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MALAYSIAN POLYTECHNIC MATHEMATICS , SCIENCE AND COMPUTER DEPARTMENT BB101 – ENGINEERING SCIENCE LAB REPORT 2
NAME
GROUP MEMBERS
MATRIX NO
SYAFINAZ BT YAHYA
16DKA 11F 1150
NURUL FATTAH MAIMUNAH BT LOKMAN HAKIM
16DKA 11F 1148
NUR FARLIYANA AZIRA BT NOOR AZHAR
16DKA11F 1152
NUR FAIRUZA SYAHIRA BT MOHD ISA
16DKA11 F 1151
NOR HAZWANI BT ZOHARI
16DKA11F 1162
RIFF SHAFIQ BIN ISMAIL
16DKA11F 1149
SYED SALAHUDDEAN AYUB BIN SYED BADRUL HISHAM
16DKA11F 1147
TITLE
PHYSICAL QUANTITIES AND MEASUREMENTS
LECTURER’S
EN.SHARUDDIN BIN HUSSAIN
NAME
23th AUGUST 2011
DATE OF SUBMISSION LECTURER’S COMMENTS
RUBRIC ITEM
MARKS 4
1.
Procedures
2.
Participation
3.
Diagrams
4.
Data
5.
Calculations
6.
Analysis
7.
Error Analysis
8.
Questions
9.
Conclusion
10.
Submission date TOTAL
3
2
1
LINEAR MOTION OBJECTIVE 1. To analyze linear motion of a moving object. 2. To determine displacement, velocity and acceleration is zero and non-uniform when acceleration is non zero.
INFERENCE 1. Linear motion is a motion along a straight line . 2. Velocity is speed in a given direction
HYPOTHESIS 1. Velocity is speed in a given direction. 2. Acceleration is the increase of velocity over a period of time. 3. Deceleration is the decrease of velocity over a period of time.
APPARATUS 1.
Ticker time
2. Runway and trolley
3. Power supply
4. Jumper Wire
5. Ruler
6. Lab Jack/ Clamp
Figure 1 PROCEDURES 1. The apparatus was set up as in figure 1. 2. The runway is inclined about 1m-2m,so the trolley was roll down freely from rest without any applied force. 3.
The ticker tape was attach to the trolley using cellophane tape.
4. The ticker timer was switch on and the trolley was release freely.
ANALYSING DATA 0
1 2
3
4
5
6
7
8
9
10
1. The 10 dot was mark and number as the figure above. 2. The ticker tape was cut and paste into 10-dot strips on the graph paper. Note : 1. Frequency of ticker – time is 50Hz. Therefore, 1 dot or 1 unit time represents 1/50 seconds or 0.02 second. 2. Time for 10 dots = 10 dots x 0.02 second = 0.2 seconds.
RESULT & CALCULATION 1
Number of 10-dot strips
2 3
Total time, =number of strips x 0.2 Total displacementof the trolley Length of runway
9 1.8s 1.485m
= 148.5cm100 = 1.485m
4
Average velocity of the trolley
0.325m/s
v= 5
Acceleration of the trolley a.Initial velocity
0.1115m/s
u=
b.Final velicity
0.725m/s
v=
c.Time for acceleration,t (number of strip-1) x(time for 10 dots) d.acceleration a=
1.6 s 0.3834m/
6
Average velocity
0.41825m/s
=
Question
1. Is there any difference in the value of average velocity between Result 4 and 6? The different between Result 4 and 6 is result 4 is a theory while result 6 is practical. Result 4 is theory because it shows the velocity of the experiment. While result 6 shows the average velocity.
CONCLUSION
Enable to determine the linear motion of a moving object.
Enable to determine displacement , velocity and acc eleration.
