LAPORAN TUGAS BESAR STRUKTUR BAJA II

LAPORAN TUGAS BESAR STRUKTUR BAJA II

1

TUGAS BESAR STRUKTUR BAJA II

FAKULTAS TEKNIK PERENCANAAN DAN DESAIN

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LAPORAN TUGAS BESAR STRUKTUR BAJA II A.

Perhitungan Sudut tanα

=

α

= 36,23˚

X2

= H2 +L2

X2

= 18,52+ 25,52

X

= 18,52+ 25,52

X2

= 31,3 meter

18,5 M

 25,25 M

B.

Perhitungan Panjang

X 18,5 M

 25,25 M

C.

Pembebanan pada Gording Baja Canal CNP 160. 65. 10,5. 7,5 h

= 160 mm

d

= 10.5 mm

A

= 24,0 cm2

Ix

= 925 cm4

Iy

= 85,3 cm4

ix

= 6,21cm

iy

= 1,89 cm

Wx

= 116 cm3

Wy

= 18,3 cm3

Berat

= 18,8 kg/m

I. Beban tetap i.

Beban mati Untukα= 36,23˚profil kanal yang digunakan baja kanal CNP 160. 65. 10,5. 7,5 Periksa kesetabilan penampang

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LAPORAN TUGAS BESAR STRUKTUR BAJA II Flans / Flange

√

=

√

…….OK!!!! Web

√

=

√ …….OK!!!! Beban atap (qat)

= BebanAtap (genteng) x JarakGording (i) = 6,5 kg/m2 x 0,8 m = 5,2 kg/m’

qatap

=

Berat sendiri (qbs)dari tabel kanal baja Berat mati(qbm)

= 18,8

=Beban atap + Beban sendiri =

+ 18,8

= 25,25 kg/m Beban aksesoris 15 %

= 15% x qbm = 15% x 25,25 = 3, 78 kg/m

qbmtotal

= qbm+ Bebana sesoris = 25,25 + 3,78 = 29,03kg/m

ii.

Beban hidup Beban orang (PH)

= 100 kg

Beban hujan (PH)

= W hujan x Luas daerah pembebanan = 20 kg/ m2 x jarak gording x jarak kuda- kuda = 20 x 0,8 x 7,4 = 118,4 kg

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LAPORAN TUGAS BESAR STRUKTUR BAJA II Beban hujan

Beban orang,maka yang digunakan beban hujan Pengaruh

kemiringan atap

Px

= PH x = 118,4 x = 69,97 kg/m

qx

= q bmx = 29,09 x = 17,16 kg/m

Py

= PH x = 118,4 x = 95,50 kg/m

qy

= q bmx = 29,09 x = 23,41 kg/m

Mmax = qx L2 + PX L Mbhx =

+

= 117,46 + 129,44 = 246,9 kg/m Mbhy = qyL2 + Py L =

+

=160,24 + 176,68 = 336,92 kg/m Periksa tegangan lentur =

=

4

=

= 290,44 kg/cm

=

= 1349,18 kg/cm



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LAPORAN TUGAS BESAR STRUKTUR BAJA II = √(

total

)

= √(

= 1380,08 iii.

( )

) (

)

1600 …..OK!!!!

Periksa tegangan geser VAX =

=

x qbmx x j + x Px x 17,16 x 7,4 + x 69,97

= 63,49 + 34,98 = 98,48 kg VAy =

=

x qbmy x j + x Py x 23,41 x 7,4 + x 95,50

= 68,62 + 47,75 = 134,37 kg x

totatotal

=

y

=

=

=

= 22,46 kg/m

= 28,16 kg/m

=√ =√ = 36,01 kg/m

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LAPORAN TUGAS BESAR STRUKTUR BAJA II = 0,6 x

ijin

= 0,6 x 1600 kg/m = 960 kg/m Maka iv.

36,01

960 …..OK!!!!

Periksa tengangan Huber Henky i

= =√ = 1381,49 kg/m

v.

1600 kg/m ….. OK !!!!!!

Periksa kekakuan lendutan pada gording =

X

= = 0,344 + 0,034 = 0,648 cm =

y

= = 5,102 + 4,5 = 9,602 cm total

=√

=√

6

= 9,624 cm



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II Lendutan Ijin Maka vi.

9,624

=

=

= 3,083

3,083 cm….. NOT OK !!!!!!

Desain Trekstang

=

= 380

Lendutan Ijin

X

=

=

= 1,583

=

= = 0,02 + 0,04 = 0,06 cm

y

=

= = 0,354 + 0,609 = 0,963 cm total

=√ =√ = 0,964

7

1,583 cm …..OK !!!!!!



TRAY OR COFFER

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LAPORAN TUGAS BESAR STRUKTUR BAJA II II. Beban sementara C

)– 0,4

= (0,02 x

= (0,02 x 36,23)-0,4 qangin

= 0,324

= Wangin x C x i = 45 x 0,324s x

= 14,48 Mangin

= x qangin x j2 = x 14,48 x 7,42 = 99.11

qay = qangin = 14,48 qax

=0

Max

=0

May

= 99.11

i. Bentuk kekuatan lentur akibat beban sementara X

=

y

=

= 290,44 + 0 = 290,44

=

= 1350, 034

Periksa kelenturan p =√ =√ = 1380,922

8

1600 cm …..OK !!!!!!



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II ii. Periksa kekuatan geser akibat bebabn sementara VAX =

x qbmx x l + x Px + x qax x l

= x 23,41 x 7,4 + x 69,97 + x 0 x 7,4 = 63,49 + 34,98 + 0 = 98,48 kg VAy =

x qbmy x j + x Py + + x qay x l

= x 23,41 x 7,4 + x 95,50 + x 14,48 x 7,4 = 68,62 + 47,75 + 53,576 = 187,943 kg =

x

y

=

=

= = 53,76 kg/m

= 16,4 kg/m =√ =√ = 56,205 kg/m ijin

= 0,6 x = 0,6 x 1600 kg/m = 960 kg/m

Maka

9

56,205

960 …..OK!!!!



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TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II iii. Periksa idiil i

=√

x 1,25

=√ = 1384,34 kg/m

1600 x 1,25 2000 kg/m ….. OK !!!!!!

“Jadi Gording profil yang digunakan adalah baja kanal CNP 160. 65. 10,5. 7,5”

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LAPORAN TUGAS BESAR STRUKTUR BAJA II PEMBEBANAN PADA KUDA – KUDA

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LAPORAN TUGAS BESAR STRUKTUR BAJA II A. BebanMati I.

BebanAtap





BebanMatiqatap= Watapx j

qtotal

= 6,5 x 7,4 = 48,1 

qa

BebanAsesoris (15%) = 7,22

= 48,1+7,22

⁄

= 55,32

=

= = 68, 37

⁄

Pa1 = qax ( a )

= 68, 37 x

(8)

= 273,28

⁄

Pa2 = qax ( a+b )

= 68, 37 x

( 8+8 )

= 546,96

⁄

Pa3 = qax ( b+c )

= 68, 37 x

( 8+4 )

= 410,22

⁄

Pa4 = qax ( c+d )

= 68, 37 x

( 4+5,25 )

= 316,21

⁄

Pa5 = qax ( d+e )

= 68, 37 x

( 5,25+11,75 )

= 581,15

⁄

Pa6 = qax ( e+f )

= 68, 37 x

( 11,75+4 )

= 538,41

⁄

Pa7 = qax ( f+g )

= 68, 37 x

( 4+9,5 )

= 461,49

⁄

Pa8 = qax ( g )

= 68, 37 x

( 9,5 )

= 324,75

⁄

12

⁄



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TEKNIK SIPIL '22

⁄

LAPORAN TUGAS BESAR STRUKTUR BAJA II II.

BebanHidup Beban Orang = 100 kg BebanHujan

= Whujanx Jarakgording x jarakKuda-kuda = 20 x 0,4 x 7,4 = 118,4 kg

PH1 = 118,4 x

8

= 473,6

⁄

PH 2 = 118,4 x

( 8+8 )

= 947,2

⁄

PH 3 = 118,4 x

( 8+4 )

= 710,4

⁄

PH 4= 118,4 x

( 4+5,25 )

= 547,6

⁄

PH 5 = 118,4 x

( 5,25+11,75 )

= 1006,4

PH 6 = 118,4 x

( 11,75+4 )

= 932,4

⁄

PH 7 = 118,4 x

( 4+9,5 )

= 799,2

⁄

PH 8 = 118,4 x

( 9,5 )

= 562,4

⁄

13

⁄



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II III.

BeratGording G

= qgordingx j = 18,8 x 7,4 = 139,12 kg

14

PG1 = 6,5 x G

= 6,5 x 139,12

= 904,28 kg

PG2 = 6,5 x G + 6 x G

= 12,5 x 139,12

= 1739 kg

PG3 = 6 x G +3 x G

= 9 x 139,12

= 1252,08 kg

PG4 = 3 x G +4 x G

= 7 x 139,12

= 973,84 kg

PG5 = 4 x G +9 x G

= 13 x 139,12

= 1808,56 kg

PG6 = 3 x G +9 x G

= 12 x 139,12

= 1669,44 kg

PG7 = 3 x G +7,5 x G

= 10,5 x 139,12

= 1460,79 kg

PG8 = 7,5 x G

= 7,5 x 139,12

= 904,28 kg



TRAY OR COFFER

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LAPORAN TUGAS BESAR STRUKTUR BAJA II IV. BeratSendiri Kuda - Kuda

NO. BATANG

PANJANG (m)

NO. BATANG

PANJANG (M)

S1

9,92

S14

8,00

S2

9,92

S15

5,86

S3

4,96

S16

9,92

S4

6,51

S17

11,72

S5

14,57

S18

10,75

S6

4,96

S19

12,90

S7

11,78

S20

13,93

S8

9,50

S21

16,75

S9

4,37

S22

14,29

S10

11,75

S23

8,14

S11

5,25

S24

6,57

S12

4,37

S25

6,96

S13

8,00

=

15



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231,65

LAPORAN TUGAS BESAR STRUKTUR BAJA II Rangka Kuda-Kuda Anak ( batang S5, L = 14,57 M )

NO. BATANG a1 a2 a3 a4 a5 a6 a7 a8 a9 a10 a11 a12 a13

PANJANG (m) 3,85 3,85 3,85 3,85 -

=

16

1,25 4,42 2,50 4,42 1,25 29,24



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NO. BATANG a1 a2 a3 a4 a5 a6 a7 a8 a9 a10 a11 a12 a13

PANJANG (m) 3,31 3,31 3,31 3,31 -

=

0,75 3,31 1,50 3,31 0,75 22,86

Rangka Kuda-Kuda Anak ( batang S20, L = 13,93 M )

NO. BATANG a1 a2 a3 a4 a5 a6 a7 a8 a9 a10 a11 a12 a13 =

17



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PANJANG (m) 3,56 3,56 3,56 3,56 0,75 3,56 1,50 3,56 0,75 24,36



18

PANJANG (m) 4,37 4,37 4,37 4,37 1,25 4,88 2,50 4,88 1,25 32,24



TRAY OR COFFER

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19

PANJANG (m) 3,79 3,79 3,79 3,79 1,25 4,36 2,50 4,36 1,25 28,88



TRAY OR COFFER

TEKNIK SIPIL '22


S

5

S21

S19

S2 0



S

22

Menentukan Profil Rangka Kuda-Kuda Utama    

m

S7 = 11,78 m (Terpanjang)

Profil siku 200.200.18 ix = 6,13 6,13 ≥ 5,89  ok…!!!! 

Struktur Utama Panjang total

= 231,65 x 2

= 463,3 m

Berat total

= 463,3 x 54,3

= 25157,19 kg

20



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LAPORAN TUGAS BESAR STRUKTUR BAJA II Qbs

=

= = 498.162 kg Asesoris (15 %)

= 498.162 x 15 % = 74,72 kg

Qbs

= 498.162 + 74,72

= 572,88 kg Pbs1 = 572,88 x

8

= 2291,52

⁄

Pbs2 = 572,88 x

x ( 8+8 )

= 4583,04

⁄

Pbs3 = 572,88 x

x ( 8+4 )

= 3437,28

⁄

Pbs4= 572,88 x

x ( 4+5,25 )

= 2649,57

⁄

Pbs5 = 572,88 x

x ( 5,25+11,75 )

= 4869,48

⁄

Pbs6 = 572,88 x

( 11,75+4 )

= 4511,43

⁄

Pbs7 = 572,88 x

( 4+9,5 )

= 3866,94

⁄

Pbs8 = 572,88 x

( 9,5 )

= 2721,18

⁄

21



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II 

Menentukan Profil Rangka Kuda-Kuda Anak

2.44 ≤ ix Gunakan Profil Siku 90.90.13

S5

2.44 ≤ 2.69 …. Ok!!!

= Panjang total x Berat sendiri profil x 2 = 29,24 x 17.1x 2

= 1000 kg

Berat Asesoris (15 %)

= 1000 x 15 % = 150 kg

Total

= 1000 + 150 = 1150 kg

S19

= Panjang total x Berat sendiri profil x 2 = 22,86 x 17,1 x 2

= 781,812 kg


= 781,812 x 15 %

= 117,27 kg

Total

= 781,812 + 117,27

= 899,083 kg

S20


= 833,112 kg


= 833,112 x 15 %

= 124,966 kg

Total

= 833,112 + 124,966 = 958,078 kg

S21


= 1102,608 kg


= 1102,608 x 15 %

= 165,391 kg

Total

= 1102,608 + 165,391 = 1267,99 kg

S22


= 987,696 kg


= 987,696 x 15 %

= 148,154 kg

Total

= 987,696 + 148,154 = 1135,850 kg

22



TRAY OR COFFER

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LAPORAN TUGAS BESAR STRUKTUR BAJA II qbx4

= Berat total (S19 +S20) = 899,083 + 958,078 = 1857,161 kg

qbx5

= Berat total (S5 +S20+S21+S22) = + 958,078 + 1267,99 + 1135,8504 = 4511,9184 kg

qbx6

= Berat total (S5 +S22) = 1150 + 1135,8504 = 2285,8504 kg

Pbs1

= 2291,52

⁄

Pbs2

= 4583,04

⁄

Pbs3

= 3437,28

⁄

Pbs4

= 2649,57 +

( 1857,161 ) = 3578,1505

Pbs5

= 4869,48 +

( 4511,9184 ) = 7125,439

Pbs6

= 4511,43 +

( 2285,8504) = 5654,3552

Pbs7

= 3866,94

⁄

Pbs8

= 2721,18

⁄

23

⁄ ⁄ ⁄



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LAPORAN TUGAS BESAR STRUKTUR BAJA II B. BebanSementara I. P. AnginKiri B E B A N A K IB A T A N G IN K IR I



MukaAngin

qangin

= Wanginx j x c

c

= ( 0,02 x

= ( 0,02 x 36,23 ) – 0,14

= 45 x 7,4 x 0,3246 = 108,092 Pag1 = qanginx ( a )

Pag2 = qanginx

) – 0,14

⁄

= 0,3246

= 108,092 x

( a+b ) = 108,092 x

= 536,136

⁄

( 9,92+9,92 ) = 1072,27

⁄

( 9,92 )

Pag3 = qanginx ( b+c ) = 108,092 x

( 9,92+4,96 ) = 804,20

⁄

Pag4 = qanginx ( c+d ) = 108,092 x

( 4,96+6,51 ) = 887,98

⁄

Pag5 = qanginx ( d )

( 6,51)

⁄

24

= 108,092 x

= 351.84



TRAY OR COFFER

TEKNIK SIPIL '22


MukaAngin

qangin

= Wanginx j x c = 45 x 7,4 x 0,4 = 133,2

⁄ ⁄

Pag5’ = qanginx ( e )

= 133,2 x

( 14,57 )

= 970,362

Pag6 = qanginx

= 133,2 x

( 14,57+4,96 )

= 1300,698

⁄

Pag7 = qanginx ( f+g )

= 133,2 x

( 4,96+11,78 )

= 1114,884

⁄

Pag8 = qanginx ( g )

= 133,2 x

( 11,78 )

= 784,548

( e+f )

II. P. AnginKanan B E B A N A K IB A T A N G IN K A N A N

25



TRAY OR COFFER

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⁄


MukaAngin

qangin

= Wanginx j x c = 45 x 7,4 x 0,3246 ⁄

= 108,092 Pag8 = qanginx ( g )

= 108,092 x

( 11,78 )

= 636,66

Pag7 = qanginx ( g+f ) = 108,092 x

( 11,78+4,96 ) = 904,730

Pag6 = qanginx

( 4,96+14,57 ) =1055,518

( f+e ) = 108,092 x

Pag5' = qanginx ( e ) 

= 108,092 x

( 14,57 )

⁄

⁄

= 787,450

MukaAngin

qangin

= Wanginx j x c = 45 x 7,4 x 0,4 = 133,2

⁄

Pag5 = qanginx ( d )

= 108,092 x

( 6,51)

= 433,566

⁄

Pag4 = qanginx ( d+c )

= 108,092 x

( 6,51+4,96)

= 763,902

⁄

Pag3 = qanginx ( c+b )

= 108,092 x

( 4,96+9,92 ) = 991,008

⁄

Pag2 = qanginx

= 108,092 x

( 9,92+9,92 ) = 1321,344

= 108,092 x

( 9,92 )

( b+a )

Pag1 = qanginx ( a )

26

⁄

= 660,672



TRAY OR COFFER

TEKNIK SIPIL '22

⁄

⁄

⁄


TABEL KOMBINASI PEMBEBANAN PADA STRUKTUR RANGKA KUDA-KUDA No. Batang

COMB1 (Kg) Tarik

Tekan

COMB2 (Kg) Tarik

Tekan

BATANG YANG DIPILIH (Ton)

COMB3 (Kg) Tarik

Tekan

Tarik

Tekan

S1

-38356,45

-38282,26

-37527,88

38,36

S2

-31743,95

-31330,91

-31332,95

31,74

S3

-32314,54

-32386,9

-31354,95

32,38

S4

-26303,14

-25909,39

-25906,53

26,30

S5

-26303,14

-26877,89

-25012,16

26,88

S6

-41782,47

-41129,67

-41405,16

41,78

S7

-37693,02

-37033,48

-37481,66

37,69

S8

30405,41

30336,95

29858,73

30,41

S9

33187,97

33113,25

32591,27

33,19

S10

33704,2

34299,92

32489,09

34,30

S11

26066,81

29163,55

22585,5

29,16

S12

27949,94

31421,35

23993,91

31,42

S13

30940,57

35027,84

26198,66

35,03

S14

30940,57

35027,84

26198,66

35,03

S15

4583,04

4583,04

4583,04

4,58

S16

-6612,5

-7736,77

-5227,07

7,74

S17

-3857,48

-4584,42

-3090,65

4,58

S18

1236,42

1011,78

1620,62

1,62

S19

13633,46

15233,36

11691,22

15,23

S20

-12866,99

S21

27695,11

S22

-14836,56 28300,9

-15190,81

-10464,27 26412,33

-13051,16

14,84 28,30

-16846,19

16,85

S23

14659,71

13764,6

15291,25

15,29

S24

5417,22

6507,93

4319,52

6,51

S25

-9435,43

27

-9405,47

-9196,26



TRAY OR COFFER

TEKNIK SIPIL '22

9,44

LAPORAN TUGAS BESAR STRUKTUR BAJA II I.

Desain Batang Tarik Dipilih Profil 2L 200. 200. 18 W

= 54,30 x 2

= 108.60 kg/m

Ab

= 69,10 x 2

= 138,20 cm2

Ixo

= Iyo

= 2600 cm4

ixo

= iyo

= 6,13 cm

a

= 2ey + t = 2 x (5,6) + 1,9 = 13,1 ijin



= 1600 kg/ cm2

Analisa kelangsingan batang tarik Batang tarik terpanjang : 11,75 m (S10) ix

= ixo = 6,13 cm

Iy

=√ =√ = 14,373 cm4

λ

= = = 191.68 < 200 …. Ok !!!



Luas penampang efektif profil An

= 0,85 x Ab = 0,85 x 138,20 = 117,47 cm2

Analisa kekuatan batang tarik Batang tarik dengan gaya tarik maksimum adalah : 35,03 σtr

= = = 149,1 < 1600 …. Ok !!!

28



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II II.

Desain Batang Tarik 

Analisa kelangsingan batang tekan majemuk Batang tekan yang terpanjang : 11,78 m (S7) Desain tekuk terhadap sumbu bahan ix

= ixo = 6,13 cm = 14,373 cm4

λx

= = = 192,17 < 200 …. Ok !!!

Desain terhadap batang tekuk ix

= ixo = 6,13 cm

Iy

=√ =√ = 14,373 cm4

λy

= = = 81,96< 200 …. Ok !!!

λw

=√ =√

m

=2

Desain optimim ( λw ≤ λx ) λx2

= λy2 + λ12

λ12

= λx2 - λy2 = 36929,18 – 6717,52

λ1

= = 173,82 cm

λ1

29

=

>> i1= in

= 2.93 cm



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II = λ1 x i1

L1

= 173,82 x 2.93 = 509,28 cm Jumlah medan n

L1

=

= =

= = 2,31 λ1

= 392,67 cm (jarak kopel)

3 buah

= =

= 134,02 Periksa kelangsingan terhadap sumbu bebas bahan λw



=√

λx

=

192,17

= 156,825

192,17 …..Ok!!!

Periksa kekuatan batang tekan Batang tekan dengan gaya maksimum : 41,78 ton λc

=

x√

= w

x√

= 1,69

1,20

maka w = 1,25

= 1,25 λc² = 1,25 x 1,692 = 3,56

tekan = = = 538,64 < 1600 ….Ok!!!

30



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II III.

Desain plat koppel Gaya tekan maksimum = 41,78 ton Menggunakan Profil 2L 200. 200. 18 a

= 13

L1

= 392,67

I1

= 2600

 Syarat kekakuan plat koppel 10

Ikoppel = 1/12 x t h3 Maka, 1/12 x t h3

10 x

t h3

10 x

t h3

10408,83

xa x 13,1 x 12

Dicoba plat Koppel tebal : 0,64 cm t h3

10408,83

h3 h3

16263,79

h

25,34

b

28 cm

= (15x2) + 1.9 = 31,9 cm

Ukuran pelat koppel : 

31.90 x 28 x 0,64

Periksa kekuatan plat koppel L

= 2% x 41780 = 835,60 kg

Atau L

31

=

x 41780

=

x 41780 = 1861,01 kg

digunakan L terbesar 1861,01 kg



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II T

= = = 55783,09 kg

Sy

= A1 x 1/2 a = 42,74 x 6,5 = 277,81 cm2

Iy

= 2 (Iyo) + 2A(1/2 a)2 = 2 x 2600 + 85,48 x 43 = 8867,31 cm4

T

=

x

=

x

= 91,80

<

Tijin

<

0,6 x σijin

<

960 ….Ok!!!!

Jadi ukuran plat koppel b = 31.90 ; h = 28 ; t = 0.64 dapat dipakai Jumlah Koppel

= 3 buah

Jarak Koppel

= 392,67 cm

32



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II Tabel Perhitungan Las NO BTNG

SUDUT

30.41

8

34.3

10 11

0

35.03

14 34.72

31.74

2

32.38 36.23 26.3

4

33.19

9

31.42

12 24

52.49

4.58

17

15.23 90 28.3

21

15.29

23

9.44

25 18

1.62 111.86 14.84

20

26.88

5 6 7 16

33

6.51 4.58

15

19

16.85 38.36

1

3

29.16 35.03

13

22

GAYA BTNG

41.78 143.77 37.69 7.74

P BAR

A

a

ln

lbr

lbr total

7.60

0.0082

1.27

0.0065

3.82

4.00

8.58

0.0093

1.27

0.0073

3.82

4.00

7.29

0.0079

1.27

0.0062

3.82

4.00

8.76

0.0095

1.27

0.0075

3.82

4.00

8.76

0.0095

1.27

0.0075

3.82

4.00

4.21

0.0040

1.27

0.0032

3.81

4.00

9.59

0.0091

1.27

0.0072

3.82

4.00

7.94

0.0075

1.27

0.0059

3.82

4.00

8.10

0.0077

1.27

0.0061

3.82

4.00

6.58

0.0062

1.27

0.0049

3.81

4.00

8.30

0.0079

1.27

0.0062

3.82

4.00

7.86

0.0075

1.27

0.0059

3.82

4.00

1.63

0.0013

1.27

0.0011

3.81

4.00

1.15

0.0007

1.27

0.0006

3.81

4.00

1.15

0.0007

1.27

0.0006

3.81

4.00

3.81

0.0036

1.27

0.0028

3.81

4.00

7.08

0.0044

1.27

0.0035

3.81

4.00

3.82

0.0024

1.27

0.0019

3.81

4.00

2.36

0.0015

1.27

0.0012

3.81

4.00

0.41

0.0003

1.27

0.0002

3.81

4.00

3.71

0.0026

1.27

0.0021

3.81

4.00

6.72

0.0064

1.27

0.0050

3.82

4.00

10.45

0.0099

1.27

0.0078

3.82

4.00

9.42

0.0090

1.27

0.0070

3.82

4.00

1.94

0.0018

1.27

0.0014

3.81

4.00



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II Perhitungan las 

Batang S1 

α = 36.23˚

Batang S2 α = 36.23˚

p p

=

= 9,59 cm p

=

p

=

= 7,94 cm

=

A = A = =

√

=

√

=0,0091 profil

200. 200. 18

=0,0075 profil

a

=

=

= 1,27 cm a

ln = lbr

=

200. 200. 18

=

=

ln =

=

= 0,0072 cm = 0,0059 cm

= ln + 3 x a lbr = ln + 3 x a

= 0,0072 + 3 x 1,27 =3,82 cm

= 0,0059 + 3 x 1,27

4 cm

=3,82 cm

34

= 1,27 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN ASISTENSI TUGAS BESAR STRUKTUR BAJA II 



Batang S3

Batang S4

α = 36.23˚

α = 36.23˚

p

=

p

=

p

=

p

=

= 8,10 cm

A =

=

A = √

=

=0,0077 profil a

lbr

200. 200. 18

=

√

=0,0062 profil

= 1,82 = 1,27 cm

ln =

= 6,58 cm

a

200. 200. 18

=

=

= 1,27 cm

ln =

=

lbr

= ln + 3 x a

= = 0,0061 cm = 0,0049 cm

= ln + 3 x a = 0,0061 + 3 x 1,27 = 0,0049 + 3 x 1,27 =3,82 cm

4 cm =3,81 cm

35



TRAY OR COFFER

TEKNIK SIPIL '22

4 cm




Batang S5

Batang S6

α = 143,77 ˚

α = 143,77 ˚

p

=

p

=

p

=

p

=

= 6,72 cm

A =

=

A = √

=

=0,0064 profil a

√

=0,0099 200. 200. 18

profil

= 1,27 cm

a

=

=

ln =

=

lbr

= ln + 3 x a

36

= 10,45cm

= 0,0050cm

200. 200. 18

=

=

= 1,27 cm

ln =

=

lbr

= ln + 3 x a

= 0,0078 cm

= 0,0050 + 3 x 1,27

= 0,0078 + 3 x 1,27

=3,82 cm

=3,82 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22

4 cm




Batang S7

Batang S8

α = 143,77 ˚

α = 0˚

p

=

p

=

p

=

p

=

= 9,42 cm

A =

=

A = √

= =0,0082

=0,0090 profil a

profil

200. 200. 18

=

=

ln =

=

a

= 1,27 cm

= 0,0070cm

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,0065 cm

lbr = ln + 3 x a

lbr = ln + 3 x a

37

= 7,60 cm

= 0,0070 + 3 x 1,27

= 0,0065 + 3 x 1,27

=3,82 cm

=3,82 cm

4 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22




Batang S9

Batang S10

α = 36,23˚

α = 0˚

p

=

p

=

p

=

p

=

= 8,30 cm

A =

=

A = √

= =0,0093

=0,0079 profil a

=

=

ln =

=

200. 200. 18

profil

= 1,27 cm

a

= 0,0062 cm

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,0073 cm

lbr = ln + 3 x a

lbr = ln + 3 x a

38

= 8,58 cm

= 0,0062 + 3 x 1,27

= 0,0073 + 3 x 1,27

=3,82 cm

=3,82 cm

4 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22




Batang S11 α = 0˚ p

=

p

=

Batang S12 α = 36,23˚

= 7,29 cm

p

=

p

=

A =

A =

=

= =0,0079

profil a

=

=

ln =

=

√

=0,0075 200. 200. 18

profil

= 1,27 cm

a

= 0,0062 cm

lbr = ln + 3 x a

39

= 7,86 cm

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,0059 cm

lbr = ln + 3 x a

= 0,0062 + 3 x 1,27

= 0,0059 + 3 x 1,27

=3,82 cm

=3,82 cm

4 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22





=

p

=

Batang S14 α = 0˚

= 8,76 cm

p

=

p

=

= 8,76 cm

A =

A =

=

=

=0,0095

=0,0095

profil a

=

=

ln =

=

200. 200. 18

profil

= 1,27 cm

a

= 0,0075 cm

lbr = ln + 3 x a

40

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,0075 cm

lbr = ln + 3 x a

= 0,0075 + 3 x 1,27

= 0,0075 + 3 x 1,27

=3,82 cm

=3,82 cm

4 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22





=

p

=

Batang S16 α = 143,77 ˚

= 1,15 cm

p

=

p

=

A =

A =

=

=

=0,0007 profil a

=

=

ln =

=

= 1,94 cm

√

=0,0018 200. 200. 18

profil

= 1,27 cm

a

= 0,0006 cm

lbr = ln + 3 x a

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,0014 cm

lbr = ln + 3 x a

= 0,0006 + 3 x 1,27

= 0,0014 + 3 x 1,27

=3,81 cm

=3,81 cm

4 cm

4 cm

\

41



TRAY OR COFFER

TEKNIK SIPIL '22





=

p

=

Batang S18 α = 111,86˚

= 1,15 cm

p

=

p

=

A =

A =

=

=

=0,0007 profil a

=

=

ln =

=

√

=0,0003 200. 200. 18

profil

= 1,27 cm

a

= 0,0006 cm

lbr = ln + 3 x a

42

= 0,4 cm

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,0002 cm

lbr = ln + 3 x a

= 0,0006 + 3 x 1,27

= 0,0002 + 3 x 1,27

=3,81 cm

=3,81 cm

4 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22





=

p

=

Batang S20 α = 112,14˚

= 3,81 cm

p

=

p

=

= 3,71 cm

A =

A =

=

=

=0,0036

=0,0026

profil a

=

=

ln =

=

200. 200. 18

profil

= 1,27 cm

a

= 0,0028 cm

lbr = ln + 3 x a

43

√

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,00021 cm

lbr = ln + 3 x a

= 0,0028 + 3 x 1,27

= 0,0021 + 3 x 1,27

=3,81 cm

=3,81 cm

4 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22





=

p

=

Batang S22 α = 34,72˚

= 7,08 cm

p

=

p

=

A =

A =

=

=

=0,0044 profil a

=

=

ln =

=

√

=0,0040 200. 200. 18

profil

= 1,27 cm

a

= 0,0035cm

lbr = ln + 3 x a

44

= 4,21cm

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,00032 cm

lbr = ln + 3 x a

= 0,0035+ 3 x 1,27

= 0,0032 + 3 x 1,27

=3,81 cm

=3,81 cm

4 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22





=

p

=

Batang S24 α = 52,49˚

= 3,82 cm

p

=

p

=

= 1,61 cm

A =

A =

=

=

=0,0024

=0,0013

profil a

=

=

ln =

=

200. 200. 18

profil

= 1,27 cm

a

= 0,0019cm

lbr = ln + 3 x a

45

√

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,00011 cm

lbr = ln + 3 x a

= 0,0019 + 3 x 1,27

= 0,0011 + 3 x 1,27

=3,81 cm

=3,81 cm

4 cm

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22



=

p

=

= 2,36 cm

A =

= =0,0015 profil a

200. 200. 18

=

=

ln =

=

= 1,27 cm

= 0,0012 cm

lbr = ln + 3 x a = 0,0012 + 3 x 1,27 =3,81 cm

46

4 cm



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN ASISTENSI TUGAS BESAR STRUKTUR BAJA II

47



TRAY OR COFFER

TEKNIK SIPIL '22


48



TRAY OR COFFER

TEKNIK SIPIL '22


49



TRAY OR COFFER

TEKNIK SIPIL '22


50



TRAY OR COFFER

TEKNIK SIPIL '22


51



TRAY OR COFFER

TEKNIK SIPIL '22


52



TRAY OR COFFER

TEKNIK SIPIL '22


53



TRAY OR COFFER

TEKNIK SIPIL '22


54



TRAY OR COFFER

TEKNIK SIPIL '22


55



TRAY OR COFFER

TEKNIK SIPIL '22

LAPORAN TUGAS BESAR STRUKTUR BAJA II

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