ING. WIDMAR AGUILAR
EJEMPLO CON POWER WORLD.-
Se trata de encontrar el cortocircuito en las barras N. 3 y N. 4 a nivel de 138 KV y 13.8 KV del esquema de la Fig. Los datos son los siguientes: G1: X= 10 % ; = 5% ; 69 kv T1, : = = = 7%
∶ = = 80 80Ω; = 60Ω Para correr el cortocircuito es necesario pasar todas las reactancias anteriores en la base 100 MVA y en lado de cada uno de los voltajes indicados, así: G1: Y-ATERRADO SOLIDAMENTE
=
= 47,61 47,61Ω = =
,
= 0,333
, , ,
=
∗ %
= 0,1667
∶ DELTA/ ESTRELLA =
= 47,61 47,61Ω = =
, , , ,
= 0,2333
=
∗ %
= 0,2333
∶ ESTRELLA/ ESTRELLA TIERRA =
= 190,44 190,44Ω = =
, , , ,
= 0,2333
=
∗ %
= 0,2333
1 ∶ =
= 190,44 190,44Ω =
,
= 0,42
=
∗ %
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ING. WIDMAR AGUILAR
=
,
= 0,3151
Los cortocircuitos simulados se aprecian en los esquemas:
CORTOCIRCUITO EN LA BARRA 3.A) MONOFASICO:
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ING. WIDMAR AGUILAR
B) TRIFASICO:
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ING. WIDMAR AGUILAR
CORTOCIRCUITO EN LA BARRA 4 (13,8 kv).A) MONOFASICO:
B) TRIFASICO:
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ING. WIDMAR AGUILAR
