PERHITUNGAN BALOK ANAK.pdf

TUGAS MERENCANA KONSTRUKSI BETON

PERHITUNGAN BALOK ANAK 15 x 20 CM

BALOK ANAK, PANJANG 5.75 METER      

b (lebar (lebar balok ) = 15 cm h (tinggi balok) = 20 cm mutu beton Fc = 25 mpa mutu baja Fy = 360 mpa Q pelat = 858.4 kg/m² bentang balok L = 5.75 m



Pembebanan : beban segitiga beban trapezium beban tembok beban kaca beban sendiri balok

= 2/3 x1/2x854.4 x 5.75 = 1637.6 kg/m =1/2 x 854.4 x 1.5 – 1/3 x1/2 x 854.4 x 1.5²/3= 534 kg/m = 0.15 x 1700 x1.5 x 4. = 1530 kg/m = 0.05 x 1.5 x 2600 x 4 = 780 kg/m = 0.15 x 0.20 x 2400 = 72 kg/m Q

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momen : m lapangan

= 1/14 x Q x L² = 1/14 x 3.773 x 5.75² m tumpuan = 1/12 x Q x L² = 1/12 x 3.773 x 5.75² D max =1/2 x 3.773 x 5.75 = 10.85 kn

=8.910 knm = 10.395 knm

= 3773.6 kg/m = 3.773 kn/m

TUGAS MERENCANA KONSTRUKSI BETON

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ρmin =1.4 /fy =1.4 / 360 =0.00388 ρmakz =((0.75 x 0.85 x 0.89 x 25) x 600 /(360 x (600 +360))) = 0.02463 momen : (fy /(0,85 x fc))= (360 /( 0,85 x 25))=16,94 mpa Penulangan : M lap = 8.910 knm Mn lap = 8.910 /0.8 = 11.137 knm d = 20 -2-0.8-0.8 = 16.4 cm =0.164 m

 

Rn=

 =

 = 2.760 kn/m

  √          √        = 0.0153

ρmakz < ρ > ρmin 0.02463 < 0.0153 > 0.00388 As

=ρxbxd = 0.0153 x 15 x 16.4 = 3.76 cm² memakai tulangan 3 Ø 16 = 6.03 cm²

A’ 

= 0.2 x 3.76 = 0.75 memakai tulangan 2 Ø 16 =4.02 cm²

Penulangan : M tum = 10.395 knm Mn tum = 10.395 /0.8 = 12.993 knm d = 20 -2-0.8-0.8 = 16.4 cm =0.164 m

  

Rn=

 =

 = 3.220 kn/m

TUGAS MERENCANA KONSTRUKSI BETON

  √          √        = 0.0178

ρmakz < ρ > ρmin 0.02463 < 0.0178 > 0.00388 yang digunakan ρ = 0.0178 untuk mencari As As

= ρ x b x d =0.0178 x 15 x 16.4 =4.37 cm² memakai tulangan 3 Ø 16 = 6.03 cm²

A’

= 0.2 x 4.37= 0.87 memakai tulangan 2 Ø 16 =4.02 cm²

BALOK ANAK, PANJANG 7.75 METER      

b (lebar balok ) = 15 cm h (tinggi balok) = 20 cm mutu beton Fc = 25 mpa mutu baja Fy = 360 mpa Q pelat = 858.4 kg/m² bentang balok L = 7.75 m

Pembebanan : beban segitiga beban trapezium beban tembok beban kaca beban sendiri balok 

= 2/3 x1/2x854.4 x 7.75 = 2207 kg/m =1/2 x 854.4 x 1.5 – 1/3 x1/2 x 854.4 x 1.5²/3= 534 kg/m = 0.15 x 1.5 x 1700 x 4 = 1530 kg/m =0.05 x 1.5 x 2600 x 4 = 780 kg/m =0.15 x 0.20 x 2400 = 72 kg/m Q

= 5123 kg/m

TUGAS MERENCANA KONSTRUKSI BETON

= 5.123 kn/m 

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momen : m lapangan

= 1/14 x Q x L² = 1/14 x 5.123 x 7.75² =21.97 knm m tumpuan = 1/12 x Q x L² = 1/12 x 5.123 x 7.75² = 25.64 knm D max =1/2 x 5.123 x 7.75 = 19.85 kn ρmin =1.4 /fy =1.4 / 360 =0.00388 ρmakz =((0.75 x 0.85 x 0.89 x 25) x 600 /(360 x (600 +360))) = 0.02463 momen : (fy /(0,85 x fc))= (360 /( 0,85 x 25))=16,94 mpa Penulangan : M lap = 21.97 knm Mn lap = 21.97 /0.8 = 27.46 knm d = 20 -2-0.8-0.8 = 16.4 cm =0.164 m

  

Rn=

 =

 = 6.806 kn/m

  √          √        = 0.0378

ρmakz < ρ > ρmin 0.02463 < 0.0378 > 0.00388 yang digunakan ρ = 0.0378 untuk mencari As As

=ρxbxd = 0.0378 x 15 x 16.4 =9.29 cm² memakai tulangan 5 Ø 16 = 10.05 cm²

A’

= 0.2 x 9.29 = 1.98 memakai tulangan 2 Ø 16 =4.02 cm²

TUGAS MERENCANA KONSTRUKSI BETON

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Penulangan : M tum = 25.64 knm Mn tum = 25.64 /0.8 = 32.05 knm d = 20 -2-0.8-0.8 = 16.4 cm =0.164 m

  

Rn=

 =

 =7.944 kn/m

  √          √        = 0.0441

ρmakz < ρ > ρmin 0.02463 < 0.0441 > 0.00388 yang digunakan ρ = 0.0441 untuk mencari As As

=ρxbxd = 0.0441 x 15 x 16.4 =10.84 cm² memakai tulangan jarak 6 Ø 16 = 12.06 cm²

A’

= 0.2 x 10.84 = 2.16 memakai tulangan 2 Ø 16 =4.02 cm²

TUGAS MERENCANA KONSTRUKSI BETON

BALOK ANAK, PANJANG 3.25 METER      

b (lebar balok ) = 15 cm h (tinggi balok) = 20 cm mutu beton Fc = 25 mpa mutu baja Fy = 360 mpa Q pelat = 858.4 kg/m² bentang balok L = 3.25 m



Pembebanan : beban segitiga beban trapezium beban tembok beban kaca beban sendiri balok

= 2/3 x1/2 x 854.4 x 3.25 = 925.6 kg/m =1/2 x 854.4 x 1.5 – 1/3 x1/2 x 854.4 x 1.5²/3= 534 kg/m = 0.15 x 1.5 x 1700 x4 = 1530 kg/m =0.05 x 1.5 x 2600 x 4 = 780 kg/m =0.15 x 0.20 x 2400 = 72 kg/m Q

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momen : m lapangan

= 3841.6 kg/m = 3.841 kn/m

= 1/14 x Q x L² = 1/14 x 3.841 x 3.25² =2.89 knm m tumpuan = 1/12 x Q x L² = 1/12 x 3.841 x 3.25² = 3.38 knm D max =1/2 x 3.841 x 3.25 = 6.24 kn ρmin =1.4 /fy =1.4 / 360 =0.00388 ρmakz =((0.75 x 0.85 x 0.89 x 25) x 600 /(360 x (600 +360))) = 0.02463 momen : (fy /(0,85 x fc))= (360 /( 0,85 x 25))=16,94 mpa Penulangan : M lap = 2.89 knm Mn lap = 2.89 /0.8 = 3.62 knm d = 20 -2-0.8-0.8 = 16.4 cm =0.164 m

 

Rn=

 =

 = 897 kn/m

TUGAS MERENCANA KONSTRUKSI BETON

  √          √        = 4.983

ρmakz < ρ > ρmin 0.02463 < 4.983 > 0.00388 yang digunakan ρmin = 4.983 untuk mencari As As

= ρmin x b x d =4.983 x 15 x 16.4 =1.22 cm² memakai tulangan jarak 2 Ø 16 = 4.02 cm²

A’ 

= 0.2 x 1.22= 0.24 memakai tulangan 2 Ø 16 =4.02 cm²

Penulangan : M tum = 3.38 knm Mn tum = 3.38 /0.8 = 4.225 knm d = 20 -2-0.8-0.8 = 16.4 cm =0.164 m

 

Rn=

 =

 = 1.047 kn/m

  √          √        = 0.00581

ρmakz < ρ < ρmin 0.02463 < 0.00581 > 0.00388

TUGAS MERENCANA KONSTRUKSI BETON

yang digunakan ρmin = 0.00581 untuk mencari As As

=ρxbxd = 0.00581 x 15 x 16.4 =1.42 cm² memakai tulangan jarak 2 Ø 16 = 4.02 cm²

A’

= 0.2 x 1.42= 0.28 memakai tulangan 2 Ø 16 =4.02 cm²