IP Addressing and Subnetting - Instructors Workbook

1 0 0 1 1 0 0 0

01 1010100

10001111100

1011100101011100 101100011101001

1011110100011010

00001010010110010 1001010101100111 1111010101000101 1101001101010011 001010010101010

1010101000110010 010101001011000 110101100011010 11010100001011 001010100110 1001010010

IP Addressing and Subnetting Workbook Version 1.1

Instructor’s Edition

11111110 10010101

00011011

11010011

10000110

IP Address Classes Class A

1 – 127

(Network 127 is reserved for loopback and internal testing) 00000000.00000000.00000000.00000000 Leading bit pattern 0 Network . Host . Host . Host

Class B

128 – 191

Leading bit pattern

10

10000000.00000000.00000000.00000000

Class C

192 – 223

Leading bit pattern

110

11000000.00000000.00000000.00000000

Class D

224 – 239

(Reserved for multicast)

Class E

240 – 255

(Reserved for experimental, used for research)

Network .

Network .

Network .

Network

Private Address Space Class A

10.0.0.0 to to 10 10.255.255.255

Class B

172.16.0.0 to 172.31.255.255

Class C

192.168.0.0 to 192.168.255.255

Default Subnet Masks Class A

255.0.0.0

Class B

255.255.0.0

Class C

255.255.255.0

Produced by: Robb Jones jonesr@ca jonesr@career reertech. tech.net net Frederick County Career & Technology Center Cisco Networking Academy Frederick County Public Schools Frederick, Maryland, USA Special Thanks to Melvin Baker and Jim Dorsch for taking the time to check this workbook for errors. Inside Cover

Host

. Network

.

.

Host

Host

Binary To Decimal Conversion 128 6 4

32

16

8

4

2

1

1

0

0

1

0

0

1

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0

1

1

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1

1

1

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1

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1

1

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Answers

146 119 255 197 246 19 129 49

11101101

120 240 59 7 27 170 111 248 32 85 62 3 237

11000000

192

00011011 10101010 01101111 11111000 00100000 01010101 00111110 00000011

Scratch Area

128 16 2 146

64 32 16 4 2 1 119

1

Decimal To Binary Conversion Use all 8 bits for each problem

128 64

32

16

8

4

2

1 = 255

1 1 1 0 1 1 1 0 0 0 1 0 0 _________________ 0 1 0 _________________________________________ ________________________

_________________________________________ _________________________ ________________ 238

0 1 1 1 1 0 1 1 0 0 1 1 0 _________________ 0 1 0 _________________________________________ ________________________ 1 1 1 1 1 ________________ 1 1 1 _________________________________________ _________________________ 1 1 0 0 1 ________________ 0 0 0 _________________________________________ _________________________ 0 0 0 0 1 _________________ 0 1 0 _________________________________________ ________________________ 1 0 0 0 1 ________________ 0 1 0 _________________________________________ _________________________ 0 0 0 0 0__________________ 0 0 1 _________________________________________ _______________________ 0 0 0 0 1 _________________ 1 0 1 _________________________________________ ________________________ 1 1 1 1 1 ________________ 0 1 0 _________________________________________ _________________________ 0 1 1 0 1 ________________ 0 1 1 _________________________________________ _________________________ 1 1 1 0 0 ________________ 0 0 0 _________________________________________ _________________________ 0 1 1 1 0__________________ 0 1 0 _________________________________________ _______________________ 1 1 0 0 0 ________________ 0 0 0 _________________________________________ _________________________ 1 0 1 0 1 ________________ 1 0 0 _________________________________________ _________________________ 0 1 1 0 0 ________________ 1 0 0 _________________________________________ _________________________ 0 1 1 1 0__________________ 1 1 1 _________________________________________ _______________________ 0 0 1 1 1 _________________ 0 0 1 _________________________________________ ________________________ 0 1 1 0 0 _________________ 0 1 0 _________________________________________ ________________________ 1 0 1 1 0 ________________ 0 1 1 _________________________________________ _________________________ 0 0 0 0 0__________________ 0 1 0 _________________________________________ _______________________

34

_________________________________________ _________________________ ________________ 123

2

50 255 200 10 138 1 13 250 107 224 114 192 172 100 119 57 98 179 2

Scrat ch Area

238 34 -128 -32 110 2 -64 -2 46 0 -32 14 -8 6 -4 2 -2 0

Address Class Identification

Ad Address

1 0.2 5 0.1 .1 1 5 0 .10 .1 5 .0 1 92 .1 4.2 .0 1 48 .1 7.9 .1 1 93 .4 2.1 .1 1 2 6 .8. 15 6 .0 2 2 0 .2 00 .2 3 .1 2 3 0 .2 3 0 .4 5 .5 8 1 7 7 .1 00 .1 8 .4 11 9 .1 8 . 4 5 .0 2 4 9 .2 4 0 .8 0 .7 8 1 9 9 .1 5 5 .7 7 .5 6 11 7 . 8 9 .5 6 . 4 5 2 1 5 .45 .4 5 .0 1 9 9 .2 00 .1 5 .0 9 5.0 .2 1.9 0 3 3 .0 .0 .0 1 5 8 .98 .8 0 .0 2 1 9 .21 .5 6 .0

Cl a s s

A _ _B ___ _ _C ___ _ _B ___ _ _C ___ _ _A_ _ _ _ _C ___ _ _D ___ _ _B ___ _ _A_ _ _ _ _E ___ _ _C ___ _ _A_ _ _ _ _C ___ _ _C ___ _ _A_ _ _ _ _A_ _ _ _ _B ___ _ _C ___ _____

3

Network & Host Identification Circle the network portion of these addresses:

Circle the host portion of these addresses:

177.100.18.4

10.15.123.50

119.18.45.0

171.2.199.31

209.240.80.78

198.125.87.177

199.155.77.56

223.250.200.222

117.89.56.45

17.45.222.45

215.45.45.0

126.201.54.231

192.200.15.0

191.41.35.112

95.0.21.90

155.25.169.227

33.0.0.0

192.15.155.2

158.98.80.0

123.102.45.254

217.21.56.0

148.17.9.155

10.250.1.1

100.25.1.1

150.10.15.0

195.0.21.98

192.14.2.0

25.250.135.46

148.17.9.1

171.102.77.77

193.42.1.1

55.250.5.5

126.8.156.0

218.155.230.14

220.200.23.1

10.250.1.1

4

Default Subnet Masks Write the correct default subnet mask for each of the following addresses:

1 7 7 .1 00 .1 8 .4 11 9 . 1 8 . 4 5 . 0 191. 191.24 249. 9.2 234. 34. 191 2 23 .2 3.2 23 .1 09 1 0 .1 0. 25 0 .1 1 2 6 .1 23 .2 3 .1 2 23 .6 9.2 30 .2 50 1 92 .1 2.3 5.1 0 5 7 7.2 5 1.2 00 .5 1 1 8 9 .2 10 .5 0 .1 8 8 .4 5. 65 .3 5 128. 128.21 212. 2.2 250. 50. 254 1 93 .10 0 .77 .83 1 25 .12 5 .25 0.1 1 .1 . 1 0 . 5 0 2 20 .90 .1 30 .45 1 3 4 .1 25 .3 4 .9 9 5 .2 5 0. 91 .9 9

255 . 255 . 0 . 0

_ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ _ _ __ _ _ _ _ _ _ __

255 . 0 . 0 . 0 255 ._255 0___ .0 ____ ______ __ _____ _____ ___ ______ ___. ____ __ ____ ______ ___ 255 _ _ _ _255 _ _ _ _ _._ _ _ _ _ _ _._255 _ _ _ _ _ _. _0 _ __ __ . _0________ _ _ _ _ _ _ _255 _ _ _ _ _ _. _0 _ _._0 ___ _ _ _ _ _ _255 _ _ _ _ _._255 _ _ _ _ _ _. _0 _ _._0 _______ 255 _ _ _ _255 _ _ _ _ _._ _ _ _ _ _ _._255 _ _ _ _ _ _. _0 _ __ __ 255 _ _ _ _255 _ _ _ _ _._ _ _ _ _ _ _._255 _ _ _ _ _ _. _0 _ _ ___ . _0________ _ _ _ _ _ _ _255 _ _ _ _ _ _. _0 _ _._0 _ __ _ _ _ _ _ _255 _ _ _ _ _._255 _ _ _ _ _ _. _0 _ _._0 _______ . _0________ _ _ _ _ _ _ _255 _ _ _ _ _ _. _0 _ _._0 ___ 255 ._255 0___ .0 ____ ______ __ _____ _____ ___ ______ ___. ____ __ ____ ______ ___ 255 _ _ _ _255 _ _ _ _ _._ _ _ _ _ _ _._255 _ _ _ _ _ _. _0 _ __ __ . _0________ _ _ _ _ _ _ _255 _ _ _ _ _ _. _0 _ _._0 __ _ . _0________ _ _ _ _ _ _ _255 _ _ _ _ _ _. _0 _ _._0 ___ 255 _ _ _ _255 _ _ _ _ _._ _ _ _ _ _ _._255 _ _ _ _ _ _. _0 _ __ __ _ _ _ _ _ _255 _ _ _ _ _._255 _ _ _ _ _ _. _0 _ _._0 _______ . _0________ _ _ _ _ _ _ _255 _ _ _ _ _ _. _0 _ _._0 ___ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __

5

ANDING With Default subnet masks Every IP address must be accompanied by a subnet mask. By now you should be able to look at an IP address and tell what class it is. Unfortunately your computer doesn’t think that way. way. For your computer to determine the network and subnet portion of an IP address it must “AND” the IP address with the subnet mask. Default Subnet Masks: Class A 255.0.0.0 Class B 255.255.0.0 Class C 255.255.255.0 ANDING Equations: 1 AND 1 = 1 1 AND 0 = 0 0 AND 1 = 0 0 AND 0 = 0 Sample:

What you see... IP Address:

192 . 100 . 10 . 33

What you can figure out in your head... Address Class: Network Portion: Host Portion:

C 192 . 100 . 10 . 33 192 . 100 . 10 . 33

In order for you computer to get the same information it must m ust AND the IP address with the subnet mask in binary. bi nary. Network

Default

Host

IP Address: 1 1 0 0 0 0 0 0 . 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 1 Subnet Mask: 1 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 0 0 0 0 0 0 0 0

(255 . 255 . 255 . 0)

AND: 1 1 0 0 0 0 0 0 . 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 0 0 0 0 0 0

(192 . 100 . 10 . 0)

(192 . 100 . 10 . 33)

ANDING ANDING with the default subnet mask allows your computer to figure out the network portion of the address.

6

ANDING With Custom subnet masks When you take a single network such as 192.100.10.0 and divide it into five smaller networks (192.100.10.16, 192.100.10.32, 192.100.10.48, 192.100.10.64, 192.100.10.80) the outside world still sees the network as 192.100.10.0, but the internal computers and routers see five smaller subnetworks. Each independent of the other. other. This can only be accomplished by using a custom subnet mask. A custom subnet mask borrows bits bits from the host portion of the address to create a subnetwork address between the network and host portions of an IP address. In this example each range has 14 usable addresses in it. The computer must still AND the IP address address against the custom subnet subnet mask to see what the network network portion is and which subnetwork it belongs to. IP Address: Custom Su Subnet Ma Mask: Address Address Ranges: Ranges:

192 . 100 . 10 . 0 255.255.255.240

192.10.10.0 to 192.100.10.15 (Invalid Range) 192.100.10.16 to 192.100.10.31 (1st Usable Range) 192.100.10.32 to 192.100.10.47 (Range in the sample below) 192.100.10.48 to 192.100.10.63 192.100.10.64 to 192.100.10.79 192.100.10.80 to 192.100.10.95 192.100.10.96 to 192.100.10.111 192.100.10.112 to 192.100.10.127 192.100.10.128 to 192.100.10.143 192.100.10.144 to 192.100.10.159 192.100.10.160 to 192.100.10.175 192.100.10.176 to 192.100.10.191 192.100.10.192 to 192.100.10.207 192.100.10.208 to 192.100.10.223 192.100.10.224 to 192.100.10.239 192.100.10.240 to 192.100.10.255 (Invalid Range) Sub Network Host

Network Custom

IP Address: 1 1 0 0 0 0 0 0 . 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 1 Subnet Mask: 1 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 1 1 1 1 0 0 0 0

(192 . 100 . 10 . 33)

AND: 1 1 0 0 0 0 0 0 . 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 0

(192 . 100 . 10 . 32) 32)

(255 . 255 . 255 . 240)

Four bits borrowed from the host portion of the address for the custom subnet mask. The ANDING process of the four borrowed bits shows which range of IP addresses this particular address will fall into.

In the next set of problems you will determine the necessary information to determine the correct subnet mask for a variety of IP addresses.

7

Custom Subnet Masks Problem 1 Number of needed usable subnets 1 4 Number of needed usable hosts 1 4 Network Address 192.10.10.0

C 255 . 255 . 255 . ______ 0 ____ ___ ______ ______ ______ ______ ______ ______ ______ _ Default subnet mask ______ 255 . 255 . 255 . ______ 240 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 16____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 14____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 16____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 14____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 4 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____

Show your work for Problem 1 in the space below.

Number of 256 128 64 32 16 8 4 2 - Hosts Number of Subnets - 2 4 8 16 32 64 128 256 128 64 32 16 8 4 2 1 - Binary values

192 . 10 . 10 . 0 0 0 0 0 0 0 0 Add the binary value numbers to the left of the line to create the custom subnet mask.

128 64 32 +16 240

Subtract 2 for the total number of subnets to get the usable number of subnets.

8

16 -2 14 16 -2 14

Observe the total number of hosts. Subtract 2 for the number of usable hosts.

Custom Subnet Masks Problem 2 Number of needed usable subnets 1000 Number of needed usable hosts 6 0 Network Address 165.100.0.0

B 255 . 255 . 0______ . ______ 0 ______ ___ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 . 255 . 255 . ______ 192 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ ____ 1,024 __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ ____ 1,022 __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 64____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 62____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 10____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____


Number of Hosts -

6 3 5 2 ,5 ,7 3 6 6 8

1 6 , 3 8 4

4 8 ,0 , 1 9 9 2 6

2 ,0 4 8

1 ,0 2 4

5 1 2

. 256 128 64 32 16 1 0 5 2 1 2 4

Number of Subnets - 2 4 8 16 32 64 128 256. Binary values - 128 64 32 16 8 4 2 1 . 128 64 32 16

165 . 100 . 0 0 0 128 12 8 64 32 16 8 4 2 +1 255 Add the binary value numbers to the left of the line to create the custom subnet mask.

8

1 6 2 4 8 , 3 , 1 0 ,0 9 8 4 9 2 4 6 8

8

4

4

2

2

1

6 3 2 5 ,5 ,7 3 6 6 8

0 0 0 0 0. 0 0 0 0 0 0 0 0 128 128 +64 192 64 -2 62 1024 -2 1,022 9 Observe the total number of hosts.

Subtract 2 for the number of usable hosts.


Custom Subnet Masks Problem 3 Network Address 148.75.0.0 /26

/26 indicates /26 indicates the total number of bits used for the network and subnetwork portion of the address. All bits remaining belong belong to the host portion of the address.



Number of Hosts -

6 3 5 2 ,5 ,7 3 6 6 8

1 6 , 3 8 4

4 8 ,0 , 1 9 9 2 6

2 ,0 4 8

1 ,0 2 4

5 1 2

. 256 128 64 32 16 1 0 5 2 1 2 4


148 . 75 . 0 0 0 128 12 8 64 32 16 8 4 2 +1 255 Add the binary value numbers to the left of the line to create the custom subnet mask.

10

8

1 6 2 4 8 , 3 , 1 0 ,0 9 8 4 9 2 4 6 8

8

4

4

2

2

1

6 3 2 5 ,5 ,7 3 6 6 8

0 0 0 0 0. 0 0 0 0 0 0 0 0 128 128 +64 192 192 64 -2 62 1024 -2 1,022 Observe the total number of hosts.

Subtract 2 for the number of usable hosts.



C 255 . 255 . 255 . ______ 0 ____ ___ ______ ______ ______ ______ ______ ______ ______ _ Default subnet mask ______ 255 . 255 . 255 . ______ 224 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 8____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 6____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 32 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 30 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 3____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____



210 . 100 . 56 . 0 0 0 0 0 0 0 0 1288 12 64 32 8 +32 -2 -2 224 30 6

11


C 255 . 255 . 255 . ______ 0 ____ ___ ______ ______ ______ ______ ______ ______ ______ _ Default subnet mask ______ 255 . 255 . 255 . ______ 252 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 64 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 62 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 4____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 2 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 6____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____



195 . 85 . 8 . 0 0 0 0 0 0 0 0 12 8 128 64 32 16 8 +4 252 12

64 -2 60

4 -2 2

Custom Subnet Masks Problem 6 Number of needed usable subnets 1 26 Number of needed usable hosts 131,070 Network Address 118.0.0.0

A 255 .______ 0 ______ . 0 ______ . 0______ ___ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 .______ 254. 0 ______ . 0 ______ ___ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 128 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 126 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 131,072 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 131,070 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 7____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____


Number of Hosts

-

4 2 1 5 2 ,0 1 ,1 ,0 6 2 3 9 4 9 2 4 1 4 8 7 ,0 ,1 ,3 ,5 ,2 ,1 5 4 0 7 7 8 2 2 4 4 6 8

6 3 1 5 2 6 ,5 ,3 ,7 3 8 6 4 6 8

1 2 , 0 ,0 5 2 1 4 2 4 8

4 8 ,0 ,1 9 9 2 6

4 ,0 9 6

Number of Subnets - 2 4 8 16 32 64 128 256 . Binary values -128 64 32 16 8 4 2 1 .. 128 64 32 16

2 1 ,0 ,0 2 4 4 8

1 6 8 ,3 ,1 9 8 2 4

8

4

5 1 2

6 3 5 2 ,5 ,7 3 6 6 8

2

. 256 128 64 32 16 8

.

4 2

1 2 4 2 5 ,0 1 ,1 ,0 6 2 3 9 4 9 2 1 4 4 8 7 ,0 ,1 ,3 ,2 ,5 ,1 5 4 0 7 7 8 2 2 4 4 6 8

1 .. 128 64 32 16

8

4

2

1

118. 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0

12 8 128 64 32 16 8 4 +2 254

128 -2 126

131,072 -2 131,070

13


B 255 . 255 . 0______ . ______ 0 ______ ___ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 . 255 . 255 .______ 224 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 2,048 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 2,046 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 32____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 30____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 11____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____


Number of Hosts -

6 3 5 2 ,5 ,7 3 6 6 8

1 6 ,3 8 4

4 8 ,0 , 1 9 9 2 6

2 ,0 4 8

1 ,0 2 4

5 1 2

. 256 128 64 32 16 1 0 5 2 1 2 4

8

1 6 2 4 8 ,3 , 1 0 ,0 9 8 4 9 2 4 6 8


8

4

4

2

2

1

6 3 2 5 ,5 ,7 3 6 6 8

178 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 1288 12 64 32 16 8 32 4 2,048 -2 -2 2 30 +1 2,046 14 255


C 255 .______ 255 . 255 . 0______ ___ ______ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 .______ 255 . 255 . 192 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 4____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 2____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 64 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 62 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 2____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____



200 . 175 . 14 . 0 0 0 0 0 0 0 0

12 8 128 +64 240

4 -2 2

64 -2 62

15

Custom Subnet Masks Problem 9 Number of needed usable subnets 6 0 Number of needed usable hosts 1,000 Network Address 128.77.0.0

B 255 . 255 . 0______ . ______ 0 ______ ___ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 . 255 . 252 . ______ 0 ____ ___ ______ ______ ______ ______ ______ ______ ______ _ Custom subnet mask ______ 64____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 62____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 1,024 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 1,022 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 6 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____


Number of Hosts -

6 3 5 2 , 5 , 7 3 6 6 8

1 6 ,3 8 4

4 8 , 0 , 1 9 9 2 6

2 ,0 4 8

1 , 0 2 4

5 1 2

. 256 128 64 32 16 1 0 5 2 1 2 4

8

1 6 2 4 8 ,3 , 1 0 , 0 9 8 4 9 2 4 6 8


8

4

4

2

2

1

6 3 2 5 ,5 ,7 3 6 6 8

128 . 77 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0

16

12 8 128 64 32 16 8 +4 252

64 -2 62

1,024 -2 1,022

Custom Subnet Masks Problem 10 Number of needed usable hosts 6 0 Network Address 198.100.10.0




198 . 100 . 10 . 0 0 0 0 0 0 0 0

12 8 128 +64 192 19 2

64 -2 62

4 -2 2

17

Custom Subnet Masks Problem 11 Number of needed usable subnets 25 0 Network Address 101.0.0.0

A . ______ 0 .______ 0 ______ . 0______ ___255 ______ ______ ______ ______ ____ _ Default subnet mask ______ . ______ 255 . 0______ . 0______ ___255 ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 256 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 254 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 65,536 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 65,534 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 8____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____


Number of Hosts

-

4 2 1 5 2 ,0 1 ,1 ,0 6 2 3 9 4 9 2 4 1 4 8 7 ,0 ,1 ,3 ,5 ,2 ,1 5 4 0 7 7 8 2 2 4 4 6 8

6 3 1 5 6 2 ,5 ,3 ,7 3 8 6 4 6 8

1 2 ,0 ,0 5 2 1 4 2 4 8

4 8 ,0 ,1 9 9 2 6

4 , 0 9 6

Number of Subnets - 2 4 8 16 32 64 128 256 Binary values -128 64 32 16 8 4 2 1 .. 128 64 32 16

.

2 , 0 4 8

1 6 8 ,3 ,1 9 8 2 4

8

4

1 ,0 2 4

5 1 2

6 3 5 2 ,5 ,7 3 6 6 8

2

. 256 128 64 32 16 8

.

4

2

2

1

1 2 4 2 5 ,0 1 ,0 ,1 6 2 3 9 4 9 2 1 4 4 8 7 ,0 ,1 ,3 ,2 ,5 ,1 5 4 0 7 7 8 2 2 4 4 6 8

1 .. 128 64 32 16

8

4

101. 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0

18

128 64 32 16 8 4 2 +1 255

256 256 -2 254

65,536 -2 65,534

Custom Subnet Masks Problem 12 Number of needed usable subnets 5 Network Address 218.35.50.0




218 . 35 . 50 . 0 0 0 0 0 0 0 0

12 8 128 64 +32 224

64 -2 62

4 -2 2

19


C . ______ 255 . 255 . 0______ ___255 ______ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ . ______ 255 . 255 . 224 ___255 ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 8____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 6____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 32 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 30 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 3____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____



218 . 35 . 50 . 0 0 0 0 0 0 0 0

20

128 64 +32 224

8 -2 6

32 -2 30

Custom Subnet Masks Problem 14 Number of needed usable subnets 1 0 Network Address 172.59.0.0

B 255 .______ 255 . 0______ . 0______ ___ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 .______ 255 . 240 . 0______ ___ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 16 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 14 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 4,096 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 4,094 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 4____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____


Number of Hosts -

6 3 5 2 ,5 , 7 3 6 6 8

1 6 , 3 8 4

4 8 ,0 , 1 9 9 2 6

2 , 0 4 8

1 ,0 2 4

5 1 2

. 256 128 64 32 16 1 0 5 2 1 2 4

8

1 6 2 4 8 , 3 , 1 0 , 0 9 8 4 9 2 4 6 8


8

4

4 2 6 3

2 5 , 5 , 7 3 6 6 8

2

1

172 . 59 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0

12 8 128 64 32 +16 240

16 -2 14

4,096 -2 4,094

21


B . ______ 255 . 0______ . 0______ ___255 ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ . ______ 255 . 255 . ______ 192____ ___255 ______ ______ ______ ______ ______ ______ _ Custom subnet mask ______ 1,024 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 1,022 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 64 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 62 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 10 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____


Number of Hosts -

6 3 5 2 , 5 , 7 3 6 6 8

1 6 , 3 8 4

4 8 ,0 ,1 9 9 2 6

2 ,0 4 8

1 ,0 2 4

5 1 2

. 256 128 64 32 16 1 0 5 2 1 2 4

8

1 6 2 4 8 ,3 ,1 0 , 0 9 8 4 9 2 4 6 8


8

4

4

2

2

1

6 3 2 5 ,5 ,7 3 6 6 8

172 . 59 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 128 64 32 16 8 4 2 12 1288 64 1,024 -2 +1 +64 -2 255 192 62 1,022 22


A 255 .______ 0 ______ . 0 ______ . 0______ ___ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 .______ 255 . 255 . 224 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 524,288 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 524,286 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 32 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 30 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 19 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ___ _ Address Addre ss class ____


Number of Hosts

-

4 2 1 5 2 ,0 1 ,1 ,0 6 2 3 9 4 9 2 4 1 4 8 7 ,0 , ,3 ,5 ,2 ,1 1 5 4 0 7 7 8 2 2 4 4 6 8

6 3 1 5 6 2 ,5 ,3 ,7 3 8 6 4 6 8

1 2 ,0 ,0 5 2 1 4 2 4 8

4 8 ,0 ,1 9 9 2 6

4 ,0 9 6

Number of Subnets - 2 4 8 16 32 64 128 256 Binary values -128 64 32 16 8 4 2 1 .. 128 64 32 16

.

2 ,0 4 8

1 6 8 ,3 ,1 9 8 2 4

8

4

1 , 0 2 4

5 1 2

6 3 5 2 ,5 ,7 3 6 6 8

2

. 256 128 64 32 16 8

.

4

2

2

1

1 2 4 2 5 ,0 1 ,1 ,0 6 2 3 9 4 9 2 1 4 4 8 7 , 0 ,1 ,3 ,2 ,5 ,1 5 4 0 7 7 8 2 2 4 4 6 8

1 .. 128 64 32 16

8

4

23 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0

12 8 128 64 +32 224

32 -2 30

524,288 -2 524,286

23

Subnetting Problem 1 Number of needed usable subnets 1 4 Number of needed usable hosts 1 4 Network Address 192.10.10.0


What is the 3rd usable subnet range? ___________________________ ________________________________________ ____________________ _______

192.10.10.48 to 192.10.10.63

What is the subnet number for the 7th usable subnet? ________________________

192 . 10 . 10 . 112

What is the subnet broadcast address for the 12th usable subnet? ________________________

192 . 10 . 10 . 207

What are the assignable addresses for the 8th usable subnet? ____ __ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __

192.10.10.129 to 192.10.10.142

24



192. 10 . 10 . 0 0 0 0 0 0 0 0

(Invalid range) 0 192.10.10.0

1 1 1 1 1 1 1 (Invalid range) 1

Custom subnet mask

1 1 1 1 0 0 0 0 1 1 1 1

1 1 0 0 1 1 0 0 1 1 0 0 1 1

1 0 1 0 1 0 1 0 1 0 1 0 1 0 1

128 64 32 +16 240

192.10.10.16 192.10.10.32 192.10.10.48 192.10.10.64 192. 10 .10 .8 0 192.10.10.96 192.1 92.10. 0.10 10.1 .112 12 192.1 92.10. 0.110.12 0.1288 192. 192.10 10.1 .10. 0.14 144 4 192.1 92.10. 0.10 10.1 .160 60 192.1 92.10. 0.10 10.1 .176 76 192.1 92.10. 0.10 10.1 .192 92 192. 192.10 10.1 .10. 0.20 2088 192. 192.10 10.1 .10. 0.22 224 4 192. 192.10 10.1 .10. 0.24 240 0

Usable subnets

16 -2 14

to to to to to to to to to to to to to to to to

192.10.10.15 192.10.10.31 192.10.10.47 192.10.10.63 192.10.10.79 192.10.10.95 192.10.10.111 192.10.10.127 19 192.10.10.143 192.1 92.10 0.10. .10.1159 192 192.10.10.175 192.10.10.191 19 192.10.10.207 192.1 2.10.1 0.10.22 .223 19 192.1 2.10.10 0.10.2 .239 39 19 192.10 .10.10. .10.25 255 5

Usable hosts

16 -2 14

The binary value of the last bit borrowed is the range. In this problem the range is 16. The first and last range of addresses are not usable.

The first address in each subnet range is the subnet number.

The first usable range of addresses addresses is: 192.10.10.16 192.10.10.16 to 192.10.10.31.

The last address in each subnet range is the subnet broadcast address.

25

Subnetting Problem 2 Number of needed usable subnets 1000 Number of needed usable hosts 6 0 Network Address 165.100.0.0


What is the 14th usable subnet range? ___________________________ ________________________________________ ____________________ _______

165.100.3.128 to 165.100.3.191


165 . 100 . 1 . 64


165 . 100 . 1 . 127


165.100.2.1 to 165.100.0.62

26


2 ,536 6 5 5 4 7 6 8 32 ,7 8

5 5 7 7 1 5 7 1 5 7 1 1 1 5 5 5 5 3 3 9 3 9 3 2 5 2 9 2 9 5 9 2 1 1 1 1 1 6 1 1 1 1 . 2 . . 2 . . 2 . . 6 . 6 . . . 2 . . . . 2 . . 6 . 5 5 0 0 1 1 1 0 . . 0 . . 0 . 1 . . 3 . 3 . . 0 . 3 . . 0 . 0 . . 3 5 5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 . 2 . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 . . . 1 . . 1 . . . . . 1 . . . . . . 0 0 1 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 . 1 . 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 5 1 1 1 1 1 1 1 1 1 1 1 1 1 1 o 6 5 1 1 6 1 t 1 o o o o o o o o o o n o o o o o o o o t t t t t t t t t t t t t t t t w t t 1 0 o 2 8 8 8 2 2 8 2 D 8 2 2 9 2 0 4 4 2 9 4 2 9 4 9 2 1 2 9 0 . 1 . 1 0 1 1 1 1 6 1 6 0 6 1 1 . . . . . 0 . . 6 . . . . . 5 5 . . . . 4 0 0 0 0 2 1 1 1 2 2 3 3 3 0 1 2 3 5 5 . . . . . . . . . . . . . . . . 2 . 2 . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 8 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 . . . . . . . . . . . . . . . . 1 1 . . 6 1 0 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 3

8 4 16,3 6 1 8,1 92 2 3 4 0 ,0 96 4 6 2 0 4 8 8 4 4 2 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 0 0 6 0 0 1 1 02 6 8 5 512 2 0 ) 1 1 0 1 0 1 0 1 0 1 0 1 0 1 1 2 e . . . . g . . . . . . . . . . . . . n 6 a 5 1 1 1 1 1 0 0 0 0 1 1 1 1 2 0 r 512 d 8 i l 2 2 4 2 1 1 1 1 1 1 1 1 0 ,0 1 a 1 0 ,0 4 8 2 0 ,0 96 4 0 2 8,1 9 8 4 16,3

) e g n a r d i l a v n I (

v 4 4 0 n I 6 (

2 8 0 3 6 6 1 1 0

1 5 8 4 2 4 2 6 8 + 5 1 2 6 3 1 8 4 2 2 8 2 2 6 9 1 + 1 4 2 2 3 0 6 - 6 k m s 4 4 o a s e t t 6 0 l s s

,76 8 32 7 2 8 2 6 ,53 1 0 6 5 5 - - . f s s f s e 0 o o t u 0 l r t e r s o 1 n a e H e b b v . b m u y m u u S r 5 N a N n i 6 B 1

b a o s h U

4 2 2 2 2 0 0 , 1 1 s e t l b e a n s b u U s

m u t C e n b u s

s i . d 4 e 6 w i s o r r e o g b n a t i r b e t h s t a l m e e l h t b f o r o p s e i u h l a t v I n y . r e a g n i n b a r e e h h T t

t o n e r a s e s s e r d d a f o e g n a r t s a l d n a t . s r l e i f b e a h s T u

: s i s e s s e r 7 d 2 d 1 a . . f 0 o 0 0 e 1 g . n 5 6 a r 1 e o l t b a 4 s 6 . u 0 t . 0 s r 0 i f 1 . e 5 h 6 T 1

e h t s i e g n a r t e n b u s h c a e n i s . s r e r e b d d m a u t n s r t i e f n e b h u T s

e h t s i e g n a r t e n b u . s s s h e c r a d e d n a i t s s s a c e r d d a d o a r t b s t a e l n e b h u T s

27

Subnetting Problem 3 Number of needed usable subnets 1 Network Address 195.223.50.0

C 255 . 255 . 255 . ______ 0 ____ ___ ______ ______ ______ ______ ______ ______ ______ _ Default subnet mask ______ 255 . 255 . 255 . ______ 192 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 4 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 2 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 64____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 62____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 2 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____

What is the 2nd usable subnet range? ___________________________ ________________________________________ ____________________ _______

195.223.50.128 - 195.223.50.191

What is the subnet number for the 1st usable subnet? ________________________

195.223.50.64

What is the subnet broadcast address for the 1st usable subnet? ________________________

195.223.50.127

What are the assignable addresses for the 2nd usable subnet? ____ __ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __

195.223.50.129 - 195.223.50.190

28



195. 223 . 50 . 0 0 0 0 0 0 0 0 (Invalid range) 0 195.223.50.0 t o 1 195.223.50.64 t o 1 0 195.223.50.128 t o (Invalid range) 1 1 195.223.50.192 t o

12 8 128 +64 192

4 -2 2

195.223.50.63 195.223.50.127 195.223.50.191 195.223.50.255

64 -2 62

29

Subnetting Problem 4 Number of needed usable subnets 75 0 Network Address 190.35.0.0

B 255 . 255 . 0______ . ______ 0 ______ ___ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 . 255 . 255 . ______ 192 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 1,024 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 1,022 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 64____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 62____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 10____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____


190.35.3.1288 to 190.35.3.191 190.35.3.12


190.35.3.0


190.35.2.127


190.35.1.65 to 190.35.1.126

30


5 5 7 7 1 5 7 1 5 7 1 1 3 2 3 2 9 5 9 5 5 3 2 9 5 3 9 2 6 . 2 . 1 . 2 . 1 . 6 . 6 . 1 . 1 . 1 . 2 . . 1 . 1 . 2 . 6 . 1 0 0 1 1 2 2 0 3 1 2 3 0 3 1 2 3 . . . . . . . . . . . . . . . . 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . . 3 . 3 . 3 . 3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 36 1 0 5 5 , 5 6 4 7 6 8 2 0 32 ,7 8

8 4 16,3

o o o o o o o o o o o o o o o o t t t t t t t t t t t t t t t t

8 2 8 2 8 2 8 2 4 2 4 2 9 4 2 9 4 2 9 9 0 6 4 0 0 1 1 1 1 6 1 0 6 . . . . 0 . . 1 . . . . . . . . 1 . 6 . 1 0 0 2 0 1 1 2 0 3 1 2 2 3 1 3 3 8 0 . . . . . . . . . . . . . . . . 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 3 6 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . 3 . . 3 . 3 . 3 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 2 3 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 4 6 0 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1

6 1 8,1 92 2 ,0 96 3 4 0 4 6 2 0 4 8 8 4 2 1 1 02 6 8 ) 5 512 2 e 0 1 2 g . . . . . n a 6 r 5 1 2 512 0 d i 8 l 2 1 2 0 a ,02 4 1 0 v ,0 4 8 2 0 ,0 96 4 0 2 8,1 9 8 4 16,3

n

1 1 0 1 0 1 0 1 0 1 0 1 0 1 . . . . . . . . . . . . 1 1 1 1 0 0 0 1 0 1 1 1 1 1 1 1 1 1 1 1

I 4 4 ( 0 6 2 8 0 3 6 6 1 1 0 8 2 3 0

4 4 8 6 6 0 7 7 , 32 2 8 2 6 3 5 5 , 1 0 5 6 - - . f s s f s e 5 o o t u 3 t r e l r s o e n a H e b b v . b m u y m 0 u u S r a N n 9 N i 1 B

1 2 8 8 6 4 4 2 2 2 + 5 1 2 6 3 1 2 4 2 2 2 - 2 0 , 0 , 1 1

8 4 2 2 6 5 1 + 2 4 2 2 6 - 6

31

Subnetting Problem 5 Number of needed usable hosts 6 Network Address 126.0.0.0

A 255 . 0______ . 0______ . 0______ ___ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 . 255 . 255 . ______ 248 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 2,097,152 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 2,097,150 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 8 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 6 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 21____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____

What is the 1st usable subnet range? ___________________________ ________________________________________ ____________________ _______

126.0.0.8 to 126.0.0.15


126.0.0.32


126.0.0.55


126.0.0.73 to 126.0.0.78

32

Show your work for Problem 5 in the space below. 3 7 9 1 5 3 7 3 9 1 5 9 7 1 0 5 2 1 1 7 . 7 . 4 . 3 . 5 . 1 . 1 . 3 . 6 . 8 . 1 . 9 . 2 . 7 . . 1 . 1 0 0 . 0 . 0 . 0 . 0 . 0 . 0 . . 0 . 0 . 0 . 0 . 0 . . 0 . 0 . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 . . . . . . . . . . . . . . . . 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

o o o o o o o o o o o o o o o o t t t t t t t t t t t t t t t t

2 4 4 4,3 0 4,1 9 6 1 ,1 52 , 9 7 2 0 2 3 4 8 5 ,5 76 ,0 1 0 4 8 6 4,2 8 8 52 2 1 62,1 4 4 6 2 5 ,0 72 2 131 0 . . 8

512 ,02 4 1 0 ,0 4 8 2 0 ,0 96 4 0 2 8,1 9 8 4 16,3 ,76 8 32 7 ,536 6 5 5 ,0 72 0 131 ,1 4 4 262 ,2 8 8 52 4 ,5 76 5 ,0 4 8 1 0 ,1 52 , 9 7 2 0 4 4,3 0 4,1 9

f s o t s r e o H b m u N

4 0 2 6 4 0 8 4 2 6 0 2 8 0 6 2 1 4 6 0 2 3 4 5 8 9 1 8 1 7 8 1 . . . . . . . . . . . . . . . 1 . 0 0 0 0 0 0 0 0 0 0 1 . 0 . 0 . . . . . . . 0 . . 0 . . . 0 . . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 . . . . . . . . . . . . . . . . 2 0 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 4 0 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

0 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 6 1 0 ) 1 1 0 1 0 1 0 1 0 1 0 1 0 1 e 2 3 0 g 1 1 1 1 0 0 0 1 n 0 1 1 1 a 4 6 0 r 1 1 1 1 1 1 1 1 8 d 2 i 1 0 l . . a 1 0 v ,536 n 6 5 5 I 8 2 0 ( 6 7 7 , 32 8 4 4 0 16,3 2 8 0 8,1 9 6 ,0 96 1 0 4 0 2 ,0 4 8 3 0 2 0 4 ,02 4 6 0 1 0 8 512 1 0 . 2 . . 6 1 5 0 2 8 2 2 1 0 4 4 6 0 8 8 2 8 4 2 6 8 3 0 + 1 2 6 3 4 6 6 1 1 0 1 2 0 2 2 8 2 3 0 5 5 1 1 4 , , 4 1 5 8 2 6 8 4 2 4 2 6 8 6 0 7 7 + 5 1 2 6 3 9 9 2 8 2 0 1 1 0 , 0 , 2 . 2 2 s e 6 u f s l o t a 2 e r e n v 1 b b y 8

m u r u S a i N n B

33




192.70.70.128 to 192.70.10.143

What is the subnet number for the 3rd usable subnet? ________________________

192.70.10.48


192.70.10.191


192.70.10.145 to 192.70.10.158

34



. 0 0 0 0 (Invalid range) 0 1 1 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 1 0 0 0 1 0 0 1 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 1 0 (Invalid range) 1 1 1 1

192 . 70 . 10 .

128 +64 240

0 0 0 0 192.70.10.0 192.70.10.16 192.70.10.32 192.70.10.48 192.70.10.64 192.70.10.80 192.70.10.96 192.70.10.112 192.70.10.128 192.70.10.144 192.70.10.160 192.70.10.176 192.70.10.192 192.70.10.208 192.70.10.224 192.70.10.240

16 -2 14

16 -2 14

to to to to to to to to to to to to to to to to

192.70.10.15 192.70.10.31 192.70.10.47 192.70.10.63 192.70.10.79 192.70.10.95 192.70.10.111 192.70.10.127 192.70.10.143 192.70.10.159 192.70.10.175 192.70.10.191 192.70.10.0207 192.70.10.223 192.70.10.239 192.70.10.255

35

Subnetting Problem 7 Network Address 10.0.0.0 /16

A ___ ______ ______ ______ ______ ______ ____ _ 255 . 0______ . 0______ . 0______ Default subnet mask ______ ___ ______ ______ ______ ______ ______ ____ _ 255 . 255 . 0______ . ______ 0 ______ Custom subnet mask ______ __ ____ ____ ____ ____ ____ ____ ____ ___ _ 256 Total number of subnets ____ __ ____ ____ ____ ____ ____ ____ ____ ___ _ 254 Number of usable subnets ____ __ ____ ____ ____ ____ ____ ____ ____ ___ _ 65,536 Total number of host addresses ____ __ ____ ____ ____ ____ ____ ____ ____ ___ _ 65,534 Number of usable addresses ____ __ ____ ____ ____ ____ ____ ____ ___ _ 8 ____ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____


10.10.0.0 to 10.10.255.255


10.5.0.0

What is the subnet broadcast address for the 1st usable subnet? ________________________

10.1.255.255


10.8.0.1 to 10.8.255.254

36


1

0 4 5 5 5 5 5 5 0 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 8 4 4 5 5 5 5 0 4,3 0 5 5 5 9 5 5 5 1 , 4 2 . . 2 . 2 . 2 . 2 6 . 2 2 2 2 2 2 2 2 8 2 1 2 2 2 5 . . . 1 , . . . . 7 . . 0 . 9 , 5 5 5 5 5 2 0 5 6 2 5 5 5 5 5 5 5 6 5 5 1 5 7 3 4 8 5 ,5 5 5 5 5 5 5 0 5 5 ,0 1 0 5 5 5 5 5 5 5 4 5 2 2 2 2 . . 2 6 . 2 . 2 . . 2 ,2 8 8 3 0 2 2 2 4 2 2 2 2 2 2 2 . . . . . . . . . 8 5 1 . 0 2 3 4 5 4 2 2 7 8 9 1 1 3 4 5 6 1 1 1 1 62,1 4 4 6 0 0 . . . . . . . . . . . . . . 1 . 1 . 6 2 8 2 5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 ,0 7 2 131 0 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 . . . . 1 512 ,536 0 6 5 5 2 o o o o o o o o o o o o o o o ,76 8 ,02 4 1 0 0 o 32 7 t t t t t t t t t t t t t t t t 4 4 ,0 4 8 8 2 0 3 , 0 16 8 2 ,0 96 8,1 9 4 0 0 0 0 0 0 0 0 . . . . 6 . 6 2 . 9 9 0 0 0 1 0 0 1 , 0 0 0 0 8 0 0 4, . 0 . 0 0 0 . . . . . . . . 0 0 0 0 . . . . . . 2 0 0 0 0 8 4 0 0 0 8 0 0 4 0 . ,0 3 0 . . . . . . . . . 0 2 0 16,3 1 2 3 4 5 4 0 2 7 8 9 1 1 1 5 1 1 1 1 3 4 6 8 4 ,76 6 0 . . . . . . . . . . . . . . . . ,02 1 0 32 7 8 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 12 2 36 5 5 5 , 5 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 6 . 1 . 0 1 . 6 1 5 ,0 72 0 1 1 1 1 1 1 1 1 131 2 0 0 0 0 0 0 0 0 0 8 2 ) 1 1 0 1 2 ,1 4 4 0 1 0 1 0 1 0 1 0 1 1 0 e 262 4 g 4 ,2 8 8 6 0 n 1 1 1 1 0 0 0 1 0 1 1 1 52 4 a 8 2 ,5 76 5 3 0 r ,0 4 8 1 0 1 1 1 1 1 1 1 1 d 6 6 2 1 0 i 1 ,1 5 l , 9 7 2 0 a 2 8 3 ,3 0 4 v 4 0 9 4,1 n 4 4 6 0 I ( f s 8 o t 2 s 2 r 1 0 e o H b m s . u e 0 N u f s l o t a e 1 r e n v 2

2

b b y m u r u S a N n i B

1 5 6 2 8 4 2 4 2 6 8 4 + 5 1 2 6 3 5 5 1 2 2 2

6 2 4 3 - 3 5 , 5 , 5 5 6 6 37

Subnetting Problem 8 Number of needed usable subnets 4 Network Address 172.50.0.0

B 255 . 255 . 0______ . ______ 0 ______ ___ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 . 255 . 224 . ______ 0 ____ ___ ______ ______ ______ ______ ______ ______ ______ _ Custom subnet mask ______ 8 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 6 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 8,192 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 8,190 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 3 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____

What is the 3rd usable subnet range? ___________________________ ________________________________________ ____________________ _______

172.50.96.0 to 172.50.127.255


172.50.128.0


172.50.191.255


172.50.64.1 to 172.50.95.254

38


2 36 1 0 5 5 , 6 5 4 7 6 8 2 0 32 ,7 8

8 4 16,3

5 5 5 5 5 5 5 5 5 5 5 5 5 2 4 0 5 5 2 . 5 2 2 . 2 . . . 2 2 2 . 9 3 5 8 0 . . 7 1 2 1 3 5 2 9 5 5 3 . 2 . 1 . 1 . 1 . 6 . 2 . . 9 6 0 1 0 0 0 0 0 0 0 0 5 2 . 5 . 5 . 5 . 5 . 5 . 5 . . 5 3 0 2 2 2 2 2 2 2 2 7 7 7 7 7 7 7 7 4 6 0 1 1 1 1 1 1 1 1

6 1 8,1 92 2 ,0 96 3 4 0 4 6 2 0 4 8 8 4 2 1 1 02 6 8 5 512 2 0 1 2 . . . . 6 5 1 2 0 512 8 2 4 1 2 0 ,02 1 0 ,0 4 8 2 0 ,0 96 4 0 2 8,1 9 8 4 16,3

o o o o o o o o t t t t t t t t

0 0 0 . 0 . . . 0 0 0 4 . . . 8 0 2 0 . 2 4 6 2 6 9 2 . 3 . 1 . 2 . 1 . 6 . 1 . 4 4 0 0 . 9 6 0 0 0 0 0 0 0 0 2 8 . 5 . 5 . 5 . 5 . 5 . 5 . . 5 0 5 3 2 2 2 2 2 2 2 2 6 6 7 7 7 7 7 7 7 7 1 1 0 1 1 1 1 1 1 1 1 8 2 1 0 1 0 1 0 1 3 0 0

) e 4 4 6 0 g n 8 2 a 2 6 3 5 5 1 0 r 6 5, - - . d i l s f s e 0 a f s v o t u o t s l 5 n e a r o r I e e n . H b b v ( b m u y m 2 u u S r a N n 7 N i 1 B ,76 8 32 7

1 1 0 1 0 1 1 1 1 1


8 4 4 2 2 6 3 2 1 + 2

8 2 6 -

2 2 0 9 9 1 , 1 , 8 8 39

Subnetting Problem 9 Number of needed usable hosts 2 8 Network Address 172.50.0.0


What is the 1st usable subnet range? ___________________________ _________________________________________ ____________________ ______

172.50.0.32 to 172.50.0.63


172.50.1.32

What is the subnet broadcast address for the 3rd usable subnet? ________________________

172.50.0.127


172.50.0.161 to 172.50.0.190

40

Show your work for Problem 9 in the space below. 5 3 9 5 7 3 1 9 7 1 2 5 3 1 5 5 9 2 2 3 1 5 5 9 5 2 9 1 1 3 1 6 2 2 1 9 3 6 1 . . . . . . . . . . . . . 1 . 2 . 2 . 0 0 0 1 1 1 0 0 0 0 0 1 1 1 1 1 . . . . . . . . . . . . . . . . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 . . . . . . . . . . . . . . . . 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 o o o o o o o o o o o o o o o o

1 0 t t t t t t t t t t t t t t t t 2 6 3 ,5 6 5 5 4 4 7 8 0 4 2 6 8 2 0 8 0 2 7 , 2 2 2 4 2 6 3 9 2 6 4 6 9 2 6 2

0 . 1 . 9 . 2 . 3 . 1 . 1 . 6 . 0 . 1 . 2 . 3 . 9 . 1 . 1 . 6 . 0 1 0 0 0 1 0 0 0 1 1 1 0 1 1 . . . . . . . . . . . . . . . 1 . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 . 5 . 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 7 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

8 4 4 0 16,3 8 0 6 1 8,1 92 2 6 ,0 96 1 0 3 4 0 4 6 2 0 4 8 2 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 3 0 0 8 ) 2 1 02 4 4 6 0 1 0 1 0 1 0 1 0 1 1 0 e g 1 1 0 1 n 6 8 2 1 5 5 2 0 a 1 1 1 1 0 0 0 1 r 0 1 1 1 1 2 . . . d i . . . . . . . . . . l 6 5 1 1 1 1 1 1 1 1 1 512 2 0 a v n 8 I 2 2 4 ( 2 0 1 ,0 1 0

8

,0 4 8 2 0

2 8,1 9

4 4 0 6 2 8 0 3 6 6 1 1 0

8 4 16,3

8 2 3 0

,0 96 4 0

4 4 6 8 6 0 7 7 , 2 3 2 8 2 6 3 5 5 , 1 0 5 6 - . 0 f s s f s t o t e o s u 5 e l r o r a . e e n H b b v b m u y m 2 u u S r a 7 N N n i 1 B

8 4 4 2 2 6 3 1 + 2 2 1 2 8 8 8 6 4 4 2 2 2 + 5 1 2 6 3 1 2

2 2 4 2 2 4 - 6 6 2 - 2 0 , 0 , 1 1 41


C 255 . 255 . 255 . ______ 0 ____ ___ ______ ______ ______ ______ ______ ______ ______ _ Default subnet mask ______ 255 . 255 . 255 . ______ 252 ___ ______ ______ ______ ______ ______ ______ ______ ____ _ Custom subnet mask ______ 64____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 62____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 4 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 2 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 6 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____

What is the 4th usable 220.100.100.16 to 220.100.100.19 subnet range? ___________________________ ______________ ___________________________ ____________________ ______ What is the subnet number 220.100.100.12 for the 3rd usable subnet? ________________________ What is the subnet broadcast address for 220.100.100.51 the 12th usable subnet? ________________________ What are the assignable addresses for the 11th 220.100.100.45 5____ to____ 220.100.100.46 usable subnet? ____ __220.100.100.4 ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __

42


9 1 5 7 7 3 3 9 3 1 5 9 1 5 3 1 4 5 3 7 2 4 1 2 3 3 1 5 5 . . . . . . . . . . . . . . . 6 . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . . 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2

s e u o o o o o o o o o o o o o o o o l t t t t t t t t t t t t t t t t a v y 6 2 8 8 4 0 4 0 6 0 2 6 2 r 4 8 4 4 0 4 2 3 6 1 2 2 3 1 5 5 a . . . . . . . . . . . . . . . . n i 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 B 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 . . . . . . . . . . . . . . . . 6 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 2 1 0 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 1 . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 8 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 0 2 4 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 8 4 6 4 0 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1

f o r e b s t m u s o N H

) 6 8 0 e 1 2 3

0 g 1 1 0 1 n 2 6 6 a 1 1 1 3 1 1 0 r d 4 8 2 i l 6 3 0 a 8 v 2 4 4 6 0 n 1 I ( 6 8

1 0 1 0 1 0 1 0 1 1 0 0 0 1 0 1 1 1 1 1 1 1 1 1 1 1

5 2 2 2 1 0 f s o t r e e n b b u m u S N

. 0 0 1 . 0 0 1 . 0 2 2

8 6 8 4 2 4 2 1 + 5 2 6 3 1 2

4 2 2 6 - 6

4 2 2 43

Subnetting Problem 11 Number of needed usable hosts 8,000 Network Address 135.70.0.0

B 255 . 255 . 0______ . ______ 0 ______ ___ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 . 255 . 224 . ______ 0 ____ ___ ______ ______ ______ ______ ______ ______ ______ _ Custom subnet mask ______ 8 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 6 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 8,192 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 8,190 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 3 ____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____

What is the 5th usable subnet range? ___________________________ _________________________________________ ____________________ ______

135.70.160.0 to 135.70.191.255


135.70.192.0

What is the subnet broadcast address for the 2nd usable subnet? ________________________

135.70.95.255


135.70.128.1 to 135.70.159.254

44


2 36 1 0 5 5 , 5 6 4 7 6 8 2 0 32 ,7

5 5 5 5 5 5 5 5 5 5 5 5 5 2 5 2 . 5 2 5 2 . 2 . . . 8 4 2 4 0 2 8 9 . . 7 . 2 1 3 5 16,3 1 3 5 2 5 9 2 5 8 6 2 0 3 1 8,1 9 . 1 . 1 . 1 . 2 . 2 . . 6 . 9 0 0 0 0 0 0 0 0 2 6 3 4 0 ,0 96 1 0 7 . 7 . 7 . 7 . 7 . 7 . 7 . . 7 4 5 5 5 5 5 5 5 5 6 2 0 4 8 2 3 0 3 3 3 3 3 3 3 3 8 1 1 1 1 1 1 1 1 2 1 02 4 4 6 0 1 6 8 o o o o o o o o 5 512 2 1 0 t t t t t t t t 2 . . . 6 . 5 1 0 0 0 . 0 512 2 0 . . . 0 0 0 4 8 . . . 8 0 2 0 2 2 4 . 4 6 2 6 9 2 ,02 1 0 0 2 1 0 1 1 9 6 . 3 . 1 . 2 . . . . . 4 8 4 4 0 0 0 0 0 0 0 0 0 0 0 7 7 7 7 7 7 7 7 2, 6 . . . . . . . . 2 8 6 9 ,0 5 5 5 5 5 5 5 3 0 5 4 0 3 3 3 3 3 3 3 3 6 6 1 1 1 1 1 1 1 1 2 1 1 0 8,1 9 8 2 3 0 4 4 8 6 6 0 7 7 , 32 2 8 2 6 3 5 5 , 1 0 5 6 - . f s s f s e 0 o o t u 7 t r e l r s o e n a . H e b b v b m u y m 5 u u S r a N n 3 N i 1 B 8 4 16,3

1 0 1 0 1 0 1 0 ) e 0 1 g 1 1 0 1 n a r d i l a v n I (

1 1 1 1 ) e g n a r d i l a v n I (

8 4 4 2 2 6 3 2 1 + 2 2 2 0 9 9 8 2 6 1 1 , , 8 8 45



What is the 1st usable subnet range? ___________________________ _________________________________________ ____________________ ______

198.125.50.64 to 98.125.50.127

What is the subnet number for the 1st usable subnet? ________________________

198.125.50.64

What is the subnet broadcast address for the 2nd usable subnet? ________________________

198.125.50.191


198.125.50.129 to 198.125.50.190

46



198 . 125 . 50 . 0 0 (Invalid range) 0 1 1 0 (Invalid range) 1 1

12 8 128 +64 192

4 -2 2

0 0 0 0 0 198.125.50.0 198.125.50.64 198.125.50.128 198.125.50.192

0 to to to to

198.125.50.63 198.125.50.127 198.125.50.191 198.125.50.255

64 -2 62

47

Subnetting Problem 13 Network Address 165.200.0.0 /26


What is the 9th usable 165.200.2.64 to 165.200.2.127 subnet range? ___________________________ ______________ ___________________________ ____________________ ______ What is the subnet number 165.200.2.128 for the 10th usable ________________________ subnet? What is the subnet 165.200.255.191 broadcast address for ________________________ the 1022nd usable subnet?

165.200.255.65 to 165.200.255.126 What are the assignable ____ __ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __ addresses for the 1021st usable subnet? 48


2 36 1 0 5 5 , 6 5 4 7 6 8 2 0 7 , 2 3 4 4 0 8 3 , 16 8 0 6 1 8,1 92 2 6 ,0 96 1 0 3 4 0 4 6 2 0 4 8 2 3 0 8 4 4 2 6 0 1 1 02 6 8 5 512 2 0 1 2 . . . . 6 5 1 512 2 0 8 2 4 1 2 0 ,02 1 0

8

,0 4 8 2 0

8 8 8 2 2 2 8 2 4 4 4 9 4 9 2 2 9 2 9 2 6 6 0 0 1 6 1 1 1 0 1 6 0 . . . . . . 1 . . . . . . . . . 1 . 1 3 0 0 3 2 2 1 0 1 3 0 3 2 1 2 1 . . . . . . . . . . . . . . . . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 2 2 2 2 2 2 2 2 . . 2 . . . . 2 . . . 2 . 2 . . 2 . . . 2 . 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

8 2 4 2 9 6 . 1 . . 1 5 5 5 5 5 5 2 . 1 . 2 . 0 0 0 0 0 0 2 2 . . 2 . 5 5 5 6 6 6 1 1 1

1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 ) e 0 1 0 1 0 1 0 1 0 1 g 1 1 0 1 n a . . . . . . . . . r d 1 1 1 1 0 0 0 1 0 1 1 1 i l a 1 1 1 1 1 1 1 1 v

1 2 3 2 2 2 0 0 0 1 1 1

n I 4 4 0 ( 6

2 8,1 9

2 8 0 3 6 6 1 1 0

8 4 16,3

8 2 3 0

,0 96 4 0

5 5 7 5 5 7 7 1 1 1 7 1 5 5 3 3 5 3 5 2 9 2 9 3 2 9 2 9 6 6 2 6 . 1 1 1 . 1 . 6 . 1 . 2 . . 2 . 1 . . . . . . 1 . 1 . 2 3 0 2 1 0 3 2 0 0 1 3 3 2 2 1 1 . . . . . . . . . . . . . . . . 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 2 2 2 2 . 2 . . 2 . . 2 . . . 2 . . 2 . 2 . 2 . 2 . 2 . 2 . 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 o o o o o o o o o o o o o o o o t t t t t t t t t t t t t t t t

7 1 5 2 9 5 1 . 1 . 2 . 5 5 5 5 5 5 2 . 2 . 2 . 0 0 0 0 0 0 2 2 . . 2 . 5 5 5 6 6 6 1 1 1 o o o t t t

4 4 6 8 6 0 7 7 , 2 3 2 8 2 0 6 3 5 5 , 1 5 6 - - . 0 f s s f s e t o o s u 0 t l e r o r e n a 2 e H b b v . b m u y m u u S r a 5 N N n i 6 B 1

1 2 8 8 8 6 4 4 2 2 2 + 5 1 2 6 3 1 2 4 2 2 2 - 2 0 , 0 , 1 1


8 4 2 2 6 1 + 5 2 4 2 2 6 - 6 49




200.10.10.192

to 200.10.10.2 200.10.10.223 23


200.10.10.128

What is the subnet broadcast address for the 3rd usable subnet? ________________________

200.10.10.127


200.10.10.161 to 200.10.10.19 200.10.10.190 0

50



200 . 10 . 10 . 0 0 0 0 0 0 0 0 (Invalid range) 0 200.10.10.0 to 1 200.10.10.32 to 1 0 200.10.10.64 to 1 1 200.10.10.96 to 1 0 0 200.10.10.128 to 1 0 1 200.10.10.160 to 1 1 0 200.10.10.192 to (Invalid range) 1 1 1 200.10.10.224 to

12 8 128 64 +32 224

8 -2 6

32 -2 30

200.10.10.31 200.10.10.63 200.10.10.95 200.10.10.127 200.10.10.159 200.10.10.191 200.10.10.223 200.10.10.255

51

Subnetting Problem 15 Network Address 93.0.0.0 \19

A 255 . 0______ . 0______ . 0______ ___ ______ ______ ______ ______ ______ ____ _ Default subnet mask ______ 255 . 255 . 224 . ______ 0 ____ ___ ______ ______ ______ ______ ______ ______ ______ _ Custom subnet mask ______ 2,048 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of subnets ____ 2,046 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable subnets ____ 8,192 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Total number of host addresses ____ 8,190 __ ____ ____ ____ ____ ____ ____ ____ ___ _ Number of usable addresses ____ 11____ __ ____ ____ ____ ____ ____ ____ ___ _ Number of bits borrowed ____ __ ____ ____ ____ __ Address Addre ss class ____


93.1.192.0 to 93.1.223.255


93.1.0.0


93.0.223.255


93.1.96.1 to 93.1.127.254

52


2 4 4 4,3 0 4,1 9 6 1 ,1 52 , 9 7 2 0 2 3 4 8 5 ,5 76 ,0 1 0 4 6 8 4,2 8 8 52 2 1 62,1 4 4 6 2 5 ,0 72 2 131 0 . . 8

5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 2 2 2 2 2 . 2 2 2 . 2 2 . 2 . . 2 . . 2 . 1 2 . 2 . . . . 7 9 1 3 5 . . 7 9 1 3 0 1 3 5 1 3 5 9 2 2 5 9 2 2 5 2 5 9 6 1 0 3 9 1 3 6 . . . . 1 1 2 1 . 2 . . . . . . . . 1 . 2 . 4 1 1 1 1 1 1 1 . 0 . 0 . . 0 . 0 0 . . . . 0 . . 0 . 0 . . 0 . 8 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 0 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 6

0 0 o o o o o o o o o o o o o o o t t t t t t t t t t t t t t t 4 6 0 8 2 1 0 0 . . 0 0 . 0 0 0 0 . . . . . . 0 0 0 1 4 0 0 6 . 2 0 . 8 3 . 0 . 2 51 5 5 . . 8 0 2 0 0 6 5, 0 . 2 2 4 6 2 9 6 . 2 2 4 6 2 6 9 ,76 8 ,02 4 1 0 1 1 0 0 9 1 3 2 32 7 6 1 0 1 3 9 6 . . . . . . . . . . . . . . 1 . 8 4 4 4 0 0 8 0 0 0 0 1 1 0 0 0 1 1 1 1 0 1 2, 3 , 0 16 . . . . . . . . . . . . . . . 8 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 2 ,0 96 8,1 9 4 0 0 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 6 6 1 2 9 9 1 0 0 , , 8 4 0 2 8 4 1 0 1 0 1 0 1 0 1 0 1 0 1 0 ,0 4 8 3 0 0 2 0 16,3 4 ,76 8 ,02 4 6 0 1 0 32 7 0 1 0 1 0 1 0 1 0 ) 1 1 0 1 8 e 6 2 ,53 51 1 0 g 1 1 1 1 0 0 0 1 6 5 5 0 1 1 . 2 . n . a . . . . . . . . 6 r 1 2 5 0 ,0 7 0 131 1 1 1 1 1 1 1 2 d 2 8 i l 2 ,1 4 4 1 0 a 262 4 4 ,2 8 8 6 4 2 0 v 5 n I 8 6 7 2 5 5 , 3 0 ( ,0 4 8 1 0 6 6 2 1 0 1 7,1 5 9 0 , 2 8 2 4 3 0 4,3 0 9 1 , 4 4 4 6 0 2 8 2 1 0 s . e 3 f s u f s l o t o t a s 9 r o e r e e n v H b m u N

1

2 3

b b y m u r u S a N n i B

8 2 6 4 1 5 8 8 8 8 6 4 4 2 2 2 4 4 0 4 2 + 1 2 6 3 2 6 , 3 2 , 0 5 1 1 + 2 2 2 2

0 2 2 9 9 1 , , 1 8 8 53

Valid and Non-Valid IP Addresses Using the material in this workbook identify i dentify which of the addresses below are correct and usable. If they are not usable addresses explain why. why.

The network ID cannot be 0.

IP Ad Address: 0.2 0.230.190.192 Subnet Mask: 255.0.0.0

____ ______ ___ _____ ______ ____ ___ _____ ______ ____ ___ _____ ______ ___ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ __

IP Address: 192.10.10.1 Subnet Mas Mask: 255 255.255.255.0

_ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ _ _ ____ ______ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __

IP Addre ddres ss: 245. 45.150. 50.190 190.10 Subnet Mas Mask: 255 255.255.255.0

245 is reserved for experimental use. ____ __ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __ This is the____ broadcast address ____ __ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __ for this range. ____ __ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __ 127 is____ reserved for loopback _testing. _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ __ _O _ _K _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ _ _ _ __ _ _ _ _ __

IP Addre ddres ss: 135. 35.70.1 0.191. 91.255 Subnet Mas Mask: 255 255.255.254.0 IP Addre ddres ss: 127. 27.100. 00.100 100.10 Subnet Mask: 255.0.0.0 IP Ad Address: 93 9 3.0.128.1 Subnet Mas Mask: 255 255.255.224.0

OK

____ ______ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __ ____ ______ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __

____ ______ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __

IP Ad Address: 200 200.10.10.128 Subn Subnet et Mask Mask:: 255. 255.25 255. 5.25 255. 5.22 224 4

This is_the subnet address for the___ ____ __ ____ ___ ____ ______ ____ ___ _____ __ ____ ____ ___ _____ ______ _ ________________________________ 3rd usable range of 200.10.10.0

IP Addr Addres ess: s: 165. 165.10 100. 0.25 255. 5.18 189 9 Subn Subnet et Mask Mask:: 255. 255.25 255. 5.25 255. 5.19 192 2

______ _________ ______ ______ ______ ______ ______ ______ ______ _____ __ ________________________________

IP Address: 190.35.0.10 Subn Subnet et Mask Mask:: 255. 255.25 255. 5.25 255. 5.19 192 2

_This _ _ _ _address _ _ _ _ _ _ _is _ _taken _ _ _ _ _from _____ __ _ _____ the first ________________________________ range for this subnet which is invalid.

IP Ad Address: 218 218.35.50.195 Subnet Mask: 255.255.0.0 IP Addr Addres ess: s: 200. 200.10 10.1 .10. 0.17 175 5 /22 /22

IP Addre ddres ss: 135. 35.70.2 0.255. 55.255 Subnet Mas Mask: 255 255.255.224.0 54

OK

This has a class B subnet mask. ___________ ______ ___________ ___________ __________ A class__________ C address must use_____ a ____ __ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __ minimum of 24 bits. ____ __ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __ This is____ a____ broadcast address. ____ ______ ___ _____ ______ ____ ___ _____ ______ ____ ___ _____ ______ ___ _ ____ ______ ___ _____ ______ ____ ___ _____ ______ ____ ___ _____ ______ ___ _

____ ______ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __

Class Class A Addressing Guide # of Bits Borrowed 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22

Subnet Mask 255.192.0.0 255.224.0.0 255.240.0.0 255.248.0.0 255.252.0.0 255.254.0.0 255.255.0.0 255.255.128.0 255.255.192.0 255.255.224.0 255.255.240.0 255.255.248.0 255.255.252.0 255.255.254.0 255.255.255.0 255.255.255.128 255.255.255.192 255.255.255.224 255.255.255.240 255.255.255.248 255.255.255.252

Total Total # of Subnets 4 8 16 32 64 128 256 512 1,024 2,048 4,096 8,192 16,384 32,768 65,536 131,072 262,144 524,288 1,048,576 2,097,152 4,194,304

Usable # of Subnets 2 6 14 30 62 126 254 510 1,022 2,046 4,094 8,190 16,382 32,766 65,534 131,070 262,142 524,286 1,048,574 2,097,150 4,194,302

Total # of Hosts 4,194,304 2,097,152 1,048,576 524,288 262,144 131,072 65,536 32,768 16,384 8,192 4,096 2,048 1,024 512 256 128 64 32 16 8 4

Usable # of Hosts 4,194,302 2,097,150 1,048,574 524,286 262,142 131,070 65,534 32,766 16,382 8,190 4,094 2,046 1,022 510 254 126 62 30 14 6 2

Total # of Hosts 16,384 8,192 4,096 2,048 1,024 512 256 128 64 32 16 8 4

Usable # of Hosts 16,382 8,190 4,094 2,046 1,022 510 254 126 62 30 14 6 2

Total # of Hosts 64 32 16 8 4

Usable # of Hosts 62 30 14 6 2

Class B Addressing Guide # of Bits Borrowed 2 3 4 5 6 7 8 9 10 11 12 13 14

Subnet Mask 255.255.192.0 255.255.224.0 255.255.240.0 255.255.248.0 255.255.252.0 255.255.254.0 255.255.255.0 255.255.255.128 255.255.255.192 255.255.255.224 255.255.255.240 255.255.255.248 255.255.255.252

Total Total # of Subnets 4 8 16 32 64 128 256 512 1,024 2,048 4,096 8,192 16,384

Usable # of Subnets 2 6 14 30 62 126 254 510 1,022 2,046 4,094 8,190 16,382

Class C Addressing Guide # of Bits Borrowed 2 3 4 5 6

Subnet Mask 255.255.255.192 255.255.255.224 255.255.255.240 255.255.255.248 255.255.255.252

Total Total # of Subnets 4 8 16 32 64

Usable # of Subnets 2 6 14 30 62

Inside Cover

IP Addressing and Subnetting - Instructors Workbook

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