Tugas 2 Perancangan Perkerasan Jalan Raya

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TUGAS 2 PERANCANGAN PERKERASAN JALAN RAYA

PERKERASAN LENTUR METODE BERTAHAP BERTAHAP

Disusun oleh: Teni Handayani

2411141096

Kelas C Sign up to vote on this title

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Tugas 2 Perancangan Perkerasan Jalan Ray

Pertanyaan: 1.

RENCANAKAN :

Tebal perkerasan untuk jalan 2 lajur 2 arah, data lalu lintas tahun 2015 seper

dibawah ini, dan jalan direncanakan dengan umur rencana UR = 4 + 8 tahun. Jik

 jalan tersebut dibuka tahun 2019 (pertumbuhan lalu lintas (i) selama pembanguna adalah 6% per tahun) 2.

DATA-DATA : Kendaraan ringan 2 ton :

1296 kendaraan

Bus 8 ton

:

309 kendaraan

Truck 2 as 13 ton

:

76 kendaraan

LHR 2015 = 1681 kendaraan/hari Perkembangan lalu lintas selama masa pelayanan adalah i = 9% 3.

BAHAN-BAHAN PERKERASAN 

Aspal Macadam (MS340)



Batu Pecah (CBR60) You're Reading a Preview Tanah / Lempung Kepasiran (CBR20)



Penyelesaian

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1. Lalu Lintas a. Jumlah Lajur Kendaraan

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Tugas 2 Perancangan Perkerasan Jalan Ray

 b. Koefisien Distribusi Lajur (C)

c. Angka Ekivalen Beban Sumbu Kendaraan (E)

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d. Lalu Lintas Harian Rata-rata dan Lintas Ekivalen

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Tugas 2 Perancangan Perkerasan Jalan Ray

LEP C

LEA 4





    ()       

Jmh

   ()       1

1

0.5

1636.170

0.5

0.00046

0.376

2309.588

0.5

0.00046

0.5

390.105

0.5

0.15924

31.060

550.666

0.5

0.15924

4

0.5

95.948

0.5

1.06482

51.084

135.439

0.5

1.06482

72

82.520



1

LEA 12

LET

   ()      

  

Jmh

1

6496.096

0.5

0.00046

1.494

LEP

82.52

1548.838

0.5

0.15924

123.318

LEA 4

116.484

380.944

0.5

1.06482

202.818

LEA 8

327.631

Jmh

99.502 205.07

327.631

LER 

You're Reading  a Preview  

Jmh

Unlock full access with a free trial.

UR  LET 4 LET 8

Download Trial LER 99.502 With 4 Free 1.67 205.076

8

2.5 LER

66.467 410.151

2. Daya Dukung Tanah Dasar (DDT) CBR tanah dasar = 5% DDT = 4.30 x log (CBR) + 1.7 = 4.30 x log (5) + 1.7 = 4.706

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Tugas 2 Perancangan Perkerasan Jalan Ray

Kelandaian 7%  Kelandaian II Iklim I < 900 mm/th

4. Indeks Permukaan (IP) a. Indeks permukaan pada akhir umur rencana (IP t)

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Tugas 2 Perancangan Perkerasan Jalan Ray

5. Mencari ITP CBR dasar tanah

= 5%

DDT

= 4.706

FR

= 1.0

IPo

= 3.9  –  3.5

IPt

= 1.5

1.67 LER 4

= 66.467

2.5 LER 12

= 410.151

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Tugas 2 Perancangan Perkerasan Jalan Ray

6. Koefisien Kekuatan Relatif (a)

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Aspal Macadam (MS340) Batu Pecah (CBR60) Tanah / Lempung Kepasiran (CBR20)

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Tugas 2 Perancangan Perkerasan Jalan Ray

7. Menetapkan tabel perkerasan UR = 4 tahun (ITP = 6) Untuk tabel lapis pertama:

Didapat tebal lapis permukaan sebesar 5 cm.

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Didapat tebal lapis pondasi sebesar 20 cm.

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Tugas 2 Perancangan Perkerasan Jalan Ray

UR = (4 + 8) tahun ITP = a1D1 + a2D2 + a3D3 8.3 = 0.26 D1 + 0.12 x 20 + 0.10 x 10 8.3 = 0.26 D1 + 3,4 D1 = 18.85 cm ≈ 19 cm

Sehingga, didapat lapisan perkerasan sebagai berikut: 

Aspal Macadam (MS340)

= 5 cm + 14 cm



Batu Pecah (CBR60)

= 20 cm



Tanah / Lempung Kepasiran (CBR20)

= 23 cm

Aspal Macadam (MS340)

14 cm

Aspal Macadam (MS340)

5 cm

You're Reading a Preview 20 cm Batu Pecah (CBR60) Unlock full access with a free trial.

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