Contoh Soal dan Penyelesaian Soal Azas Teknik Kimia

Diketahui :
Kelebihan uap 200%
Konversi metana reaksi (a) = 100%
Konversi karbon dioksida reaksi (b) = 50%
Metana masuk 100 mol/jam

Gas yang keluar dari reator I :
CO2 = 100 mol
H2 = 400 mol
H2O sisa = 600 – 200 = 400 mol
+
Total = 900 mol

% CO2 = = 11,11%

%H2 = = 44,44%

%H2O = = 44,44%


Reaksi (a)
CH4 + 2H2O CO2 + 4H2
100 mol ~ 200 mol ~ 100 mol ~ 400 mol

Dalam bahan bakar telah ada 100% uap (200 mol)
Kelebihan Uap (H2O) = 200%
H2O yang masuk = 300/100 x 200 mol H2O
= 600 mol H2O

Jawab
Basis : 100 mol metana per satu jam operasi
Reactor I
Konversi metana = 100%
Metana yang bereaksi = konversi/100% x metana mula-mula
= 100%/100% x 100 mol
= 100 mol metana reaksi


200%
Kelebihan uap
Reactor
I
Metana
100 mol/jam
???
Ditanya
Uap yang dibutuhkan
Komposisi gas yang keluar dari reactor I dan reactor II
Terima Kasih
200%
Kelebihan uap
Reactor
I
Reactor
II
Metana
100 mol/jam
Produk
Reactor II
Konversi karbon dioksida = 50%
Karbon dioksida yang bereaksi
=
=
= 50 mol CO2 yang bereaksi




Reactor
II
CO2 11,11%
H2 44,44%
H2O 44,44%

???
%CH3OH = = 6,25%
%H2 = = 56,25%
%CO2 = = 6,25%
%H2O = = 31,25%

Gas yang keluar dari reactor II :
CH3OH = 50 mol
H2 = 400 + 50 = 450 mol
CO2 sisa = 100 - 50 = 50 mol
H2O sisa = 400 - 150 = 250 mol +
Total = 800 mol





1431410059
1-E
Delia Damayanti
Reaksi (b)
CO2 + 3H2O CH3OH + H2
50 mol ~ 150 mol ~ 50 mol ~ 50 mol
Suatu proses sintesa metanol seperti ditunjukkan di bawah ini:
CH4 + 2H2O CO2 + 4H2 (a)
CO2 + 3H2O CH3OH + H2 (b)
200% kelebihan uap, berdasarkan pada reaksi (a) dimasukkan ke reactor I, dan konversi dari metana 100%. Hasil dari reactor I dimasukkan ke reactor II, dengan reaksi (b), konversi dioksida 50%. Dengan masukan metan 100 mol/jam. Hitung uap yang dibutuhkan dan komposisi gas yang keluar dari reactor I dan reactor II.
UAS ATK1 Th.2013/2014 No.6
Jadi, uap yang dibutuhkan untuk proses sintesa metanol
= H2O reaksi (a) + H2O reaksi (b)
= 200 mol + 150 mol
= 350 mol H2O
Komposisi bahan yang keluar dari reactor
Reactor I
% CO2 = 11,11%
%H2 = 44,44%
%H2O = 44,44%
Reactor II
%CH3OH = 6,25%
%H2 = 56,25%
%CO2 = 6,25%
%H2O = 31,25%


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