LAPORAN TETAP SATUAN OPERASI 2
DISUSUN OLEH :
ALMER SUDHIARTA
(061430400316)
BELLA DWI AULINA
(061430401245)
MUHAMMAD RICKY
(061430400325)
NOVITA SARI
(061430401231) (061430401231)
SHANTY NURMEUTIA
(061430401238)
YONADA KHAIRUNNISA
(061430400334)
KELAS : 4KB
INSTRUKTUR : IR SELASTIA YULIATI! M SI
JURUSAN TEKNIK KIMIA POLITEKNIK NEGERI SRIWIJAYA 2016
EKTRAKSI CAIR-CAIR 2 I"#$%&'#&% : I% I% '$*" M A+,"! M S,
EKTRAKSI CAIR-CAIR 1 I"#$%&'#&% : I% I% '$*" M A+,"! M S,
EVAPORATOR 2 I"#$%&'#&% : I% '$*" M A+,"! M S,
EVAPORATOR 1 I"#$%&'#&% : I% '$*" M A+,"! M S,
PENGERINGAN ZAT PADAT 1 I"#$%&'#&% : I% S*-$#, Y&-,#,! M S,
PENGERINGAN ZAT PADAT 2 I"#$%&'#&% : I% S*-$#, Y&-,#,! M S,
REACTOR CONTINUE 1 DAN 2 I"#$%&'#&% : E"."/ S&%#,! ST! MT
DISTILASI CONTINUE 1 I"#$%&'#&% : E"."/ S&%#,! ST! MT
DISTILASI CONTINUE 2 I"#$%&'#&% : E"."/ S&%#,! ST! MT
HEAT EXCHANGER 1 I"#$%&'#&% : I% S*-$#, Y&-,#,! M S,
HEAT EXCHANGER 2 I"#$%&'#&% : I% S*-$#, Y&-,#,! M S,
EKSTRAKSI CAIR-CAIR 2
I.
TUJUAN PERCOBAAN
— M$,$ ++& +*"/*%$,'" -# L,,&. E#%#," .*"/" 7,' — M$,$ +& +*"/*#&, % '*% -# *'$#%'$, ,%9,% .*"/" -,%" &"#*% &%%*"#
— M$,$ ++& +*"*"#&''" '*,$,*" *+,$" ." "*% +$$ II.
ALAT DAN BAHAN A!" #!$% &'%($!)!$
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—
—
—
—
NOH A$+ A$*## I".,'#% == A,% E#,- A$*##
III.
DASAR TEORI 1. P+$%+,"'!$ E)",!)'
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IV.
PROSEDUR KERJA
1. M*"<,'" 7" <"/ '" .,/&"'" (**. $*%# S-*"#) 2. M*"/&7&"/'" '7*- '* $&+7*% '"#' . M*+&#% #+7- '* $,$, " /. M*+&#% '#& + 1 ." + 2! '*+&.," +*+&#% '#& *'$#%' ."
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V.
DATA PENGAMATAN V.1 D!"! P+$%!4!"!$ D+5!$"+,
N 1 2
N
S+*-
V- T,#%" (+L)
5 +- E#,- A$*## G 3 #*#*$ I".,'#% == 5 +- CH3COOH G 3 #*#*$ I".,'#% ==
11!? 1!8
S+*- .-+ D*
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E'$#%'
R,"#
E'$#%'
R,"#
1
#1
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102
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3
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101
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4!?
-
M!! #!$% D'+,7+*
N
M$$ (/%)
1
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2
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106!81
3
E'$#%' 2
84!55
4
R,"# 2
100!21
5
E'$#%' 3
83!85
6
R,"# 3
100!2?
V.2 D!"! P+$%!4!"!$ A!" C7$"'$(+
N
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1
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E'$#%'
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E'$#%'
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35
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5 +L
5
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2
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8 -,#*%
3 V-&+* S-*"# ',%
5520 +L
5!5 L
4 V-&+* **. ',%
1260 +L
1!2 L
5 V-&+* R,"#
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1!1 L
6 V-&+* E'$#%'
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5 +- E#,- A$*## G 3 #*#*$ I".,'#% == 5 +- CH3COOH G 3 #*#*$ I".,'#% ==
18 +L @!5 +L
VI.
PERHITUNGAN
!. P+,*'"($%!$ P,7+ C7$"'$(+
VI1 •
M*"/,#&"/ D*"$,#$ AD,'
: + ,'" '$"/ V =,'"
A . ρ solven=
B.ρfeed =
33!05 /% 24! @806 +L
( 57,47−33,05 ) gr 24,7806 ml
( 57,37 −33, 05 ) gr 24,7806 ml
C . ρ ekstrak 1=
=0,9855
= 0,9814
( 62,13−33, 05) gr 24,7806 ml
ρ Ekstrak 2=
ρ Ekstrak 3 =
D . ρ Rafinat 1=
gr ml
=1,1735 gr
ml
( 62,04 −33,05 ) gr 24,7806 ml
( 61,98 −33,05 ) gr 24,7806 ml
( 62,30−33,05 ) gr 24,7806 ml
gr ml
=1,1699
gr ml
=1,1674 gr
ml
=1,1803
gr ml
ρ Rafinat 1=
ρ Rafinat 1=
VI2
( 62,18 −33,05 ) gr 24,7806 ml
( 62,12− 33,05 ) gr 24,7806 ml
=1,1755
gr ml
=1,1731
gr ml
=*%,#&"/" K"$*"#%$, A-
A A$+ A$*## G A,% V C H COOH × N C H COOH + H o =V NaOH × N NaOH 3
3
2
5 ml× X =7,5 mL × 1 N
X =1,5 N B E#,- A$*## V C H COOH × N C H COOH + H o =V NaOH × N NaOH 3
3
2
18 mL × 1 N 5 ml×X= X =3,6 N
VI3 •
K"$*"#%$, E'$#%' A 35 +*",# V ekstrak × N ekstrak =V NaOH × N NaOH
5 mL× 1 N 5 ml×X= X =1 N B 50 +*",# V ekstrak × N ekstrak =V NaOH × N NaOH
5 ml× X = 4 mL× 1 N
X =0,8 N C 65 +*",# V ekstrak × N ekstrak =V NaOH × N NaOH 5 ml× X =4 mL× 1 N
X =0,8 N
•
R,"# A 35 +*",# V ekstrak × N ekstrak =V NaOH × N NaOH 5 ml× X = 9,5 mL× 1 N
X =1,9 N
B 50 +*",# V ekstrak × N ekstrak =V NaOH × N NaOH
10 mL× 1 N 5 ml×X= X =2 N C 65 +*",# V ekstrak × N ekstrak = V NaOH × N NaOH 5 ml× X = 10,5 mL× 1 N
X =2,1 N
VI4
M*"%, N,-, ! ! E! ." R X f =1,5
X c =3,6 X E=
1 + 0,8 + 0,8 3
=0,86
X f =
VI5
1,9 + 2 + 2,1 3
=2
M*"/,#&"/ K*,$,*" D,$#%,7&$, A 35 +*",# konsentrasi!at terlar"t dalam ekstrak d = konsentrasi!at terlar"t dalamrafinat
¿
0,8 N 2 N
= 0,53
B 50 +*",# konsentrasi!at terlar"t dalam ekstrak d = konsentrasi!at terlar"t dalamrafinat
¿
0,8 N 2 N
= 0,4
C 65 +*",# konsentrasi!at terlar"t dalam ekstrak d = konsentrasi!at terlar"t dalamrafinat
¿
0,8 N
= 0,38
2,1 N
VI6
M*"/,#&"/ S*-*'#,,#$ $raksi massasol"t dalam rafinat $raksi massa dil"ent dalam ekstrak # = $raksi massasol"t dalam rafinat $raksi massa dil"ent dalam ektsrak
X 1=
8387,6 / 148
8387,6 / 148 ( 0,949 ×
¿
X 1=1 −0,51830 = 0,4817
1000 18
=0,51830 )
X 2=
1340 / 60
1340 / 60 ( 0,949 ×
1000 18
= 0,3 )
¿
X 2=1 −0,3=−0,7
VI@
M*"/,#&"/ M$$ •
D# A $eed = ρ ×V
¿ 0,9814
gr × 8000 mL ml
¿ 8145,62 gr %olvent = ρ ×V
¿ 0,9855 × 8000 mL ¿ 7174,44 gr
— M$$ E'$#%' E=1,1731
gr × 7150 ml ml
¿ 8387,6 gr
— M$$ R,"# E=1,1763
gr × 1140 ml ml
¿ 1340,982 gr
•
D# A',%
A . $eed = 0,9814
¿ 1236,56 gr
gr × 1260 mL mL
B . %olven=0,9855
gr × 5520 m L mL
¿ 5439,7 gr
N*% M$$
$ × X $ + C × X C = E × X E + R × X R
8145,62 ( 1,5 )+ 7174,44 ( 3,6 )=8387,6 ( 0,86 )+ 1340,98 ( 2)
38046,41 = 9895,26
K+"*"
I"&#
O&#&#
/%
/%
/%
/%
**.
1!5
0!?814
8145!62
12218!43
1236!56
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3!6
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@1@4!44
2582@!?8
543?!@
1?582!?2
E'$#%'
0!86
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9
9
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@213!336
R,"#
2
1!1@63
9
9
1340!?
2681!8
J
38046!41
8. P+,*'"($%!$ P,7+ B!"5*
VI1
=*%,#&"/" K"$*"#%$, A-
A A$+ A$*## G A,% V C H COOH × N C H COOH =V NaOH × N NaOH 3
3
5 ml×N =1,8 mL× 1 N
N =0,36 N B E#,- A$*## V C H COOH × N C H COOH =V NaOH × N NaOH 3
3
5 ml×N =11,9 mL × 1 N
N =2,4 N
3131?!8?
VI2 •
K"$*"#%$, E'$#%' A #1 V ekstrak × N ekstrak =V NaOH × N NaOH 5 ml×N = 2,8 mL× 1 N
N =0,56 N B #2
V ekstrak × N ekstrak =V NaOH × N NaOH 5 ml×N = 2,5 mL× 1 N
N =0,5 N C #3
V ekstrak × N ekstrak =V NaOH × N NaOH 5 ml×N =2 mL× 1 N
N =0,4 N
•
R,"# A #1 V ekstrak × N ekstrak =V NaOH × N NaOH 5 ml×N =5,8 mL× 1 N
N =1,1 N
B #2
V ekstrak × N ekstrak =V NaOH × N NaOH 5 ml×N = 4,8 mL× 1 N
N =0,96 N C #3 V ekstrak × N ekstrak =V NaOH × N NaOH 5 ml×N = 4,9 mL× 1 N
N =0,98 N
VI3
M*"%, N,-, ! ! E! ." R X f =0,36
X c =2,4 X E= X f =
VI4
0,56 + 0,5+ 0,4 3
= 0,48
1,1 + 0,96 + 0,98 3
=1,01
M*"/,#&"/ K*,$,*" D,$#%,7&$, D #1
d =
¿
konsentrasi!at terlar"t dalam ekstrak konsentrasi!at terlar"t dalamrafinat
0,56 N 1,1 N
= 0,5
E #2
d =
¿
konsentrasi!at terlar"t dalam ekstrak konsentrasi!at terlar"t dalamrafinat
0,5 N
= 0,52
0,96 N
#3
d =
¿
konsentrasi!at terlar"t dalam ekstrak konsentrasi!at terlar"t dalamrafinat
0,4 N
=0,4
0,98 N
VI5
M*"/,#&"/ S*-*'#,,#$ $raksi m assa sol"t dalam rafinat $raksi massa dil"ent dalam ekstrak # = $raksi massasol"t dalam rafinat $raksi massa dil"ent dalam ektsrak
262,79 / 148
X 1=
262,79 / 148 ( 0,949 ×
1000 18
= 0,0325 )
¿
X 1=1 −0,0325 = 0,9675
307,31 / 60
X 2=
307,31 / 60 ( 0,949 ×
¿
X 2=1 −0,088= 0,912
¿
# =
X 1 : X 1 ¿
X 2 : X 2
¿ 0,0325 : 0,9675 0,088:0,912
¿
0,033 0,096
¿ 0,348
1000 18
=0,088 )
VII.
ANALISA PERCOBAAN
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VIII.
KESIMPULAN
D%, *%7" <"/ #*- .,-'&'" .# .,$+,&-'" 7 : 1 E'$#%'$, ,% +*%&'" $&#& +*#.* *+,$" #& *"/+7,-" ># #*%-%&# .-+ -%&#" .*"/" +*"//&"'" *-%&# -," 2 E'$#%'$, ,%9,% +*"//&'" $-*"# <,#& E#,- A$*##! S-&# <,#& A$+ A$*##! ." .,-&*"# <,#& ,% 3 =%$*$ "#,"&* +*"/-+, *%,"." +$$ <"/ -*7, 7,'
DA9TAR PUSTAKA
S"&%! < 2011 Kumpulan Buku-Buku Wajib Dimiliki Bagi! (O"-,"*)! ( ##:FF#*',+$#,- 7-/ $#+F2011F12F&+&-"97&'&97&'&9,79.,+,-,',97/,#+-! D,&".& 24 M*, 2016)
M%.,'! S,#, &>, 2012 Ekstraksi Cair-Cair, (O"-,"*)! ( ##:FF$,#,&>,+%.,'7-/
$#+F2012F08F*'$#%'$,9,%9,%9,#+-$#$#'TDES.& ! D,&".& 24 M*,
2016)
GAMBAR ALAT
