Ujian Tengah Tengah Semester : Mata Uji Dosen Pe Pembina Hari/Tanggal 'akt Si*at
: Teknik Reaksi Kimia 3 : Ir Ir. Mi Mining Ha Harsanti MS MSc. : Mingg/!" #$ril %&!& : !%& menit (% jam) : +ka +k
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Soal 1 (nilai 50) 'e are consi-ering getting something o* ale *rom aste stream o* a $rocess. This stream (%&&&& liters/-a0) contains chemical # (&.&! kg/liter) hich can be h0-rol01ein a2eos soltion to gie chemical R (ale 4!.&&/kg trans*orme-). Pro-ct R can be recoere- *rom the soltion at negligible cost hile nreacte- # goes to aste. 5rom the in*ormation belo calclate calclate the 1ise o* Mi6e- Reactor an- conersion leel hich ill ma6imi1e a) the $ro*it b) the rate o* retrn on inestment ine stment
Data : 7n an ann annal al basi basiss the the cost cost o* reac reacto torr anan- s$$ s$$or orti ting ng e2i e2i$m $men ent8 t8 incl incl-in ing g -e$reciation an- interest charges is : 4m 4%%9 !/% 8 olme in liters ;abor an- o$erating cost 4%&/o$erating -a08 3&& o$erating -a0/0ear. The h0-rol0sis reaction is *irst or-er ith res$ect to # ith a rate constant k &.%9/hor. Penyelesaian : reaksi *asa cair :
ja-i :
R
& = # = #& (! < 6 # )
+erlangsng -i -alam Mi6e- Reactor : :=STR 5#&
#
6# 6 = #& . & # < r # < r #
Reaksi or-e>sat terha-a$ # -engan k &8%9/jam r k = # k = #& (! < 6 # ) A
:=STR 5#&
&8%9 = #& (! < 6 # ) jam
6# 6 = #& . & # < r # < r #
:=STR =#& . &
6# &8%9 jam
= #& (! < 6 # )
:=STR . &
6# &8%9 (! < 6 # ) jam
:=STR %& &&&
:=STR
6#
!& &&& 3
liter
(! < 6 # )
+ia0a ntk reactor berikt $eraatan -an $eralatan $en-kngn0a serta -e$resiasi $er tahn : SM 4 %%9 :!/%
6# liter ! hari hari %? jam &8%9 (! < 6 # ) jam
@
: -alam liter
+ia0a brh 4%&/hari@ ! tahn 3&& hari kerja = #& &8&! kg/liter
Pro-k R 0ang -ihasilkan : = R = #& 6 #
Untk laj alir olmetric : . & %& &&& liter/hari 1at # -alam aliran m$an &8&!
Untk ! tahn $ro-ksi : R 0ang -ihasilkan %&& 6 #
4!8& kg
kg tahn
4A& &&& 6 # tahn
4%%9 tahn
!/ %
!/%
:
!& &&& 4%%9 3
+ia0a ntk brh $er tahn : +ia0a ntk brh
B A& &&& 6 #
+ia0a ntk reactor $ertahn : +ia0a ntk reaktor
kg 3&& hari kg A& &&& 6 # hari tahn tahn
Harga jal $ro-k R : Sale $ro-k R
kg liter kg %& &&& %&& liter hari hari
4%& 3&& hari 4A&&&/tahn hari tahn
Pro*it ata kentngan $ertahn : Pro*it harga $ro-k < bia0a $ro-ksi
!/%
6 # ! < 6 #
!/%
P 4 A& &&& 6 #
!& &&& < 4 %%9 3
!/%
6 # ! < 6 #
< 4 A&&&
P * (6 # ) -P & -6 #
Pro*it maksimm jika :
!/%
!& &&& < %%9 3
P A& &&& 6 #
-P -6 #
!/%
!& &&& A& &&& < %%9 3 !/%
!& &&& A& &&& < %%9 3 !/%
6 # - ! < 6 #
-
!/%
6 # - ! < 6 #
!/%
6 # - ! < 6 #
!/%
6 # - ! < 6 #
!/%
6 # - ! < 6 #
< A&&&
!/%
6 # - ! < 6 #
< &
!/%
6 # - ! < 6 #
6 !/% # (! < 6 # )! / %
&
!/ % (! < 6 # )! / % -(6 # )! / % < 6 !/% # - (! < 6 # )
(! < 6 # ) % / %
(! < 6 # ) % / % !/% (6 # ) < ! / % (! < 6 # )!/ % (! < 6 # ) % / %
!/%
6 # - ! < 6 #
!/%
6 # ! < 6 #
! % (6 # ) ! / % (! < 6 # )! / %
(! < 6 # ) % / % % (6 # ) ! / % (! < 6 # ) 3 / %
(! < 6 # ) % (6 # )
!/ %
(! < 6 # )
3/ %
<
<
<
<
!/% (6 # ) ! / % (! < 6 # ) < ! / % (! < 6 # ) % / %
(6 # ) ! / % % (! < 6 # ) 3 / %
(6 # ) !/ % (6 # ) ! / % % (6 # ) ! / % (! < 6 # ) 3 / %
6# % (6 # )
!/ %
(! < 6 # ) 3 / %
!/%
6 # - ! < 6 #
(! < 6 # ) < 6 #
% (6 # ) ! / % (! < 6 # ) 3 / %
!/%
6 # - ! < 6 #
!
% (6 # )
!/ %
(! < 6 # ) 3 / %
!/%
!& &&& A& &&& < %%9 3
!/%
6 # - ! < 6 #
!/%
!& &&& A& &&& < %%9 3
! % (6 # ) ! / % (! < 6 # ) 3 / %
!/%
!& &&& A& &&& %%9 3
(6 # )
!/ %
(6 # )
!/ %
(! < 6 # )
3/ %
(! < 6 # )
3/ %
(6 # ) (! < 6 # )
3
&
! % (6 # )
!/ %
(! < 6 # ) 3 / %
%%9 !& &&& % (A& &&&) 3
!/%
(3) (C9) !& &&& % ("&&) (C9) 3
(3) % (!A&&)
%
&
!/%
!& &&& 3
(6 # ) (! < 3 6 # 3 6 %# < 6 3# )
(6 # ) (! < 3 6 # 3 6 %# < 6 3# )
3& &&& (!A) % (!& &&&)
3 (%9A)
%9A (6 # ) (! < 3 6 # 3 6 %# < 6 3# ) 3 %9A 6 ?# < 3 (%9A) 6 3# 3 (%9A) 6 %# < %9A 6 # 3 &
Di-a$at : 6# &8C9
a.
6#
:=STR
!& &&& 3
(! < 6 # )
:=STR
!& &&&
&8C9
3
liter
(! < &8C9)
!& &&&
3 !& &&& liter
3
b. Rate o* Retrn on Inesment (R7I) R7I
$ro*it $er tahn 6 !&&D total in.esment !/%
P 4 A& &&& 6 #
!& &&& < 4 %%9 3
!/%
6 # ! < 6 # !/%
!& &&& P 4 A& &&& (&8C9) < 4 %%9 3
< 4 A&&&
!/%
&8C9 ! < &8C9
P 4 A& &&& (&8C9) < 4 %% 9&& < 4 A &&& 4 !A 9&&
!/%
!& &&& In.estasi 4 %%9 3
4 %% 9&& 4 A &&& 4 %" 9&&
R7I
!/%
&8C9 ! < &8C9
4 !A 9&& 6 !&&D 9"D 4 %" 9&&
4 A&&&
< 4 A&&&
Soal 2 (nilai 50) Reaksi *asa cair : # E + P a-alah reaksi searah -an elementer 8 berlangsng -i-alam reactor alir -engan m$an 1at # -an 1at + $a-a jmlah 0ang e2imolar $a-a tem$eratre %C o= -an laj alir olmetric sebesar % liter/-etik. a) a$abila reaksi berlangsng secara a-iabatik8 hitng olme =STR 0ang -i$erlkan ntk menca$ai konersi sebesar FF. b) hitng tem$eratre m$an mask maksimm8 s$a0a tem$eratre reaksi (0ait titik -i-ih cairan reaksi) ti-ak boleh melebihi 99& K sekali$n ntk konersi sem$rna. Diketahi : Panas $embentkan : H#o ($a-a %C3 K) < %& kcal/mol. H+o ($a-a %C3 K) < !9 kcal/mol. HPo ($a-a %C3 K) < ?! kcal/mol. Konsentrasi aal # =#& &8! mol/liter Ka$asitas $anas (=$) =$# =$+ !9 cal/(mol K) =$P 3& cal/(mol K) Konstanta laj reaksi (k) $a-a tem$eratre 3&& K a-alah &8&! liter/(mol -etik) Gnergi aktiasi G !& &&& cal/mol.
Pen0elesaian : B) Reaksi *asa cair berarti reaksi ti-ak mengalami $erbahan olme *li-a ata $erbahan laj alir olmetric ( &) B) = # = #& (! < 6 # ) B) reaksi elementer : < r # k = # = + B) -ignakan m$an $a-a jmlah e2imolar8 berarti : n #& n +& 0 #& 0 +& !/% B) -ari $ersamaan stokiometri reaksi : = # =+ % % % B) ja-i $ersamaan laj reaksi menja-i : < r # k = # k = #& (! < 6 # )
B) reaksi berlangsng -i -alam =STR :
:=STR 5#&
6# 6 =#& .& # < r # < r #
6#
:=STR =#& .&
k =%#& (! < 6 # )%
&8FF k (&8!) (! < &8FF) %
:=STR %
!8F" k (&8!) (&8&!)%
:=STR
(!8F") (!&) (!&&&&) (!8F") (!&)9 :=STR k k
Konstanta laj reaksi (k) $a-a tem$eratre 3&& K a-alah &8&! liter/(mol -etik) Gnergi aktiasi G !& &&& cal/mol. k #e
<
G RT
B) Mencari/menghitng nilai k $a-a tem$eratre T B) menghitng tem$eratre T $a-a konersi sebesar 6# &8FF
T
in
6 < H (TR ) o R
i
= $ i T& 6 = $ TR
i !
in
= $ i
i
6 = $
i !
H oR (TR ) H o*8 P (TR ) < H o*8 # (TR ) < H o*8 + (TR )
H oR (TR ) < ?! %& !9 < A kkal/mol < A&&& kal/mol in
= $ i
i
( # = $ #
+
= $ + P = $ P )
i !
in
i
= $ i (! B!9 ! B !9 & B 3&) 3&
i !
= $ =$ P < =$ # < =$ + 3& < !9 < !9 &
&8FF (< (
T
<
e
k ?F" K
<
e <
!&&&&
<
(!8F")(?F" )
k 3&& K
!&&&& (!8F"C)(3& &)
G RT
<
e <
e
G R(?F")
<
!&&&& (!8F")(?F" ) !&&&&
(&8&!)
(!8F"C)(3& &)
G !8F"C(?F")
k ?F" K #e e e G G G < < < k 3&& K # e RT e R(3&&) e !8F"C(3&&) a. Menghitng olme reactor ntk menca$ai konersi sebesar FF
(!8F") (!&) (!&&&&) (!8F") (!&)9 :=STR k k
b. Menentkan tem$eratre m$an s$a0a tem$eratre reaksi -i -alam reactor ti-ak lebih -ari 99& K
99&
in
6 < H (TR ) o R
i
= $i T& 6 = $ TR
i !
in
= $ i
i
6 = $
i !
99& 99&
!8& (< (
!A9&& A&&& 3& T& !&9&& 3& T& T& 39& K