Desain Alinyemen Horizontal

DESAIN ALINYEMEN HORIZONTAL

Tikungan Pertama

x

y

P0

272639.736

9804469.644

P1

272143.336

9804642.503

P2

272278.252

9804971.533

en = 4% emax = 10 % V = 30 km/jam b = 3.5 m R = 43.5 m Menghitung  -1 

Az1 = tan



-1 

Az2 = tan



-1

= tan

-1

= tan

   

0

0

= -70 482.14 (K.IV) = 289 1157.86 0

= 22 1744.42 (K.I)

 = Az2 - Az1 = 2201744.42 - 28901157.86 = -26605413.44 = 9300546.56

Mencari Ls y

y

y

y

y

y

V mean

= 0.8 V = 0.8 x 30 km/jam = 24 km/jam V < 50 km/jam Fmax = 0.270  0.02 V = 0.270  0.02 (30) = 0.21 2 Dmax = (1432.394 x 127)(emax + fmax) / V 2 = (1432.394 x 127)(0.1 + 0.19) / 30 = 62.65927976 D = 1432.394/R = 1432.394/43.5 = 32.9285977 2 DPI = (1432.394 x 127) emax / Vmean 2 = (1432.394 x 127) 0.1 / 24 = 31.58229826 HPI = { V2 x DPI / (1432.394 x 127)}  emax = {302 x 31.58229826 /(1432.394 x 127)}  0.1

y

SI

y

S2

y

mo

y

y

y

y

y

= 0.05625 = HPI / DPI = 0.05625 / 31.58229826 -3 = 1.781061009 x 10 = (fmax  HPI) / (Dmax  DPI) = (0.21  0.05625) / (62.65927976 - 31.58229826) -3 = 4.947391691 x 10 = (DPI / 2Dmax) (S2  S1) (Dmax  DPI) -3 -3 = (31.58229826/ 2 x 62.65927976) (4.947391691 x 10 - 1.781061009 x 10 )( 62.65927976 - 31.58229826) = 0.0247983871

D > DPI f

2

= mo {(Dmax  D)/(Dmax  DPI)} + HPI + S2 x (D  DPI) = 0.0247983871 {(62.65927976 - 31.58229826) / (62.65927976 - 31.58229826)}2 + 0.05625 + 4.947391691 x 10-3 (32.9285977 - 31.58229826) = 0.0856069946 e = V2 / 127 R  f  2 = 30 / 127 (43.5) - 0.0856069946 = 0.07730367605 Ls (1) = 2 x 1000/3600 x V = 2 x1000/3600 x 30 = 16.667 m V < 80 km/jam   = 0.035 Ls(2) = 1000/3600 x V (e+en) /  = 1000/3600 x 30 (0.07730367605 + 0.04) / 0.035 = 27.929 m m = 2V + 40 = 2(30) + 40 = 100 Ls(3) = b x m(e+en) = 3.5 x 100 (0.07730367605 + 0.04) = 41.056 m

Maka Ls diambil = 50 m

Mencari

Ts , Es dan K 

= 0.5747126437 rad = 3205542.99

s

=

y

c

=  - 2 s 0 0 = 93 0546.56  2(32 5542.99) 0 = 27 1420.58 = 0.4754110873 rad

y

Xc

= Ls (1 -



=



y











+







-







+





)

= 48.374 m y

Yc

y

P

y

k



= Ls (



-





+





-





+





)

= 9.355 m = Yc  R(1  cos s) 0 = 9.355  43.5 ( 1  cos 32 5542.99 ) = 236.659 m = Xc  R sin s

0

y

Es

y

Ts

y

Lc

= 48.374  43.5 sin 32 5542.99 = 24.727 m = ( R + p ) sec ½  - R 0 = ( 43.5 + 236.659 ) sec ½ (93 0546.56)  43.5 = 23.191 m = k + (R + p) tan ½  0 = 24.727 + (43.5 + 236.659) tan ½ (93 0546.56) = 73.142 m = c x R = 0.4754110873 x 43.5 = 20.680 m

Karena Lc < 25 m  Full Spiral Maka dilakukan Perhitungan sebagai berikut : y

c

=0

y

s

=

y

Ls

= 2 s x R = 2 x 0.8124181873 x 43.5 = 70.680 m

y

Xc

= Ls (1 -







=







+







0

= 46 3253.28 x

-





+







= 0.8124181873 rad

)

= 66.156 m y

Yc

y

P

y

k

y

Es

y

Ts

y

Lc



= Ls (



-





+





-





+





)

= 18.257 m = Yc  R(1  cos s) 0 = 18.257  43.5 ( 1  cos 46 3253.28 ) = 4.674 m = Xc  R sin s 0 = 66.156  43.5 sin 46 3253.28 = 34.577 m = ( R + p ) sec ½  - R 0 = ( 43.5 + 4.674 ) sec ½ (93 0546.56)  43.5 = 26.546 m = k + (R + p) tan ½  0 = 34.577 + (43.5 + 4.674 ) tan ½ (93 0546.56) = 85.427 m = c x R = 0 x 43.5 =0

Tikungan Kedua

x

y

P1

272143.336

9804642.503

P2

272278.252

9804971.533

P3

271825.672

9804793.621

en = 4% emax = 10 % V = 30 km/jam b = 3.5 m R = 90 m Menghitung  -1 

Az1 = tan

Az2 = tan-1

  

-1

= tan

= tan-1

   

0

= 22 1744.42 = 6803223.65 (K.III) = 24803223.6

 = Az2 - Az1 = 24803223.6 - 2201744.42 0

=266 1439.2 - 360

0

0

= -133 4520.8 Mencari Ls y

y

y

y

y

y

y

V mean

= 0.8 V = 0.8 x 30 km/jam = 24 km/jam V < 50 km/jam Fmax = 0.270  0.02 V = 0.270  0.02 (30) = 0.21 Dmax = (1432.394 x 127)(emax + fmax) / V2 2 = (1432.394 x 127)(0.1 + 0.19) / 30 = 62.65927976 D = 1432.394/R = 1432.394/90 = 15.91548889 2 DPI = (1432.394 x 127) emax / Vmean 2 = (1432.394 x 127) 0.1 / 24 = 31.58229826 HPI = { V2 x DPI / (1432.394 x 127)}  emax = {302 x 31.58229826 /(1432.394 x 127)}  0.1 = 0.05625 SI = HPI / DPI = 0.05625 / 31.58229826

-3

y

S2

y

mo

y

y

y

y

y

= 1.781061009 x 10 = (fmax  HPI) / (Dmax  DPI) = (0.21  0.05625) / (62.65927976 - 31.58229826) -3 = 4.947391691 x 10 = (DPI / 2Dmax) (S2  S1) (Dmax  DPI) -3 -3 = (31.58229826/ 2 x 62.65927976) (4.947391691 x 10 - 1.781061009 x 10 )( 62.65927976 - 31.58229826) = 0.0247983871

D > DPI f

= mo {(Dmax  D)/(Dmax  DPI)}2 + HPI + S2 x (D  DPI) = 0.03464406929 e = V2 / 127 R  f  2 = 30 / 127 (90) - 0.03464406929 = 0.04409608819 Ls (1) = 2 x 1000/3600 x V = 2 x1000/3600 x 30 = 16.667 m V < 80 km/jam   = 0.035 Ls(2) = 1000/3600 x V (e+en) /  = 1000/3600 x 30 (0.04409608819+ 0.04) / 0.035 = 20.023 m m = 2V + 40 = 2(30) + 40 = 100 Ls(3) = b x m(e+en) = 3.5 x 100 (0.04409608819+ 0.04) = 29.434 m

Maka Ls diambil = 30 m

Mencari

Ts , Es dan K 

= 0.16666667 rad = 903257.47

s

=

y

c

=  - 2 s 0 0 = 133 4520.8  2(9 3257.47) 0 = 114 3925.86 = 2.001145382 rad

y

Xc

= Ls (1 -



=



y











+







-







+





)

= 29.917 m y

Yc

y

P

y

k

y

Es



= Ls (



-





+





-





+





)

= 1.663 m = Yc  R(1  cos s) 0 = 1.663  90 ( 1  cos 9 3257.47) = 41.625 m = Xc  R sin s 0 = 29.917  90 sin 9 3257.47 = 14.986 m = ( R + p ) sec ½  - R 0 = ( 90 + 41.625 ) sec ½ (133 4520.8)  90 = 140.247 m

y

Ts

y

Lc

= k + (R + p) tan ½  = 14.986 + (90 + 41.625 ) tan ½ (13304520.8) = 226.738 m = c x R = 2.001145382 x 90 = 180.103 m

Karena f < 0.04  Full circle Maka dilakukan perhitungan sebagai berikut : y

Lc

=xR = 2.334478716 x 90 = 210.103 m

y

Ts

= R tan





= 90 tan

  

= 210.776 m y

y



Es

= R { (sec )  1 }

Tc

= 139.187 m = 90 tan ½  = 210.777 m

