02 - Cálculos de cementación en una etapa.pdf

Single Stage Calculations

Engineer’s Handbook 1 foot

2

Single St Stage Cementing

1. OD 2. LBS/FT 3. CUFT/FT 4. Displacement BBL/FT


1 foot

3

Single St Stage Cementing


1. OD outside casing 2. LBS/FT outside casing 3. OD inside casing 4. CUFT/FT


1 foot

1 foot

4

Single Stage Cementing


1. OD outside casing 2. LBS/FT outside casing 3. OD inside casing 4. CUFT/FT

1. OD casing 2. OH diameter 3. CUFT/FT

Volumes to be Calculated : Step A 1. Casing in casing

1

Previous Casing

Open Hole

3

Collar Shoe

5



1

2. Casing in open hole

2

3

Previous Casing

Open Hole

Collar Shoe

6



1

2. Casing in open hole

Previous Casing

3. Inside casing (between collar and shoe) 2

3 3

Open Hole

Collar Shoe

7


Cement Calculations z

Volume of open hole below the casing shoe is not calculated.

z

Cement circulates out of the shoe and up the annulus.

z

Any cement displacing the mud below by gravity is considered negligible.

8


Problem 1 Casing

:

7” - 32 LB/Ft

Shoe

:

4600’

Collar

:

4510’

Previous casing

:

9 5/8 - 47 LB/Ft

Shoe

:

2670’

Open hole

:

8.5”

Top of cement

:

1000’

Calculate Total Amount of Slurry Required in CuFt 9


Solution Capacities 1. Cas-Cas

- 0.1438 cuft/ft

2. Cas - OH

- 0.1268 cuft/ft

1000ft 1

3. Cas

- 0.2025 cuft/ft, 0.0361 bbl/ft

Volumes 2670ft 2

3 3

4510ft 4600ft

10 Single Stage Cementing


- 0.1438 cuft/ft

2. Cas - OH

- 0.1268 cuft/ft

1000ft 1

3. Cas

- 0.2025 cuft/ft, 0.0361 bbl/ft

Volumes 2670ft

1. (2670ft - 1000ft) x 0.1438 cuft/ft = 240.2 cuft 2

3 3

4510ft 4600ft



- 0.1438 cuft/ft

2. Cas - OH

- 0.1268 cuft/ft

1000ft 1

3. Cas

- 0.2025 cuft/ft, 0.0361 bbl/ft

Volumes 2670ft


2. (4600ft - 2670ft) x 0.1268 cuft/ft = 244.7 cuft 3 3

4510ft 4600ft



- 0.1438 cuft/ft

2. Cas - OH

- 0.1268 cuft/ft

1000ft 1

3. Cas

- 0.2025 cuft/ft, 0.0361 bbl/ft

Volumes 2670ft


2. (4600ft - 2670ft) x 0.1268 cuft/ft = 244.7 cuft 3. (4600ft - 4510ft) x 0.2025 cuft/ft = 18.2 cuft


3 3

4510ft 4600ft


- 0.1438 cuft/ft

2. Cas - OH

- 0.1268 cuft/ft

1000ft 1

3. Cas

- 0.2025 cuft/ft, 0.0361 bbl/ft

Volumes 2670ft


2. (4600ft - 2670ft) x 0.1268 cuft/ft = 244.7 cuft 3. (4600ft - 4510ft) x 0.2025 cuft/ft = 18.2 cuft TOTAL VOLUME = 503.1 CUFT 14 Single Stage Cementing

3 3

4510ft 4600ft

Excess

Excess in only calculated on Annular Volume in THE OPEN HOLE

Only Here


Example: Problem 1 z

OH 50% Excess

z

OH volume (2) of the previous problem: cuft

z

Excess Volume:

Total OH Volume: z

OR


244.7

244.7 cuft x 50/100 = 122.35 cuft 367.05 cuft

244.7 cuft x 1.50 = 367.05 cuft

Slurry Yield - Step B The volume of slurry produced when one sack of cement is mixed with water is called

YIELD


Slurry Yield - Step B The volume of slurry produced when one sack of cement is mixed with water is called YIELD

CEMENT


+


CEMENT


+

WATER

=


CEMENT

+

WATER

=

The unit of slurry yield is cuft /sack


SLURRY

Note: 1 sack of cement of 94 lbs

= 1 cuft

4.97 gals of water

= 0.66 cuft



= 1 cuft

4.97 gals of water

= 0.66 cuft

1 cuft + 0.66 cuft

= 1.66 cuft



= 1 cuft

4.97 gals of water

= 0.66 cuft

But the Handbook states:

1.15 cuft /sack

WHY ? 1 cuft + 0.66 cuft

23 Si Sing ngle le Sta Stage ge Cem Cemen enti ting ng

= 1.66 cuft

Bulk Bu lk volu volume me vs vs Ab Abso solu lute te volu volume me One drum full of dry cement (1 drum = 1 cuft)

Same size drum 0.66 of water

24 Si Sing ngle le Sta Stage ge Cem Cemen enti ting ng

Bulk vo volu lum me vs Absolute vo volume One drum full of dry cement (1 drum = 1 cuft)

Pour water into cement Same size drum 0.66 of water Air in pore spaces will be displaced by water 25 Si Sing ngle le Sta Stage ge Cem Cemen enti ting ng

Note……… z

Yield varies with density

Basically, when you change the density you alter the z

Water / Cement ratio ....this changes the yield

z

Normally ........ as you increase the water content the yield increases


Bentonite API States: Ideal Mix (15.8 ppg)

Lightweight Slurry (12.8) ppg

1 cu/ft

4.97 gals

1 cu/ft

Cement

Water

Cement

Water

12% BWOC

Extra Water

1.15 cuft/sack

Bentonite


4.97 gals

Bentonite API States: Ideal Mix (15.8 ppg)

Lightweight Slurry (12.8) ppg

1 cu/ft

4.97 gals

1 cu/ft

Cement

Water

Cement

Water

12% BWOC

Extra Water

Bentonite

7.18 gals

1.15 cuft/sack

4.97 gals

Only 4.97 gals water is required for the cement. A chemical has to be added to react with the extra water. 28 Single Stage Cementing

Bentonite z z z

z

Bentonite is used in large quantities in oilfield slurries. As much as 25% BWOC is possible Offshore this presents a problem due to limited storage capacities and dry blending facilities. If Bentonite is mixed with fresh mix water instead of being dry blended only 1/4 of the amount is needed

This is called: Example :


Dry 2%BWOC 4%BWOC 10%BWOC

In Mix Water 0.5%BWOC 1% BWOC 2.5%BWOC

Handbook Gives: Ref Class “G” Neat

- Density 15.8 lbs/gals

Yield = 1.15 cuft/sack

700.06 Water 4.97 gals/sack Ref Class “G” + 6% D20 - Density 13.9 lbs/gals 700.013 Water 8.56 gal/sx


Yield = 1.655 cuft/sack

Step C - Cement Calculations z

If you know what volume of slurry a sack of cement [YIELD] produces at a certain weight, you can calculate the amount of sacks required when you know a volume.


Step C - Cement Calculations z

If you know what volume of slurry a sack of cement [YIELD] produces at a certain weight, you can calculate the amount of sacks required when you know a volume. VOLUME[cuft] = Sacks YIELD [cuft/sacks]


Example: Problem 1 (Continued) Previous Problem: Lead volume [1] : 367.05 cuft

240.2 cuft

Tail volume [2 + 3] : + 18.2 cuft 385.35 cuft



240.2 cuft


Use: Lead Slurry : Tail Slurry Neat

Class G + 6% D20 at 13.9 ppg : Class G at 15.8 ppg

Cement volume Lead: 34 Single Stage Cementing


240.2 cuft


Use: Lead Slurry : 6% D20 at 13.9 ppg Tail Slurry Neat : 15.8 ppg Cement volume Lead: Cement volume Tail: 240.2 cuft sacks 1.655 cuft/sack


= 145.2

Example: Problem 1 (Continued) Previous Problem: Lead volume [1] :

240.2 cuft

Use: Lead Slurry : Tail Slurry Neat : Cement volume Lead:

Cement volume Tail:


Tail volume [2 + 3] : 367.05 cuft + 18.2 cuft 385.35 cuft

6% D20 at 13.9 ppg 15.8 ppg 240.2 cuft 1.655 cuft/sack

= 145.2 sacks

385.25 cuft 1.15 cuft/sack

= 335.0 sacks

Mix Water - Step D z

If you know the number of sacks then you find the gal/sk of mix water required and multiply

z

Mix Fluid = gal/sack x number of sacks

(Your displacement tanks are in bbls)


Mix Water Quality z

In the laboratory, clean location water is used for cement test. Test results are only obtainable in the field when same water (= clean) is used.

z

Causes for contamination: – Dirty rig tanks – Left over chemicals/mud in lines and pumps – Dirty displacement tanks


Total Water Available 1. Calculated mix water for cement + 20% safety + 2. Water (ahead, behind, CW, spacer) + 20 bbls minimum (priming and washing up) = TOTAL WATER NEEDED


Example: Problem 1 (Continued) Lead mix water


145sx x 8.56 gal/sx

Example: Problem 1 (Continued) Lead mix water = 29.55 bbls

145sx x 8.56 gal/sx

=

42 gal/bbl


1241.2 gal


145sx x 8.56 gal/sx

=

42 gal/bbl Tail mix water


335sx x 4.97 ga/sx

1241.2 gal


145sx x 8.56 gal/sx

=

1241.2 gal

42 gal/bbl Tail mix water 39.64 bbls

335sx x 4.97 ga/sx

=

1664.95 gal =

42 gal/bbl



145sx x 8.56 gal/sx

=

1241.2 gal

=

29.55 bbls

1664.95 gal =

39.64 bbls

42 gal/bbl

Tail mix water

335sx x 4.97 ga/sx

=

42 gal/bbl

Total mix water


69.19 bbls


145sx x 8.56 gal/sx

=

1241.2 gal

=

29.55 bbls

1664.95 gal =

39.64 bbls


335sx x 4.97 ga/sx

=

42 gal/bbl Total mix water

69.19 bbls

20% safety margin : 66.19 bbl x 20/100 =

13.84 bbls



145sx x 8.56 gal/sx

=

1241.2 gal

=

29.55 bbls

1664.95 gal =

39.64 bbls


335sx x 4.97 ga/sx

=


69.19 bbls


13.84 bbls

No water ahead, behind, CW, spacer


0 bbls


145sx x 8.56 gal/sx

=

1241.2 gal

=

29.55 bbls

1664.95 gal =

39.64 bbls


335sx x 4.97 ga/sx

=


69.19 bbls


13.84 bbls

No water ahead, behind, CW, spacer Priming, washing up


0 bbls 20 bbls


145sx x 8.56 gal/sx

=

1241.2 gal

=

29.55 bbls

1664.95 gal =

39.64 bbls


335sx x 4.97 ga/sx

=


69.19 bbls


13.84 bbls

No water ahead, behind, CW, spacer

0 bbls

Priming, washing up

20 bbls

Total water needed

103 bbls


Additives - Step E z

Solid Additives

z

Calculated as a % by weight of dry cement. – Except: Salt – Small amounts will not effect calculation

z

Liquid Additives

z

Calculated as gallons of additives per sack of bulk cement

z

Subtract total amount of liquid additives from amount of mix fluid to have real amount of mix water.


Example: Problem 1 (Continued) Lead 6% D20 BWOC Tail 0.2 gal/sack of D80 Solid Additives

(145 sks) (335 sks)

145 sacks x 94 lbs/sack x 6/100 Liquid Additives

= 817.8 lbs

335 sacks x 0.2 gal/sack

= 67 gal

Mix fluid: 335sx x 4.97 gal/sk =1664.95 gal Mix water = Mix fluid - liquid additives 1664.95 gal - 67 gal = 38.1 bbl 42 gal/bbl 50 Single Stage Cementing

Displacement z

To FLOAT COLLAR unless otherwise stated

Exceptions 1. STAB-IN CEMENTING: – Displacement to 10-15’ before stab-in shoe – Check returns - OK - pull out and circulate

2. GUIDE SHOE: – Displace to 20-30’ before shoe


Displacement z

To FLOAT COLLAR unless otherwise stated

Exceptions 1. STAB-IN CEMENTING: – Displacement to 10-15’ before stab-in shoe – Check returns - OK - pull out and circulate

2. GUIDE SHOE: – Displace to 20-30’ before shoe


Estimated Job Time - Step G MIXING TIME + DISPLACEMENT TIME + 10 MINUTES (DROP PLUGS ...) = ESTIMATION OF JOB TIME 1 1/2 HOUR (SAFETY) = MINIMUM THICKENING TIME 53 Single Stage Cementing

Estimated Job Time - Problem 1 (Continued) z

Mixing time + Displacement time + Plugs mixing time: Lead Tail

42.8 68.6

: :

Displacement: Dropping Plugs Total z

4 bpm 8bpm

10.5 mins 8.5 mins

11mins 9 mins

4510ft x 0.0361 bbl/ft = 162.8 bbl : 12 bpm13.6 mins 14 mins 10 mins 44 mins

To allow a safe margin to do this job we expect at least 1 hr extra for the cement to be still pumpable after it is put in place. ie, 1hrs 44 mins


Examples - Example 1 Calculate : Slurry Volumes, Cement Volumes, Mix Water, Additives, Displacement Job Time Well Data: 9 5/8” 53.5 lb/ft casing, shoe at 9800’, collar at 9760’, OH 12 1/4” + 25% excess, previous casing 13 3/8” 68 lb/ft at 2900’

Slurries:

Lead: 5 bpm 9300’ - surface

Class “G” @ 12.8 ppg 12% BWOC Bentonite 0.3% BWOC D13 Tail: 3 bpm 9800’ - 9300’ Class “G” Neat @ 15.8 ppg 0.05% BWOC D28 0.5% BWOC D65 Displacement: 8 bpm 55 Single Stage Cementing

Examples - Example 1 Calculate : Slurry Volumes, Cement Volumes, Mix Water, Additives, Displacement Job Time

13 3/8" , 68 lbs/ft

Well Data: 9 5/8” 53.5 lb/ft casing, shoe at 9800’,

1

collar at 9760’, OH 12 1/4” + 25% excess, previous casing 13 3/8” 68 lb/ft at 2900’

Sluuries:

Lead: 5 bpm 9300’ - surface

Class “G” @ 12.8 ppg

2900'

12% BWOC Bentonite 0.3% BWOC D13 Tail: 3 bpm 9800’ - 9300’ Class “G” Neat @ 15.8 ppg 0.05% BWOC D28 0.5% BWOC D65 Displacement: 8 bpm 56 Single Stage Cementing

9 5/8", 53.5 lbs/ft

2

2

9300'

3 4

12 1/4" OH 9760'

3

9800'

Solution - Example 1 z

Capacities – CAS/CAS

: 0.3354 cuft/ft

– CAS OH

: 0.3132 cuft/ft

– CAS z

: 0.3973 cuft/ft , 0.0708 bbl/ft

1. Volumes



Capacities – CAS/CAS

: 0.3354 cuft/ft

– CAS OH

: 0.3132 cuft/ft

– CAS z

: 0.3973 cuft/ft , 0.0708 bbl/ft

1. Volumes Lead (1) 2900ft x 0.3354 cuft/ft (2) 9300ft - 2900ft x 0.3132

= 972.7 cuft = 2004 cuft

Excess = 2004 cuft x 0.25 =

501 cuft

Total = 3477 cuft


Tail (3) 9800ft - 9300ft x 0.3132 cuft/ft = 156.cuft (4) 40ft x 0.3973 cuft/ft = 15.9 cuft Excess 156.6 cuft x 0.25

= 39.2 cuft

Total = 211.7 cuft

Solution - Example 1 •

• Lead (1) 2900ft x 0.3354 cuft/ft (2) 9300ft - 2900ft x 0.3132

= 972.7 cuft = 2004 cuft

Excess = 2004 cuft x 0.25 =

501 cuft

Total = 3477 cuft

•


Tail (3) 9800ft - 9300ft x 0.3132 cuft/ft = 156.cuft (4) 40ft x 0.3973 cuft/ft = 15.9 cuft Excess 156.6 cuft x 0.25

= 39.2 cuft

Total = 211.7 cuft

z

3. Cement Lead :

Solution - Example 1 3477 cuft

= 1606 sacks

2.165 cuft/sk

Tail :

211.7 cuft = 184 sacks 1.15 cuft/sk

z

4. Mix Fluid Lead :

1606sk x 12.15 gals/sk

= 464.5 bbls

42 gal/bbl

Tail :

184sk x 4.97 gals/sk 42 gal/bbl


=

21.8 bbls


5. Additives Lead :

D20 : 1606sk x 94lbs/sk x 0.12

= 18116 lbs

D13 : 1606sk x 94lbs/sk x 0.003 = 453 lbs Tail :

D28 : 184sk x 94lbs/sk x 0.0005 = 8.6 lbs D65 : 184sk x 94lbs/sk x 0.005


= 86 lbs


6. Displacement 9760ft x 0.0708 bbl/ft = 691 bbls

z

7. Job Thickening Time Lead

3477 cuft

= 124 min

5.6146 cuft/bbl x 5 bpm Tail :

211.7 cuft

= 13 min

5.6146 cuft/bbl x 3 bpm Displacement:

691 bbls

= 86 min

8 bpm Drop Plugs

= 10 min

Safety

= 60 min 298 min

Minimum TT is 62 Single Stage Cementing

4 hrs 53 min

Example 2

Data : Casing

:

Open hole

:

Cement

:

Calculate :


9 5/8”, 53.5 lbs/ft, 8600’ 7”, 29 lbs/ft, 14300’ Float collar - 14230’ 8 1/2” Section from 10200’ - 10800’ : 9” Lead : - Top surface @ 7 bpm - “G” at 13.5 ppg - 0.05 gals/sk D109 - 0.1 gals/sk D80 - 8% BWOC - D20 Tail : - 250 sacks @ 5 bpm - Class “G” @ 15.7 ppg - 30% BWOC D66 - 0.1 gals/sk D81 - 0.5 gals/sk D603

Slurry Volume Cement Volume Mix water Additives Displacement @ 7 bpm Job Time

Solution - Example 2 9 5/8" , 53.5 lbs/ft

1

2

2

3

8600' 8.5" OH 7", 29 lbs/ft 10200' 9" OH 10800'

44 3 5


11507' 14230'

6

14300'

z

Capacities – CAS/CAS – CAS/OHX

z

Solution - Example 2 : 0.1301 cuft/ft : 0.1745 cuft/ft

CAS OH CAS

: 0.1268 cuft/ft : 0.2086 cuft/ft , 0.0371 bbl/ft

1. Volumes Tail : Yield is 1.475 cuft/sk 250 sacks ---> 250 x 1.475 = 368.75 cuft Volume (5) + (6) = 368.75 cuft (6) = 70 x 0.2086 = 14.6 cuft (5) = 368.75 - 14.6 = 354.15 cuft Height in annulus 354.15 cuft = 2793’ 0.1268 cuft/ft 14300 - 2793' = 11, 507' Lead: Surface - 11, 507' (1) 8600 x 0.1301 = 1118.86 cuft (2) (10200 - 8600) x 0.1268 = 202.88 cuft (3) (10800 - 10200) x 0.1745 = 104.70 cuft (4) (11507 - 10800) x 0.1268 = 89.64 cuft Total Lead = 1516.1 cu ft



2. Cement sacks Lead

:

Handbook : 13.5 ppg Class"G" 8% D20 Yield = 1.825 cuft/Sk

1516.1 cuft 1.825 cuft/sack Tail z

:

= 830.7

=

250 sacks

3. Mix fluid Lead

:

831sk x 9.76 gal/sk

=

193.1 bbls

=

36.6 bbls

42 gal/bbl Tail 66 Single Stage Cementing

: 250 sks x 6.15 gals/sk 42 gal/bbl

831 sacks

z

4. Additives Lead:

Tail:D66

z

5. Mix water Lead: Tail:


Solution - Example 2 D20 : 831 sks x 94 x 0.08 = 6249 lbs D109 : 831 sks x 0.05 gals/sk = 41.5 gals D80 : 831 sks x 0.1 gals/sk = 83.1 gals Total fluid = 124.6 gals : 250 sks x 94 x 0.3 = 7050 lbs D81 : 250 sks x 0.1 gals/sk = 25 gals D603 : 250 sks x 0.5 gals/sk = 125 gals Total fluid = 150 gals

193.bbls - 124.6gal = 190.1 bbls 42gal/bbl 36.6bbls - 150gal = 33.0 bbls 42gal/bbl


6. Displacement – 14230ft' x 0.0371 bbl/ft

z

= 527.9 bbl

7. Job Thickening Time

Lead Tail

: 270 bbls : : 65.7 bbls :

5 bpm

Plugs Displacement 527.9 bbls Safety Margin

7 bpm

=

38.5

=

13.1

min

: :

7 bpm

=

: Min TT is 3 hrs 16 min


min

=

10

75

min

=

60

min min

Job Pressures z

Example No 1 13 3/8" , 68 lbs/ft

z

Tail Slurry at 15.8 ppg

1

– Top of Tail at 9300 Ft – Lead slurry at 12.8 ppg to surface z z

2900'

Displace with 11.5 ppg Mud Find differential pressure at end of Job


9 5/8", 53.5 lbs/ft

2

2

12 1/4" OH

9300'

3 4

9760'

3

9800'

Hydrostatic Pressure Calcs Tubing Hydrostatic Mud Hydrostatic z – Pmud = 11.5 x 9760 x 0.052 – Pmud = 5836 psi Annular Hydrostatic Tail Slurry Hydrostatic z – PTail = 15.8 x(9760 - 9300)x 0.052 – PTail = 378 psi z Lead Slurry Hydrostatic – PLead= 12.8 x 9300 x 0.052 – PLead = 6190 psi z Differential pressure – PDiff= Annular Hyd. - Tubing Hyd. z

= (6190 +378) - 5836

– PDiff = 732 psi = Surface pump pressure 70 Single Stage Cementing

13 3/8" , 68 lbs/ft

1

2900' 9 5/8", 53.5 lbs/ft

2

2

9300'

3 4

12 1/4" OH 9760'

3

9800'

Long String Cement Calcs z

z

z

71

Primary Cement Job – 9 5/8” Csg , 40 lbs/ft – Shoe @ 9980’ - Collar @ 9900’ – Tail slurry @ 15.8 ppg to 9480’ – Lead slurry @ 12.8 ppg to 2100’ – 50 Bbls Chemical Wash ahead. Previous Casing – 13 3/8“ Csg ,77 lbs/ft – Shoe @ 3150’ 12 1/4” OH - Assume 10% Excess. – Find Lead, Tail and Displacement Volumes required. – Calculate Differential pressure at the end of the job (ignore friction). Single Stage Cementing

13 3/8" , 77 lbs/ft Mud @ 11.3 ppg

1 2100’

Chemical wash @ 8.4 ppg Lead Slurry @ 12.8 ppg 3150' 9 5/8", 40 lbs/ft

2

2

9480'

3 4

3

12 1/4" OH 9900' Tail Slurry @ 15.8 ppg 9980'

Long String Cement Calcs - Solution z

z

z

Capacities – Csg/OH Ann = 0.0558 bbls/ft – Csg/Csg Ann = 0.0564 bbls/ft – 9 5/8” Csg cap (40 #/ft) = 0.0758 bbls/ft Tail volume = Vol of Shoe track + Vol outside csg (with XS) = 0.0758 x (9980 - 9900) + 0.0558 x (9980 - 9480) x 1.10 = 6.06 + 30.69 = 36.75 = 37 Bbls = 206.3 cuft Lead volume = Vol in Csg/OH Ann (with XS) + Vol in Csg/Csg Ann = 0.0558 x (9480 - 3150) x 1.10 + 0.0564 x (3150 - 2100) = 388.53 + 59.22 = 447.75 = 448 Bbls = 2514.04 cuft


13 3/8" , 77 lbs/ft Mud @ 11.3 ppg

1 2100’


2

2

9480'

3 4

3



z

z

Capacities – Csg/OH Ann = 0.0558 bbls/ft – Csg/Csg Ann = 0.0564 bbls/ft – 9 5/8” Csg cap (40 #/ft) = 0.0758 bbls/ft Displacement volume = Csg Vol to float collar = 0.0758 x 9900 = 750 Bbls Differential pressure at end of Job : = Hydrostatic of Lead and tail cement columns + Hydrostatic of wash + Hydrostatic of remaining mud in annulus LESS Hydrostatic of displacing fluid + Hydrostatic of Tail cement in shoe joint


13 3/8" , 77 lbs/ft Mud @ 11.3 ppg

1 2100’


2

2

9480'

3 4

3



z

z

Capacities – Csg/OH Ann = 0.0558 bbls/ft – Csg/Csg Ann = 0.0564 bbls/ft – 9 5/8” Csg cap (40 #/ft) = 0.0758 bbls/ft Height of Chemical wash in Csg/Csg Ann = 50 / 0.0564 = 886 ft Height of Tail = 9980 - 9480 = 500 ft Height of Lead = 9480 - 2100 = 7380 ft Height of Chem Wash = 886 ft Remainder is Mud behind casing = 9900 - (420 + 7380 + 886) = 1214 ft


13 3/8" , 77 lbs/ft Mud @ 11.3 ppg

1 2100’


2

2

9480'

3 4

3


02 - Cálculos de cementación en una etapa.pdf

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