!"#$% '$()$* +$,-$. 1.
!+! '$/.$01$. +23.0$
If the coefficient of sliding friction…
6. A 250-g stone is attached to a 50-cm…
N = W = 150 lb
F
(
)(
F = µ N = 0.05 150
=
) 7.
F = 7.5 lb
Fforward = F = 7.5 lb
mv 2 r
=
(0.25 kg) ( 2 m/s)
=
2N ! Ans
A 600 N block rests on a 30° plane…
I
=
I
=
I
=
11. An inverted cone (apex down) has….
A 3200 lb car traveling with a speed…
3mr 2 10 3(10)(2)2 I 10 I 12 ! Ans I
Fc
m
=
v
2
KD
r
Q
! ft $ # 88 s & % 3200 lb "
=
ft
32.2
s Fc
KD
=
484 ft
12. A car is traveling at 60 kph….
!F
2
1590 lb
=
x
' Ans
=
0
Pcos30° Pcos30° = F + 600sin30° 600sin30°
3.
=
=
2
Fc
2mr 2 3 2(10)(3)2 3 60 ! Ans
ND KD
2.
10. Determine the moment of inertia…
2
0.50 m
Ans
!
4!56 7
A 400 kN block is resting on a rough… N=W
Pcos30° Pcos30° = µN µ N + 600sin30° 600sin30°
!Fy
N = 400 kN
=
!
Eq. 1
0
a
=
a
=
!v !t
40
" $ hr #
km 1000 m
=
1 km
% " 1 hr % ' $ 3600 s ' & # &
6s
1.85 m/s
2
( Ans
13. A man, standing on a cliff overlooking…
F = µN
(
F = 0.40
N = 600cos30° + Psin30°
)( 400)
4.
Eq. 2
s = v o t ±
F = 160 kN P = F = 160 kN
!
Substitute Eq. 2 in Eq. 1:
Ans
!
!
y = 0 !
Pcos30 = 0.2 0.2 ! 600co 600cos30 s30 + Psin30 # +
"
A skier is on a 25° slope. His mass…
$
1 2 at 2
2 1 9.81) ( 2) ; y = 19.6 m ( 2
"
Ans
14. A tennis ball is dropped from the…
600sin30 0.866P = 103.923 + 0.1P + 300
% Ans
P = 527.31 N
40 =
!
8.
A pipeline crossing a river is… w = wp + wc
=
14 + 1 = 15 kg/m
1 2 at 2 1 2 0! 9.81 t ; t = 2.86 s 2
s = v o t ±
(
)
"
Ans
15. Two blocks weighing 8 kg and… Block 1:
2
N
H=
wL
8d
=
15(100) 8(2)
N = W cos25 cos25°
! wL $ # 2 & " %
T=
N = 711.27 N F = µN
)(711.27)
9.
" 56.90 = 80a a = 3.43 m/s
2
# Ans
5. A trapezoid with parallel bases…
A cable suspended from a level… Using squared property of parabola: 2
100
a+b 3
=
2( 2) + 4 3 2+ 4 3
x =
30
2a + b h
H2
! 15(100) $ 2 + 9375 #" 2 & % T = 9405 kg ' Ans
! F = ma
y =
+
Block 2:
T=
F = 56.9 N
°
9375 kg
2
F = 0.08
( 80)( 9.81) sin25
=
2
( )( 9.81) cos25°
N = 80
(
2
1.33 ! Ans
x
10 100
2
x
=
=
16. A car travels at the constant speed… The average speed is equal to that of the constant speed which would be required for the object to travel the same distance d in the same time t.
2
2
=
Solve for a in eq. 1 and eq. 2: a = 1.4 2 m/s
3 57.8
! Ans
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P9,)%9; +PQQB 8%=:F 'F <9?9 6-F E$%F OKNR7JM
!"#$% '$()$* +$,-$. v = v =
!+! '$/.$01$. +23.0$
dtotal
v x = v ox ± a x t
t total
v x = 160cos53° + 0
20 + 20 + 20 20 20 20 + + 30 40 50
v x = 96 ft/s
v = 38.2 mph
!
!
Ans
Analyze the vertical component of the motion. Note: The vertical acceleration is due to gravity (ay = g)
Ans
4!56 7 1 2 at 2
s = Vot ±
2 1 a (0.6 ) 2 450 cm/s 2
81 = 0 + a =
F = ma
(
F = (1000 g ) 450 cm/s 2
17. During the takeoff, an Airbus A380…
F = 450,000 dynes
)
!
Ans
26. A baseball pitcher throws a ball… Get the resultant of the two components:
m
18. A dragster reaches a quarter mile… 2
W
v =
v 2x + v 2y
v =
962 + 642
=
mg W g
=
1 lb 3
=
ft
32.2
s2
2
v = v o ± 2as
(
2
80 = 0 + 2a 402 a = 7.96 m/s
)
v = 115.4 ft/s
m !
F = ma
22. A ball is thrown with an initial velocity… v = v o ± at
(
t = 10 s
!
0.01 slugs
Ans
2
80 m / s = 0 + 7.96 m/s
=
2
)t
Ans
19. A ball is released from rest at a…
Analyzing just the vertical component of the motion, at the highest point the velocity (vertical component only) is zero:
(
F = ( 0.01 slugs ) 480 ft/s 2 F
=
5 lb
sin ! = ! =
0 = 160sin53 ° ! ( 32.2) t "
tan ! =
Ans
23. A ball is thrown with an initial velocity… R
=
R
=
R
=
Ans
!
27. The outside curve on a highway…
v y = v oy ± ayt t = 4 s
tan7.66° =
Vo2 sin2!
4 30 7.66° v2 Rg v2
(150) (32.2)
v = 25.4 ft/s
"
Ans
g 1602 s in 2 ( 53 ) 32.2 764 ft " Ans
28. A satellite is placed in a circular… R = Rearth + 100 6
20. An airplane lands on a carrier deck…
)
5
R = 6.4 ! 10 m + 1.6 ! 10 m
24. A 65-lb horizontal force is sufficient… N = W = 65 lb
Fgravity
Fapplied = F = 1200 lb F = µN 1200 = µ ( 65) µ=
0.054
!
6
R = 6.5 ! 10 m
Ans
25. A 1000-gram mass slides down an… 21. A ball is thrown with an initial velocity… This is a problem in projectile motion. Analyze first the horizontal component of the motion. Note: The ball is not accelerating horizontally.
=
mg
=
g
=
v
=
mv2 R v2 R
! "
# 9.81
v 8000 =
T
m $
( 6.5 ' 10 m) 6
% s2 &
m s
2!R =
v
(
6
)
2! 6.5 " 10 m T
=
8000 T
89:3)2; <)'+ 83)%=),:> 49?3@ +$,-.3A BB> CD EF 5%2,02 6-F> G$* H3#I9, +<; DJ7C JKL MNKO
Fc
=
85 min
m s
#
Ans
P9,)%9; +PQQB 8%=:F 'F <9?9 6-F E$%F OKNR7JM
!"#$% '$()$* +$,-$.
!+! '$/.$01$. +23.0$
4!56 7 2
29. A cable 800 m long weighing 15.5…
tan ! =
35. When a 3000 N boat is moving at…
2
" m % $# 215 s ' & tan ! = " m % (1750 m) $# 9.81 s2 ' & ! = 69.6° ( Ans
v 2 = vo2 ± 2as 0 = 32 ! 2as a =
4.5 s
w a = R = 30V g
s+y c 400 + 500 300loge 300 330 m ! Ans
x = cloge x = x =
39. A flywheel 6 ft in diameter accelerates…
w 4.5 = 30V g s
30. From the cable in the previous…
V = V =
!
v1 + v 2
!
2
!
3+0
=
=
=
" f # " i t
& rev 2% rad 1 min ) ( 4 min $ 1 rev $ 60 s + # 0 ' * 10 s 0.42 rad/s
9.81
s
v = x
( )
30 1.5
"80 =
!3 =
(
)
0 ! 9.81 t
x = 422 m
2
Ans
!h
= 0!
2
at
Vertical component of the motion:
"
y = Voyt ±
Ans
2400 =
!
33. Suppose that you throw a ball…
t = !
(
)
2 9.81 h
Horizontal component of the motion:
h = 5.10 m x = Vox t ± hmax = 5.10 + 2 hmax = 7.10 m
"
Ans
(
1
x = 1200
2
axt
+
4
Ans
"
( vmax )
2
Rg
=
21.7 m/s $ Ans
h
=
h
=
1 gt t 2 12 1 (32.2)(1) ( 2) 2
=
32.2 s
!
Ans
43. A car starting from rest accelerates…
2
1000
( )
5 5
42. A man standing at the foot of a…
1 0 ! ( 9.81) t 2 2 22.12 s " Ans
2
2
!
4
=
v max
1 2 at 2 y
v = v o ± 2as 0 = 10
( )
+
( vmax ) 0.80 ) ( 60) (9.81)
2
(9.81)( 0.306) 2
h = 0.459 m
2
(
#1
tan 0 + tan
2
1
2
2
37. A rocket is released from a jet… 1
5x
2 5
tan (! + ") =
t = 0.306 s
s = Vo t ±
!
!
Note: since the curve is “unbanked”, angle of elevation ! = 0; " is called angle of friction and is equal to Arctan µ where µ is the coefficient of friction
2 ( 60) cos2 30°
#
3
2
41. What is the maximum speed at which…
2v 2 cos2 ! (9.81) x 2
x tan30° "
2x
v = 54 m/s
gx 2
v = v o ± at
!
( )
36. A projectile is fired with an initial…
32. Water drops from a faucet at the rate…
3
v = 5
s = 30.6 m ! Ans
y = xtan ! "
Ans
40. What is the velocity of a particle after…
31. On a certain stretch of the railroad… =
,
2
2
V = 1.5 m/s
3000 4.5
v Rg
1
2
) 3600 ( 22.12) + 2 (0.6)( 9.81)( 22.12)
x = 8813 m
34. A man weighing 70 kg is in an…
v = v o ± at
( )
120 = 0 + a 4 ; a = 30 ft/s s = v o t ± s = 0 +
38. An airplane makes a turn in a…
1 2
at
2
2
1
2
(30 ft/s )( 2) ; s = 60 ft 2 2
!
Ans
44. A car is traveling at 40 kph… v = v o ± at
" km 1000 m % " m % ( 6 t $# 40 hr ! 3600 s ' & $# s ' & t = 1.85 s ) Ans
0 =
89:3)2; <)'+ 83)%=),:> 49?3@ +$,-.3A BB> CD EF 5%2,02 6-F> G$* H3#I9, +<; DJ7C JKL MNKO
2
P9,)%9; +PQQB 8%=:F 'F <9?9 6-F E$%F OKNR7JM
!"#$% '$()$* +$,-$.
!+! '$/.$01$. +23.0$
45. A projectile is fired from the top… Vertical component of the motion:
Upward motion:
Horizontal component of the motion: v ox t ±
=
1
ax t
2
F
sx
=
(1314cos45) (58) + 0
sx
=
53,890 ft
!
Ans
=
=
20 lb
!
Ans
mg
=
!
Ans
57. What is the combined kinetic energy…
51. What is the resultant force on a body…
2
(120)
6
174 = ( 6 + m) ( 9.67); m = 12 kg
It will also take 12.23 s to move downwards. Therefore, total time is 25 s.
t = 58 s
sx
W
0 = 120 ! 9.81t ; t = 12.23 s
1 (32.2) t 2 2
=
56. Two blocks of mass 6 kg and m kg…
v = v o ± at
!200 = (1314sin45) t !
1
Won moon
50. A tennis ball is projected upward…
1 2 at 2 y
sy = v oyt ±
4!56 7
KE
=
1 mv2 2
=
" km 1000 m % 1 ( 225 kg) $# 40 hr ! 3600 s ' & 2
2
ma
F
=
( 48 kg) ( 6 m/s )
KE
F
=
288 N
KE 13.89 kJ
2
Ans
!
=
( Ans
58. If a certain object with mass of 15 kg…
52. Two horses on opposite banks… 46. Two cars A and B are traveling in… y d
=
d
=
100 m +"( 70)10 ! ( 60)10 $ # % 200 m & Ans
PE
=
PE
=
PE
=
200 kN
47. A block weighing 400 N is pulled… ! Fhorizontal = 0
x
Phorizontal " f = 0
(
)=0
µ = 0.42 # Ans
240 kN
48. A moon revolves around the earth…
aN 2.7
mm s
2
=
1m "
=
1000 mm
2
r
( r )
=
( 2.7
r #6
" 10
=
)
=
3.7 " 10 m
r $
0
!Fy =
200sin # " 240sin ( 60 " #)
Ans
v
2
v
2
= 50 = v =
2 o
13.89
=
hr
# =
R=
s
2
13.89
v = 38.38
+
( )(
2 2 320
v =
atotal
=
an
atotal
=
4.6
r
= 2
2
= 4.6
2
( "381.5)
= 5
m s
2
' Ans
=
12.5mv
=
12mv
$
2
2
=
P
=
P
=
=
61. A charger delivers current of 6 A… E
ma
E
=
1.55 ! 10 J
=
90a 1.3 m/s
=
(1800 kg) $# !20
=
t =
IV
( 6 A ) (12 V )( 6 hr ) 6
"
3600 s 1 hr
Ans 3
2
# Ans
54. A car (mass = 1800 kg) is traveling…
F
2
Ans
=
"
12.5mv
=
R" W
=
=
W mgh ( 30) ( 9.81) (10) t t 60 49 W ! Ans
IVt
ma
)
Ans
=
=
2
2
E
F
2
(
m 25v 2
ma
=
2
" 0.5mv # 1 & 24 % mv ( $ 2 '
=
1000 " ( 90) ( 9.81)
1m * , 3.3 ft +
=
)
24x
=
1
2
( )
m 5v
! Fy
a 2
+0
0.5mv
IV;
2
2
2
-
=
=
at +
2
2
P
m s
1
mv
53. What is the upward acceleration…
s
320
+
!F + ! F
)
m
! m $ #" 38.38 s & %
an
2 y
R = 381.5 kN
2
2
2 x
m $ * ' 100 ft % ,+ )( s2 &
60. Find the average power necessary…
33°
m
2at s
+
=
2
0 = 200sin # " 240sin ( 60 " #) R=
vo
KE2
!KE
!Fy =
49. A car enters a 350-m radius curve… km
=
!KE
240cos( 60 " # )
!Fx = " 200cos # "
r
2
6
r
!
2
1
KE1
!KE
2
!
' 1 ! ( 1500 J . Ans
(15 kg ) ) 3 #" 9.81
59. If a car with initial velocity, v…
220cos40° " µ 400
v
mgh
cm % 1 m & 100 cm s2 '
!360 N ( Ans
62. Find the volume (in cm ) of a piece…
!
=
m ;v v
m =
=
!
70 g g 2.33 cm3
=
30cm3 " Ans
63. A golf ball was hit with a velocity of…
55. What is the weight of a person on…
89:3)2; <)'+ 83)%=),:> 49?3@ +$,-.3A BB> CD EF 5%2,02 6-F> G$* H3#I9, +<; DJ7C JKL MNKO
P9,)%9; +PQQB 8%=:F 'F <9?9 6-F E$%F OKNR7JM
!"#$% '$()$* +$,-$. Ft
=
!+! '$/.$01$. +23.0$
!mv "
F
=
!mv
t F 15 N
(0.050 kg) $# 90 s ' & ( 0
=
0.3 s
P
V =
t E
V =
E
=
=
Pt
=
=
I
2
! Ans
2
( 220 V )
E
;
=
2
T
R 60 s 15 ohms 194 kJ ! Ans
(IV ) t
(52.8 kW
hr )
!
24 hr 52.8 kW ! hr 1 day =
P2.50 P132 " Ans 1 kW ! hr =
66. A 200 gram apple is thrown from… 1
!KE
=
!KE
=
!KE
=
!KE
=
!KE
=
mv 2f "
2 1
1 2
(
=
2 9.81
2!
=
2.8 s
F
=
F
=
k
Q1Q2 2
=
d 15,000 N
(9
9
10
!
)
=
1 k1
+
1 k2
=
"
202
1 20
+
1 cal
T = 0.92 s
=
E = 4.56 ! 10
"34
"19
Js
J
)(
6.88 ! 10
s
"1
)
Ans
#
3
I 10log =
2
t = Ft
=
Ft
=
mv 2 " mv1
=
0"0
( )
18 5 " 12t t
=
! mv
d
1 30
2! 12
v
3
2
+5
2000 9.11 Fx
=
=
2
273
=
4000 m
"
W
12
2 =
86 dB
Ans
#
m2
I Io
I 10log =
10
;k eff = 12
lb
"
in
" !10 W % " 100 cm % $# 10 cm2 ' & $# 1 m ' &
lb
=
W
!12
60 dB
m2
79. A human ear can distinguish a…
in
Note: The time it travels one way is just 0.10 s.
ft 2
s 12 in
d
vt
=
=
1 ft
! #"
$ ( & %
ft 1150 0.10s s
)
=
' Ans
115ft
80. A ray of light travels from air at an…
m
341.9
1.33
c =
v 3 ! 10
=
v
T s
;v
2.26 ! 10
=
m
8
s
" Ans
81. Find the period of the 100-cm…
m s
= 11.7
8
!
Ans
=
( )
2 1s
=
2s
! Ans
82. The speed of light in a particular…
s
75. An electron at rest has a mass of…
7.5 s
69. Three concurrent forces at the origin… =
20
341.9
4! ( 20m)
Ans
#
=
Ans
2
Note: Solve first for the speed of sound in air at 20°C. The speed of sound in air at 0°C is approximately 330 m/s
68. A body initially at rest is acted upon…
10log
=
n
v = 330 1 +
"
39I Io
-10
74. How long will it take for sound to travel…
"19
10log
78. A sound has an intensity of 10 …
(0.003)( 0.005)
32.2
k eff
)
4.186 J 50.17 cal $ Ans
6.63 ! 10
d
16 dB
10
100lb m
SIL
Ans
"
!
2W
Ans
73. A block, weighing 100 lbs is suspended…
T = 2! 2
"
72. Two electrons (Q1 and Q2) of electrical…
1
)
( 0.2 kg ) (50 2
210 J #
2!
L g
mv 2i
m v 2f " v 2i
2 1
=
k eff
E = hf
(
!
I Io
77. What is the intensity level at a point…
67. What is the energy of emitted light…
E=
=
71. A 2-m long pendulum is pulled aside…
(1 A )( 220 V ) (10 days)
cost
c
v = 0.904c
65. A 1-A lamp on a 220 V line operates… E
=
(0.75c )( 0.48c )
1+
2
I 10log
R
E =
c
2
0.75c + 0.48c
v =
64. A toaster connected to a 220 V…
76. A choir is composed of 39 singers…
v1v 2
1+
) Ans
=
v1 + v 2
v =
m %
4!56 7
+7
2
=
9.11
=
E
=
E
=
E
3
"14
8.198 ! 10 !
mc
2
(9.11
"31
! 10
) (3
"14
8.198 ! 10
8
! 10
2
)
J
83. A 10-g mass attached to a spring…
Fx 660 N
E
=
mV
2
(
"31
J = 2 9.11! 10
Ans
v
8
=
)v
2.12 ! 10 m/s
Get the spring constant first using the period of the motion given in the problem:
2
#
Ans
70. A meteor is moving away from a…
89:3)2; <)'+ 83)%=),:> 49?3@ +$,-.3A BB> CD EF 5%2,02 6-F> G$* H3#I9, +<; DJ7C JKL MNKO
P9,)%9; +PQQB 8%=:F 'F <9?9 6-F E$%F OKNR7JM
!"#$% '$()$* +$,-$. !
=
!+! '$/.$01$. +23.0$
2" f
1
l' = l
2"
v
1!
c
=
f
2
2" =
2 10
(
m
2"
l' = 1 m
( 0.5c ) 1!
)
c
k
!
=
o is + if object is on the same side of the lens as the incident light (real object) o is – if the object is on the other side
2
=
2
f is – for a diverging lens (thinner in the center than at the sides)
2
!
T
4!56 7
2
l' = 0.866 m
0.010 k
87. An observer measures the length…
k = 0.10 N/m l' = l
Use the spring formula: F = kx
(
F = 0.10 F = 10
!2
(
0.5 m = 1 m
)(0.10 )
v = 2.59
!
1 s
l' = l
" 10
v
1!
(
l' = 5 m
4.068 ! 10 m 16
=
# %$ 3 " 10
2
& ( s '
m
c
s
m
=
2
V=
Time based on an Earth clock 8
d = 4.3 LY !
3 ! 10 m 1 s
!
( 0.385c ) 1! c
2
v1 + v 2 1+
V=
1 year
2
0.75c + 0.75c 1+
31,536,000 s
v1v 2 c
( 0.75c)( 0.75c) c 1.5c
4 0.55 (erect, smaller)
Note:
m = 1 means object and image have same size m < 1 means image is smaller m > 1 means image is larger 92. A penny is placed 4.0 cm in front… 1 1 1 = + f i o 1 1 1 = + 15 cm i 4 cm i = !5.45 cm (virtual)
m ! =
V = 0.96c
d = 4.068 ! 10 m
( !2.2)
2
1 + 0.5625
16
=
i o
+ value of m means image is erect - value of m means image is inverted
89. A spaceship moving away from the…
85. The star nearest Earth, Alpha Centauri…
=
m !
2
)
m !
m
l' = 4.61 m
V=
m ! =
90. An incident ray from water makes…
d = vt 4.068 ! 10 m
i o
( !5.45 )
4 m 1.4 (erect, larger) =
16
=
" m % 0.95 $ 3 ! 108 ' s & # 6 t = 142.74 ! 10 s v
v
2
t = 4.53 yr
d
!
8
1 year
" 8 m % 0.95 $ 3 ! 10 s ' # & 6 t = 142.74 ! 10 s
t=
1
31,536,000 s
d = vt v
)
Use formula for Lateral Magnification: 2
88. A rocket is moving with a velocity…
3 ! 108 m
d = 4.068 ! 10 m
d
2
N
16
t=
c
2
8
84. The star nearest Earth, Alpha Centauri… d = 4.3 LY !
v
!
1
i is + if the image is on the side of the lens opposite the incident light (real) i is – if the image is on the same side (virtual)
t = 4.53 yr
91. A diverging lens has a focal length of…
Use time dilation (since clock is now moving): t=
For reflection, angle of incidence is always equal to the angle of reflection. Therefore, the angle of reflection is also 55 degrees.
Use Thin-Lens Equation (it is assumed that the focal length is much greater than the thickness of the lens):
t' 1!
1 1 1 = + f i o 1 1 1 = + !5 cm i 4 cm i = !2.22 cm (virtual)
v2 c2 t'
4.53 =
2
1!
(0.95c) c2
t' = 1.41 years
86. An observer moves past a meter…
Note: f is + for a converging lens (thicker at the center than at the sides)
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93. A flea is located 3.0 cm from a… Spherical mirrors are curved mirrors used as image-forming devices. You can still use the thin-lens equation. Focal length of the spherical mirror is half its radius. 1 1 1 = + f i o 1 1 1 = + !5 cm i 3 cm i = ! 1.9 cm (virtual)
"
Ans
94. A far-sighted classmate is unable… Nearsightedness (myopia) can be corrected by using a diverging lens while Farsightedness (hyperopia) can be corrected by using a converging lens. P9,)%9; +PQQB 8%=:F 'F <9?9 6-F E$%F OKNR7JM
!"#$% '$()$* +$,-$.
f
=
D = D =
f 1 1 +
Meyepiece
+
10
i o 1 1 i
o 1
1
+
1.25 0.3 2.5 diopters
f eyepiece
!
D =
"
Ans
Note: i is – because the image and object are on the same side of the lens (image must be virtual) 95. A photographer has an 8x magnifier… Magnifying glasses are converging lenses.
=
=
=
=
25 cm f eyepiece 25 cm f eyepiece 2.5 cm
!
Ans
100. Given the microscope in… Mtotal = MobjectiveMeyepiece Mtotal = ( 20) (10) Mtotal = 200x
( 200) (9 nm) = 1.8µm
!
Ans
END
25 cm
M
4!56 7
99. From the previous problem…
1
D = 1
!+! '$/.$01$. +23.0$
f 25 cm
8
=
f
=
f 3.1 cm
!
Ans
96. A biology student wishes to use… M
25 cm =
f 25 cm
M
=
M
=
6 cm 4.17
=
4x
!
Ans
97. For the biology student in the… 25 cm
Mmax M=
=
f
25 cm
+1
6 cm
M = 5x
!
Ans
98. A laboratory microscope has a 20X… A typical microscope consists of a tube with a converging lens at both ends. The lens close to the object is called the objective lens. The lens through which one looks is called the eyepiece/ocular lens 16 Mobjective f objective =
Meyepiece
=
Mtotal
=
Mobjective 20 f objective
25 f eyepiece MobjectiveMeyepiece
=
16 cm f objective
=
16 cm f objective
=
0.8 cm
!
Ans
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