UNIVERSIDAD NACIONAL DE TRUJILLO
Facultad de Ingeniería Ingeniería Mecatrónica.
Mecánica de Fluidos Análisis de altura neta y potencia generada para una turbina pelton
ASIGNATURA Mecánica de Fluidos DOCENTE Ing. Bengoa Seminario, Juan AUTORES Narciso Vera Willy Ortiz Basilio Eli Paz Tadeo Edén
Martes, 24 de enero de 2017
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INDICE
INDICE ....................................................................................................................................................................... i Lista de ilustraciones ............................................................................................................................................... ii Introducción ........................................................................................................................................................... iii Objetivos ................................................................................................................................................................. iv Objetivo General………………………………………………………………………………………………………………………………………iv Objetivos Secundarios………………………………………………………………………………………………………………………………iv 1
Desarrollo………………………………………………………………………………………………………………………………………………….5 1.1 Datos otorgados por la dirección del proyecto…………………………………………………………………………………………5 1.2 Supuestos para el cálculo matemático……………………………………………………………………………………………………..5 1.3 Calculo de altura neta disponible para turbina Pelton, en 3 escenarios……………………………………………………6 1.3.1 Escenario 1: Altura Altura neta de diseño diseño……………………………………………………………………………………………….7 1.3.2 Escenario 2: Altura Altura neta máxima………………………………………………………………………………………………….9 1.3.3 Escenario 2: Altura Altura neta neta mínima mínima…………………………………………………………………………………………………13 1.4 Calculo de potencia generada para turbina Pelton, en 3 escenarios……………………………………………………….13 1.4.1 Escenario 1: Altura Altura neta de diseño……………………………………………………………………………………………..14 1.4.2 Escenario 2: Altura Altura neta máxima………………………………………………………………………………………………..14 1.4.3 Escenario 2: Altura Altura neta neta mínima mínima…………………………………………………………………………………………………14
2
Resultados Resulta dos ................................... .................. ................................... ................................... ................................... ................................... ................................... ................................... .......................... ......... 1 5
3
Conclusiones Conclusio nes ................................... .................. ................................... ................................... ................................... ................................... ................................... ................................... ....................... ...... 1 7
4
Bibliografía Bibliograf ía ................................... .................. ................................... ................................... ................................... ................................... ................................... ................................... .......................... ......... 1 8
5
Anexos .................................... .................. ................................... .................................. ................................... ................................... ................................... .................................... ................................ .............. 1 9
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LISTA DE ILUSTRACIONES
Figura Figura Figura Figura
1 Esquema de Central Hidroeléctrica Hidroeléctri ca .............................................. .................................................................................... ...................................... 6 2: Tipos de Turbinas Pelton ................................................. ..................................................................................................... .....................................................19 .19 3: Grafica de la ecuación ecuación implícita de Colebrrok Colebrrok ................................................................... ................................................................... 21 4: Grafica de la ecuación implicita implicita.............................................................................................. 24
LISTA DE TABLAS
Tabla 1 : Número de Reynolds y fricción para cada nivel de cámara de carga ........................ ...................... ..15 Tabla 2: Perdidas en la tubería .................................................................................................................... 16 Tabla 3: Altura neta disponible para la turbina Pelton (m) ................................................................. 16 Tabla 4: Potencia generada por la l a turbina Pelton (MW) ..................................................................... 16
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INTRODUCCIÓN
En la actualidad existen muchas fuentes de potencia mecánicas, como son los motores, las turbinas y los motores eléctricos que operan de forma eficiente a altas velocidades. Enfatizando en el presente informe en la turbina Pelton, el cual es uno de los tipos más eficientes de de turbina turbina hidráulica. Una Una turbo turbo máquina máquina motora, motora, de flujo flujo trasversal, trasversal, admisión admisión parcial y de acción. Consiste en una rueda (rodete o rotor) dotada de cucharas en su periferia, las cuales están especialmente realizadas para convertir la energía de un chorro de agua que incide i ncide sobre las cucharas. Las turbinas Pelton están diseñadas para explotar grandes saltos hidráulicos de bajo caudal. Las centrales hidroeléctricas dotadas de este tipo de turbina cuentan, la mayoría de las veces, con una larga tubería llamada galería de presión para trasportar al fluido desde grandes alturas. Al final de la galería de presión se suministra el agua a la turbina por medio de una o varias válvulas de aguja, también llamadas inyectores, los cuales tienen forma de tobera para aumentar la velocidad del flujo que incide sobre las cucharas. En este trabajo, con base en los conocimientos de energía por unidad de peso y potencia generada por la turbina Pelton en 3 distintos escenarios, como lo son en niveles máximo, normal y mínimo de operación en cámara de carga; se llegó a establecer la altura neta correspondiente y su potencia generada para estas condiciones, tomando datos otorgados por la dirección del del Proyecto y realizando supuestas condiciones para su análisis matemático. Finalmente se obtuvieron los resultados para los datos antes mencionados, los cuales se analizaron a través de gráficas y tablas, los cuales se muestran en el informe, así como las principales observaciones, conclusiones conclusiones y recomendaciones recomendaciones obtenidas de la experiencia.
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OBJETIVOS
OBJETIVO GENERAL
Determinar la altura neta neta disponible en términos de energía energía por unidad de peso de la turbina Pelton y la potencia generada por ésta, de acuerdo a los niveles normal, máximo y mínimo en cámara de carga, carga, para poder poder ser usada usada en una posterior posterior evaluación de generación del proyecto hidroeléctrico hidroeléctrico “Central UNT”.
OBJETIVOS SECUNDARIOS
Establecer la ecuación general determinada de energía y las pérdidas en esta aplicación, en especial, de esta turbo maquina motora.
Determinar el cálculo del número de Reynolds y el factor de fricción, para cada tipo de niveles de cámara de carga.
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UNIVERSIDAD NACIONAL DE TRUJILLO
1.1
Mecánica de Fluidos
DATOS OTORGADOS POR LA DIRECCIÓN DEL PROYECTO: La dirección del proyecto entrega para su análisis la siguiente información: información: NIVELES EN LA CAMARA DE CARGA: Nivel Máximo Nivel Normal Nivel mínimo de operación
: 2102.8 m.s.n.m : 2100.8 m.s.n.m : 2097.8 m.s.n.m
Características obra de aducción Tipo Longitud en tramo recto Diámetro interno Número y tipo de codos Bocatoma
: tubería exterior (pen stock) : 1227.8 m : 0.9 m : 2 codos a 45° (k=0.4) : bordes redondeados redondeados
NIVEL COTA MEDIA DEL INYECTOR Caudal: 5 m3/s
1.2
: 1416.8 m.s.n.m
SUPUESTOS PARA EL CÁLCULO MATEMÁTICO:
Las presiones son las mismas e iguales a la presión atmosférica así tenemos: P 1= P2=Patm Como el proyecto hidroeléctrico está ubicado en la provincia de Sánchez Carrión, la temperatura considerada es de 10°C. Se considera el estanque muy muy grande donde la velocidad velocidad del fluido es 0, así así mismo se deprecia la velocidad de salida: ν 1=0 m/s; ν2=0 m/s.
ℰ
Se ha considerado un tipo de material para la tubería de “hierro forjado”,
cuya rugosidad es =0.5x10-3. Para el caso de la viscosidad dinámica se ha considerado el valor de µ=1.139x10-3 a una temperatura de 10 °C. La densidad del agua a temperatura de 10°C tiene un valor de ρ=999.1 Kg/m 3.
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UNIVERSIDAD NACIONAL DE TRUJILLO
1.3
Mecánica de Fluidos
CALCULO DE ALTURA NETA DISPONIBLE PARA TURBINA PELTON, EN 3 ESCENARIOS:
Figura 1 Esquema de de Central Hidroeléctrica Hidroeléctrica Fuente: Diapositivas de Turbinas Pelton http://slideplayer.es/slide/8837496/
Calculando de altura bruta ( Z1 - Z2 ) : H1=Nmáx-Niny = (2102.8-1416.8 ) m.s.n.m H1=686m
H2 (Nivel medio y caudal 5 m3/s):
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UNIVERSIDAD NACIONAL DE TRUJILLO
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Despejando “Hn”, tenemos lo siguiente:
Hn = = + + 12 + ∗ ∗ ℎ ∗ ∗ Diferencia de altura
Perdidas en la tubería
Perdidas en los codos
Perdidas en la bocatoma
Considerando lo siguiente: P1= P2=Patm; ν1=0 0 m/s; ν2=0 m/s; la ecuación queda expresada de la siguiente manera:
1.3.1 Escenario 1: Altura neta de diseño
Hn = = 1 22 ℎ 12 ∗∗ 22 ∗
Dónde: k1=0.4, K2=0.2
Para calcular “Hn”,necesitamos ”,necesitamos conocer el valor de “ h f ”, cuya ecuación está dada
de la siguiente manera:
ℎ = f∗∗L2∗∗ ℰ
Donde f es el coeficiente de fricción que viene expresado a través de la siguiente ecuación:
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UNIVERSIDAD NACIONAL DE TRUJILLO
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2. −51 ℰ = √ ∗0. ∗ 0.1√ 3.7 ∗
Buscando el número de Reynolds (Re) para encontrar el factor de fricción (f) Calculando el número de Reynolds, tenemos:
Re999. =999.(1ρ∗∗7.νµ8598∗5D9)∗ 0.9 Re =Re(= 6204332. 1.139∗ 139 ∗ 10054− )
En la ecuación (IV) se remplaza el valor de Re y la constante de rugosidad para encontrar el factor de fricción se utilizó dos métodos A Través de la función Zero de Matlab encontramos encontramos que el factor de fricción es 0.0230 (deserrado a detalle en en Anexos 5.2). A través del método analítico nos da el valor del factor de fricción: 0.0172 la cual es más acertada para este análisis: Donde; f1=0.0172
f 1 ∗ L ∗ hf1 = = ∗ 2 ∗ 1720.9∗ ∗1227. 1222∗2 ∗7.9.88018∗07.1 859 hf1 = = 0.0172∗ hf1 = 73.935
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UNIVERSIDAD NACIONAL DE TRUJILLO
Mecánica de Fluidos
AHORA REEMPLAZANDO LOS VALORES OBTENIDOS EN LA ECUACIÓN GENERAL DE LA ENERGÍA PARA ENCONTRAR LA ALTURA NETA:
P1 P2 1 2 1 2 Hn = ( + ) + 1 22 + 2 ∗ 2 ∗ ℎ 2 ∗∗ 2 ∗ 1 2 Hn = = 12 12 ℎ 2 ∗ 2 ∗∗ Hn = 684684 73.73.935935 + 0.362 362 2 ∗0.9.9.4801 ∗ 4∗ ∗0.59 2 ∗0.9.9.2801 ∗ 4∗0.∗∗5∗0.59 Hn = 684684 74.74.297 97 2 ∗ 1.261261 0.630630 Hn = 606.551 1.3.2 Escenario 2: Altura neta máxima
1 2 Hn = = 1 22 ℎ 2 ∗∗ 2 ∗
Dónde : k1=0.4 k1=0.4 , K2=0.2
Para calcular “Hn”,necesitamos ”,necesitamos conocer el valor de “ h f ”, cuya ecuación está dada
de la siguiente manera:
f ∗ L ∗ ℎ = ∗ 2 ∗
Donde f es el coeficiente de fricción que viene expresado a través de la siguiente
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UNIVERSIDAD NACIONAL DE TRUJILLO
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− √ 0.1 3.7ℰ∗ = 2.∗ ∗5 1√
2. −51 ℰ = √ ∗0. ∗ 0.1√ 3.7 ∗ Re = (ρ ∗ νµ ∗ D) 999.1.1139∗ ∗1390.∗78671086−∗ 0.9) Re =Re(999. = 620512.151
Calculando el número de Reynolds, tenemos:
En la ecuación (IV) se remplaza el valor de Re y la constante de rugosidad para encontrar el factor de fricción se utilizó dos métodos A Través de la función Zero de Matlab encontramos encontramos que el factor de fricción es 0.260 (deserrado a detalle en en Anexos 5.3). A través del método analítico nos da el valor del factor de fricción: 0.0178 la cual es más acertada para este análisis: Donde; f2=0.0178
hf2 = = f2 ∗∗L2∗∗ 1780.9∗ ∗1227. 1222∗2 ∗7.9.88018∗00.1 786 hf2 = = 0.0178∗
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Como son dos tramos entonces:
hf 2 = 2 ∗ 0.0019 = 0.0038
AHORA REEMPLAZANDO LOS VALORES OBTENIDOS EN LA ECUACIÓN GENERAL DE LA ENERGÍA PARA ENCONTRAR LA ALTURA NETA:
P1 P2 1 2 1 2 Hn = ( + ) + 1 22 + 2 ∗ 2 ∗ ℎ 2 ∗∗ 2 ∗ 1 2 Hn = = 12 12 ℎ 2 ∗ 2 ∗∗ Hn = 686686 0.765+0.0038 038 2∗ 2 ∗0.9.4801801 ∗ ∗20.9 2 ∗0.9.92.801 ∗ ∗20.9 Hn = 6860.76882∗0.0130.0063 Hn = 685.199
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UNIVERSIDAD NACIONAL DE TRUJILLO
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ℰ − 0.1√ = 3.7 + 2.∗ ∗5 1√ − √ 0.1 3.7ℰ∗ = 2.∗ ∗5 1√
2. −51 ℰ = √ ∗0. ∗ 0.1√ 3.7 ∗
Calculando el número de Reynolds, tenemos:
Re999. =999.(1ρ∗∗7.νµ8598∗5D9)∗ 0.9 Re =Re(= 6204332. 1.139∗ 139 ∗ 10054− )
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UNIVERSIDAD NACIONAL DE TRUJILLO
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0. 0178 0 1 78∗ ∗ 3∗ 3 ∗ 7. 859 8 5 9 hf = = 0.9 ∗ 2 ∗ 9.801801 hf = 0.187 hf 3 = 2∗2 ∗ 0.187187 = 0.374374
Como son dos tramos entonces:
AHORA REEMPLAZANDO LOS VALORES OBTENIDOS EN LA ECUACIÓN GENERAL DE LA ENERGÍA PARA ENCONTRAR LA ALTURA NETA:
P1 P2 1 2 1 2 Hn = ( + ) + 1 22 + 2 ∗ 2 ∗ ℎ 2 ∗ 2 ∗∗ 2 ∗ 1 2 Hn = = 12 12 ℎ 2 ∗ 2 ∗ 2 ∗∗
Hn = 681681 73.935+0.37474 2∗ 2 ∗0.9.4801801 ∗ ∗200.9 2 ∗0.9.92.801 ∗ ∗200.9
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UNIVERSIDAD NACIONAL DE TRUJILLO
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1.4.2 Escenario 2: Altura neta máxima
Sean 2=91.65%, el valor de eficiencia de la turbina, entonces la ecuación queda expresada de la siguiente manera:
P2 = ∗ ∗ ∗ ∗ ∗ η1 P2 = 999. 999.1 ∗ 9.9P2.801∗01= 3.∗ 0685. 68755.199199 ∗ 0.5 ∗ 0.9165 9165 1.4.3 Escenario 3: Altura neta mínima
Sea 3=92.20%, el valor de eficiencia de la l a turbina, entonces la ecuación queda expresada de la siguiente manera:
P3 = ∗ ∗ ∗ ∗ ∗ η1
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UNIVERSIDAD NACIONAL DE TRUJILLO
Mecánica de Fluidos
Para el desarrollo de la ecuación general de energía y con el objetivo principal de obtener las alturas netas disponibles para la turbina Pelton, así como su respectiva potencia generada por ésta; para distintos escenarios de niveles de cámara de carga, fueron necesarios obtener valores como como :
Numero de Reynolds: Re
factor de fricción: f
hf1,hf2,hf3 hf ′1,1, hfhf 2,hf 3
Perdidas devido a la friccion en la tubería del scenario 1,2 y 3 respectivamente:
Perdidas en los tramos de tuberia agregados del scenario 1,2 y 3 respectivamente:
ℎ
Perdidas en la tuberia:
Altura neta disponible para la turbina:
Hn
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UNIVERSIDAD NACIONAL DE TRUJILLO
Mecánica de Fluidos
Tabla 2: Perdidas en la tubería PERDIDAS EN LA TUBERIA (m)
ALTURA NETA DE DISEÑO ALTURA NETA MAXIMA ALTURA NETA MINIMA
ℎ
PERDIDAS POR FRICCION 73,935
PERDIDAS POR TRAMOS AGREGADOS 0,362
TOTAL DE PERDIDAS
0,765 73,935
0,0038 0,374
0,7688 74,309
74,297
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Mecánica de Fluidos
Se logró determinar determinar la altura neta (cabeza) (cabeza) y la potencia potencia generada por la turbina Pelton en distintos niveles de cámara de carga y caudal turbinado, los cuales servirán para la evaluación de la generación de energía eléctrica del proyecto hidroeléctrico denominado “Central UNT”.
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Víctor L. Streeter. (1972). Mecánica de los fluidos . México: Pearson
Yunus. A. Cengel and Michel. A. Boles. (2010). Fluid Mechanics. México
Taller de fundición [En Línea], [Fecha de Consulta Consulta 20 de enero 2017] Disponible en : https://sites.google.com/site/ https://sites.goog le.com/site/tallerdefundici tallerdefundicion2015/7-cual-es-la-densi on2015/7-cual-es-la-densidad-del-agua dad-del-agua
Mecánica de Fluidos
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UNIVERSIDAD NACIONAL DE TRUJILLO
Mecánica de Fluidos
Solución de factor de fricción para la primera altura neta a través de métodos numéricos numéricos utilizando la función Zero para encontrar la gráfica de la ecuación y el valor v alor de f %Programa para encontrar el valor del factor de friccicon %Por: Narciso Vera Willy Marco %Al: 23/01/17 %---------------------------------------------------------------------------clc; clear all all; ; close all all; ; %INGRESO DE DATOS fprintf ('Ingreso ('Ingreso de datos :\n' :\n'); ); R = input ('ingrese el numero de reynolds (ejemplo 6204332.054) : '); '); E = input ('ingrese Rugosidad del material (ejemplo 0.5*10^-3) : '); ');
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Para la altura neta máxima y a 10% 1 0% del caudal del diseño cambia la velocidad vel ocidad del caudal
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