Home
Add Document
Sign In
Register
Math Bac Cours 10
Home
Math Bac Cours 10
...
Author:
Youssef NEJJARI
213 downloads
314 Views
622KB Size
Report
DOWNLOAD .PDF
Recommend Documents
Math Bac Cours 10
Cours+Math+-+Suites+(cours+complet)+-+Bac+Math+Mr+Dhaouadi+Nejib+www.sigmaths.co.cc
suites pour bac tunisien
Cours Math Fonctions
Cours complet math financière
Bac blanc (Lycée pilote Karouan) - Mathématiques - Bac Math (2007-2008)
Description complète
Math 10 Learning Module
Unit 1 of Grade 10 Mathematics
Mental Math Grade 10
mathDescripción completa
Cours Anglais Program Bac Science Maroc Najib
Description complète
Formulas for Grade 10 Math
All of the formulas you will need in your grade 10 math course Student generatedFull description
Math 10-4 Advanced Algebra
Math 10-4 syllabus
Lesson Plan in Math 10
unfinished lesson planFull description
Math 10 Unit 4 LM
Math 10 ModuleFull description
math
Descripción completa
math
Descripción: disfruta
Cours+-+SVT+-+Bac+Sciences+exp+(2014-2015)+Mr+Ezzeddini+Mohamed
cours svt bac science tunisieDescription complète
BAC engleza
bac englezaFull description
istorie bac
Material Bac
Un material util celor care se pregatesc pentru examenul de bacalaureat la geografie
BAC RESOLUTION
sample
formule BAC
Full description
Geografie BAC
OPERE BAC
Cours+ Rlc +Bac+Sciences+Exp+(2011 2012)+Mr+Tlili+Touhami
Cours
اﻟﺠﺪاء اﻟﺴﻠﻤﻲ ﻓﻲ اﻟﻔﻀﺎء و ﺗﻄﺒﻴﻘﺎﺗﻪ -Iاﻟﺠﺪاء اﻟﺴﻠﻤﻲ -1ﺗﻌﺮﻳﻒ ﻟﺘﻜﻦ vو uﻣﺘﺠﻬﺘﻴﻦ ﻣﻦ اﻟﻔﻀﺎء ،و Aو Bو Cﻧﻘﻂ ﻣﻦ اﻟﻔﻀﺎء ﺣﻴﺚ u = ABو . v = AC ﻳﻮﺟﺪ ﻋﻠﻰ اﻻﻗﻞ ﻣﺴﺘﻮى ) ( Pﺿﻤﻦ اﻟﻔﻀﺎء ﻳﻤﺮ ﻣﻦ اﻟﻨﻘﻂ Aو Bو . C اﻟﺠﺪاء اﻟﺴﻠﻤﻲ ﻟﻠﻤﺘﺠﻬﺘﻴﻦ vو uﻓﻲ اﻟﻔﻀﺎء هﻮ اﻟﺠﺪاء اﻟﺴﻠﻤﻲ AB ⋅ ACﻓﻲ اﻟﻤﺴﺘﻮى ) ( Pﻧﺮﻣﺰ ﻟﻪ ﺑـ u ⋅ v
ﻣﻠﺤﻮﻇﺔ ﺟﻤﻴﻊ ﺧﺎﺻﻴﺎت اﻟﺠﺪاء اﻟﺴﻠﻤﻲ ﻓﻲ اﻟﻤﺴﺘﻮى ﺗﻤﺪد إﻟﻰ اﻟﻔﻀﺎء -2ﻧﺘﺎﺋﺞ ﻟﺘﻜﻦ vو uﻣﺘﺠﻬﺘﻴﻦ ﻣﻦ اﻟﻔﻀﺎء ،و Aو Bو Cﻧﻘﻂ ﻣﻦ اﻟﻔﻀﺎء ﺣﻴﺚ u = ABو . v = AC * إذا آﺎن v ≠ 0و u ≠ 0ﻓﺎن u ⋅ v = AB × AC × cos BAC u ⋅v = 0 ﻓﺎن * إذا آﺎن u = 0أو v = 0 * إذا آﺎن u ≠ 0ﻓﺎن ' u ⋅ v = AB ⋅ AC = AB ⋅ AC ﺣﻴﺚ' Cاﻟﻤﺴﻘﻂ اﻟﻌﻤﻮدي ﻟـ Cﻋﻠﻰ )(AB 1 = u ⋅v * AB 2 + AC 2 − BC 2 2
(
)
-3ﻣﻨﻈﻢ ﻣﺘﺠﻬﺔ ﻟﺘﻜﻦ uﻣﺘﺠﻬﺔ و Aو Bﻧﻘﻄﺘﻴﻦ ﻣﻦ اﻟﻔﻀﺎء ﺣﻴﺚ
u = AB
اﻟﻌﺪد اﻟﺤﻘﻴﻘﻲ u ⋅ uﻳﺴﻤﻰ اﻟﻤﺮﺑﻊ اﻟﺴﻠﻤﻲ ﻟـ uو ﻳﻜﺘﺐ u 2 = AB 2 اﻟﻌﺪد اﻟﺤﻘﻴﻘﻲ اﻟﻤﻮﺟﺐ u 2
ﻳﺴﻤﻰ ﻣﻨﻈﻢ اﻟﻤﺘﺠﻬﺔ uﻧﻜﺘﺐ u = u 2
ﻣﻼﺣﻈﺔ و آﺘﺎﺑﺔ 2 * u = u2 *
إذا آﺎن
v ≠ 0وu ≠ 0
-4ﺧﺎﺻﻴﺎت ∈ ∀α
3 3
ﻓﺎن
) (
u ⋅ v = u v cos u ; v
∀ (u ,v ,w ) ∈V
ﻣﺘﻄﺎﺑﻘﺎت هﺎﻣﺔ
u ⋅v = v ⋅ u * * u ⋅ (v + w ) = u ⋅v + u ⋅w * (v + w ) ⋅ u = v ⋅ u + w ⋅ u * ) u ⋅ αv = αu ⋅v = α × (u ⋅v -5ﺗﻌﺎﻣﺪ ﻣﺘﺠﻬﺘﻴﻦ : ﺗﻌﺮﻳﻒ ﻟﺘﻜﻦ vو uﻣﺘﺠﻬﺘﻴﻦ ﻣﻦ اﻟﻔﻀﺎء .V3
ﺗﻜﻮن vو uﻣﺘﻌﺎﻣﺪﻳﻦ إذا وﻓﻘﻂ إذا آﺎن
u ⋅v = 0
ﻣﻼﺣﻈﺔ اﻟﻤﺘﺠﻬﺔ 0ﻋﻤﻮدﻳﺔ ﻋﻠﻰ أﻳﺔ ﻣﺘﺠﻬﺔ ﻣﻦ اﻟﻔﻀﺎء V3 ﺗﻤﺮﻳﻦ اﻟﻤﻜﻌﺐ ABCDEFGHاﻟﺬي ﻃﻮل ﺣﺮﻓﻪ a أﺣﺴﺐ AE.BGو AE.AGو AG.EB
1
ﻧﻜﺘﺐ
(u + v ) = u + v + 2u ⋅v 2 (u − v ) = u 2 + v 2 − 2u ⋅v (u + v )(u − v ) = u 2 − v 2
u ⊥v
2
2
2
-IIﺻﻴــــــﻎ ﺗﺤﻠﻴﻠﻴـــــــــﺔ -1اﻷﺳﺎس و اﻟﻤﻌﻠﻢ اﻟﻤﺘﻌﺎﻣﺪان اﻟﻤﻤﻨﻈﻤﺎن ﺗﻌﺮﻳﻒ ﻟﺘﻜﻦ iو jو kﺛﻼث ﻣﺘﺠﻬﺎت ﻏﻴﺮ ﻣﺴﺘﻮاﺋـــــﻴﺔ ﻣﻦ اﻟﻔﻀﺎء V3و Oﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻀﺎء. ) (i ; j ;kأﺳﺎ س ﻟﻠﻔﻀﺎء V3
ﻳﻜﻮن اﻷﺳﺎس ) (i ; j ;kﻣﺘﻌﺎﻣﺪ )أو اﻟﻤﻌﻠﻢ ) (O ; i ; j ; kﻣﺘﻌﺎﻣﺪ( إذا وﻓﻘﻂ إذا آﺎﻧﺖ اﻟﻤﺘﺠﻬﺎت iو jو k ﻣﺘﻌﺎﻣﺪة ﻣﺜﻨﻰ ﻣﺜﻨﻰ. ﻳﻜﻮن اﻷﺳﺎس ) (i ; j ;kﻣﺘﻌﺎﻣﺪ و ﻣﻤﻨﻈﻢ )أو اﻟﻤﻌﻠﻢ ) (O ; i ; j ; kﺗﻌﺎﻣﺪ وﻣﻤﻨﻈﻢ( إذا وﻓﻘﻂ إذا آﺎﻧﺖ
اﻟﻤﺘﺠﻬﺎت iو jو kﻣﺘﻌﺎﻣﺪة ﻣﺜﻨﻰ ﻣﺜﻨﻰ و i = j = k = 1 -2اﻟﺼﻴﻐﺔ اﻟﺘﺤﻠﻴﻠﻴﺔ ﻟﻠﺠﺪاء اﻟﺴﻠﻤﻲ أ -ﺧﺎﺻﻴﺔ اﻟﻔﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ.م.م ) (O ; i ; j ; k إذا آﺎﻧﺖ
)
;u xو ) ' v ( x'; y'; zﻓﺎن ( y; z
' u ⋅ v = xx '+ yy '+ zz
ﻣﻼﺣﻈﺔ إذا آﺎﻧﺖ ) u( x; y; zﺑﺎﻟﻨﺴﺒﺔ ﻟﻠﻤﻌﻠﻢ.م.م ) (O ; i ; j ; kﻓﺎن
u ⋅i = x ; u⋅j =y ; u ⋅k = z ب -اﻟﺼﻴﻐﺔ اﻟﺘﺤﻠﻴﻠﻴﺔ ﻟﻤﻨﻈﻢ ﻣﺘﺠﻬﺔ و ﻟﻤﺴﺎﻓﺔ ﺑﻴﻦ ﻧﻘﻄﺘﻴﻦ * -إذا آﺎﻧﺖ ) u( x; y; zﺑﺎﻟﻨﺴﺒﺔ ﻟﻠﻤﻌﻠﻢ.م.م ) (o;i ; j ;kﻓﺎن u = x 2 + y 2 + z 2 * -اذا آﺎﻧﺖ ) A ( x A ; y A ; z Aو ) B ( xB ; yB ; z Bﺑﺎﻟﻨﺴﺒﺔ ﻟﻠﻤﻌﻠﻢ.م.م ) (o;i ; j ;k ﻓﺎن ﺗﻤﺮﻳﻦ ﻧﻌﺘﺒﺮ
( xB − x A ) 2 + ( y B − y A ) 2 + ( z B − z A ) 2
)
(
)
A 1;1; 2و 2; − 2;0
(
B
= AB
(
)
و C −1; −1; − 2
ﺑﻴﻦ أن ABCﻣﺜﻠﺚ ﻣﺘﺴﺎوي اﻟﺴﺎﻗﻴﻦ وﻗﺎﺋﻢ اﻟﺰاوﻳﺔ -3ﺗﺤﺪﻳﺪ ﺗﺤﻠﻴﻠﻲ ﻟﻤﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ Mﻣﻦ اﻟﻔﻀﺎ ء ﺑﺤﻴﺚ u.MA = k ﻟﺘﻜﻦ ) u ( a;b;cﻣﺘﺠﻬﺔ ﻏﻴﺮ ﻣﻨﻌﺪﻣﺔ و ) A ( x A ; y A ; z Aﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻀﺎء ﻧﻌﺘﺒﺮ ) M ( x; y; z
u.MA = k ⇔ ........ ⇔ ax + by + cz + d = 0 ﺧﺎﺻﻴﺔ ﻟﺘﻜﻦ ) u ( a;b;cﻣﺘﺠﻬﺔ ﻏﻴﺮ ﻣﻨﻌﺪﻣﺔ و Aﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻀﺎء ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ Mﻣﻦ اﻟﻔﻀﺎ ء ﺑﺤﻴﺚ u.MA = kهﻲ ﻣﺴﺘﻮى ﻣﻌﺎدﻟﺘﻪ ax + by + cz + d = 0ﺣﻴﺚ dﻋﺪد ﺣﻘﻴﻘﻲ ﻣﺜﺎل ﻧﻌﺘﺒﺮ ) u ( 2; −1;1ﻣﺘﺠﻬﺔ و ) A (1; −1; 2ﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻀﺎء ﺣﺪد ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ Mﻣﻦ اﻟﻔﻀﺎ ء ﺑﺤﻴﺚ u.MA = −1 -IIIﺗﻄﺒﻴﻘﺎت اﻟﺠﺪاء اﻟﺴﻠﻤﻲ ﻓﻲ اﻟﻔﻀﺎء -1ﺗﻌﺎﻣﺪ اﻟﻤﺴﺘﻘﻴﻤﺎت و اﻟﻤﺴﺘﻮﻳﺎت ﻓﻲ اﻟﻔﻀﺎء أ -ﺗﻌﺎﻣﺪ ﻣﺴﺘﻘﻴﻤﻴﻦ ﻟﻴﻜﻦ ) (D1و ) (D2ﻣﺴﺘﻘﻴﻤــﻴﻦ ﻣﻦ اﻟﻔﻀﺎء ﻣﻮﺟﻬﻴﻦ ﺑﺎﻟﻤﺘﺠﻬﺘﻴﻦ u 1و u 2ﻋﻠﻰ اﻟﺘﻮاﻟﻲ ( D1 ) ⊥ ( D 2 ) ⇔ u 1 ⋅ u 2 = 0
ب -ﺗﻌﺎﻣﺪ ﻣﺴﺘﻘﻴﻢ و ﻣﺴﺘﻮى ﺧﺎﺻﻴﺔ ﻟﻴﻜﻦ ) (Pﻣﺴﺘﻮى ﻣﻮﺟﻪ ﺑﺎﻟﻤﺘﺠﻬﺘﻴﻦ u 1و u 2و ) (Dﻣﺴﺘﻘﻴﻢ ﻣﻮﺟﻪ ﺑﺎﻟﻤﺘﺠﻬﺔ u 3 u2 ⊥ u3و
( D ) ⊥ ( P ) ⇔ u1 ⊥ u 3 2
ج -ﻣﻼﺣﻈﺎت واﺻﻄﻼﺣﺎت * اﻟﻤﺘﺠﻬﺔ uاﻟﻤﻮﺟﻬﺔ ﻟﻤﺴﺘﻘﻴﻢ ) (Dاﻟﻌﻤﻮدي ﻋﻠﻰ ﻣﺴﺘﻮى ) (Pﺗﺴﻤﻰ ﻣﺘﺠﻬﺔ ﻣﻨﻈﻤﻴﺔ ﻟﻠﻤﺴﺘﻮى ).( P * اذا آﺎﻧﺖ uﻣﻨﻈﻤﻴﺔ ﻟﻤﺴﺘﻮى ) (Pﻓﺎن آﻞ ﻣﺘﺠﻬﺔ vﻣﺴﺘﻘﻴﻤﻴﺔ ﻣﻊ uﺗﻜﻮن ﻣﻨﻈﻤﻴﺔ ﻟﻠﻤﺴﺘﻮى )(P * اذا آﺎﻧﺖ uﻣﻨﻈﻤﻴﺔ ﻟﻤﺴﺘﻮى ) (Pو vﻣﻨﻈﻤﻴﺔ ﻟﻤﺴــﺘﻮى )' (Pوآﺎﻧﺘﺎ uو vﻣﺴﺘﻘﻴﻤﻴﺘﻴﻦ ﻓﺎن ) (Pو)'( P ﻣﺘﻮازﻳﺎن 2 * إذا آﺎن ) ( A ; B ) ∈ ( Pو uﻣﻨﻈﻤﻴﺔ ﻟﻤﺴﺘﻮى ) (Pﻓﺎن u ⊥ AB
ﺗﻤﺮﻳﻦ ﻓﻲ اﻟﻔﻀﺎء اﻟﻤﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ .م(O ; i ; j ; k ) . ﺣﺪد ﺗﻤﺜﻴﻞ ﺑﺎراﻣﺘﺮي ﻟﻠﻤﺴﺘﻘﻴﻢ ) (Dاﻟﻤﺎر ﻣﻦ) A(-1; 2 0و اﻟﻌﻤﻮدي ﻋﻠﻰ اﻟﻤﺴﺘﻮى ) (Pاﻟﻤﻮﺟﻪ ﺑـﺎﻟﻤﺘﺠﻬﺘﻴﻦ ) u(1;−1;1و )v(2;1;1 ﺗﻤﺮﻳﻦ ﻓﻲ اﻟﻔﻀﺎء اﻟﻤﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ .م (O ; i ; j ; k ) .ﻧﻌﺘﺒﺮ اﻟﻤﺴﺘﻮى ) (Pاﻟﺬي ﻣﻌﺎدﻟﺘﻪ ax-2y+z-2=0و اﻟﻤﺴﺘﻘﻴﻢ ) (Dﺗﻤﺜﻴﻠﻪ ﺑﺎراﻣﺘﺮي
t ∈ IR
x= 2t y =1+ 3 t z = − 2 + bt
-1ﺣﺪد ﻣﺘﺠﻬﺘﻴﻦ ﻣﻮﺟﻬﺘﻴﻦ ﻟﻠﻤﺴﺘﻮى )(P -2ﺣﺪد aو bﻟﻜﻲ ﻳﻜﻮن ) (D )⊥(P د -ﺗﻌﺎﻣﺪ ﻣﺴﺘﻮﻳﻴﻦ ﺗﺬآﻴﺮ ﻳﻜﻮن ﻣﺴﺘﻮﻳﺎن ﻣﺘﻌﺎﻣﺪﻳﻦ اذا و ﻓﻘﻂ اذا اﺷﺘﻤﻞ أﺣﺪهﻤﺎ ﻋﻠﻰ ﻣﺴﺘﻘﻴﻢ ﻋﻤﻮدي ﻋﻠﻰ اﻟﻤﺴﺘﻮى اﻵﺧﺮ.
ﺧﺎﺻﻴﺔ ﻟﻴﻜﻦ ) (Pو )' (Pﻣﺴﺘﻮﻳﻴﻦ ﻣﻦ اﻟﻔﻀﺎء و uو vﻣﺘﺠﻬﺘــﻴﻦ ﻣﻨﻈﻤﻴﺘﻴﻦ ﻟﻬﻤﺎ ﻋﻠﻰ اﻟﺘﻮاﻟﻲ ) (P')⊥(Pاذا وﻓﻘﻂ اذا آﺎن u ⊥v
-2ﻣﻌﺎدﻟﺔ ﻣﺴﺘﻮى ﻣﺤﺪد ﺑﻨﻘﻄﺔ و ﻣﺘﺠﻬﺔ ﻣﻨﻈﻤﻴﺔ ﻋﻠﻴﻪ .aﻣﺴﺘﻮى ﻣﺤﺪد ﺑﻨﻘﻄﺔ و ﻣﺘﺠﻬﺔ ﻣﻨﻈﻤﻴﺔ ﻋﻠﻴﻪ ﻣﺒﺮهﻨﺔ ﻟﺘﻜﻦ uﻣﺘﺠﻬﺔ ﻏﻴﺮ ﻣﻨﻌﺪﻣﺔ و Aﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻀﺎء * اﻟﻤﺴﺘﻮى اﻟﻤﺎر ﻣﻦ Aو اﻟﻤﺘﺠﻬﺔ uﻣﻨﻈﻤﻴﺔ ﻟﻪ هﻮ ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ Mﻣﻦ اﻟﻔﻀﺎء ﺣﻴﺚ AM ⋅ u = 0 * ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ Mﻣﻦ اﻟﻔﻀﺎء ﺣﻴﺚ AM ⋅ u = 0اﻟﻤﺴﺘﻮى اﻟﻤﺎر ﻣﻦ Aو اﻟﻤﺘﺠﻬﺔ uﻣﻨﻈﻤﻴﺔ ﻟﻪ .bﻣﻌﺎدﻟﺔ ﻣﺴﺘﻮى ﻣﺤﺪد ﺑﻨﻘﻄﺔ و ﻣﺘﺠﻬﺔ ﻣﻨﻈﻤﻴﺔ ﻋﻠﻴﻪ ﺧﺎﺻﻴﺔ * آﻞ ﻣﺴﺘﻮى ) (Pﻓﻲ اﻟﻔﻀﺎء و ) u(a;b;cﻣﻨﻈﻤﻴﺔ ﻋﻠﻴﻪ ﻳﻘﺒﻞ ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻣﻦ ﻧﻮع ax + by + cz + d = 0 * آﻞ ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻣﻦ ﻧﻮع ax + by + cz + d = 0ﺣﻴﺚ ) ( a; b ; c ) ≠ ( 0;0;0هﻲ ﻣﻌﺎدﻟﺔ ﻣﺴﺘﻮى ) (Pﻓﻲ اﻟﻔﻀﺎء ﺗﻤﺮﻳﻦ
ﺑﺤﻴﺚ ) u(a;b;cﻣﻨﻈﻤﻴﺔ ﻋﻠﻴﻪ
ﻧﻌﺘﺒﺮ -1 -2 -3 -4
x+y-2z+1=0 (P) : 2x-y+3z+1=0 (D): x-y+z-2=0 ﺣﺪد ﻣﺘﺠﻬﺔ uﻣﻨﻈﻤﻴﺔ ﻋﻠﻰ ) (Pوﻧﻘﻄﺔ ﻣﻨﻪ. ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى اﻟﻤﺎر ﻣﻦ) A (2;0;3و ) n(1,2,1ﻣﻨﻈﻤﻴﺔ ﻋﻠﻴﻪ. ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى اﻟﻤﺎر ﻣﻦ) A' (2;0;3واﻟﻌﻤﻮدي ﻋﻠﻰ )(D ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى اﻟﻤﺎر ﻣﻦ) A (2;0;3و اﻟﻤﻮازي ﻟـ )(P
3
-3ﻣﺴﺎﻓﺔ ﻧﻘﻄﺔ ﻋﻦ ﻣﺴﺘﻮى -1ﺗﻌﺮﻳﻒ و ﺧﺎﺻﻴﺔ اﻟﻔﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ.م.م ) (o;i ; j ;k ﻣﺴﺎﻓﺔ ﻧﻘﻄﺔ Aﻋﻦ ﻣﺴﺘﻮى ) (Pهﻲ اﻟﻤﺴﺎﻓﺔ AH ﺣﻴﺚ Hاﻟﻤﺴﻘﻂ اﻟﻌﻤﻮدي ﻟـ Aﻋﻠﻰ) (Pﻧﻜﺘﺐ AB ⋅ u = d ( A; ( P ) ) = AH u ﺣﻴﺚ ) B ∈ (Pو uﻣﻨﻈﻤﻴﺔ ﻋﻠﻰ)(P -2ﺧﺎﺻﻴﺔ ﻟﻴﻜﻦ ) (Pﻣﺴﺘﻮى ﻣﻌﺎدﻟﺘﻪ ax + by + cz + d = 0
ax 0 + by 0 + cz 0 + d a2 + b 2 + c 2 ﻣﺜﺎل ﻟﻴﻜﻦ ) (Pﻣﺴﺘﻮى ﻣﺎر ﻣﻦ ) B ( 2;1;3و u 1; −1; 2 ﺣﺪد
)) d ( A ; ( P
(
)
و ) A ( x 0 ; y 0 ; z 0ﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻀﺎء
= )) d ( A ; ( P ﻣﻨﻈﻤﻴﺔ ﻋﻠﻴﻪ ﻟﺘﻜﻦ )A (1;2;0
ﺗﻤﺮﻳﻦ1 ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ . ﻧﻌﺘﺒﺮ ) A(1;-1;1و ) B(3;1;-1و ) (Pاﻟﻤﺴﺘﻮى ذا اﻟﻤﻌﺎدﻟﺔ 2x-3y+2z=0و ) (Dاﻟﻤﺴﺘﻘﻴﻢ اﻟﻤﻤﺜﻞ x = 3t ﺑﺎرا ﻣﺘﺮﻳﺎ ﺑـ ∈ x = − 2 − 3t t z = 2 + 4t -1ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى ) (Qاﻟﻤﺎر ﻣﻦ Aواﻟﻌﻤﻮدي ﻋﻠﻰ اﻟﻤﺴﺘﻘﻴﻢ )(D ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى )´ (Qاﻟﻤﺎر ﻣﻦ Aو Bواﻟﻌﻤﻮدي ﻋﻠﻰ اﻟﻤﺴﺘﻮى )(P -2أﺣﺴﺐ )) d(A;(Pو ))d(A;(D -3ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى )´´ (Qاﻟﻤﺎر ﻣﻦ Bو اﻟﻤﻮازي ﻟﻠﻤﺴﺘﻮى )(P ﺗﻤﺮﻳﻦ2 ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ. ﻧﻌﺘﺒﺮ اﻟﻤﺴﺘﻮى) (Pذا اﻟﻤﻌﺎدﻟﺔ 3x+2y-z-5=0و ) (Dاﻟﻤﺴﺘﻘﻴﻢ اﻟﻤﻌﺮف ﺑـ x − 2 y + z − 3 = 0 x− y−z+2=0 -1ﺣﺪد ﺗﻤﺜﻴﻼ ﺑﺎرا ﻣﺘﺮﻳﺎ ﻟﻠﻤﺴﺘﻘﻴﻢ )(D ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى )´ (Pاﻟﺬي ﻳﺘﻀﻤﻦ ) (Dو اﻟﻌﻤﻮدي ﻋﻠﻰ )(P -IVﻣﻌﺎدﻟﺔ ﻓﻠﻜﺔ
اﻟﻔﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ) (O ; i ; j ; k
-1
ﻣﻌﺎدﻟﺔ ﻓﻠﻜﺔ ﻣﻌﺮﻓﺔ ﺑﻤﺮآﺰهﺎ وﺷﻌﺎﻋﻬﺎ *+
∈ rو) S(Ω;rاﻟﻔﻠﻜﺔ
ﻟﺘﻜﻦ ) Ω(a;b;cﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻀﺎء ) (Eو اﻟﺘﻲ ﻣﺮآﺰهﺎ Ωو ﺷﻌﺎﻋﻬﺎ r ﻟﻴﻜﻦ) M(x;y;zﻣﻦ اﻟﻔﻀﺎء )(E )(x-a)2+(y-b)2+(z-c)2=r2 ⇔ ΩM=r ⇔ M ∈ S(Ω;r
4
ﻣﺒﺮهﻨﺔ اﻟﻔﻀﺎء اﻟﻤﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ . o;i ; j ;k ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻔﻠﻜﺔ ) S(Ω;rاﻟﺘﻲ ﻣﺮآﺰهﺎ ) Ω(a;b;cو ﺷﻌﺎﻋﻬﺎ r (x-a)2+(y-b)2+(z-c)2=r2 هﻲ ﻣﻼﺣﻈﺎت و اﺻﻄﻼﺣﺎت * إذا آﺎن Aو Bﻧﻘﻄﺘﻴﻦ ﻣﻦ اﻟﻔﻠﻜﺔ ) S(Ω;rﺣﻴﺚ Ωﻣﻨﺘﺼﻒ ] [A;Bﻓﺎن ] [A;Bﻗﻄﺮا ﻟﻠﻔﻠﻜﺔ * ﺗﻮﺟﺪ ﻓﻠﻜﺔ وﺣﻴﺪة أﺣﺪ أﻗﻄﺎرهﺎ ] [A;Bﻣﺮآﺰهﺎ Ωﻣﻨﺘﺼﻒ ] [A;Bو ﺷﻌﺎﻋﻬﺎ r =½ AB * ﻟﻠﻔﻠﻜﺔ ) S(Ω;rﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻣﻦ ﺷﻜﻞ x²+y²+z² +αx+βy+γz+δ=0ﺣﻴﺚ αو βو γوδ أﻋﺪاد ﺣﻘﻴﻘﻴﺔ. * اﻟﻔﻠﻜﺔ ) S(O; rﺣﻴﺚ Oأﺻﻞ اﻟﻤﻌﻠﻢ ﻣﻌﺎدﻟﺘﻬﺎ x²+y²+z²=r² ﻟﺘﻜﻦ ) S(Ω;rﻓﻠﻜﺔ اﻟﺘﻲ ﻣﺮآﺰهﺎ ) Ω(a;b;cو ﺷﻌﺎﻋﻬﺎ r * اﻟﻜﺮة اﻟﻜﺮة ) B(Ω;rاﻟﺘﻲ ﻣﺮآﺰهﺎ ) Ω(a;b;cو ﺷﻌﺎﻋﻬﺎ rهﻲ ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ )M(x;y;z ﺣﻴﺚ (x-a)2+(y-b)2+(z-c)2≤r2 -2ﻣﻌﺎدﻟﺔ ﻓﻠﻜﺔ ﻣﻌﺮﻓﺔ ﺑﺄﺣﺪ أﻗﻄﺎرهﺎ Sﻓﻠﻜﺔ أﺣﺪ اﻗﻄﺎرهﺎ ][A;B [AMB] ⇔ M ∈ Sزاوﻳﺔ ﻗﺎﺋﻤﺔ أو M=Aأو AM ⋅ BM = 0 ⇔ M=B ﻣﺒﺮهﻨﺔ Aو Bﻧﻘﻄﺘﺎن ﻣﺨﺘﻠﻔﺎن ﻓﻲ اﻟﻔﻀﺎء ﻓﻲ اﻟﻔﻀﺎء ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ Mاﻟﺘﻲ ﺗﺤﻘﻖ AM ⋅ BM = 0هﻲ ﻓﻠﻜﺔ اﻟﺘﻲ أﺣﺪ اﻗﻄﺎرهﺎ ][A;B ﺧﺎﺻﻴﺔ اذا آﺎﻧﺖ ) A(xA;yA;zAو ) B(xB;yB;zBﻧﻘﻄﺘﻴﻦ ﻣﺨﺘﻠﻔﺘﻴﻦ ﻓﺎن ﻣﻌﺎدﻟﺔ اﻟﻔﻠﻜﺔ اﻟﺘﻲ أﺣﺪ اﻗﻄﺎرهﺎ ][A;B (x -xA)(x-xB)+(y-yA)(y-yB)+(z-zA)(z-zB)=0 هﻲ ﺗﻤﺮﻳﻦ
)
ﻓﻲ
(
اﻟﻔﻀﺎء اﻟﻤﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ )
(
، O ; i ; j ; kﻧﻌﺘﺒﺮ ) Ω(1;2;-1و ) A(2;1;2و )B(4;1;2
-1ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻔﻠﻜﺔ Sاﻟﺘﻲ ﻣﺮآﺰهﺎ Ωو اﻟﻤﺎر ﻣﻦ A -2ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻔﻠﻜﺔ ´ Sاﻟﺘﻲ ﻗﻄﺮهﺎ ][A;B -3دراﺳﺔ اﻟﻤﻌﺎدﻟﺔ (1): x²+y²+z²-2ax-2by-2cz+d=0 ﻟﺘﻜﻦ Eﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ ) M(x;y;zاﻟﺘﻲ ﺗﺤﻘﻖ اﻟﻤﻌﺎدﻟﺔ )(1 (x-a)2+(y-b)2+(z-c)2=a²+b²+c²-d ⇔ M ∈E ﻟﺘﻜﻦ )Ω(a;b;c * -إذا آﺎن a²+b²+c²-d <0ﻓﺎنE =Ø * -اذا آﺎن a²+b²+c²-d =0ﻓﺎن } . E={Ωﻓﻠﻜﺔ ﻣﺮآﺰهﺎ Ωو ﺷﻌﺎﻋﻬﺎ ﻣﻨﻌﺪم a²+b²+c²-d = r² * -اذا آﺎن a²+b²+c²-d >0ﻓﺎن ) E=S(Ω;rﺣﻴﺚ ﻣﺒﺮهﻨﺔ aو bو cو dأﻋﺪاد ﺣﻘﻴﻘﻴﺔ ﺗﻜﻮن ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ ) M(x;y;zاﻟﺘﻲ ﺗﺤﻘﻖ اﻟﻤﻌﺎدﻟﺔ x²+y²+z²-2ax-2by-2cz+d=0ﻓﻠﻜﺔ إذا وﻓﻘﻂ إذا آﺎن a²+b²+c²-d ≥0 ﺗﻤﺮﻳﻦ ﻧﻌﺘﺒﺮ Eﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ ) M(x;y;zاﻟﺘﻲ ﺗﺤﻘﻖ اﻟﻤﻌﺎدﻟﺔ x²+y²+z²+4x-2y -6z+5=0 ﺑﻴﻦ إن Eﻓﻠﻜﺔ ﻣﺤﺪدا ﻋﻨﺎﺻﺮهﺎ اﻟﻤﻤﻴﺰة ﺣﻴﺚ ) A(2;0;-1و )B(-1;1;-1 ﺗﻤﺮﻳﻦ ﺣﺪد ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ Mاﻟﺘﻲ ﺗﺤﻘﻖ 2MA²+3MB²=16 – IIﺗﻘﺎﻃﻊ ﻣﺴﺘﻮى و ﻓﻠﻜﺔ ﺗﻘﺎﻃﻊ ﻟﻠﻔﻠﻜﺔ ) S(Ω;rو اﻟﻤﺴﺘﻮى )(P -1 ﻓﻲ اﻟﻔﻀﺎء Eﻧﻌﺘﺒﺮ اﻟﻔﻠﻜﺔ ) S(Ω;rو اﻟﻤﺴﺘﻮى ) (Pو اﻟﻨﻘﻄﺔ Hاﻟﻤﺴﻘﻂ اﻟﻌﻤﻮدي ﻟـ Ωﻋﻠﻰ اﻟﻤﺴﺘﻮى )(P ﻧﻀﻊ d ( Ω; ( P ) ) = HΩ = d r
d
d=r
5
d≺r
ﺧﺎﺻﻴﺔ ﻟﻴﻜﻦ ) (Pﻣﺴﺘﻮى ﻓﻲ اﻟﻔﻀﺎء و Sﻓﻠﻜﺔ ﻣﺮآﺰهﺎ Ωو ﺷﻌﺎﻋﻬﺎ rو Hاﻟﻤﺴﻘﻂ اﻟﻌﻤﻮدي ﻟـ Ωﻋﻠﻰ اﻟﻤﺴﺘﻮى)(P ﻳﻜﻮن ﺗﻘﺎﻃﻊ ) (Pو : S * داﺋﺮة ﻣﺮآﺰهﺎ Hو ﺷﻌﺎﻋﻬﺎ ) ) r 2 − d 2 ( Ω; ( Pاذا آﺎن d(Ω;(P))< r
* ﻧﻘﻄﺔ اذا آﺎن d(Ω;(P))= rﻓﻲ هﺬﻩ اﻟﺤﺎﻟﺔ ﻧﻘﻮل ) (Pﻣﻤﺎس ﻟﻠﻔﻠﻜﺔ Sﻋﻨﺪ اﻟﻨﻘﻄﺔ H * اﻟﻤﺠﻤﻮﻋﺔ اﻟﻔﺎرﻏﺔ اذا آﺎن d(Ω;(P))>r -2ﻣﺴﺘﻮى ﻣﻤﺎس ﻟﻔﻠﻜﺔ ﻓﻲ أﺣﺪ ﻧﻘﻄﻬﺎ ﺗﻌﺮﻳﻒ ﻟﺘﻜﻦ Aﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻠﻜﺔ )S(Ω;r ﻧﻘﻮل إن اﻟﻤﺴﺘﻮى ) (Pﻣﻤﺎس ﻟﻠﻔﻠﻜﺔ Sﻋﻨﺪ اﻟﻨﻘﻄﺔ Aاذا آﺎن ) (Pﻋﻤﻮدي ﻋﻠﻰ ) (ΩAﻓﻲ A ﺧﺎﺻﻴﺔ ﻟﺘﻜﻦ Aﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻠﻜﺔ )S(Ω;r ) ∀M∈(P ΩA ⋅ AM = 0 ⇔ ) (Pﻣﻤﺎس ﻋﻠﻰ ) S(Ω;rﻓﻲ A ﺗﻤﺮﻳﻦ
ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ )
(
، O ; i ; j ; kﻧﻌﺘﺒﺮ S1اﻟﻔﻠﻜﺔ اﻟﺘﻲ ﻣﻌﺎدﻟﺘﻬﺎ
x²+y²+z²-4x+2y-2z-3=0و S2اﻟﻔﻠﻜﺔ اﻟﺘﻲ ﻣﺮآﺰهﺎ Ω2و ﺷﻌﺎﻋﻬﺎ , 2و ) (Pاﻟﻤﺴﺘﻮى اﻟﺬي و )´ (Pاﻟﻤﺴﺘﻮى اﻟﺬي ﻣﻌﺎدﻟﺘﻪ . 2x-y-2z-1=0 ﻣﻌﺎدﻟﺘﻪ x-2y+z+1=0 -1ﺗﺄآﺪ أن ) (Pو S1ﻳﺘﻘﺎﻃﻌﺎن وﻓﻖ داﺋﺮة ﻣﺤﺪدا ﻋﻨﺎﺻﺮهﺎ اﻟﻤﻤﻴﺰة. -2أدرس ﺗﻘﺎﻃﻊ )´ (Pو . S2 -3ﺣﺪد ﻣﻌﺎدﻟﺔ اﻟﻤﺴﺘﻮى اﻟﻤﻤﺎس ﻟﻠﻔﻠﻜﺔ S1ﻋﻨﺪ اﻟﻨﻘﻄﺔ )A(1;1; 3 --3ﺗﻘﺎﻃﻊ ﻣﺴﺘﻘﻴﻢ و ﻓﻠﻜﺔ ﻓﻲ اﻟﻔﻀﺎء Eﻧﻌﺘﺒﺮ اﻟﻔﻠﻜﺔ) S(Ω;rو اﻟﻤﺴﺘﻘﻴﻢ ) ∆ ( و اﻟﻨﻘﻄﺔ Hاﻟﻤﺴﻘﻂ اﻟﻌﻤﻮدي ﻟـ Ωﻋﻠﻰ اﻟﻤﺴﺘﻘﻴﻢ ) ∆ (
ﻧﻀﻊ d ( Ω; ( ∆ ) ) = HΩ = d r
d
ﺗﻘﺎﻃﻊ اﻟﻤﺴﺘﻘﻴﻢ ) ∆ ( اﻟﻔﻠﻜﺔS
r
d≺r
d
اﻟﻤﺴﺘﻘﻴﻢ ) ∆ ( ﻳﺨﺘﺮق اﻟﻔﻠﻜﺔS
اﻟﻤﺴﺘﻘﻴﻢ ) ∆ ( اﻟﻔﻠﻜﺔS ﻳﺘﻘﺎﻃﻌﺎن ﻓﻲ اﻟﻨﻘﻄﺔH
هﻮ اﻟﻤﺠﻤﻮﻋﺔ اﻟﻔﺎرﻏﺔ ﺗﻤﺮﻳﻦ ﻧﻌﺘﺒﺮ S : x²+y²+z²-2y +4z+4=0
∈t
x = 1 + 2t ( D1 ) : y = 1 + t z = −3 + t
∈t
x = 3t ( D 2 ) : y = 2 z = −2 + t
ﺣﺪد ﺗﻘﺎﻃﻊ Sﻣﻊ آﻞ ﻣﻦ ) (D1و ) (D2و )(D3
6
ﻓﻲ ﻧﻘﻄﺘﻴﻦ ﻣﺨﺘﻠﻔﺘﻴﻦ
∈t
−1 x = 2 + 2t 1 ( D 3 ) : y = + 3 t 3 z = −2
ﺗﻤﺎرﻳﻦ ﺗﻤﺮﻳﻦ1
ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ) (O ; i ; j ; k
ﻧﻌﺘﺒﺮ ) A(1;0;1و ) B(0;0;1و ) C(0;-1;1و اﻟﻤﺴﺘﻘﻴﻢ ) (Dاﻟﻤﺎر ﻣﻦ Cواﻟﻤﻮﺟﻪ ﺑـ )u(−1;2;1 -1ﺑﻴﻦ أن ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ Mﺣﻴﺚ MA=MB=MCﻣﺴﺘﻘﻴﻢ وﺣﺪد ﺗﻤﺜﻴﻼ ﺑﺎرا ﻣﺘﺮﻳﺎ ﻟﻪ -2ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى ) (Pاﻟﻌﻤﻮدي ﻋﻠﻰ ) (Dﻓﻲ C -3اﺳﺘﻨﺘﺞ ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻔﻠﻜﺔ Sاﻟﻤﺎرة ﻣﻦ Aو Bو اﻟﻤﻤﺎﺳﺔ ﻟـ ) (Dﻓﻲ C ﺗﻤﺮﻳﻦ2
ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ )
(
O ; i ; j ; kﻧﻌﺘﺒﺮ ) A(0;3;-5و ) B(0;7;-3و )C(1;5;-3
-1أﻋﻂ ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى )(ABC -2أﻋﻂ ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى ) (Qاﻟﻤﺎر ﻣﻦ Aﺣﻴﺚ ) u(−1;2;1ﻣﻨﻈﻤﻴﺔ ﻋﻠﻴﻪ -3ﻟﻴﻜﻦ ) (Pاﻟﻤﺴﺘﻮى اﻟﻤﺤﺪد ﺑﺎﻟﻤﻌﺎدﻟﺔ x+y+z=0 أ -ﺗﺄآﺪ أن )(Pو ) (ABCﻳﺘﻘﺎﻃﻌﺎن وﻓﻖ ﻣﺴﻨﻘﻴﻢ )(D ب -ﺣﺪد ﺗﻤﺜﻴﻼ ﺑﺎرا ﻣﺘﺮﻳﺎ ﻟـ )(D
ﻧﻌﺘﺒﺮ ﻓﻲ اﻟﻔﻀﺎء اﻟﺪاﺋﺮة ) (Cاﻟﺘﻲ اﻟﻤﺤﺪدة ﺑـ x 2 + z 2 +10z +9=0 y =0
-4
أ -ﺣﺪد ﻣﻌﺎدﻟﺔ ﻟﻠﻔﻜﺔ Sاﻟﺘﻲ ﺗﺘﻀﻤﻦ اﻟﺪاﺋﺮة ) (Cو ﻳﻨﺘﻤﻲ ﻣﺮآﺰهﺎ إﻟﻰ )(ABC ب ﺣﺪد ﺗﻘﺎﻃﻊ Sو )(AC ﺗﻤﺮﻳﻦ3 ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻣﺒﺎﺷﺮ ﻧﻌﺘﺒﺮ ) A(1;-1;1و ) B(3;1;-1و ) (Pاﻟﻤﺴﺘﻮى ذا اﻟﻤﻌﺎدﻟﺔ (D) 2x-3y+2z=0اﻟﻤﺴﺘﻘﻴﻢ اﻟﻤﻤﺜﻞ ﺑﺎرا ﻣﺘﺮﻳﺎ ﺑـ
x = 3t ∈ x = −2 − 3t t z = 2 + 4t
-1ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى ) (Qاﻟﻤﺎر ﻣﻦ Aو Bواﻟﻌﻤﻮدي ﻋﻠﻰ اﻟﻤﺴﺘﻘﻴﻢ )(D -2ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى )´ (Qاﻟﻤﺎر ﻣﻦ Aو Bواﻟﻌﻤﻮدي ﻋﻠﻰ اﻟﻤﺴﺘﻮى )(P -3أﺣﺴﺐ )) d(A;(Pو ))d(A;(D -4ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى )´´ (Qاﻟﻤﺎر ﻣﻦ Bو اﻟﻤﻮازي ﻟﻠﻤﺴﺘﻮى )(P ﺗﻤﺮﻳﻦ4 ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻧﻌﺘﺒﺮ اﻟﻤﺴﺘﻮى ) (Pذا اﻟﻤﻌﺎدﻟﺔ 3x+2y-z-5=0 و ) (Dاﻟﻤﺴﺘﻘﻴﻢ اﻟﻤﻌﺮف ﺑـ
x − 2 y + z − 3 = 0 x− y−z+2=0
-1ﺣﺪد ﺗﻤﺜﻴﻼ ﺑﺎرا ﻣﺘﺮﻳﺎ ﻟﻠﻤﺴﺘﻘﻴﻢ )(D -2ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى )´ (Pاﻟﺬي ﻳﺘﻀﻤﻦ ) (Dو اﻟﻌﻤﻮدي ﻋﻠﻰ ).(P ﺗﻤﺮﻳﻦ5 ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻧﻌﺘﺒﺮ اﻟﻤﺴﺘﻮى ) (Pذا اﻟﻤﻌﺎدﻟﺔ x+y+z+1=0 و اﻟﻤﺴﺘﻮى ) (Qذا اﻟﻤﻌﺎدﻟﺔ 2x-2y-5=0 و ) (Sﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ ) M(x;y;zاﻟﺘﻲ ﺗﺤﻘﻖx²+y²+z²-2x+4y+6z+11=0 -1ﺑﻴﻦ أن ) (Sﻓﻠﻜﺔ ﻣﺤﺪدا ﻣﺮآﺰهﺎ و ﺷﻌﺎﻋﻬﺎ -2ﺗﺄآﺪ أن ) (Pﻣﻤﺎس ﻟﻠﻔﻠﻜﺔ و ﺣﺪد ﺗﻘﺎﻃﻌﻬﻤﺎ -3ﺣﺪد ﺗﻤﺜﻴﻼ ﺑﺎراﻣﺘﺮﻳﺎ ﻟﻠﻤﺴﺘﻘﻴﻢ ) (Dاﻟﻤﺎر ﻣﻦ ) A(0;1;2و اﻟﻌﻤﻮدي ﻋﻠﻰ )(P -4ﺗﺤﻘﻖ أن ) ( P ) ⊥ ( Qو أﻋﻂ ﺗﻤﺜﻴﻼ ﺑﺎراﻣﺘﺮﻳﺎ ﻟﻠﻤﺴﺘﻘﻴﻢ )´(Dﺗﻘﺎﻃﻊ ) (Pو)(Q ﺗﻤﺮﻳﻦ6 ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻧﻌﺘﺒﺮ اﻟﻨﻘﻄﺔ )A(-2;3;4 اﻟﻤﺴﺘﻮى ) (Pذا اﻟﻤﻌﺎدﻟﺔ (S) x+2y-2z+15=0ﻣﺠﻤﻮﻋﺔ اﻟﻨﻘﻂ ) M(x;y;zاﻟﺘﻴﺘﺤﻘﻖ x²+y²+z²-2x+6y+10z-26=0و ) (Cاﻟﺪاﺋﺮة اﻟﺘﻲ ﻣﻌﺎدﻟﺘﻬﺎ -1 -2 -3
-4
ﺑﻴﻦ أن ) (Sﻓﻠﻜﺔ ﻣﺤﺪدا ﻋﻨﺎﺻﺮهﺎ اﻟﻤﻤﻴﺰة ﺑﻴﻦ أن ) (Pو ) (Sﻳﺘﻘﺎﻃﻌﺎن وﻓﻖ داﺋﺮة آﺒﺮى )' (Cو ﺣﺪدهﺎ ﺣﺪد ﻣﻌﺎدﻟﺘﻲ اﻟﻤﺴﺘﻮﻳﻦ اﻟﻤﻤﺎﺳﻴﻦ ﻟﻠﻔﻠﻜﺔ ) (Sو اﻟﻤﻮازﻳﻴﻦ ﻟـ )(P أآﺘﺐ ﻣﻌﺎدﻟﺔ اﻟﻔﻠﻜﺔ )' (Sاﻟﻤﺎر ﻣﻦ Aاﻟﻤﺘﻀﻤﻦ ﻟﻠﺪاﺋﺮة )(C
7
x2 + y 2 − 2 x − 8 = 0 z =0
اﻟﺠﺪاء اﻟﻤﺘﺠﻬﻲ І־ ﺗﻮﺟﻴﻪ اﻟﻔﻀﺎء -1ﻣﻌﻠﻢ ﻣﻮﺟﻪ ﻓﻲ اﻟﻔﻀﺎء ﻧﻨﺴﺐ اﻟﻔﻀﺎء Eإﻟﻰ ﻣﻌﻠﻢ
) (O ; i ; j ; k
ﻟﺘﻜﻦ Iو Јو Kﺛﻼث ﻧﻘﻂ ﺣﻴﺚ OI = i »
رﺟﻞ أﻣﺒﻴﺮ « ﻟﻠﻤﻌﻠﻢ )
(
OK = k
OJ = j
O ; i ; j ; kهﻮ رﺟﻞ ﺧﻴﺎﻟﻲ رأﺳﻪ ﻓﻲ اﻟﻨﻘﻄﺔ Kﻗﺪﻣﺎﻩ ﻋﻠﻰ اﻟﻨﻘﻄﺔ Oو ﻳﻨﻈﺮ
إﻟﻰ I ,اﻟﻨﻘﻄﺔ Jإﻣﺎ ﺗﻮﺟﺪ ﻋﻠﻰ ﻳﻤﻴﻦ» رﺟﻞ أﻣﺒﻴﺮ « أو ﻋﻠﻰ ﻳﺴﺎرﻩ .
ﻣﻌﻠﻢ ﻣﺒﺎﺷﺮ
) (O ; i ; j ; k
ﺗﻌﺮﻳﻒ : اﻟﻔﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ
أﻣﺜﻠﺔ
ﻣﻌﻠﻢ ﻏﻴﺮ ﻣﺒﺎﺷﺮ
) (O ; i ; j ; k
) (O ; i ; j ; k ﻧﻘﻮل إن (O ; i ; j ; k ) * :ﻣﻌﻠﻢ ﻣﺒﺎﺷﺮ إذا وﺟﺪت Jﻋﻠﻰ ﻳﺴﺎر » رﺟﻞ أﻣﺒﻴﺮ « * ) (O ; i ; j ; kﻣﻌﻠﻢ ﻏﻴﺮ ﻣﺒﺎﺷﺮ إذا وﺟﺪت Jﻋﻠﻰ ﻳﻤﻴﻦ » رﺟﻞ أﻣﺒﻴﺮ « ﻧﻌﺘﺒﺮ ) (O ; i ; j ; kﻣﻌﻠﻢ ﻣﺒﺎﺷﺮ * )
.ﻟﺘﻜﻦ Iو Јو Kﺛﻼث ﻧﻘﻂ ﺣﻴﺚ OI = i
(O ; j ; i ; kﻣﻌﻠﻢ ﻏﻴﺮ ﻣﺒﺎﺷﺮ
)
(O ; j ; k ; iﻣﻌﻠﻢ ﻣﺒﺎﺷﺮ
)
(O ; i ; j ; − kﻣﻌﻠﻢ ﻏﻴﺮ ﻣﺒﺎﺷﺮ
ABCDEFGHﻣﻜﻌﺐ ﻃﻮل ﺣﺮﻓﻪ 1 ** A; AB; AD ; AE ; B; BC ; BA; BF
) ) ( E ; EA ; EF ; EH
)
(
,
(
OJ = j
OK = k
) ( A ; AD ; AB ; AE
ﻣﻌﻠﻤﺎن ﻣﺒﺎﺷﺮان ﻣﻌﻠﻤﺎن ﻏﻴﺮ ﻣﺒﺎﺷﺮﻳﻦ
-2اﻷﺳﺮة اﻟﻤﺒﺎﺷﺮة ﻳﻤﻜﻨﻨﺎ ﺗﻮﺟﻴﻪ اﻟﻔﻀﺎء , V3اذا وﺟﻬﻨﺎ ﺟﻤﻴﻊ أﺳﺎﺳﺎﺗﻪ ﺗﻌﺮﻳﻒ ﻧﻘﻮل إن اﻷﺳﺎس اﻟﻤﺘﻌﺎﻣﺪ اﻟﻤﻤﻨﻈﻢ ) ( i ; j ; kﻣﺒﺎﺷﺮ ادا آﺎن
) ( o; i ; j ; kم.م.م .ﻣﺒﺎﺷﺮ ﻣﻬﻤﺎ آﺎﻧﺖ اﻟﻨﻘﻄﺔ O
ﻣﻦ اﻟﻔﻀﺎء -3ﺗﻮﺟﻴﻪ اﻟﻤﺴﺘﻮى ﻟﻴﻜﻦ ) (Pﻣﺴﺘﻮى ﻓﻲ اﻟﻔﻀﺎء و kﻣﺘﺠﻬﺔ واﺣﺪﻳﺔ و ﻣﻨﻈﻤﻴﺔ ﻋﻠﻰ ) , (Pو Oﻧﻘﻄﺔ ﻣﻦ اﻟﻤﺴﺘﻮى )(P O ; i ; jم.م.م ﻟﻠﻤﺴﺘﻮى )(P
)
ﻟﺪﻳﻨﺎ
(
)
(
O ; i ; j ; kﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻟﻠﻔﻀﺎء E 8
ﻳﻜﻮن اﻟﻤﻌﻠﻢ اﻟﻤﺘﻌﺎﻣﺪ اﻟﻤﻤﻨﻈﻢ ) اﻟﻤﻤﻨﻈﻢ ) (O ; i ; j ; kﻣﺒﺎﺷﺮا
(
O ; i ; jﻓﻲ اﻟﻤﺴﺘﻮى ) (Pﻣﻌﻠﻤﺎ ﻣﺒﺎﺷﺮا اذا آﺎن اﻟﻤﻌﻠﻢ اﻟﻤﺘﻌﺎﻣﺪ
* ﻳﺘﻢ ﺗﻮﺟﻴﻪ ﻣﺴﺘﻮ ى ) (Pﺑﺘﻮﺟﻴﻪ ﻣﺘﺠﻬﺔ ﻣﻨﻈﻤﻴﺔ ﻋﻠﻴﻪ. آﻞ اﻟﻤﺴﺘﻮﻳﺎت اﻟﻤﻮازﻳﺔ ﻟـ) (Pﻟﻪ ﻧﻔﺲ ﺗﻮﺟﻴﻪ اﻟﻤﺴﺘﻮى )(P * – IIاﻟﺠﺪاء اﻟﻤﺘﺠﻬﻲ -1ﺗﻌﺮﻳﻒ u = OA ﻟﺘﻜﻦ uو vﻣﺘﺠﻬﺘﻴﻦ ﻣﻦ اﻟﻔﻀﺎء V3و Aو Bﻧﻘﻄﺘﻴﻦ ﻣﻦ اﻟﻔﻀﺎء Eﺑﺤﻴﺚ v = OB اﻟﺠﺪاء اﻟﻤﺘﺠﻬﻲ ﻟﻠﻤﺘﺠﻬﺘﻴﻦ uو vﻓﻲ هﺪا اﻟﺘﺮﺗﻴﺐ ,هﻮ اﻟﻤﺘﺠﻬﺔ اﻟﺘﻲ ﻟﻬﺎ ﺑـ u ∧ vاﻟﻤﻌﺮﻓﺔ آﻤﺎ ﻳﻠﻲ : ﻓﺎن . u ∧ v = o * إذا آﺎﻧﺘﺎ uو vﻣﺴﺘﻘﻴﻤﻴﺘﻴﻦ u ∧ vهﻲ اﻟﻤﺘﺠﻬﺔ اﻟﺘﻲ ﺗﺤﻘﻖ : * إذا آﺎﻧﺘﺎ uو vﻏﻴﺮ ﻣﺴﺘﻘﻴﻤﻴﺘﻴﻦ ﻓﺎن u ∧ vﻋﻤﻮدي ﻋﻠﻰ آﻞ ﻣﻦ uو v ) ( u ; v ; u ∧ vأﺳﺎس ﻣﺒﺎﺷﺮ .v sin θ -
أﻣﺜﻠﺔ * ﻧﻌﺘﺒﺮ
)
u ∧v = u
ﺣﻴﺚ θﻗﻴﺎس اﻟﺰاوﻳﺔ
(O ; i ; j ; kﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻣﺒﺎﺷﺮ
AOB
i ∧i = j ∧ j = k ∧k =0 k ∧i = j i ∧k =−j
j ∧k =i k ∧ j = −i
i ∧ j =k j ∧ i = −k
* إذا آﺎن uو vﻣﺘﺠﻬﺘﻴﻦ واﺣﺪﻳﺘﻴﻦ و ﻣﺘﻌﺎﻣﺪﺗﻴﻦ ﻓﺎن ) ( u ; v ; u ∧ vأﺳﺎس ﻣﺒﺎﺷﺮ .
ﻧﺤﺴﺐ u ∧ vﻋﻠﻤﺎ أن [ θ ∈ ]0;π
ﺗﻤﺮﻳﻦ
(u; v ) = θ
u ⋅ v = −5
v =2
u =5
-2ﺧﺎﺻﻴﺎت أ -ﺧﺎﺻﻴﺔ إذا آﺎﻧﺖ Aو Bو Cﺛﻼث ﻧﻘﻂ ﻏﻴﺮ ﻣﺴﺘﻘﻴﻤﻴﺔ ﻣﻦ اﻟﻔﻀﺎء ﻓﺎن اﻟﻤﺘﺠﻬﺔ AB ∧ ACﻣﻨﻈﻤﻴﺔ ﻋﻠﻰ اﻟﻤﺴﺘﻮى ).(ABC ﻟﺘﻜﻦ Aو Bو Cﺛﻼث ﻧﻘﻂ ﻏﻴﺮ ﻣﺴﺘﻘﻴﻤﻴﺔ ﻣﻦ اﻟﻔﻀﺎء θﻗﻴﺎس اﻟﺰاوﻳﺔ ﻋﻠﻰ )(AB
HC = AC sin θ
AB ∧ AC = AB. AC.sin θ AB ∧ AC = AB × HC
ﺧﺎﺻﻴﺔ
ﻣﺴﺎﺣﺔ اﻟﻤﺜﻠﺚ ABCهﻮ ﻧﺼﻒ AB ∧ AC ﻧﺘﻴﺠﺔ ﻣﺴﺎﺣﺔ ﻣﺘﻮازي اﻷﺿﻼع ABDCهﻲ AB ∧ AC د -ﺧﺎﺻﻴﺔ ﻟﺘﻜﻦ uو vﻣﺘﺠﻬﺘﻴﻦ ﻣﻦ اﻟﻔﻀﺎء ﻳﻜﻮن u ∧ vﻣﻨﻌﺪﻣﺎ أداو ﻓﻘﻂ آﺎن uو vﻣﺴﺘﻘﻴﻤﻴﺘﻴﻦ اﻟﺒﺮهﺎن * ⇒ )ﺑﺪﻳﻬﻲ – اﻟﺘﻌﺮﻳﻒ(- *⇐
9
H , CAB اﻟﻤﺴﻘﻂ اﻟﻌﻤﻮدي ﻟـ C
u ∧v =0⇔ u ∧v ⇒ u v sin θ = 0 sin θ = 0 sont liés
∨
uetv
v =0 ∨
∨
v =0
⇔ u =0 ∨
⇔u = 0
Aو Bو Cﻣﺴﺘﻘﻴﻤﻴﺔ ⇔ AB ∧ AC = 0 ﻣﻼﺣﻈﺔ ج -اﻟﺠﺪاء اﻟﻤﺘﺠﻬﻲ واﻟﻌﻤﻠﻴﺎت)ﻧﻘﺒﻞ(
(u + v ) ∧ w = u ∧ w + v ∧ w ) (α u ) ∧ v = α ( u ∧ v ) u ∧ v = − (v ∧ u
∈ ∀α
∀ ( u ; v ; w ) ∈ V33
u ∧u = 0∧u = u ∧0 = 0 ﺗﻤﺮﻳﻦ
) ( o; i ; j ; kﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻣﺒﺎﺷﺮ .
أﺣﺴﺐ
( i + 2k ) ∧ j
i ∧3j
ﺗﻤﺮﻳﻦ ﻟﺘﻜﻦ ; a ∧ b = c ∧ d
( i + j − 2k ) ∧ k
) ( 2i − j ) ∧ ( 3i + 4 j
a∧c =b ∧d
ﺑﻴﻦ إن a − dو b − cﻣﺴﻨﻘﻴﻤﻴﺘﺎن -3اﻟﺼﻴﻐﺔ اﻟﺘﺤﻠﻴﻠﻴﺔ ﻟﻠﺠﺪاء اﻟﻤﺘﺠﻬﻲ ﻓﻲ م.م.م ﻣﺒﺎﺷﺮ. ) ( o; i ; j ; kﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻣﺒﺎﺷﺮ
)
) u ( x; y; z
)' v ( x '; y '; z
(
( )
u ∧ v = xi + yj + zk ∧ x ' i + y ' j + z ' k
= ( yz '− zy ') i + ( zx '− xz ') j + ( xy '− yx ') k
ﺧﺎﺻﻴﺔ اﻟﻔﻀﺎء Eﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻣﺒﺎﺷﺮ ) (O ; i ; j ; kو ) u ( x; y; zو )' v ( x(; y '; zﻣﺘﺠﻬﺘﺎن ﻣﻦV3
إﺣﺪاﺛﻴﺎت اﻟﺠﺪاء اﻟﻤﺘﺠﻬﻲ u ∧ vﺑﺎﻟﻨﺴﺒﺔ ﻟﻸﺳﺎس ) ( i ; j ; kهﻮ ) (X;Y;Zﺣﻴﺚ
' Z = xy '− yx
' X = yz '− zy
' Y = zx '− xz
ﻣﻼﺣﻈﺔ ﻳﻤﻜﻦ اﺳﺘﻌﻤﺎل اﻟﻮﺿﻌﻴﺔ اﻟﺘﺎﻟﻴﺔ
ﻣﺜﺎل
ﻧﻌﺘﺒﺮ )v ( −2; −1;1
ﺣﺪد u ∧ v – IIIﺗﻄﺒﻴﻘﺎت اﻟﺠﺪاء اﻟﻤﺘﺠﻬﻲ
) u (1; 2;0
)A (1; 2;1
) B ( 0; −3; 2
أﺣﺴﺐ ﻣﺴﺎﺣﺔ اﻟﻤﺜﻠﺚ )(ABC
10
)C (1; 2;1
-1ﻣﻌﺎدﻟﺔ ﻣﺴﺘﻮى ﻣﻌﺮف ﺑﺜﻼث ﻧﻘﻂ ﻏﻴﺮ ﻣﺴﺘﻘﻴﻤﻴﺔ ﺧﺎﺻﻴﺔ ﻟﺘﻜﻦ Aو Bو Cﺛﻼث ﻧﻘﻂ ﻏﻴﺮ ﻣﺴﺘﻘﻴﻤﻴﺔ ﻣﻦ ﻓﻀﺎء ﻣﻨﺴﻮب اﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻣﺒﺎﺷﺮ M ∈ ( ABC ) ⇔ AB ∧ AC ⋅ AM
)
(
ﺣﺪد ﻣﻌﺎدﻟﺔ اﻟﻤﺴﺘﻮى )(ABC
ﻣﺜﺎل ﻧﻌﺘﺒﺮ ) A(1;2;3و ) B(1;-1;1و )C(2;1;2 -2ﺗﻘﺎﻃﻊ ﻣﺴﺘﻮﻳﻴﻦ ﻧﻌﺘﺒﺮ ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب اﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻣﺒﺎﺷﺮ (P) : ax+by+cz+d=0 (P´) : a´x+b´y+c´z+d´=0 ﻟﺪﻳﻨﺎ ) n ( a; b; cﻣﻨﻈﻤﻤﻴﺔ ﻟـ ) (Pو )' n ' ( a '; b '; cﻣﻨﻈﻤﻤﻴﺔ ﻟـ )´(P
* اذا آﺎن ) (Pو)´ (Pﻣﺘﻘﺎﻃﻌﻴﻦ ﻓﺎن اﻟﻤﺴﺘﻘﻴﻢ ) (Dﺗﻘﺎﻃﻊ ) (Pو)´ (Pﻣﻮﺟﻪ ﺑـ ' n ∧ n * اذا آﺎن n ∧ n ' ≠ 0ﻓﺎن ) (Pو)´ (Pﻣﺘﻘﺎﻃﻌﺎن وﻓﻖ ﻣﺴﺘﻘﻴﻢ ﻣﻮﺟﻪ ﺑـ ' n ∧ n ﺗﻤﺮﻳﻦ ﺣﺪد ﺗﻘﺎﻃﻊ (P): x+2y-2z+3=0و (P´): 4x-4y+2z-5=0
-3ﻣﺴﺎﻓﺔ ﻧﻘﻄﺔ ﻋﻦ ﻣﺴﺘﻘﻴﻢ ﻓﻲ اﻟﻔﻀﺎء ) (Dﻣﺴﺘﻘﻴﻢ ﻣﺎر ﻣﻦ Aو ﻣﻮﺟﻪ ﺑـ M , uﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻀﺎء و Hﻣﺴﻘﻄﻬﺎ اﻟﻌﻤﻮدي ﻋﻠﻰ)(D AM ∧ u = AH + HM ∧ u = HM ∧ u AHetu liés
)
= HM . u
π 2
(
AM ∧ u = HM ∧ u = HM . u sin AM ∧ u u
= HM
ﺧﺎﺻﻴﺔ ﻓﻲ اﻟﻔﻀﺎء ) (Dﻣﺴﺘﻘﻴﻢ ﻣﺎر ﻣﻦ Aو ﻣﻮﺟﻪ ﺑـ M , uﻧﻘﻄﺔ ﻣﻦ اﻟﻔﻀﺎء. ﻣﺴﺎﻓﺔ اﻟﻨﻘﻄﺔ Mﻋﻦ اﻟﻤﺴﺘﻘﻴﻢ ) (Dهﻲ
AM ∧ u u
= )) d ( M ; ( D
ﺗﻤﺮﻳﻦ )A(3;2;-1
∈t
x = 2−t ( D ) : y = 2t z = 1+ t
? = ) ) d ( A; ( D
ﺗﻤﺮﻳﻦ ﻓﻲ ﻓﻀﺎء ﻣﻨﺴﻮب إﻟﻰ ﻣﻌﻠﻢ ﻣﺘﻌﺎﻣﺪ ﻣﻤﻨﻈﻢ ﻣﺒﺎﺷﺮ ﻧﻌﺘﺒﺮ )A(1;2;1و ) B(-2;1;3و ) (Dاﻟﻤﺴﺘﻘﻴﻢ اﻟﺬي x − 2y + z − 3 = 0 ﻣﻌﺎدﻟﺘﻪ 2 x + 3 y − z − 1 = 0 -1ﺣﺪد OA ∧ OBﺛﻢ ﺣﺪد ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻤﺴﺘﻮى )(OAB -2ﺣﺪد ))d(A;(D -3أﻋﻂ ﻣﻌﺎدﻟﺔ دﻳﻜﺎرﺗﻴﺔ ﻟﻠﻔﻠﻜﺔ )(Sاﻟﺘﻲ ﻣﺮآﺰهﺎ Aو ﻣﻤﺎﺳﺔ ﻟﻠﻤﺴﺘﻘﻴﻢ )(D
11
×
Report "Math Bac Cours 10"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
×
Sign In
Email
Password
Remember me
Forgot password?
Sign In
Our partners will collect data and use cookies for ad personalization and measurement.
Learn how we and our ad partner Google, collect and use data
.
Agree & close