1.2 PRACTICE EXAMINATION QUESTIONS MARK SCHEME
1.
(a) (a)
(i) (i)
23
Avogad ogadro ro’’s num numbe ber/ r/co cons nsta tant nt of mole molecu cule les/ s/pa part rtic icle les/ s/sp spec ecie iess / 6 × 10 [Not ‘atoms’]
1
Or same number of particles as (there are atoms) [Not molecules]
in 12.(00)g of
(ii)
12
1
0.3$0 &2 !oles "2 # 32 (# 1.0% × 10 mo mol)
1
&2
(iii (iii))
# 2% (× 1.0% × 10 ) [Accept answers via 4 separate mole calculations]
1
# 0.316 & 0.31' mol anser to 3* sf+ [Mar [Markk cons conseq eq on on err erro ors in in M1/ M1/M2 M2]]
1
&2
!oles !oles of nitr nitrog ogl, l,ce cerin rinee # - × 1.0% × 10 [Mark conseq on teir moles o! " 2 ]
(1) (1)
(# 0.0-3 mol)
M r of of nitrogl,cerine # 22' or number string
1 1
!oles of nitrogl,cerine # 22' × 0.0-3 # %.%0 & %.%3(g) [answer to #$ s!] [%! strin& "' ut !inal answer wron& ten allow M ut A* !or M+] [Mark conseq on error in M r ]
[,enalise wron& units] units]
[,enalise si&- !i&- errors once onl. in wole question]
(b)
n p # n or p # or p # 0.'3 × .31 × 1100 n 1.00 × 10 −3 p # / # # '%00%3 or '%0 or '. '.% [i&nore s-!-]
1 1 1
units # a or a or !a
(as appropriate) 1 [%! error in conversion !rom ,a treat as a contra0iction o! te units mark] [%! trans!er error error mark conseq ut penalise M2] [%! 0ata !rom outsi0e o! aove use0 penalise M2 an0 M#] [%! p epression incorrectl. rearran&e0 penalise M2 an0 M#] [i! 3 1#+# ' use0 penalise M2] [11]
2. (a)
4a
l "
21.6 23
33.3 3$.$ -$.1 16 1
0. 0.%(3%)
0.%(3) 2.(2)
5ence
1 1 3 1
Accept bacards calculation7 i.e. from formula to 8 composition7 and also accept route via ! r to 239 3$.$9 -7 and then to 113 [%! 5 values incorrectl. copie0 allow M1 onl.] [%! an. wron& Ar values/atomic numers use0 6* 78 (b)
3l2 * 64a"5 → $4al * 4al" 3 * 352"
1 [3]
3.
(penalt, for sig fig error #1mar per :uestion) (a )
=3
(i)
moles ;4"3 # 1.00/101.1 # %.% < 10 (m (mol)
1
(ii)
p # n or n # p/
1
p1
100000 × 1.22 × 10 & -
moles "2 # n # 93 # (1)
.31 × 2%
2
(1)
# -.%3 < 10=3 (mol) 1 (mark answer !irst : ceck ack i! wron&) (transcription error lose M# mark M4 conseq on error) (i! ‘untraceale’ !i&ures !i&ures use0 M#M47) (i! wron& temp conversion : lose M# : conseq M4) (i! n 93/p 6* lose M# an0 M4)
(b) (b)
(i) (i) (ii)
simp simple lest st/l /lo oes estt rat ratio io of atom atomss of of eac each h / elem elemen ent/s t/s in a com compo poun und d/ substance / species / entit, / molecule
1
'
N
-$.% 3%.1
"
16.$ 3'.6 1-
16
(1) 1.1' 1
1.1 2.3$ 1
2
;4"2 3
(1)
(M# tie0 to M2) (M# can e trans!erre0 !rom equation i! ratio correct ut *; not &iven) (i! calc inverte0 lose M2 an0 M#) (i! use0 At N 1 / wron& No !or Ar ten 6* lose M2 an0 M#) (i! 5 o! " missin& awar0 M2 onl.)
(c )
2;4"3 > 2;4"2 * "2 or fractions/multiples
1
(accept 2 'N"# < ' 2 N N 2"4 $ "2 ) ) (0o N"3 accept ‘=’ in equation) [10]
4.
(penalt. !or si& !i& error 1mark per question) M r (!g(4"3)2 # $(.3) (i! $(.3) (i! At N> use0 lose M1 an0 M2)
1
2
moles !g("5)2 # 0.01'2 (conse: on rong ! ) (anser to 3* s.f.)
1
moles 5l # 2 < 0.01'2 # 0.03-- or 0.03-3 (mol) (process mark)
1
0.03-3 × 1000 1
vol 5l # (i! can0i0ate
used 7-71+ 7-71+
# 3-.3 & 3-.$ (cm 3) (unless wron& unit)
1
or 7-71+1 lose M2)
(?ust answer wit no workin& i! in ran&e (4)- i! s a. #4 ten (2)) (i! not 2@1 ratio lose M# an0 M4) (i! work on 6l 6* 7/4) [4]
2A1* 3ul 2
5.
→
2A113 * 3u9 (accept multiples/!ractions) " 2*
2A1* 3u * 3u9
→ 2A1
3*
1 [1]
6.
(a )
moles 5403
# 1'$ ?
&3
10 < 1.$ # (0.262$ mol)9 moles b(4"3 )2 0.262$ # (0.131 mol)9 !r b(4"3 )2 mass b(4"3 )2 0.131#-3.$ g9 (accept 4#-2 B 4#-C) (M1 D M2 are process marks- %! error in M1 or in M2 0o not mark M4 consequentiall. i-e- 0o not awar0 M4) (i! atomic numers use0 in M# 0o not awar0 M4)
1 # @< 1 # 331(.2)9 1 #331.2 1
(b)
(i)
p # n9 n=
p/
1 &-
=
100000 ×1.$ ×10 .31 × $00
1
&3
#
3.61 ? 10 9 (%! pressure not converte0 to ,a ma 2) 93 (%! n
(ii)
9
p1
1
use0 6*E M2 M# 7)
moles402
# -/$ -/$ <
&3
3.61 < 10 9 [mark is !or use o! 4/F] &3
2.% < 10
1 &3
"9 1.'<10 9
1
!r 4"2
# -69 1
mass4"2
# &3
-6 <2.%
# 0.1.33(g) "9 0.021 (g)9 1 ( i! atomic numers use0 M# M4 7) [11]
7.
(a )
(b) (b)
24a * 2453
(i) (i)
→
24a452 * 52
(or multiples)
Bim Bimples plestt rat ratio io of atom atomss of of eac each h ele elem ment ent in in a comp compou ound nd / sub subst stan ance ce / species / entit, / molecule
(ii)
1
1
!g "
4 1
16.2
16.2 1.%
(2-)
2-.3
1-
6-.% 16 (7-+F)
0.66' 1.3' -.06 1 1 6 !g42"6
2
(Mark M1 !irst- %! an. wron& Ar use0 6* 7) (Accept M&(N" 3 )2 !or M# i! aove workin& sown) [4]
8.
(a )
&3
< 0.$00
&2
100
#
$.00 < 10
(ii)
2'.3 <10 < 0.600
#
1.6- < 10 / 1.63 < l0 (m (mol) onl,
(iii)
1.6- <10 (m ( mol) Mark conseq on (ii)
(iv)
$.00 < 10 = 1.6- < 10 # 3.36 < 10 (m (mol) Mark conseq on (i) D (iii)
(v)
3.36 < 10 < G 1.6 < 10 (mol) Mark conseq on (iv)
&3
(mol)
&2
(i)
accept $ <10 / 0.0$
&2
1
&2
1
&2
&2
1
&2
&2
&2
&2
1
&2
&2
%! 2-+C H 17 used 1.3% < 10
&2
1
&2
1.6 < 10 < l32(.l)
or 1.3% < 10 < 132(.l) 1
Mark !or M r # 2.22 g
(b)
or 1.3 g 1
p # n
1
n = 0.1-3 1'
# .-(1) .-(1) &3
< 10 (m (mol)
1 100000 × 2.6 ×10−-
p/
=
n
#
.31× .- ×10− 3
(1) 1
# -0.$ & -10.$ (;) 1 Mark conseq on moles Note
Ii&- !i&- penalt. B appl. once i! sin&le s! &iven unless calc works eactl. [11]
9.
%0eal &as equation equation p # n (1) 103000 × 12' × 10 −6 (.31 × -1$) 6alculation 6alculation n # p/ # (1) mark !or volume conversion !ull. correct &3
# 3.'% < 10 (mol) (1) :#
:#
ran&e #-+J H 17 to #-C H 17 &3
!r # m/n # .30-/3.'% < 10 # 0.1 (1) ran&e C7 : C7-# min 2 s-!- conseq %! ‘’ wron& lose M2E M2E ‘p’ wron& lose M#E M#E ‘inverte0’ lose M#
$
an0 M4 [5]
1.
(a)
!1 8 b, mass of 5 # '.'(0)8 (1)
!2 mol # %2.3 / 12 # '.6% (1) !3 (ratio 11
∴)
mol 5 # '.'0 / 1 # '.'0
5
''
'
Credit variations for M2 78 × 100 = 6 and 12 Correct answer = 3 marks
×
%2.3 100 = 6
' (b) (b)
(5 (5 has has empi empiri rica call mas masss of of 13 13 and and 13 # 6 ∴) 656 Correct answer 1 mark
[4]
11.
23
23/6.023 < 10 (1) 6* 7 i! inverte0 or multiplie0 &23
tied to !1 3.(2) < 10
2=$ sig figs+ (1) 2 [2]
12.
(a) (b)
(simplest) ratio of atoms of each element in compound (1) 8 o,gen # 3%.$8 (1) 4a 2.-/23
r 32.1/$2 " 3%.$/16 (1) # 1.23 # 0.61' # 2.-' (21-) so empirical formula # 4a 2r"- (1) %! 5 o.&en not calculate0 onl. onl. M2 availaleE i! A r values wron& onl. M1 availale [4]
(a)
13.
0×240 (1)
!r (i1-) # 1%0 (1)
0 ⋅ 2moles i1- #
-
# 0×06 (1)
mass # 0×06 < 1%0 # 11×- (1)
(b)
-
moles 4a"5
# moles 5l # 0.12 (1)
moles # conc (1)
vol 4a"5
0 ⋅ 12 3 # 1 ⋅ 1 # 10%cm (1) 3
moles 51 (c )
moles 52
#
2
# 0×06 (1)
(allow conseq) conseq)
n93
#
p
, # # n93 (1) or ,
0 ⋅ 06 × ⋅ 31 × 2%3 #
% 000 &3
(1) 3
# 1×-% < 10 m (1)etc (if chemical error on moles 5 27 ma2) (2)
[11]
10
10.0 14.
(a)
moles of B # 32.1 ( # 0.312$)
allo 32 (1)
mass of sodium sulphide 0.312 < '.1 i.e. 2-.- g or 2-.3' g (accept 2-.3 g or 2-.33 g) (no sig.fig. penalt,) (ignore units) (1)
2
$.00 (b) (b)
mole moless of of h,dr h,drog ogen en sulp sulphi hide de
3-.1
(i.e. 0.1-66 or 0.1-' mol) (1)
moles of h,drogen gas needed # moles of 5 2B (1) volume 0.1-66 0.1-66 < 2-$00 i.e. 3$%2 or 3$%0 3$%0 cm (3602 or 3600 if 0.1-' used) (1)
3
3 3
anser must be in cm ie < 2-$007 not < 2-.$ / no s.f. penalt, / ignore units allo , allo , # # n93 method method ith remembered value of 9 of 9 [5]
(a)
15.
Ideal gas equation law (1)
n = (b)
Moles o! X
,
1
110000 × 2.3- × 10
93 (1) !
-
−
.31 × -'3 &3
# 6.$$ < 10 (1) !3
65 to 66 × 10
n = $f write
" min 2 si# fi#s
93 , %ero &ere" '(t can score M r m
9elative molecular mass o! X !r #
n
(1)
# 62 (1) 615 to 625
(c) (c)
8 o o,gen # $1.6 (2) #3.' / 12
5 # %.6 / 1
" # $'.6 (2) / 16
# 3.23
# %.6
# 3.23
1 3 1
∴
(1)
53" (1)
$f no ) * or if wron# + r (sed t&en ma, 1 Correct em-irica. form(.a earns a.. t&ree marks
3
62 (d)
( 31 < 53") # 256"2 (1)
1 [/]
mass 16.
(a )
!oles 5l #
1%.6
! r
# 36.$ (1) (# 0.$3') 0.$3'
oncentration # 0.2$ (1) &3
# 2.1$ (mol dm ) (1)
mass !
r correct Conse on min 2 d- 214 to 215 $#nore (nits + .ose one mark
3
21.'
(b)
×
1000
(i)
0.263
–3
= 5.7(1) × 10 (mol) (1)
!3
57 to 571 × 10
$.'1 × 10
3
−
&3
2
(ii)
# 2.$ < 10 (mol) (1)
Conse
0.3%(iii)
2.$ × 10 −3 # 13 (1) Conse
(iv) 9elative atomic mass o! M 13 = 60 # ' (1) ' 2 ! 3% (1) *
%0enti!. o! M otassium or ; or ; (1) Conse $f 78 = M r t&en M = se.eni(m
6 [/]
1.00' 17.
(a )
C # 1.6'3- × 10
mass of 1 mol −
2-
(1) or mass of 1 atom m(st s&ow workin#
# 6.022$ < 10
23
(1) $#nore wron# (nits answer on. scores 1
2
(b)
e:ual (1) *r same or 11
1 ,1
(c )
# n (or n # 93 ) (1)
%000 × 0.03$2 #
.31 × 2%
(1)
# 1.3% (1) +..ow 13/0 to 13/5 i#nore (nits even if incorrect answer = 14 .oses .ast mark
3
1000 (d)
&3 0.'32 < 2$0 # 2.%3 (1) mol.dm (1)
3
!1
* M" mo.dm " mo.. a..ow 2/28 to 2/3
ote (nit mark tied to c(rrent answer '(t a..ow (nit mark if answer = 2/ or 3
2
2$ (e )
(i)
moles 52B"- # 1000 < 1.2- # 0.0310 $f (se m1v1 = m2v2 scores 3 if answer is correct ot&erwise %ero 3
moles 453 in 30. cm # 0.0310 < 2 # 0.0620 (1) Mark is for ×2 C if × 2 not (sed
1000 3 &3 moles of 45 3 in 1 dm # 0.620 < 30. # 2.01 (1) (mol dm )
+..ow 2010 to 2015 o (nits *" wron# (nits .ose .ast mark
(ii)
moles (45-)B"- # moles 52B"- # 0.310 (1) +..ow conse(entia. wron# mo.es in -art 9i: if c.ear ; 2<*4=9;4:<*4 ron# form(.a for 9; 4:<*4 C=0
!r (45-)B"- # 132.1 (1) +..ow 9132:
mass # moles < !r # 0.0310 < 132.1 # -.10 (1) "# $o%&' o# (NH4)SO4 o *%&+r CE 9#: wron# (nit .oses mark +..ow 40/ ! 41 ! 411
6
(f)
!g3 42 * 652" → 3!g("5)2 * 245 3 >orm(.ae 91: a.anced e(ation 91:
2 [16]
average mass of an entit, (1) mass of 1 atom of 12
(a)
18.
× 12 (1)2
(b)
simplest ratio of atoms of each element in a compound
(c )
(i)
1
8" # 6$.' (1)
32.% 1.-0 6$.' 1 16 (1) 5" # 12 # 1.%6 1 2.%3 # 2 5"3 (1) (ii)
- 52 "6 (1)
mass ! r (d)
=
-
1000 16 (1) # 62.$ (1)
(i)
7-72F scores one
(ii)
p# n (1) (1)
n93
=
2 × 62.$ × .31 × 2% 100000
# , 1 0 m
(1)
3
# 3.
(1)
(allow consequential markin& ut i! !actor o! 2 in missin& ma 2)
6 [13]
Avogadro’s number of molecules (1)
19.
2#
allow to -1 H 17 molecules "9 No- o! atoms in 12& o!
12
6
1
[1]
2.
(a ) 1 (b)
Avogadro’s (i)
p#n (1)
n93
m
allo D# , etc.7 p# Mr
n93 (ii)
# ,
1 × ⋅ 31× 2% #
100 000
# 0.02-
(1) 3
m (1)
(allow 7-724+ to 7-72F) allow use us e o! 177 !or !o r , i! ans &iven & iven as 24-C 2 4-C 0m
#
p n# # $00000 × 0.00$
(iii)
.31 × 2'3
(1)
s
9treat 500 as +!1 ot&er va.(es . 2mar st
00051000 .oses 1 two marks
# 1.10mol (1) (allow 1-1 to 1-11) !r ("2)
# -- (1)
treat wron# Mr as +!1
mass
# --<1.10 # -.$ (g) (1)
(allow 4C:4J) , 11 1 3 st 9note can (se ca.c(.ation invo.vin# 3 and 224 dm instead of 1 mark ? re(ires same acc(rac for f(.. marks:
'
100 (c )
# 1000 < $.0 # 0.$(0)(mol) (1)
moles 51
moles 51 moles 52
#
2
(1) # 0.2$ (mol)
9if no factor of 2 C = * from &ere:
mass 52 (d)
(i)
%"
# 0.2$<2 # 0.$(0) (g) (1) 3 # --.- (1)
9if incorrect 9if
*" +!1:
* omitted can score ma, 1 for >eC 2:
3.% ratio >eC* = $$.
16.' --.9or 50:
12.0 16.0 9if (se +t" C: # 1 2 Ee 2 "- (1)
(ii)
" (1) 9mark inde-endent of d 9ii::
[15]
20.0 21.
(a )
# 1'.0 (1)
moles of 453 moles of 54" 3
# moles of 453 # 1.1
1.1 volume
# 3
# 0.$ (1) dm (1)
(b)
(i)
(1)
-
n
2
# n (1)
%$000 × 0.0$00
# #
.31 × 2%
(1)
# 1.%2 mol (1)
1.%2 (ii)
1.$ (1) 1.2 mol
Moles o! ammonium nitrate Mass o! ammonium nitrate
mass # 1.2 < 0 (1) # 102 g (1) 6 [10]
12 1.%% × 10 & 23 1+ # 6.03<1023 (1)
22.
2 [2]
(a)
23.
mass ratio of "2;l"3 # %6 / 2-$.2 ( # 0.3%2) &2
or moles of " 2 # 3/2 < 1.20 < 10 or e:uivalent (1)
mass of "2 ! 0.3%2 < 1.-' # 0.$'6g (1) (b (b)
2
moles "2 ! 1.00/2-.00 ( # 0.0-1' mol) (1) moles ;l"3 # 2/3 moles " 2 # 0.0-1' < 2/3 # (0.02' mol) (1) mass ;l"3 # 0.02' < 122.6 # 3.-lg (1)
3
give one mar for p for p # n93 # n93 to get n for " 27 then second and third mar as above or
2/3 mole of ;l" 3 → 1 !ole of " 2 (1) 3
1.'g → 2- dm "2 (1) 1.' 2-
3
g # 3.-lg → 1 dm "2 (1)
penalise other than 2 & $ sig. figs. once in (d)(i) and (ii) penalise missing or rong units once in (d)(i) (d)(i) and (ii) [5]
24.
(a) (a)
!ass !ass of of each each elem elemen entt in the the com compo poun und d (1)
1
(b) (b)
4umbe 4umberr of atom atomss of eac each h elem elemen entt in a mole molecu cule le (1)
1
(c )
(i)
!r Fa(4"3)2 # 261 (1)
$ moles Fa(4"3)2 # 261 (1) # 0.01%2 1
moles gas # 2 2 < 0.01%2 (1) # 0.0-'% n 0.0-'% × .31 × 2% p 100000 # (1) # &3
3
# 1.1% <10 m (1) (ii) (ii)
moles les 5l 5l # 2 < 0.01 0.01%2 %2 (1) # 0.030.03vol 5l #
1 .2
3
3
# 0.032 dm (1) (or 32 cm )
' [/]
25. percentage b, mass of o,gen # 3.08 3.08 (1) ratio of elements # -2.%/12 2.-/1 16.'/1- 3.0/16 (1) # 3.6 2.- 1.2 2.empirical formula is 352 4"2 (1) molecular formula is 65- 42"- (1)
[4]
26.
(a)
85 # 1. (1) 1.2 1. F 5 # 10. 1
(1)
# 2 $ F 25$ (1)
(b)
F-510 (1)
[4]
27.
(a)
mean mass of o f an entit , (or molecule) molecu le) (1) < 12 (1) mass of 1 atom of
12
2
12 (b)
1.%%3 × 10 & 23
#
6.02 < 10
23 (1)
(allo 6.020 to 6.023)
1 [3]
28.
(b)
(i)
8E
# -2× (1)
GE
$' ⋅ 2
-2 ⋅
# 12' #
1%
(1)
# GE$ (1) (ii)
G2 * $E2 → 2GE$ (1) (o (or < @)
[4]
29. C 22.2412 = 1.!5 " 3.711 = 3.71 #$ 74.057%.% = 0.%27 (1) $atio C&"$ = 2&4&1 ∴C2"4#$ (1) em'i$ial mass = 107.% ∴ mol o$mula = 215.!107.% × C 2"4#$ = C4"!#$2 (1) must use 8 to Hustif, anser
or (22.2-/100) < 21$. # -'.%% i.e. -/12 # - carbon atoms (1) 5 (3.'1/100) < 21$. # .01 i.e. /1 # h,drogen atoms atoms (1) Fr ('-.0$/100) < 21$. # 1$%. 1$%. i.e. 1$%./'%.% # 2 bromine bromine atoms (1)
or (-/21$.) < 100 # 22.2-8 (1) 5 (/21$.) < 100 # 3.'1 8 (1) Fr (1$%./21$.) < 100 # '-.0$8 '-.0$8 (1)
3 [3]