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Hubung singkat salah satu sumber.
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Hitung Arus (I) dan arahnya di tiap-tiap cabang.
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Hubung singkat salah satu sumber lainnya.
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Hitung Arus (I) dan arahnya di tiap-tiap cabang.
Hitung Arus (I) dan arahnya di tiap-tiap cabang gabungan.
I5=I3-I4=2,845-0,448=2,397 A
I6=Eab/R5=3,588/6=0,598 A
I7=I5-I6=2,397-0,598=1,799 A
I1'
I3'
I2'
I4'
I5'
I6'
I7'
E2
+
-
R1
R2
R3
R5
R6
R7
d
c
Hubung singkat salah satu sumber lainnya.
Hitung Arus (I) dan arahnya di tiap-tiap cabang.
Dengan menggunakan prinsip pembagian Arus , I' dapat dicari:
JADI:
Arus gabungannya adalah :
I = I '+ I "= 1 A = + 0,25 A =1,25 A
CONTOH SOAL 2
Dengan teorema superposisi,hitung I1,I2,I3,I4,I5,I6,I7 dan I1',I2',I3',I4',I5',I6',I7'
I1
I3
I2
I4
I5
I6
I7
E2
+
-
+
-
E1
R1
R2
R3
R5
R6
R7
Jawab :
I1
I3
I2
I4
I5
I6
I7
+
-
E1
R1
R2
R3
R5
R6
R7
a
b
Diketahui :
R1=2 ,R2=6 ,R3=4 ,R4=8 ,R5=6 ,R6=2 ,E1=10v,E2=20v
Rs1=R2+R3=6+4=10 Rt=Rp+R1=120/107+2
1/Rp1 =1/10+1/8+1/6+1/2 =3,121
1/Rp1 = 107/120 Eab=I1.Rp
Rp1 =120/107 =3,204.120/107
I1=E1/Rt=10/3,121 =3,588 V
=3,204 A
I2=Eab/Rs=3,588/10=0,3588 A
I3=I1-I2=3,204-0,3588=2,845 A
I4=Eab/R4=3,588/8=0,448 A
Arus gabungan :
I7'-I7 =6,41-1,799=4,611 A ke kiri
I6+I6' =0,598+1,2=1,798 A ke bawah
I5'-I5 =5,21-2,397=2,8 A ke kiri
I4'+I4 =0,9+0,448=1,348 A ke bawah
I3'-I3 =4,31-2,845=1,465 A ke kiri
I2'+I2 =1,2+0,3588=1,5588 A ke bawah
I1-I1' =3,204-3,11=0,94 A
Dengan menggunakan prinsip pembagian Arus , I' dapat dicari:
Dengan menggunakan teorema superposisi, tentukan ukuran aliran (I) melalui R2 di seri berikut!
CONTOH SOAL 1
1/Rp=1/2+1/10+1/8+1/6 Rt=Rp+R6
1/Rp=1o7/120 =120/107+2
Rp = 120/107 =3,121
I7'=E2/Rt
=20/3,121=6,41 A
Ecd=I7'.Rp=6,41.120/107=7,2 V
I6'=Ecd/R5=7,2/6=1,2 A
I5'=I7'-I6'=6,41-1,2=5,21 A
I4'=Ecd/R4=7,2/8=0,9 A
I3'=I5'-I4'=5,21-0,9=4,31 A
I2'=Ecd/R2=7,2/6=1,2 A
I1'=I3'-I2'=4,31-1,2=3,11 A
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NAMA KELOMPOK:
PENGERTIAN:
Arus yang melalui atau tegangan pada sebuah elemen dalam sebuah jaringan linear dua arah yang memiliki beberapa sumber sama dengan jumlah aljabar arus atau tegangan yang dihasilkan secara terpisah oleh masing-masing sumber
Teorema Superposisi
LANGKAH PENYELESAIAN:
JAWAB:
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