Contoh-contoh soal metode iterasi jacobiDeskripsi lengkap
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Nama : Dani Indra Kusworo Nim
: 10/307635/DPA/03760
1. Soal 4x 10y 6z 30 −
=
3x 5y 7z 15 6x 8y 6z 8 −
−
=
=−
A. = 4 -10 6
3
5 -7
6 -8 6 b. =
30 15 -8
Langkah pertama tuliska matriknya di scilab console -->A=[4 -10 6;3 5 -7; 6 -8 6] A = 4. - 10. 6. 3.
5. - 7.
6. - 8.
6.
-->b=[30;15;8] b = 30. 15. 8. Kemudian buat Jacobi.sci akar= function akar = jacobi( jacobi(A, b)
epsilon =0.0000000000000001 ; // dalam program ini mengunakan ketelitian 0.000000000000001 counter=0; [baris kolom]=size(A); x0=zeros(baris,1); while%T counter=counter+1; for i=1:baris sigma=0; for j=1:kolom if i~= j sigma=sigma+(A(i,j)*x0( j)); end end x1(i)=1 / A(i,i)*(b(i)-sigma); end if abs (norm(x0-x1))>epsilon x0=x1; else break ; end; end akar=x0; disp(counter); endfunction