Perhitungan Dan Grafik Peluncuran

PERHITUNGAN DAN GRAFIK PELUNCURAN

Ukuran utama dan koefisien bentuk : Lpp = 89

m

B

= 14.30 m

H

= 6.66 m

T

= 5.60 m

Cb = 0.741 Cwl = 0.816 Cm = 0.987 Cp = 0.751

I. Perhitungan berat kapal dan titik berat kapal Dipakai metoda Lloyd’s Register 1964. Register 1964. 1. Berat badan kapal sampai dengan upper deck. Beban merata : q = a * m (t/m) Dimana : m

= 43.4 * H * L/10 4 (t/m)

a

= f(Cb), didapatkan dari grafik gambar 3 dan gambar 4.

H

= C1 * B + C2 * D + C 3 * d + C4 * W0 * NT + C5 + 2.5h

L

= 89

B

= 14.3 m.

D

= 6.66 m.

d

= 5.6

m.

m.

C1 sampai dengan C4 = f(Wd), didapatkan dari grafik gambar 1b. Wd

= jumla deck

C1

= 1.048

C3

= 1.05

C2

= 1.1

C4

= 1.1

W0

= f(L), didapatkan dari grafik gambar 1a.

W0

= 0.284

C5

= f(L), didapatkan dari grafik gambar 2.

C5

= -5.2

Panambahan C5 Dengan adanya sekat memanjang, ada penambahan C 5 C5

= 11 (l/L) W0

l

= panjang total sekat memanjang, 112.9 m.

C5

= 11 (112.9/89) 0.284 = 3.965

C5

= -5.2 + 3.965 = -1.235

NT

= jumlah sekat melintang, 7 buah

h

= tinggi pelintang alas, 0.37 m.

H

= 1.408 * 14.3 * 1.1 * 6.66 + 1.05 * 5.6 + 1.1 * 0.284 * 7 – 1.235 + 2.5 * 0.37

H

= 35.223

I. Perhitungan berat kapal dan titik berat kapal Dipakai metoda Lloyd’s Register 1964. Register 1964. 1. Berat badan kapal sampai dengan upper deck. Beban merata : q = a * m (t/m) Dimana : m

= 43.4 * H * L/10 4 (t/m)

a


H

= C1 * B + C2 * D + C 3 * d + C4 * W0 * NT + C5 + 2.5h

L

= 89

B

= 14.3 m.

D

= 6.66 m.

d

= 5.6

m.

m.

C1 sampai dengan C4 = f(Wd), didapatkan dari grafik gambar 1b. Wd

= jumla deck

C1

= 1.048

C3

= 1.05

C2

= 1.1

C4

= 1.1

W0

= f(L), didapatkan dari grafik gambar 1a.

W0

= 0.284

C5

= f(L), didapatkan dari grafik gambar 2.

C5

= -5.2

Panambahan C5 Dengan adanya sekat memanjang, ada penambahan C 5 C5

= 11 (l/L) W0

l

= panjang total sekat memanjang, 112.9 m.

C5

= 11 (112.9/89) 0.284 = 3.965

C5

= -5.2 + 3.965 = -1.235

NT

= jumlah sekat melintang, 7 buah

h

= tinggi pelintang alas, 0.37 m.

H

= 1.408 * 14.3 * 1.1 * 6.66 + 1.05 * 5.6 + 1.1 * 0.284 * 7 – 1.235 + 2.5 * 0.37

H

= 35.223

m

= 43.4 * 35.223 * 89/10 4 = 13.605 t/m

q

= a * m (t/m)

a


Dari grafik gambar 3 dan gambar 4, untuk m = 13.605 t/m, diperoleh : q=m*a

FAKTOR

(t/m)

SIMPSONS

STATION

a

q*S

n

q*S*n

AP

0.32

4.354

1

4.354

-10

-43.536

1

0.462

6.281

4

25.126

-9

-226.133

2

0.612

8.333

2

16.666

-8

-113.33

3

0.713

9.704

4

38.818

-7

-271.726

4

0.803

10.929

2

21.858

-6

-131.148

5

0.866

11.78

4

47.117

-5

-235.586

6

0.91

12.38

2

24.761

-4

-99.044

7

0.957

13.015

4

52.062

-3

-156.185

8

1

13.605

2

27.21

-2

-54.42

9

1

13.605

4

54.42

-1

-54.42

10

1

13.605

2

27.21

0

0

11

1

13.605

4

54.42

1

54.42

12

1

13.605

2

27.21

2

54.42

13

1

13.605

4

54.42

3

163.261

14

1

13.605

2

27.21

4

108.841

15

0.966

13.14

4

52.559

5

262.796

16

0.915

12.449

2

24.897

6

149.384

17

0.819

11.145

4

44.581

7

312.068

18

0.667

9.069

2

18.138

8

145.106

19

0.45

6.122

4

24.489

9

220.403

FP

0.12

1.632

1

1.632

10

16.325

∑1= 669.162

∑2 = 101.496

W = 1/3 * L/20 * 1 = 1/3 * 4.45 m * 669.162 t/m = 992.59 t Titik berat badan kapal terhadap midship = 1/2

= 101.496/669.162 * 4.45 m = 0.675 m

1.1 Berat badan kapal di ujung belakang. (dibelakang AP sepanjang 0.05 Lpp)

W = 0.01133 * m * Lpp (t) W = 0.01133 * 13.605 t/m * 89 m = 13.719 t Distribusi beban berbentuk parabola dibelakang AP sepanjang 0.05 L

Letak titik berat berat terhadap midship midship

= - (89 m/2 + 2/5 * 0.05 * 89 m) = - 46.28 m

1.2 Berat badan kapal diujung depan (didepan FP sepanjang 0.025 Lpp)

W = 0.00175 * m * Lpp (t) W = 0.00175 * 13.605 t/m * 89 m = 2.119 t Distribusi beban berbentuk segitiga didepan FP sepanjang 0.025 Lpp

Letak titik berat berat terhadap midship

= + (89 m/2 + 1/3 * 0.025 * 89 m) = 45.242 m

Titik berat badan kapal sampai upper deck terhadap midship = 992.59 t * 0.675 m + 13.719 t * (-46.28 m ) + 2.119 t * 45.242 m 1008.428 t Titik berat badan kapal sampai upper deck terhadap midship = 0.1298 m

2. Berat lokal 2.1 Perhitungan fore peak tank dan letak titik beratnya terhadap midship Panjang tangki ceruk haluan = 7.656 m Berat tangki ceruk haluan, W = 0.0538 V (t), dimana V = volume tangki (m 3)



= W/V = 0.0538 t/m 3

NOMOR

 (t/m3) *

FAKTOR

q*S

GADING

A(m2) * q(t/m)

SIMPSONS

(t/m)

127

2.582

1

128

2.356

129

n

q*S*n

2.582

0

0

4

9.426

1

9.426

2.141

2

4.282

2

8.565

130

1.926

4

7.704

3

23.112

131

1.711

2

3.422

4

13.686

132

1.453

4

5.81

5

29.052

133

1.151

2

2.303

6

13.816

134

0.839

4

3.357

7

23.5

135

0.646

2

1.291

8

10.33

136

0.495

4

1.98

9

17.82

137

0.355

2

0.71

10

7.102

138

0.247

4

0.99

11

10.89

139

0

1

0

12

0

1 =

43.858

2 =

167.298

W = 1/3 * 0.638 m * 43.858 t/m = 9.327 t Letak titik berat terhadap gading nomor 127 = 167.298/43.858 * 0.638 m = 2.434 m Letak titik berat terhadap midship = 37.004 m + 2.434 m = 39.438 m

2.2 Perhitungan after peak tank dan letak titik beratnya terhadap midship Panjang tangki ceruk buritan = 7.656 m Berat tangki ceruk buritan, W = 0.0538 V (t), dimana V = volume tangki (m 3)



= W/V = 0.0538 t/m 3

NOMOR

 (t/m3) *

FAKTOR

q*S

GADING

A(m2) * q(t/m)

SIMPSONS

(t/m)

6`

0.124

1

5`

0.186

4`

n

q*S*n

0.124

-12

-1.485

4

0.742

-11

-8.167

0.253

2

0.506

-10

-5.057

3`

0.333

4

1.334

-9

-12.008

2`

0.414

2

0.828

-8

-6.628

1`

0.495

4

1.98

-7

-13.859

AP

0.581

2

1.162

-6

-6.972

1

0.699

4

2.798

-5

-13.988

2

0.807

2

1.614

-4

-6.456

3

0.936

4

3.744

-3

-11.233

4

1.081

2

2.163

-2

-4.325

5

1.237

4

4.95

-1

-4.95

6

1.399

1

1.399

0

0

23.344

2 =

1 =

-95.129

W = 1/3 * 0.638 m * 23.344 t/m = 4.964 t Letak titik berat terhadap gading nomor 6

= -95.129/23.344 * 0.638 = -2.6 m

Letak titik berat terhadap midship = -40.194 m – 2.6 m = -42.794 m

2.3 Perhitungan berat fuel oil tank dan letak titik beratnya terhadap midship Seperti terlihat pada gambar dibawah : -

Lebar ruang pompa pada daerah fuel oil tank

=6m

-

Tinggi ruang pompa

= 7.7 m

Maka luas dinding ruang pompa = 6 m * 7.7 m

= 46.2 m 2

Perhitungan luas dinding melinteng keseluruhan dari fuel oil tank pada tiap nomor gading : Luas diding tersebut adalah luas penampang kapal dikurangi dengan luas dinding ruang pompa, semua peninjauan dilakukan pada nomor gading yang sama. Luas dinding fuel oil tank pada tiap nomor gading (A) : No. gading

27 = 76.2 m2 – 46.2 m2

= 30

m2

28 = 77.9 m 2 – 46 2 m2

= 31.7 m2

29 = 79.2 m 2 – 46.2 m2

= 33

30 = 80.7 m 2 – 46.2 m2

= 34.5 m2

31 = 81.8 m 2 – 46.2 m2

= 35.6 m2

32 = 83 m 2 – 46.2 m2

= 36.8 m2

33 = 84.3 m 2 – 46.2 m2

= 38.1 m2

34 = 85.4 m 2 – 46.2 m2

= 39.2 m2

35 = 86.4 m 2 – 46.2 m2

= 40.2 m2

m2

Berat fuel oil tank, W= 0.0538 V(t), dimana V= Volume tangki (m 3)

γ

= W/V = 0.0538 t/m 3

NOMOR

 (t/m3) *

FAKTOR

q*S

GADING

A(m2) * q(t/m)

SIMPSONS

(t/m)

27

1.614

1

28

1.705

29

n

q*S*n

1.614

-8

-12.912

4

6.822

-7

-47.754

1.775

2

3.55

-6

-21.3

30

1.856

4

7.424

-5

-37.12

31

1.915

2

3.83

-4

-15.32

32

1.98

4

7.92

-3

-23.76

33

2.05

2

4.1

-2

-8.2

35

2.109

4

8.436

-1

-8.436

35

2.163

1

2.163

0

0

45.859

2 =

1 =

-174.802

W = 1/3 * 0.638m * 45.859 t/m = 9.753 t Letak titik berat terhadap gading nomor 35 = -174.802/45.859 * 0.638 m = -2.432 m Letak titik berat terhadap midship = -2.432 m – 22 m = -24.432 m

2.4 Perhitungan berat ruang pompa dan titik beratnya terhadap midship. Berat ruang pompa, W = 0.1005 V (t), dimana V = Volume ruang pompa (m 3) Ruang pompa dibagi menjadi 2 bagian, seperti terlihat pada gambar sebelumnya. -

Bagian I o

Lebar

=6m

o

Panjang

= 8 * 0.638 m = 5.104 m

o

Tinggi

= 7.7 m

Volume bagian I

= 6 m * 5.104 m * 7.7 m

= 235.805 m 3

Berat bagian I

= 0.1005 * 235.805

= 23.698 t

Letak titik berat bagian I terhadap midship

= -(5.104m/2 + 21.938m) = -24.49 m

-

Bagian II

Berat ruang pompa, W = 0.1005 * V (t), dimana V = Volume ruang pompa (m 3)



= W/V = 0.1005 t/m 3

NOMOR

 (t/m3) *

FAKTOR

q*S

GADING

A(m2) * q(t/m)

SIMPSONS

(t/m)

35

8.683

1

35`

8.733

36

8.784

n

q*S*n

8.683

-2

-17.366

4

34.934

-1

-34.934

1

8.784

0

0

1 =

52.4005

2 =

-52.3

Berat bagian II = 1/3 * 0.319 m * 52.4005 t/m = 5.572 t Letak titik berat terhadap gading nomor 36 = -52.3/52.4005 * 0.319 m = - 0.3184 m Letak titik berat terhadap midship

= -(0.3184 m + 21.3 m) = -21.618 m

Berat keseluruhan ruang pompa

= 23.698 t + 5.572 t = 29.27 t

Letak titik berat terhadap midship

=

 t(- m)  t- m  t

= -23.943 m

2.5 Baling baling dan poros diluar kamar mesin W

= ls (0.01641 + S) (t)

Ls

= panjang poros dari baling baling diluar kamar mesin, 2.75 m

S

= f (ls/L), didapatkan dari grafik gambar 5a.

Ls/L

= 2.75 m/89 m = 0.031, S = 5

W

= 2.75 (0.0164 * 89 + 5) = 17.764 t

Distribusi beban berbentuk segiempat Letak titik berat terhadap AP = ls/2 + 1.825 m = 3.2 m

Letak titik berat terhadap midship = - (Lpp/2 – 3.2 m) = -41.3 m

2.6 Perhitungan berat slop tank dan titik beratnya terhadap midship Seperti gambar di bawah ini : -

Lebar cargo oil tank V tengah, pada daerah slop tank

=4m

-

Tinggi cargo oil tank

= 6.7 m

Maka luas didind cargo oil tank = 4 m * 6.7 m = 26.8 m 2 Perhitungan luas dinding keseluruhan slop tank sama caranya denga fuel oil tank. Luas dinding keseluruhan slop tank pada tiap nomor gading (A) : No. gading

36

= 87.4 m 2 – 26.8 m2

= 60.6 m 2

37

= 88.1 m 2 – 26.8 m2

= 61.3 m 2

38

= 88.6 m 2 – 26.8 m2

= 61.8 m 2

39

= 89.1 m 2 – 26.8 m2

= 62.3 m 2

40

= 89.6 m 2 – 26.8 m2

= 62.8 m 2

Berat slop tank, W = 0.0538 V (t), dimana V = Volume tangki (m 3)

γ

= W/V = 0.0538 t/m 3

NOMOR

 (t/m3) *

FAKTOR

q*S

GADING

A(m2) * q(t/m)

SIMPSONS

(t/m)

36

3.26

1

37

3.298

38

n

q*S*n

3.16

-4

-13.041

4

13.192

-3

-39.575

3.325

2

6.65

-2

-13.3

39

3.352

4

13.407

-1

-13.407

40

3.379

1

3.379

0

0

39.888

2 =

1 =

-79.323

W = 1/3 * 0.638 m * 39.888 t/m = 8.483 t Letak titik berat terhadap gading nomor 40 = -79.323/39.888 * 0.638 m = -1.269 Letak titik berat terhadap midship

= -1.269 m – 18.725 m = -19.994 m

2.7 Perhitungan berat kamar mesin dan titik beratnya terhadap midship Berat kamar mesin : W

= Wm + (0.044L – 1.17) le (t)

Dimana : Wm

= Wm.e + Wa.e (metoda Watson)

Wm.e = berat mesin induk (MAN type 12 ASV 25/30, 3600 HP) Wm.e = 20.52 t (dari brosur mesin) Wa.e

= berat mesin mesin bantu

Wa.e

= 0.98 (BHP)0.7 = 0.59 (3600) 0.7 = 182.77 t

Wm

= Wm.e + Wa.e = 20.52 t + 182.081 t = 202.6 t

le

= panjang kamar mesin, 13.9 m

W

= 202.6 + (0.044 * 89 – 1.17) 13.9 = 240.77 t

Maka :

Distribusi beban berbentuk segiempat panjang le. Letak titik berat terhadap AP = le/2 + 3.9 m = 10.85 m

Letak titik berat terhadap midship = -(Lpp/2 – 10.85 m) = -33.65 m

II. Berat Peluncuran II.1. Berat kapal yang diluncurkan.

Berat (t)

Nama Bagian

W

Badan Kapal

Titik Berat Terhadap Midship

W * G (t.m)

(m) G

1008.428

0.1298

130.914

Tangki ceruk haluan

9.327

39.438

367.835

Tangki ceruk buritan

4.964

-42.794

-212.446

Tangki bahan bakar

9.753

-24.432

-238.285

Ruang pompa

29.27

-23.943

-700.831

Slop tank

8.483

-19.994

-169.609

kamar mesin

17.764

-41.3

-733.649

Kamar mesin

240.77

-33.65

-8101.9105

1328.759

2 =

-9657.983

Baling baling dan poros diluar

1 =

Berat kapal yang diluncurkan = 1 = 1328.759 t Letak titik berat kapal yang diluncurkan terhadap midship = 2 / 1 = -9657.983 t.m / 1328.759 t = -7.268 m

II.2. Berat perlengkapan peluncuran. Dari “STATIC AND DYNAMICS OF THE SHIP” oleh SEMYONOV Berat perlengkapan peluncuran (7 + 16)% berat kapal yang diluncurkan Diambil 10% 1328.759 t = 132.8759 t

Berat peluncuran = 1328.759 t + 132.8759 t = 1461.635 t Titik berat peluncuran terhadap midship =  t  - m   t   m  t

= -6.607 m

III. Sepatu peluncuran (S). Dari “STATIC AND DYNAMICS OF THE SHIP” oleh SEMYONOV -

Panjang sepatu peluncur 80% Lpp = 71.2 m ~ diambil 72 m

-

Tekanan rata rata (D) maksimum yang diizinkan pada sepatu peluncur D = (15 + 30) t/m 2 Dari tabel “TEORI BANGUNAN KAPAL II” oleh Ir P ANDRIANTO

Lpp (m)

D (t/m2)

50

15

100

20

Lpp

= 89 m

D

=  

- (20 – 15 ) = 18.9 t/m 2 -

Diambil D = 19 t/m2

-

Ukuran sepatu peluncur Dari “SHIP BUILDING TECHNOLOGY” oleh DORMIDONTOV b

=

W n    D

Dimana : b

: lebar sepatu peluncur (m)

W

: berat peluncuran (t)

n

: jumlah sepatu peluncur

D

: permissible specific pressure (t/m2)

l=S

: panjang sepatu peluncur (m)

Maka : b

=

 t  = 1.068 m    m   tm

Ukuran sepatu peluncur : -

Pada arah memanjang kapal, terdiri dari 12 potongan sepatu peluncur dengan panjang tiap potongan 6 m. Tiap potongan terdiri dari 3 lajur balok kayu, dimana lapisan teratas dan lapisan yang tengah balok kayu mempunyai ukuran penampang (200 x 200) mm, sedangkan pada lapisan terbawah balok kayu mempunyai ukuran penampang (100 x 200) mm.

-

Tinggi sepatu peluncur adalah 500mm.

IV. Pemeriksaan kapal sesudah keluar dari landasan

a. Panjang landasan dibawah air : AC = λ = m b. Sudut kemiringan landasan terhadap permukaan air, Tg α

= AB/BC = 1/17

BC

= 17 AB

Pada Δ ABC : AC2 = AB2 + BC2 = AB2 + (17 AB)2 = 290 AB2 2

AB = B

AC





= AB

=

 m





= 1.245 m 2

= 1.1157 m

Displacement kapal yang diluncurkan

= 1461.635 t

LCG

= -6.607 m

Moment displacement

= -9657.022 t.m

Dari diagram trim didapatkan :

c. Sarat buritan, Ta = 3.06 m d. Sarat haluan, Tf = 0.32 m

Sarat air diatas ujung sepatu peluncur (Y)

Lpp

= 89 m

S

= 72 m

X : ( X + Lpp ) = Tf : Ta Ta * X = Tf * X + Tf * Lpp X=

Tf  Lpp = 10.394 Ta - Tf

( X + 8.5 m ) : ( X + Lpp ) = Y : Ta Ta ( X + 8.5 m ) = Y ( X + Lpp ) Y=

Ta  X   m  = 0.582 X  Lpp

T = Y + 0.5 m = 1.082 m H = 1.1157 m H > T, maka tidak terjadi pukulan haluan kapal keujung landasan (jumping).

V. Gambar peluncuran.

γ

Keterangan gambar: a

: jarak titik berat G keujung landasan

b

: jarak titik tekan B keujung landasan

c

: jarak titik berat G keujung depan sepatu peluncur

d

: jarak titik tekan B keujung depan sepatu peluncur

h

: jarak ujung belakang sepatu peluncur ke AP

f

: jarak titik tekan B ke AP

g

: jarak titik tekan G ke AP

LCG

: jarak titik berat G ke midship, -7.268 m

LCB

: jarak titik tekan B ke perpotongan lunas dengan permukaan air

Lx

: panjang langkah, jarak AP ke perpotongan lunas dengan permukaan air

S

: panjang sepatu peluncur

S’

: panjang sepatu peluncur yang masih berada diatas landasan

λ

: panjang landasan dibawah permukaan air, 19 m

X

: jarak gaya reaksi landasan Q keujung landasan

X’

: jarak gaya reaksi landasan Q keujung belakang sepatu peluncur

Ta

: sarat air pada AP

P

: berat peluncuran, 1328.759 t

γ

: gaya tekan keatas dari air

Q

: gaya reaksi pada landasan, (P – γ)

Harga harga yang tetap selama peluncuran

H g

Lpp - S  m –  m = = 8.5 m   Lpp  m = - LCG = – 7.268 m = 37.232 m   =

S

= 72 m

C

= h + S – g = 43.268 m

λ

= 19 m

Tahap tahap peluncuran Pada perhitungan peluncuran memanjang dibagi 3 tahap / periode Periode I

: dimulai pada waktu kapal dilepaskan dan berakhir pada waktu

kapal menyentuh permukaan air

Periode II :dimulai pada akhir periode I dan berakhir pada waktu buritan kapal mulai mengapung ( stern lift ) Periode III : dimulai pada akhir periode II dan berakhir pada waktu kapal meninggalkan landasan

VI. Periode I.

VI.1 Syarat kapal dapal bergerak F1 > F3 , dimana : W

: berat peluncuran (t)

F1

: W sin α

F3

: f * F2 = f  W cos α

f

: koefisien gesek, berharga antara 0.01 – 0.05

Dari “PRINCIPLE OF NAVAL ARCHITECTURE” dengan editor JOHN P COMSTOCK

a , dimana:  t   √ p

f

=

a

: suatu koefisien, besarnya 8.5

t

: temperatur grease, 29° F - 85° F

p

= D = tekanan rata rata pada landasan = 19 t/m2 = 1.765 t/ft2

Maka :

 = 0.0346     √ 

f

:

F1

: W sin α =  t  sin ° ’ =  t

F3

: f  W cos α =    t  cos ° ’ =  t

F1 > F3, maka kapal dapat meluncur

VI.2. Pembebanan pada periode I Pembebanan rata rata yang bekerja pada landasan tiap meter adalah: q

= W/S = 1328.759 t / 72 m = 18.455 t/m

pembebanan pada landasan dapat digambarkan sebagai trapesium qf

= beban dibagian depan

qa

= beban dibagian belakang

X’

= jarak gaya reaksi landasan keujung belakang sepatu peluncur

X’

= S/2 – LCG = 72 m/2 – 7.268 m = 28.732 m

qf

=

q X – S = ----------------------------------------- = 7.277 t/m S

qa

=

q S – X = --------------------------------------- = 29.632 t/m S

VII. Periode II dan Periode III PERHITUNGAN DISPLACEMENT DAN LCB Pada perhitungan ini, dilakukan tiap tiap station kapal bergerak masuk kedalam air dengan jarak station 4.450 m 1. LANGKAH 1. Kapal bergerak sampai station 2 menyentuh air. l = 2 * 4.45 m = 8.90 m Ta =   tg α =  m   =  m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

2

-

1

0.210

4

0.84

1

0.84

2

0

1

0

0

0

1 =

0.84

2 =

-0.84

Volume (V)

= 1/3 * d * Z1 = 1/3 * 4.45 m * 0.84 m2 = 1.246 m3

γ

= 1.246 * 1.004 * 1.025 = 1.828 t

LCB

= 1 / 2 * d = 0.84/0.84 * 4.45 = 4.45 m

2. LANGKAH 2. Kapal bergerak sampai station 4 menyentuh air l = 4 * 4.45 m = 17.80 m Ta = 17.80 m * 1/17 = 1.047 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

4

-

1

0.805

4

3.22

3

9.66

2

1.82

2

3.64

2

7.28

3

1.54

4

6.16

1

6.16

4

0

1

0

0

0

1 =

13.02

2 =

23.10

Volume (V)

= 1/3 * 4.45 m * 13.02 m2

= 19.313 m3

γ

= 19.313 * 1.004 * 1.025

= 19.875 t

LCB

= 23.10/13.02 * 4.45 m

= 7.895 m

3. LANGKAH 3. Kapal bergerak sampai station 6 menyentuh air l

= 6 * 4.45 m = 26.70 m

Ta

= 26.7 m * 1/17 = 1.57 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

6

-

1

1.47

4

5.88

5

29.4

2

3.85

2

7.7

4

30.8

3

4.62

4

18.48

3

55.44

4

4.725

2

9.45

2

18.9

5

2.8

4

11.2

1

11.2

6

0

1

0

0

0

1 =

52.71

2 =

145.74

Volume (V)

= 1/3 * 4.45 m * 52.71 m2

= 78.186 m3

γ

= 78.186 * 1.004 * 1.025

= 80.462 t

LCB

= 145.74/52.71 * 4.45 m

= 12.304 m


= 8 * 4.45 m = 35.6 m

Ta

= 35.6 m * 1/17 = 2.09 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

8

-

1

2.45

4

9.8

7

68.6

2

5.95

2

11.9

6

71.4

3

8.05

4

32.2

5

161.0

4

9.52

2

19.04

4

76.16

5

8.925

4

35.7

3

107.1

6

6.23

2

12.46

2

24.92

7

3.36

4

13.44

1

13.44

8

0

1

0

0

0

1 =

134.54

2 =

522.62

Volume (V)

= 1/3 * 4.45 m * 134.54 m2

= 199.568 m3

γ

= 199.568 * 1.004 * 1.025

= 205.375 t

LCB

= 522.62/134.54 * 4.45 m

= 17.286 m


= 10 * 4.45 m = 44.5 m

Ta

= 44.5 m * 1/17 = 2.618 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

10

-

1

3.43

4

13.72

9

123.48

2

8.54

2

17.08

8

136.64

3

12.005

4

48.02

7

336.14

4

14.525

2

29.05

6

174.3

5

15.05

4

60.2

5

301.0

6

12.6

2

25.2

4

100.8

7

10.01

4

40.04

3

120.12

8

6.65

2

13.3

2

26.6

9

3.43

4

13.72

1

13.72

10

0

1

0

0

0

1 =

260.33

2 =

1332.8

Volume (V)

= 1/3 * 4.45 m * 260.33 m2

= 386.156 m3

γ

= 386.156 * 1.004 * 1.025

= 397.393 t

LCB

= 1332.8/260.33 * 4.45 m

= 22.7825 m


= 12 * 4.45 m = 53.4 m

Ta

= 53.4 m * 1/17 = 3.14 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

12

-

1

4.62

4

18.48

11

203.28

2

11.2

2

22.4

10

224.0

3

16.17

4

64.68

9

582.12

4

20.09

2

40.18

8

321.44

5

21.35

4

85.4

7

597.8

6

19.39

2

38.78

6

232.68

7

16.8

4

67.2

5

336.0

8

13.3

2

26.6

4

106.4

9

10.43

4

41.72

3

125.16

10

7.0

2

14.0

2

28.0

11

3.5

4

14.0

1

14.0

12

0

1

0

0

0

1 =

433.44

2 =

2770.88

Volume (V)

= 1/3 * 4.45 m * 433.44 m2

= 642.936 m3

γ

= 642.936 * 1.004 * 1.025

= 661.645 t

LCB

= 2770.88/433.44 * 4.45 m

= 28.45 m


= 14 * 4.45 m = 62.3m

Ta

= 62.3 m * 1/17 = 3.665 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

14

-

1

6.02

4

24.08

13

313.04

2

15.05

2

30.1

12

361.2

3

20.65

4

82.6

11

908.6

4

25.9

2

51.8

10

518.0

5

27.65

4

110.6

9

995.4

6

26.6

2

53.2

8

425.6

7

23.8

4

95.2

7

666.4

8

20.58

2

41.16

6

246.96

9

17.5

4

70.0

5

350.0

10

15.75

2

31.5

4

126.0

11

10.5

4

42.0

3

126.0

12

7.0

2

14.0

2

28.0

13

3.15

4

12.6

1

12.6

14

0

1

0

0

0

1 =

658.84

2 =

5077.80

Volume (V)

= 1/3 * 4.45 m * 658.84 m2

= 977.279 m3

γ

= 977.279 * 1.004 * 1.025

= 1005.718 t

LCB

= 5077.8/658.84 * 4.45 m

= 34.297 m


= 16 * 4.45 m = 71.2 m

Ta

= 71.2 m * 1/17 = 4.188 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

16

-

1

7.525

4

30.1

15

451.5

2

17.36

2

34.72

14

486.08

3

25.55

4

102.2

13

1328.6

4

31.85

2

63.7

12

764.4

5

34.3

4

137.2

11

1509.2

6

33.88

2

67.76

10

677.6

7

30.975

4

123.9

9

1115.1

8

28.0

2

56.0

8

448.0

9

24.85

4

99.4

7

695.8

10

21.42

2

42.84

6

257.04

11

17.64

4

70.56

5

352.8

12

14.0

2

28.0

4

112.0

13

9.625

4

38.5

3

115.5

14

6.475

2

12.95

2

25.9

15

2.975

4

11.9

1

11.9

16

0

1

0

0

0

1 =

919.73

2 =

8351.42

Volume (V)

= 1/3 * 4.45 m * 919.73 m2

= 1364.27 m3

γ

= 1364.27 * 1.004 * 1.025

= 1403.97 t

LCB

= 8351.42/919.73 * 4.45 m

= 40.4073 m

Periode III. Langkah 8a. l

= 16 * 4.45 m = 71.2 m

Ta

= 2/3 * 4.188 = 2.792 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

14

-

1

3.85

4

15.4

13

200.2

2

9.73

2

19.46

12

233.52

3

14.35

4

57.4

11

631.4

4

18.13

2

36.26

10

362.6

5

19.67

4

78.68

9

708.12

6

18.9

2

37.8

8

302.4

7

17.325

4

69.3

7

485.1

8

15.05

2

30.1

6

180.6

9

13.3

4

53.2

5

266.0

10

11.2

2

22.4

4

89.6

11

8.75

4

35.0

3

105.0

12

7.175

2

14.35

2

28.7

13

3.85

4

15.4

1

15.4

14

1.925

1.461

2.812

0

0

a

0.963

1.843

1.774

-0.461

-0.817

b

0

0.461

0

-0.921

0

1 =

489.336

2 =

3607.823

Volume (V)

= 1/3 * 4.45 m * 489.336 m2

= 725.8484 m3

γ

= 725.8484 * 1.004 * 1.025

= 746.971 t

LCB

= 3607.823 /489.336* 4.45 m = 32.81 m

Langkah 8b. l

= 16 * 4.45 m = 71.2 m

Ta

= 1/3 * 4.188 = 1.396 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

12

-

1

1.4

4

5.6

11

61.6

2

4.2

2

8.4

10

84

3

6.3

4

25.2

9

226.8

4

8.4

2

16.8

8

134.4

5

9.1

4

36.4

7

254.8

6

8.4

2

16.8

6

100.8

7

7.7

4

30.8

5

154.0

8

6.3

2

12.6

4

50.4

9

5.25

4

21.0

3

63.0

10

3.85

2

7.7

2

15.4

11

2.59

4

10.36

1

10.36

12

1.26

1.281

1.614

0

0

a

0.63

1.124

0.708

-0.281

-0.199

b

0

0.281

0

-0.562

0

1 =

193.928

2 =

1155.361

Volume (V)

= 1/3 * 4.45 m * 193.982 m2

= 287.74 m3

γ

= 287.74 * 1.004 * 1.025

= 296.1135 t

LCB

= 1155.361 /193.928 * 4.45 m = 26.5043 m

LANGKAH 9. l

= 18 * 4.45 m = 80.1 m

Ta

= 80.1 m * 1/17 = 4.712 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

0

1

0

18

0

1

9.345

4

37.38

17

635.46

2

20.86

2

41.72

16

667.52

3

30.695

4

122.78

15

1841.7

4

38.01

2

76.02

14

1064.28

5

41.16

4

164.64

13

2140.32

6

41.23

2

82.46

12

989.52

7

38.465

4

153.86

11

1692.46

8

35.21

2

70.42

10

704.2

9

32.375

4

129.5

9

1165.5

10

29.015

2

58.03

8

464.24

11

25.2

4

100.8

7

705.6

12

21.21

2

42.42

6

254.52

13

16.975

4

67.9

5

339.5

14

13.3

2

26.6

4

106.4

15

9.45

4

37.8

3

113.4

16

4.9

2

9.8

2

15.6

17

2.1

4

8.4

1

8.4

18

0

1

0

0

0

1 =

1230.53

2 =

12912.62

Volume (V)

= 1/3 * 4.45 m * 1230.53 m2

= 1825.2862 m3

γ

= 1825.2862 * 1.004 * 1.025

= 1878.402 t

LCB

= 12912.62 /1230.53* 4.45 m = 46.696 m

Langkah 9a. l

= 18 * 4.45 m = 80.1 m

Ta

= 2/3 * 4.712 = 3.14 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

0

1

0

17

0

1

4.83

4

19.32

16

309.12

2

11.55

2

23.1

15

346.5

3

17.15

4

68.6

14

960.4

4

22.05

2

44.1

13

573.3

5

24.15

4

96.6

12

1159.2

6

23.8

2

47.6

11

523.6

7

22.4

4

89.6

10

896.0

8

20.65

2

41.3

9

371.7

9

18.9

4

75.6

8

604.8

10

9.87

2

19.74

7

138.18

11

14.7

4

58.8

6

352.8

12

12.53

2

25.06

5

125.3

13

9.45

4

37.8

4

151.2

14

7.7

2

15.4

3

46.2

15

5.32

4

21.28

2

42.56

16

2.66

1.5

3.99

1

3.99

16.5

1.855

2

3.71

0.5

1.855

17

1.05

0.896

0.941

0

0

a

0.532

1.584

0.843

-0.396

-0.334

b

0

0.396

0

-0.792

0

1 =

693.384

2 =

6606.371

Volume (V)

= 1/3 * 4.45 m * 693.384 m2

= 1028.5196 m3

γ

= 1028.5196 * 1.004 * 1.025

= 1058.45 t

LCB

= 6606.371 /693.384 * 4.45 m = 42.398 m

Langkah 9b. l

= 18 * 4.45 m = 80.1 m

Ta

= 1/3 * 4.712 = 1.571 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

17

-

1

1.75

4

7.0

16

112.0

2

5.18

2

10.36

15

155.4

3

7.7

4

30.8

14

431.2

4

10.5

2

21.0

13

273.0

5

12.25

4

49.0

12

588.0

6

11.83

2

23.66

11

260.26

7

11.27

4

45.08

10

450.8

8

10.36

2

20.72

9

186.48

9

9.45

4

37.8

8

302.4

10

8.4

2

16.8

7

117.6

11

7.35

4

29.4

6

176.4

12

6.23

2

12.46

5

62.3

13

4.55

4

18.2

4

72.8

14

3.57

2

7.14

3

21.42

15

2.275

4

9.1

2

18.2

16

1.05

1.5

1.575

1

1.575

16.5

0.595

2

1.19

0.5

0.595

17

0.14

0.6921

0.097

0

0

a

0.07

0.7684

0.0538

-0.1921

-0.0103

b

0

0.1921

0

-0.384

0

1 =

341.4358

2 =

3230.42

Volume (V)

= 1/3 * 4.45 m * 341.4358 m2

= 506.463 m3

γ

= 506.463 * 1.004 * 1.025

= 521.201 t

LCB

= 3230.42/341.4358 * 4.45 m = 42.103 m

LANGKAH 10. l

= 20 * 4.45 m = 89 m

Ta

= 89m * 1/17 = 5.2353 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

END

-

0.1573

-

20.3146

0

Ap’

3.15

0.6292

1.98198

20.1573

39.9514

AP

6.3

1.1573

7.291

20

145.82

1

11.76

4

47.04

19

893.76

2

24.85

2

49.7

18

894.6

3

35.84

4

143.36

17

2437.12

4

44.275

2

88.55

16

1416.8

5

48.125

4

192.5

15

2887.5

6

48.405

2

96.81

14

1355.34

7

46.025

4

184.1

13

2393.3

8

42.875

2

85.75

12

1029

9

39.9

4

159.6

11

1755.6

10

36.47

2

72.94

10

729.4

11

32.62

4

130.48

9

1174.32

12

28.7

2

57.4

8

459.2

13

24.85

4

99.4

7

695.8

14

20.37

2

40.74

6

244.44

15

15.855

4

63.42

5

317.1

16

11.2

2

22.4

4

89.6

17

6.3

4

25.2

3

75.6

18

2.45

2

4.9

2

9.8

19

0.35

4

1.4

1

1.4

FP

0

1

0

0

0

1 =

1574.96

2 =

19045.45

Volume (V)

= 1/3 * 4.45 m * 1574.963 m2

= 2336.195 m3

γ

= 2336.195 * 1.004 * 1.025

= 2404.1784 t

LCB

= 19045.45 /1574.96 * 4.45 m = 53.8122 m

Langkah 10a. l

= 20 * 4.45 m = 89 m

Ta

= 2/3 * 5.2353 = 3.49 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

20

-

1

5.6

4

22.4

19

425.6

2

13.65

2

27.3

18

491.4

3

20.3

4

81.2

17

1380.4

4

25.9

2

51.8

16

828.8

5

28.7

4

114.8

15

1722

6

29.05

2

58.1

14

813.4

7

27.65

4

110.6

13

1437.8

8

25.9

2

51.8

12

621.6

9

24.43

4

97.72

11

1074.92

10

22.4

2

44.8

10

448

11

20.3

4

81.2

9

730.8

12

17.85

2

35.7

8

285.6

13

15.05

4

60.2

7

421.4

14

13.09

2

26.18

6

157.08

15

10.5

4

42

5

210

16

7.35

2

14.7

4

58.8

17

4.55

4

18.2

3

54.6

18

2.03

2

4.06

2

8.12

19

0.35

4

1.4

1

1.4

FP

-

1

-

0

-

1 =

954.16

2 =

11171.72

Volume (V)

= 1/3 * 4.45 m * 954.16 m2

= 1415.337 m3

γ

= 1415.337 * 1.004 * 1.025

= 1456.5236 t

LCB

= 11171.72 /954.16 * 4.45 m

= 52.1025 m

Langkah 10b. l

= 20 * 4.45 m = 89 m

Ta

= 1/3 * 5.2353 = 1.745 m

Station

Luasan (m2) A

Faktor Simpson S

A*S

Lengan m

A*S*m

AP

-

1

-

20

-

1

2.03

4

8.12

19

154.28

2

5.95

2

11.9

18

214.2

3

9.45

4

37.8

17

642.6

4

13.02

2

26.04

16

416.64

5

15.4

4

61.6

15

924

6

15.4

2

30.8

14

431.2

7

15.4

4

61.6

13

800.8

8

14.63

2

29.26

12

351.12

9

14.175

4

56.7

11

623.7

10

13.475

2

26.95

10

269.5

11

12.46

4

49.84

9

448.56

12

11.48

2

22.96

8

183.68

13

9.8

4

39.2

7

274.4

14

9.1

2

18.2

6

109.2

15

7.805

4

31.22

5

156.1

16

5.6

2

11.2

4

44.8

17

4.2

4

16.8

3

50.4

18

2.1

2

4.2

2

8.4

19

0.63

4

2.52

1

2.52

FP

-

1

-

0

-

1 =

546.91

2 =

6106.10

Volume (V)

= 1/3 * 4.45 m * 546.91 m2

= 811.25 m3

γ

= 811.25 * 1.004 * 1.025

= 834.86 t

LCB

= 6106.10/546.91 * 4.45 m

= 49.68 m

PERIODE II LANGKAH KE 2 lx Ta

= 17.8 m = 1.047 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 19.313

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 19.875

t

;c

= h + S – g

= 43.268

m

3. LCB

= 7.895

m

; ’

=

= 8.5

m

= 9.905 m

; S’

= h + S – f – b

= 73.2

m

;a

= lx – g -  + ’ = -29.932

4.

f

= lx – LCB

5.

b

= lx – f -  + ’ = -2.605 m

6.

d

= h + S – f

m

= 70.595 m

7. P * a= - 39772.414

t.m

; γ * b = -51.774

t.m

8. P * c= 57492.744

t.m

; γ * d = 1403.076

t.m

9.

Q = P - γ

= 1308.884 t

10. X = γ * b – P * a)Q-1

= 30.347 m, jarak Q ke ujung landasan

 X’ = X -  - h + lx + ’

= 29.146 m, jarak Q ke ujung belakang sepatu peluncur

Lx – h + ’

= 24 m



= 19 m

lx – h + ’ < 

Berarti bagian belakang sepatu peluncur belum meninggalkan ujung l andasan 12. 1/3 S = 24 1

/3 S’=

m;

2

= 48

m.

m;

2

=

m.

/3 S /3 S’

13. q = Q/S = 18.179 q = Q/3X = 14. qf = q x’ – S))/S qa = (2q (2S – x’S

1

/3 S < X < 2/3 S

t/m ;

q = QS’

=

t/m

t/m ;

q = Q S’– X) =

t/m

= 7.797

t/m

= 28.561

t/m


= 26.7 m = 1.57 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 78.186

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 80.462

t

;c

= h + S – g

= 43.268

m

3. LCB

= 12.304

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 64.3

m

;a

= lx – g -  + ’ = -21.032

4.

f

= lx – LCB

= 14.396 m

5.

b

= lx – f -  + ’ = 1.804 m

6.

d

= h + S – f

m

= 66.104 m

7. P * a= - 27946.4593

t.m

; γ * b = 145.1534

t.m

8. P * c= 57492.744

t.m

; γ * d = 5318.86

t.m

9.

Q = P - γ

= 1248.297 t

10. X = γ * b – P * a)Q-1


 X’ = X -  - h + lx + ’


Lx – h + ’

= 26.7 m



= 19 m

lx – h + ’ > 

Berarti bagian belakang sepatu peluncur sudah meninggalkan ujung landasan 12. 1/3 S =

m;

2

/3 S

=

m.

m;

2

/3 S’

= 42.867

m. 1/3 S’ < X < 2/3 S'

13. q = Q/S =

t/m ;

q = Q/S’

= 19.414

q = Q/3X =

t/m ;

q = Q S’– X) =

1

/3 S’= 

14. qf = q x’ – S))/S qa = (2q (2S – x’S

= 1.9396

t/m

= 36.888

t/m

t/m t/m


= 35.6 m = 2.094 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 199.568

m3

;g

= ½ Lpp – LCG

= 37.232

m

 γ

= 205.375

t

;c

= h + S – g

= 43.268

m

3. LCB

= 17.286

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 55.4

m

;a

= lx – g -  + ’ = -12.132

4.

f

= lx – LCB

= 18.314 m

5.

b

= lx – f -  + ’ = 6.786 m

6.

d

= h + S – f

m

= 62.186 m

7. P * a= -16120.504

t.m

; γ * b = 1393.6747

t.m

8. P * c= 57492.744

t.m

; γ * d = 12771.45

t.m

9.

Q = P - γ

= 1123.384 t

10. X = γ * b – P * a)Q-1


 X’ = X -  - h + lx + ’


Lx – h + ’

= 35.6 m



= 19 m

lx – h + ’ > 

Berarti bagian belakang sepatu peluncur sudah meninggalkan ujung landasan 12. 1/3 S = 1

/3 S’= 

m;

2

/3 S

=

m.

m;

2

/3 S’

= 36.933

m. X < 1/3 S'

t/m ;

q = QS’

=

t/m

t/m ;

q = Q S’– X) =

t/m

13. q = Q/S = q = Q/3X = 24.018 14. qf = 0 qa = 2q = 48.037 t/m


= 44.5 m = 2.618 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 386.156

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 397.393

t

;c

= h + S – g

= 43.268

m

3. LCB

= 22.782

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 46.5

m

;a

= lx – g -  + ’ = -3.232

4.

f

= lx – LCB

= 21.717 m

5.

b

= lx – f -  + ’ = 12.283 m

6.

d

= h + S – f

m

= 58.783 m

7. P * a= - 4294.5491

t.m

; γ * b = 4881.1782

t.m

8. P * c= 57492.744

t.m

; γ * d = 23359.97

t.m

9.

Q = P - γ

= 931.366 t

10. X = γ * b – P * a)Q-1


 X’ = X -  - h + lx + ’


Lx – h + ’

= 44.5 m



= 19 m

lx – h + ’ > 


/3 S’= 

m;

2

/3 S

=

m.

m;

2

/3 S’

= 31

m. X < 1/3 S'

t/m ;

q = QS’

=

t/m

t/m ;

q = Q S’– X) =

t/m

13. q = Q/S = q = Q/3X = 31.5122 14. qf = 0 qa = 2q = 63.024 t/m


= 53.4 m = 3.141 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 642.936

m3

;g

= ½ Lpp – LCG

= 37.232

m

 γ

= 661.645

t

;c

= h + S – g

= 43.268

m

3. LCB

= 28.45 m

; ’

=

4.

f

= lx – LCB

= 24.95 m

5.

b

= lx – f -  + ’ = 17.95 m

6.

d

= h + S – f

= 8.5

m

; S’

= h + S – f – b

= 37.6

;a

= lx – g -  + ’ = 5.668

m m

= 55.55 m

7. P * a= 7531.406

t.m

; γ * b = 11876.52775

t.m

8. P * c= 57492.744

t.m

; γ * d = 36754.38

t.m

9.

Q = P - γ

= 667.114 t

10. X = γ * b – P * a)Q-1


 X’ = X -  - h + lx + ’


Lx – h + ’

= 53.4 m



= 19 m

lx – h + ’ > 


/3 S’= 

m;

2

/3 S

=

m.

m;

2

/3 S’

= 25.067

m.

t/m ;

q = QS’

=

t/m

t/m ;

q = Q S’– X) =

t/m

13. q = Q/S = q = Q/3X = 34.141 14. qf = 0 qa = 2q = 68.282 t/m

X < 1/3 S'


= 62.3 m = 3.665 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 977.279

m3

;g

= ½ Lpp – LCG

= 37.232

m

 γ

= 1005.718

t

;c

= h + S – g

= 43.268

m

3. LCB

= 34.297

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 28.7

m

;a

= lx – g -  + ’ = 14.568

4.

f

= lx – LCB

= 28.003 m

5.

b

= lx – f -  + ’ = 23.797 m

6.

d

= h + S – f

m

= 52.497 m

7. P * a= 19357.3611

t.m

; γ * b = 23933.0712

t.m

8. P * c= 57492.744

t.m

; γ * d = 52797.178

t.m

9.

Q = P - γ

= 323.041 t

10. X = γ * b – P * a)Q-1


 X’ = X -  - h + lx + ’


Lx – h + ’

= 62.3 m



= 19 m

lx – h + ’ > 

Berarti bagian belakang sepatu peluncur sudah meninggalkan ujung landasan 12. 1/3 S =

m;

2

/3 S

=

m.

m;

2

/3 S’

= 19.133

m. 1/3 S’ < X < 2/3 S'

13. q = Q/S =

t/m ;

q = QS’

= 11.256

q = Q/3X =

t/m ;

q = Q S’– X) =

1

/3 S’= 

14. qf = q x’ – S))/S qa = (2q (2S – x’S

= 10.8195

t/m

= 11.6925

t/m

t/m t/m

PERIODE

: III

LANGKAH

: Stern Lift

Lx

= 65

m



= 19

m

P

= 1328.759

m

’

= 8.5

m

S

= 72

m

Dari gambar didapatkan : 1. γ

= 1100

t

2. γ * d

= 57492.744 t.m

3. Ta

= 3.795

4. d

= γ  dγ)-1

= 52.266

m

5. f

= h + S – d

= 28.234

m

6. LCB

= lx – f

= 36.766

m

7. b

= lx – f -  + ’

= 26.266

m

8. S’

= S + h – f – b

= 26

m

9. a

= lx – g -  + ’

= 17.268

m

10. P * a

= 22945.0104 t.m

11. γ * b

= 28892.6

12. Q

= P - γ

= 228.759

t

13. X

= γ * b – H * a)Q -1 = 25.9994

m

14. q

= Q(0.05 S)-1

t/m

m

t.m

= 63.544

PERIODE III LANGKAH KE 8 lx Ta

= 71.2 m = 4.188 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 1364.27

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 1403.97

t

;c

= h + S – g

= 43.268

m

3. LCB

= 40.4073

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 19.8

m

;a

= lx – g -  + ’ = 23.468

4.

f

= lx – LCB

= 30.793 m

5.

b

= lx – f -  + ’ = 29.907 m

6.

d

= h + S – f

m

= 49.707 m

7. P * a= 31183.3162

t.m

; γ * b = 41988.531

t.m

8. P * c= 57492.744

t.m

; γ * d = 69787.137

t.m

9.

Q = P - γ

=

t, γ * b) > (P * c) kapal sudah stern lift

10. X = γ * b – P * a)Q-1

=

m, jarak Q ke ujung landasan

 X’ = X -  - h + lx + ’

=

m, jarak Q ke ujung belakang sepatu peluncur

Lx – h + ’

=

m



=

m

Berarti bagian belakang sepatu peluncur 12. 1/3 S = 1

/3 S’=

lx – h + ’



meninggalkan ujung landasan

m;

2

/3 S

=

m.

m;

2

/3 S’

=

m.

13. q = Q/S =

t/m ;

q = QS’

=

t/m

q = Q/3X =

t/m ;

q = Q S’– X) =

t/m

14. qf = qa =

PERIODE III LANGKAH KE 8a lx Ta

= 71.2 m = 2.792 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 725.8484

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 746.9706

t

;c

= h + S – g

= 43.268

m

3. LCB

= 32.8094

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 19.8

m

;a

= lx – g -  + ’ = 23.468

4.

f

= lx – LCB

= 38.391 m

5.

b

= lx – f -  + ’ = 22.309 m

6.

d

= h + S – f

m

= 42.109 m

7. P * a= 31183.3162

t.m

; γ * b = 16664.1671

t.m

8. P * c= 57492.744

t.m

; γ * d = 31454.185

t.m

9.

Q = P - γ

=

t

10. X = γ * b – P * a)Q-1

=


 X’ = X -  - h + lx + ’

=


Lx – h + ’

=

m



=

m


/3 S’=

lx – h + ’




m;

2

/3 S

=

m.

m;

2

/3 S’

=

m.

13. q = Q/S =

t/m ;

q = QS’

=

t/m

q = Q/3X =

t/m ;

q = Q S’– X) =

t/m

14. qf = qa =

PERIODE III LANGKAH KE 8b lx Ta

= 71.2 m = 1.396 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 287.7403

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 296.1135

t

;c

= h + S – g

= 43.268

m

3. LCB

= 26.5043

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 19.8

m

;a

= lx – g -  + ’ = 23.468

4.

f

= lx – LCB

= 44.696 m

5.

b

= lx – f -  + ’ = 16.004 m

6.

d

= h + S – f

m

= 35.804 m

7. P * a= 31183.3162

t.m

; γ * b = 4739

t.m

8. P * c= 57492.744

t.m

; γ * d = 10602.048

t.m

9.

Q = P - γ

=

t

10. X = γ * b – P * a)Q-1

=


 X’ = X -  - h + lx + ’

=


Lx – h + ’

=

m



=

m


/3 S’=

lx – h + ’




m;

2

/3 S

=

m.

m;

2

/3 S’

=

m.

13. q = Q/S =

t/m ;

q = QS’

=

t/m

q = Q/3X =

t/m ;

q = Q S’– X) =

t/m

14. qf = qa =

PERIODE

: III

LANGKAH

:8

Lx

= 71.2

m



= 19

m

P

= 1328.759

m

’

= 8.5

m

S

= 72

m


= 1195

t

2. γ * d

= 57492.749 t.m

3. Ta

= 3.75 m

4. d

= γ  dγ)-1

= 48.111

m

5. f

= h + S – d

= 32.389

m

6. LCB

= lx – f

= 38.811

m

7. b

= lx – f -  + ’

= 28.311

m

8. S’

= S + h – f – b

= 19.8

m

9. a

= lx – g -  + ’

= 23.468

m

10. P * a

= 31183.3162 t.m

11. γ * b

= 33831.645 t.m

12. Q

= P - γ

= 133.759

t

13. X

= γ * b – H * a)Q -1 = 19.799

m

14. q

= Q(0.05 S)-1

t/m

= 37.155


= 80.1 m = 4.712 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 1825.2862

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 1878.402

t

;c

= h + S – g

= 43.268

m

3. LCB

= 46.6963

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 10.9

m

;a

= lx – g -  + ’ = 32.368

4.

f

= lx – LCB

= 33.4037 m

5.

b

= lx – f -  + ’ = 36.1963 m

6.

d

= h + S – f

m

= 47.096 m

7. P * a= 43009.2713

t.m

; γ * b = 67991.2023

t.m

8. P * c= 57492.744

t.m

; γ * d = 88465.221

t.m

9.

Q = P - γ

=

t

10. X = γ * b – P * a)Q-1

=


 X’ = X -  - h + lx + ’

=


Lx – h + ’

=

m



=

m


/3 S’=

lx – h + ’




m;

2

/3 S

=

m.

m;

2

/3 S’

=

m.

13. q = Q/S =

t/m ;

q = QS’

=

t/m

q = Q/3X =

t/m ;

q = Q S’– X) =

t/m

14. qf = qa =


= 80.1 m = 3.14 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 1028.5196

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 1058.45

t

;c

= h + S – g

= 43.268

m

3. LCB

= 42.398

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 10.9

m

;a

= lx – g -  + ’ = 32.368

4.

f

= lx – LCB

= 37.702 m

5.

b

= lx – f -  + ’ = 31.898 m

6.

d

= h + S – f

m

= 42.798 m

7. P * a= 43009.2713

t.m

; γ * b = 33762.438

t.m

8. P * c= 57492.744

t.m

; γ * d = 45299.543

t.m

9.

Q = P - γ

=

t

10. X = γ * b – P * a)Q-1

=


 X’ = X -  - h + lx + ’

=


Lx – h + ’

=

m



=

m


/3 S’=

lx – h + ’




m;

2

/3 S

=

m.

m;

2

/3 S’

=

m.

13. q = Q/S =

t/m ;

q = QS’

=

t/m

q = Q/3X =

t/m ;

q = Q S’– X) =

t/m

14. qf = qa =


= 80.1 m = 1.571 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 506.463

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 521.201

t

;c

= h + S – g

= 43.268

m

3. LCB

= 42.103

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

= 10.9

m

;a

= lx – g -  + ’ = 32.368

4.

f

= lx – LCB

= 37.997 m

5.

b

= lx – f -  + ’ = 31.603 m

6.

d

= h + S – f

m

= 42.503 m

7. P * a= 43009.2713

t.m

; γ * b = 16471.5152

t.m

8. P * c= 57492.744

t.m

; γ * d = 22152.61

t.m

9.

Q = P - γ

=

t

10. X = γ * b – P * a)Q-1

=


 X’ = X -  - h + lx + ’

=


Lx – h + ’

=

m



=

m


/3 S’=

lx – h + ’




m;

2

/3 S

=

m.

m;

2

/3 S’

=

m.

13. q = Q/S =

t/m ;

q = QS’

=

t/m

q = Q/3X =

t/m ;

q = Q S’– X) =

t/m

14. qf = qa =

PERIODE

: III

LANGKAH

:9

Lx

= 80.1

m



= 19

m

P

= 1328.759

m

’

= 8.5

m

S

= 72

m


= 1290

t

2. γ * d

= 57492.744 t.m

3. Ta

= 3.607

4. d

= γ  dγ)-1

= 44.568

m

5. f

= h + S – d

= 35.932

m

6. LCB

= lx – f

= 44.168

m

7. b

= lx – f -  + ’

= 33.668

m

8. S’

= S + h – f – b

= 10.9

m

9. a

= lx – g -  + ’

= 32.368

m

10. P * a

= 43009.271 t.m

11. γ * b

= 43431.72

12. Q

= P - γ

= 38.759

t

13. X

= γ * b – H * a)Q -1 = 10.8994

m

14. q

= Q(0.05 S)-1

t/m

m

t.m

= 10.766


= 89 m = 5.2353 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 2336.1951

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 2404.1784

t

;c

= h + S – g

= 43.268

m

3. LCB

= 53.8122

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

=2

;a

= lx – g -  + ’ = 41.268

4.

f

= lx – LCB

= 35.188 m

5.

b

= lx – f -  + ’ = 43.312 m

6.

d

= h + S – f

m m

= 45.312 m

7. P * a= 54835.2264

t.m

; γ * b = 104129.7748

t.m

8. P * c= 57492.744

t.m

; γ * d = 108938.132

t.m

9.

Q = P - γ

=

t

10. X = γ * b – P * a)Q-1

=


 X’ = X -  - h + lx + ’

=


Lx – h + ’

=

m



=

m


/3 S’=

lx – h + ’




m;

2

/3 S

=

m.

m;

2

/3 S’

=

m.

13. q = Q/S =

t/m ;

q = Q/S’

=

t/m

q = Q/3X =

t/m ;

q = Q S’– X) =

t/m

14. qf = qa =


= 89 m = 3.4903 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 1415.337

m3

;g

= ½ Lpp – LCG

= 37.232

m

 γ

= 1456.5236

t

;c

= h + S – g

= 43.268

m

3. LCB

= 52.1025

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

=2

;a

= lx – g -  + ’ = 41.268

4.

f

= lx – LCB

= 36.897 m

5.

b

= lx – f -  + ’ = 41.603 m

6.

d

= h + S – f

m m

= 43.603 m

7. P * a= 54835.2264

t.m

; γ * b = 60595.7513

t.m

8. P * c= 57492.744

t.m

; γ * d = 63508.798

t.m

9.

Q = P - γ

=

t

10. X = γ * b – P * a)Q-1

=


 X’ = X -  - h + lx + ’

=


Lx – h + ’

=

m



=

m


/3 S’=

lx – h + ’




m;

2

/3 S

=

m.

m;

2

/3 S’

=

m.

13. q = Q/S =

t/m ;

q = QS’

=

t/m

q = Q/3X =

t/m ;

q = Q S’– X) =

t/m

14. qf = qa =


= 89 m = 1.7451 m

h P

= 8.5 m = 1328.759 t

S

= 72 m



= 19 m

1. Volume

= 881.25

m3

;g

= ½ Lpp – LCG

=37.232

m

 γ

= 834.86

t

;c

= h + S – g

= 43.268

m

3. LCB

= 49.683

m

; ’

=

= 8.5

m

; S’

= h + S – f – b

=2

;a

= lx – g -  + ’ = 41.268

4.

f

= lx – LCB

= 39.317 m

5.

b

= lx – f -  + ’ = 39.183 m

6.

d

= h + S – f

m m

= 41.183 m

7. P * a= 54835.2264

t.m

; γ * b = 32712.3194

t.m

8. P * c= 57492.744

t.m

; γ * d = 34382.039

t.m

9.

Q = P - γ

=

t

10. X = γ * b – P * a)Q-1

=


 X’ = X -  - h + lx + ’

=


Lx – h + ’

=

m



=

m


/3 S’=

lx – h + ’




m;

2

/3 S

=

m.

m;

2

/3 S’

=

m.

13. q = Q/S =

t/m ;

q = QS’

=

t/m

q = Q/3X =

t/m ;

q = Q S’– X) =

t/m

14. qf = qa =

Perhitungan Dan Grafik Peluncuran

Recommend Documents