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Descripción: Segundo Parcial Mecanica 2016-2 - Solución- unimag
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Examen Parcial de Simulación
Descripción: modelo de examen
Descripción: PARCIAL SEMANA 4
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examen parcial 2Descripción completa
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: Dinámica de Suelos – 2016-2 Curso Docente: Dr. Ing. Reynaldo Reyes Roque Fecha : 17 de enero del 2017. EXAMEN PARCIAL
Nota: Se calificará la adecuada presentación y resolución del problema planteado.
Parte a. PROBL!"
1. Para el #uro de contenc$%n #ostrado& calcular:
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$%L&CI%N
'#'#( )eterinación de la capacidad de carga adisible para condiciones e ( De la teor*a de Ca'ac$dad de Carga D$n)#$ca:
Donde: q =γ ∗ Df
q =¿ 1.<=>2 q =3.30 ?n3#2 ;q y ;y son actores de ca'ac$dad de carga que se o(t$enen de la $gura 4.2@
Ca'ac$dad de Carga D$n)#$ca. De la $gura 4.2@ adAunta en la s$gu$ente ')g$na se o(ser-a:
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F$gura 4.2@
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Nγ =15
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Calculo de la ca'ac$dad de carga ad#$s$(le:
Sheet Music
qadm =
qadm =
79.6125 3
qu F . S .
=26.5375 Tn / m 2
qadm =26.5375 Tn / m 2 )eterinación de la capacidad de carga adisible para condiciones s+sicas* ( De la teor*a de Ca'ac$dad de Carga D$n)#$ca:
Calculo de ;q y ;y:
q =γ ∗ Df q =¿ 1.<=>2 q =3.30 ?n3#
Del gr)$co 4.2:
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ntonces& halla#os las relac$ones:
ra$co 4.2
1.
NγE = 0.31 Nγ
2.
NγE= 0.31∗15 NγE= 4.65
NqE =0.58 Nq
NqE =0.58∗11 NqE =6.38
F$nal#ente: quE =3.30∗¿ <.4@0.=>1.<=>4.=>.<= quE =34.48 Tn / m 2
'## -erificar la capacidad de carga adisible por asentaientos# You're Reading a Preview Unlock full access with a free trial.
2
Si E=
q B ( 1− v ) Es
If …. (¿)
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Donde: 2
(
Es=1200 tn / m v =0.25 Sign up to vote on this title B =3.5 m Useful Not useful If =120
( )
( )
(
3.5 1 + 0.5 11 +
( )
0.5 11
)) (
2.4
)
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( Calcular los asentaientos .ue tiene la estructura, as+ co asentaiento por siso con -/0#12s " A/0#3 #
Donde: V =0.4 m / s A = 0.3
g= 9.81 m / s
2
¿
Calculams! h D"la figu#a 3.30 c $a#a ∅ =26 % ( Cnsid"#ams 3 0 % ) & FS =3 '
Df = 0.57 B
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tan ( AE=0.7 5
Ree#'la5ando en la ecuac$%n: 2
( 0.4 ) S Eq ( m )=0.17 ( 0.3 ) ( 9.81 )
| |( 0.26 0.3
−4
0.75 )Reading a Preview You're
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S Eq =0.01229 m=12.29 mm
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'#3 Realizar el an!lisis est!tico del uro# Sign up to vote on this title
Ealla#os el a:
(
∅
)
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) A =
1 2
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( 0.3905 ) ( 1.65 ) ( 12 ) + ( 0.3905 ) ( 1 ) 2
) A =46.7819 tn
Ealla#os el P ': ) $=
) $=
1 2
1 2
( K$ ) ( γ ) ( D ) 2
( 2.5611 ) ( 1.65 ) ( 2 ) 2
) $=8.4516 tn
Ealla#os Reacc$%n en la (ase del #uro:
N = +m + ) AV ... ( 1 ) •
Ealla#os 'eso del #uro +9#/
(
+m=
( )
(
)
3.5 1 + 0.5 11 +
+m=28.2 tn
(
( )
0.5 11 2
))(
2.4
)
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•
Ealla#os P" :
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) AV =sin , ( ) A ) ) AV =sin 30 % ( 46.7819 ) ) AV =23.391 tn •
Ealla#os P"E :
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F . S v =
(
of 11
)
(
28.2 1.5 + 23.391 3.5 1 3
P. Geotecnia
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)
( 40.5143 ) ( 12 ) F . S v =¿ 0.7<<
Calcula#os el 4AC5%R )E $E6&RI)A) C%N5RA )E$LI7AMIEN5%
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F . S d =
51.591 tan 30 % 40.5143
−8.4516
F . S d =0.929 Sign up to vote on this title
'#1 Realizar el an!lisis s+sico del uro, con los 8todos Useful Not useful de $eed " 9 :itan
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Calcula#os el 4AC5%R )E $E6&RI)A) C%N5RA )E$LI7AMIEN5
Sheet Music
F . S d =
51.591 tan30 %
40.5143 −8.4516 + 2.271
F . S d =0.548
Calcula#os el 4AC5%R )E $E6&RI)A) C%N5RA EL -%L5E
F . S v =
1 3
(
28.2 1.5
) + 23.391 ( 3.5 )
( 40.5143 ) ( 12 ) +0.6 ( 12 ) ( 22.279 )
F . S v =0.696 You're Reading a Preview Unlock full access with a free trial.
( Mononobe(%abe
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= tan
(
(
−1 0.25 9.81
9.81
of 11
)
)=
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0.2449 /A = 14.04 %
( 26 −¿ 0 −14.04 )
cos 2
[√
( + 0 + 14.04 ) 1 +
cos14.04 % cos 0 % cos 30
( + 26 ) sin ( 26−0 −14.0 cos ( 30 + 0 + 14.04 ) cos ( 0−
sin 30
K AE=¿ K AE= 0.6328 ) AE= ) A + ) E
You're Reading a Preview
) AE= 46.7819 +22.279 =69.0609 tn 1
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2
) AE= K AE * γ 2
) AE=
1 2
2
( 0.6328 ) 12 ( 1.65 ) =75.176 tn Sign up to vote on this title
ANALI$I$
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9h$t#an es de 0.<<& d$s#$nuyendo en 10.41G res'ecto al an)l est)t$co.
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•
l actor de segur$dad res'ecto al desl$5a#$ento del #uro en un est)t$co es de 0.2& #$entras que en el an)l$s$s d$n)#$co 'or 8e 9h$t#an es de 0.=@& d$s#$nuyendo en un 1G res'ecto al an)l est)t$co
•
Por el #6todo de !onono(e O,a(e o(tene#os un P" de 7=.1 no d$sta #ucho con la su#a s$#'le del P" y P 'ara o(tener el <.0<& que d$s#$nuyo en un @.1G
C%NCL&$I%NE$
•
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l s$s#o aecta la ca'ac$dad de carga ad#$s$(le de la estructura d$s#$nuy6ndola en un 4.41G en nuestro #uro.
La ca'ac$dad de carga ad#$s$(le 'or asenta#$ento resulta ser un You're Reading a Preview 'equeHo co#'arado con la ca'ac$dad de carga ad#$s$(le& y su full access with a free trial. asenta#$ento d$na#$coUnlock (orda 'or los 1 c# 'ara nuestro 'ro(le# Download With Free Trial
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•
l actor de segur$dad res'ecto al -olteo d$s#$nuye en 10.41G e an)l$s$s d$na#$co 'or 8eed y 9h$t#an res'eto al an)l$s$s estat$c nuestro 'ro(le#a. l actor de segur$dad res'ecto al desl$5a#$ento d$s#$nuye Sign up to vote on this title cons$dera(le#ente en 1G en el an)l$s$s d$na#$co 'or 8eed y Useful Not useful 9h$t#an res'eto al an)l$s$s estat$co en nuestro 'ro(le#a.
