Matematik ushtrime 5 matricat inverse.docx

Te njehsohet matrica inverse e matrices A

(

 A =

2

0

1

−1

3

−1

2

1

0

|

2

det A = −1

(

2

 A11 adj A =  A 21  A 31

)

0 3 1

1

| | 2 0

−1 −1 3 =¿ 0 + 0 -1 + 0 + 2 - 6= - 5

A12 A22 A32

0

det A

2 1

A 13 A 23 A 33

=

-5

) 1

 A 11=(− =(−1)

| − |= + =

+1 3

1

1

+

1

+

0

0

2

2

=(− − )=− | |=(− −1

3

2

1

1

6

7

| |=−( − )=−(− )=

+ 0

1

1

0

2 1

 A 21=(−1 )

1

2

1 3

 A 13=(−1 )

1

|− − |=−( + )=−

1 2

 A 12=(−1 )

0 1

0

0

1

1

1

1

2

0

0

2

1

+

+

(

1 1

−3

)(

−2 −7 T  1 −3 1 = −2 −2 −2 −2 1 −7 −2 6 1 6

)

( ) 1

 A

−1

=

1

−5

adjA =

1

(

1

1

2 2 −5 − − −7 − 2

−3 1 6

−5 = −2 −5 −7 −5

)

1

−3 −5

−5 −2 1 − 5 −5 −2 6 − 5 −5

0

1

2

0

2

3

3

|− − |=−(− + ) =−(− )= 2

1

1

3 3

 A 33=(−1 )

2

1

3

3 2

 A 32=(−1 )

2

| − |= − =−

+ 0

3 1

 A 31=(−1 )

0

| |=−( − )=−

+ 2

2 3

 A 23=(−1 )

| |= − =−

+ 2

2 2

 A 22=(−1 )

2

1

|− |= + = 2

1

0

3

6

0

6

1

1

1