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By: Shreya Rajpal Abhinav Public School, Delhi th
Class: 12 Science
Certificate This is to certify that Shreya Rajpal of class XII science of Abhinav Public School, Delhi has completed his demonstration file under the supervision of Mr. Yadvendra Singh. She has taken proper care and shown utmost sincerity in the completion of this file.
I certify this file is up to my expectations and as per the guidelines issued by C.B.S.E.
Mr. Yadvendra Singh Signature
Project Report On Determination of the Oxalate Content in Guava Fruit
ACKNOWLEDGEMENT I express my deep sense of gratitude to my teacher Mr. Yadvendra Singh for his valuable guidance, inspiration inspiration and help provided in every aspect if this project. I am thankful to him for his constant evaluation of the project. Last but not the least, I extend my sincere thanks to my School, Assistant, and Friends, who played an important role in proper tunings of my project.
Shreya Rajpal 12 th Science
EXPERIMENT AIM: Guava is mainly a winter fruit. It has medicinal properties and is cultivated in almost every part of India. Approximate composition of this fruit is:
Constituents
% Amount
Water
76.10
Protein
1.50
Fats
0.20
Calcium
0.01
Phosphorus
0.04
Vitamin ´Cµ
0.03
Organic matter
14.50
Guava a fruit that contains maximum amount of Vitamin C, after Amala but amount of Vitamin C decreases with the ripening of Fruits.Vitamin C gets converted into oxalate with ripening of fruit. Thus amount of oxalate in the fruit is a reflection on the amount of Vitamin C in the fruit and its determination. Therefore, makes an important study.
OBJECTIVE: Determination of the oxalate ions in guava fruit at different stages of its ripening.
THEORY:
Oxalate content of fruit is made into the solution by boiling its pulp with distilled water and its amount in the solution in determined by redox titration using solution. potassium permagnate (KMnO 4 4 )
Transfer the pulp obtained into a 250ml beaker. Wash the pestle and mortar well with about 100ml of water and transfer the washing also into the beaker.
Boil the contents in the beaker for about 10 minutes. Cool and filter through a funnel. Collect the filtrate in a 250ml measuring flask. Make the volume up to the mark i.e. 250 ml by adding Distilled water. Label the flask as "Ripe guava solution".
Similarly, prepare 250 ml solution of 25g Semi Ripe, Raw Guava.
Now, Pipette out 10 Ml of Solution from one of the flask into a conical flask. Add 10 Ml of Dilute H 2 SO SO 4 4 to it. Warm the flask about 60 degree Centigrade and titrate it with 0.05M KMnO 4 4 Solution until the colour of the solution just changes to permanent Pink. Repeated the experiment with same solution till three concurrent readings are obtained.
Similarly, find out the amount of 0.05M KMnO 4 4 consumed for 10 Ml of three guava solutions. The guava solution which consumes maximum volumes of per magnate solution obtains maximum oxalate ions.
Compare the three titre value i.e. volume of KMnO 4 4 consumed for 10ml of the three guava solutions. The Guava solution contains maximum oxalate Ions. NOTE: The amount of oxalate ion present in the solution i.e. Fruit can be calculated quantitavely also. For this first standardizes the KMnO 4 4 solution by titrating it against standard oxalic acid solution. Then calculate the amount of oxalate ions by applying N 1V 1=N 2 2 V V2 2 and Strength = Equivalent Weight X N equation.
OBSERVATION: Molarity of the KMnO 4 4 Solution=0.05 Solution=0.05 M End point = Colourless to pink. Volume of guava solution Taken each time for titration=10 ML.
Guava Solution Ripped Guava Semi Ripped Guava Raw Guava
Buretting Initial
Reading Final
Volume of KmNo4
Concurrent Reading (ML)
CONCLUTION: The amount of oxalate ions increases with the ripening of Guava.
PRECAUTIONS:
Do not mix three fruits or their Solutions.
Boiled the crushed fruit with equal amount of water and for the same length of time in all cases.
Wash the pestle and mortar well before after every use.