= 60N Unlock full access with a free trial. Download With Free Trial

                    R= 67N

       

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4.-Dos fuerzas actúan sobre el automóvil, la fuerza A es igual a 120N, hacia el

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VECTORES

ANGULOS

A=120N B= 200N

O° °



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COMPONENTE X Ax= -120N Bx= -B ° = (200N) (.5) You're Reading a Preview = -100N



COMPONENTE Y Ay= 0N By= B  = (200N) (.866) = 173.20N



Unlock full access with a free trial.

Rx= -220N

Ry= 173.20N

Download With Free Trial

                       

      

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You're Reading a Preview Unlock full access with a free trial.


VECTOR

ANGULO

A=600N B= 400N

90° 20°

COMPONENTE X

COMPONENTE Y  this title Ax= 0NSign up to vote onAy= 600N useful  Not Bx= -b Useful By= B   By= (400N) (.342 By= 136.8N Bx= -375.8N

  

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              R= 695.10N

6.-Calcule la resultante de las siguientes fuerzas aplicando el método de las componentes. A= (200N, 30 grados), B= (300N, 330 grados), C= (400N, 250 grados)

You're Reading a Preview Unlock full access with a free trial.


VECTOR A=200N

ANGULO 30°

B= 300N

330° 30°

C= 400N

250° 70°

COMPONENTE X Ax= A  = (200N) ( .866) = 173.2N Bx= B 

COMPONENTE Ay= A  = (200N) (.5) = 100N By= -B  By= -(300N) (.5) By= 150N  Bx= 259.8N on this Cx= -C -Ctitle  Sign up to voteCy=  Not useful  Useful Cy= Cx= -(400N) (.3420) -(400N) (.9396) Cx= -136.8N Cy= -375.8N





   

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