Test Bank for Biology 11th Edition Raven

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Chapter Chapter 03 The Chemical Building Blocks of Life Multiple Choice Questions

1. Organic molecules have a carbon backbone and _____ such as -OH and -NH 2 that affect their chemical properties. A. chemical A. chemical groups B. R B. R groups C. extension C. extension groups D. functional groups

Blooms Level: 2. 2. Understand Gradable: automatic LO: 03.01.01 Describe Describe the relationship relationship between functional functional groups groups and macromolecules. macromolecules. Section: 03.01 Topic: Carbon: The Framework of Biological Molecules

2. A modified form of cellulose found in the exoskeletons exoskel etons of insects and crustaceans is known as: A. chitin B. starch B. C. amylose C. D. glycogen D.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.02.02 Relate Relate the structure of polysacch polysaccharides arides to their functions. functions. Section: 03.02 Topic: Carbohydrates: Energy Storage and Structural Molecules

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3. These biological compounds are non-polar and insoluble in water: A. proteins A. B. nucleic acids C. lipids D. carbohydrates D.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.05.01 Describe Describe the structure of of triglycerides. Section: 03.05 Topic: Lipids: Hydrophobic Molecules



























4. A DNA molecule containing 32% thymine would contain how much much cytosine? A. 18% B. 32% B. C. 36% C. D. 64% D.



























Clarify Question

What is the key concept addressed by the question? o The question asks about base pairing in DNA. What type of thinking is required? o You are being asked to analyze the percentage of thymine in a DNA molecule and calculate the amount of cytosine. What key words does the question contain and what do they mean? o 32% thymine – thymine – this this means that 32% of the total nucleotides in the DNA molecule are thymine Gather Content

What do you know about base pairing? How does it relate to the question? o DNA is double stranded and between the strands a thymine pairs with adenine and cytosine pairs with guanine through hydrogen bonds. Consider Possibilities

What other information is related to the t he question? Which information is m ost useful? o If 32% of the bases are thymine then there will be an equal amount of adenine (32%). The sum of thymine and adenine is thus 64%. o The rest of the nucleotides must be cytosine and guanine, 100% - 64% = 36% Choose Answer

Given what you now know, what information and/or problem solving approach is most likely to produce the correct answer? o If cytosine and guanine add up to 36% of the total nucleotides, and there are equal amounts of both nucleotides, then cytosine and guanine each comprise 18% of the total nucleotides in the DNA molecule. Reflect on Process

Did your problem-solving problem -solving process lead you to the correct answer? If not, where did the process break down do wn or lead you astray? How can you yo u revise your approach to produce a more desirable result? o This question asked you to analyze the composition of a DNA molecule to predict the amount of cytosine. If you got the correct answer, great job! If you got an incorrect answer, where did the process break down? Did you recall that thymine and adenine pair and will be present in equal amounts? Did you recall t hat cytosine and guanine al so pair and will be



























Blooms Level: 4. 4. Analyze Gradable: automatic LO: 03.03.01 Describe Describe the structure of of nucleotides. nucleotides. Section: 03.03 Topic: Nucleic Acids: Information Molecules

5. The covalent bonds connecting monomer units in sugars can be formed by the removal of a water molecule. This reaction is referred to as: rev: 09_11_2014_QC_53628 A. a hydrolysis reaction. B. an oxidation-reduction oxidation-reductio n reaction. reactio n. C. a dehydration reaction. D. a hydration reaction. reactio n.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.01.03 List List the different kinds kinds of biological biological macromolecules. macromolecules. Section: 03.01 Topic: Carbon: The Framework of Biological Molecules

6. This atom in its unbound state has four valence electrons. These electrons readily form single, double, and even triple bonds among themselves to become stable. This atom is: A. carbon. B. hydrogen. B. C. oxygen. C. D. nitrogen. D. E. phosphorus. E.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.01.01 Describe Describe the relationship relationship between functional functional groups groups and macromolecules. macromolecules. Section: 03.01 Topic: Carbon: The Framework of Biological Molecules



























7. Macromolecules are broken down to monomers in ___ A. dehydration A. dehydration reactions. B. denaturation B. denaturation reactions. C. hydrolysis reactions. D. anabolic D. anabolic reactions.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.01.03 List List the different kinds kinds of biological biological macromolecules. macromolecules. Section: 03.01 Topic: Carbon: The Framework of Biological Molecules

8. Relatively Relativel y small organic organic molecules with a central carbon atom which is bonded to a carboxyl group, an amino group, a carbon containing group, and a hydrogen atom are called: A. amino acids. B. fatty acids. C. enzymes. C. D. peptides. D. E. nucleotides. E.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.04.01 Describe Describe the possible levels levels of protein structure. structure. Section: 03.04 Topic: Proteins: Molecules with Diverse Structures and Functions Functions

9. Macromolecules Macromolecul es that are used by most organisms to store hereditary information are called: A. proteins. A. B. transfer RNA RNA molecules. C. ribosomal RNA molecules. molecules. D. DNA molecules. E. messenger RNA molecules.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.03.03 Discuss Discuss the functions functions of DNA and and RNA. Section: 03.03 Topic: Nucleic Acids: Information Molecules





























10. DNA and RNA RNA contain functi functional onal units units known as: A. peptides. A. B. enzymes. B. C. amino acids. D. nucleotides. E. fatty acids.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.03.01 Describe Describe the structure of of nucleotides. nucleotides. Section: 03.03 Topic: Nucleic Acids: Information Molecules

11. Carbohydrates are polymers formed of structural structural units called: A. amino acids. B. fatty acids. C. nucleotides. C. D. glycerols. D. E. monosaccharides.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.02.01 Describe Describe the structure of of simple sugars with with three to six carbons. carbons. Section: 03.02 Topic: Carbohydrates: Energy Storage and Structural Molecules

12. Proteins are polymers formed of structural units called: A. fatty acids. B. amino acids. C. nucleotides. C.



























13. Lipids are the only class of macromolecules that contain: A. amino acids. B. nucleotides. B. C. fatty acids. D. phosphate groups. E. monosaccharides. E.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.05.01 Describe Describe the structure of of triglycerides. Section: 03.05 Topic: Lipids: Hydrophobic Molecules



























14. A double stranded DNA strand contains 26 pyrimidines. How many purines will the copied strand contain? A. 0 B. 13 C. 26 D. 52



























Clarify Question

What is the key concept addressed by the question? o The question asks about base pairing between pyrimidines and purines. What type of thinking is required? o You are being asked to apply your knowledge of how pyrimidines and purines bind to each other in forming a double strand of DNA. What key words does the question contain and what do they mean? o Pyrimidines – Pyrimidines – the the nucleotides cytosine and thymine. o Purines – Purines – the the nucleotides adenine and guanine. Gather Content

What do you know about base pairing? How does it relate to the question? o Pyrimidines and purines on complementary strands of DNA through hydrogen bonding. Thymine pair s with adenine and cytosine pair s with guanine. Consider Possibilities

What other information is related to the question? Which information is most useful? o Because pyrimidines and purines form base pairs, for each pyrimidine there will be a purine. Choose Answer

Given what you now know, what information and/or problem solving approach is most likely to produce the correct answer? o If there are 26 pyrimidines in a double strand of DNA, then there will be 26 purines. Reflect on Process

Did your problem-solving problem -solving process lead you to the correct answer? If not, where did the



























15. The simplest and the most common monosaccharide is a six six-carbon -carbon sugar called: called: A. galactose. A. B. lactose. B. C. cellulose. C. D. glucose. E. sucrose. E.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.02.01 Describe Describe the structure of of simple sugars with with three to six carbons. carbons. Section: 03.02 Topic: Chemistry

16. Humans are unable to get metabolic energy from from cellulose because: A. cellulose contains very very little chemical energy. B. cellulose is not part of a normal diet. C. cellulose digesting enzymes are absent from the human gut. D. cellulose does not taste good. E. cellulose is present present in large quantities quantities in the gut.

Blooms Level: 2. 2. Understand Gradable: automatic LO: 03.02.02 Relate Relate the structure of polysacch polysaccharides arides to their functions. functions. Section: 03.02 Topic: Carbohydrates: Energy Storage and Structural Molecules

17. Chitin, a modified form of cellulose, is not only cross-linked cross -linked with proteins but its glucose units are modified with atoms of: A. nitrogen. B. hydrogen. B.





























18. The biological macromolecule that is least soluble in water is a(n): A. lipid. B. nucleic acid. C. protein. C. D. carbohydrate. D. E. enzyme E.

Blooms Level: 2. 2. Understand Gradable: automatic LO: 03.01.03 List List the different kinds kinds of biological biological macromolecules. macromolecules. Section: 03.01 Topic: Carbon: The Framework of Biological Molecules

19. Common lipids for energy storage are: A. steroids. A. B. phospholipids. B. C. cholesterols. C. D. waxes. D. E. triglycerides.



























21. Biological membranes contain bilayers containing containing mostly ______. ______ . A. oils A. B. prostaglandins B. C. triglycerides C. D. cholesterol D. E. phospholipids

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.05.03 Apply Apply knowledge of the structure structure of phospholipids phospholipids to the formation formation of membranes. membranes. Section: 03.05 Topic: Lipids: Hydrophobic Molecules

22. This type of lipid is found in pigments such as chlorophyll, in the visual pigment pigment retinal, and in rubber: A. steroid. A. B. wax. B. C. prostaglandin. C. D. terpene. E. phospholipid. E.



























24. The specific amino acid sequence of a protein is its ____. A. primary structure B. secondary structure C. tertiary structure C. D. quaternary structure

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.04.01 Describe Describe the possible levels levels of protein structure. structure. Section: 03.04 Topic: Chemistry

25. What is the difference in the bonding between alpha-helix and beta sheets? A. Hydrogen A. Hydrogen bonding between the amides only occurs in one of these two types of secondary structures. B. Hydrogen bonding occurs between the amides of adjacent chains in the sheets instead of between the amides in different di fferent parts of the t he helices. C. Sulfur C. Sulfur bridges allow the spring like turns in alpha helices and van der Waals dispersion allows the folds in beta sheets. D. Hydrogen D. Hydrogen bonding always occurs in the alpha helices but only occurs in parallel beta sheets.



























27. The information storage storage molecules of cells are called: A. hormones. A. B. proteins. B. C. phospholipids. C. D. enzymes. D. E. nucleic acids.

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.03.03 Discuss Discuss the functions functions of DNA and and RNA. Section: 03.03 Topic: Nucleic Acids: Information Molecules

28. The nitrogenous base that is only found in DNA and not in RNA is: rev: 02_22_2014_QC_45858

A. cytosine. A. cytosine. B. uracil. B. uracil.



























30. Fructose and galactose both have six carbon atoms, twelve hydrogen atoms and six oxygen atoms, just like glucose. A friend of yours says: "Since those sugars have the same number of atoms, they should have the same name." You answer: "While they do have the same number and type of atoms, A. they are all polysaccharides and have slightly different functions within organisms and therefore have different names." B. they are named differently because of their quaternary structures, which is very important in carbohydrates, especially glucose." C. they are named differently because when heated above their optimal temperature they become denatured and will not react with their th eir substrates." D. they are named differently because they are involved in different DNA nucleotide formation." E. they are named differently because they are alternate forms of the monosaccharide, glucose."

Blooms Level: 2. 2. Understand Gradable: automatic LO: 03.01.02 Recognize Recognize the different kinds kinds of isomers. Section: 03.01 Topic: Carbon: The Framework of Biological Molecules





























31. A candy bar contains 108 calori calories es per serving. There are 4 grams of carbohydrate, 5 grams of protein, and 8 grams of fat in a serving. How many of the calories come from fat? A. 72 B. 16 C. 18 D. 20



























Clarify Question

What is the key concept addressed by the question? o The question asks about calculating calories in fat. What type of thinking is required? o You are being asked to apply the number of calories per gram of fat to calculate the fat calories in a candy bar. What key words does the question contain and what do they mean? o 8 grams of fat – fat – to to calculate how many of the calories come from fat, you need to know how much fat is in the candy bar. Gather Content

What do you know about calories per gram? How does it relate to the question?



























Blooms Level: 3. 3. Apply Gradable: automatic LO: 03.05.02 Explain Explain how fats function function as energy-storage molecules. molecules. Section: 03.05 Topic: Lipids: Hydrophobic Molecules



























32. A low fat cookie with 2 grams of fat, 10 grams of carbohydrate, carbohydrate, and 2 grams of protein contains: A. 14 calories A. B. 56 calories B. C. 66 calories D. 126 calories



























Clarify Question

What is the key concept addressed by the question? o The question asks about the number of calories per gram of carbohydrate, fat, and protein. What type of thinking is required? o You are being asked to apply the calories per gram of fat, carbohydrate or protein to calculate the total calories in a cookie. What key words does the question contain and what do they mean? o 2 grams of fat, 10 grams of carbohydrate, and 2 grams of protein – protein – these these three compounds will make up all of the calories in the cookie. Gather Content





























calories?

Blooms Level: 3. 3. Apply



























35. Proteins are created with: A. phosphodiester A. phosphodiester bonds. B. peptide bonds. C. triglycerides. triglycerides.



























38. Enzymes function to: A. react with other enzymes to form a product. reaction s. B. catalyze chemical reactions. C. transport molecules and ions across membranes.



























40. Which of the following reactions is a dehydration dehydration reaction? A. A + H2O  B + C B. A + B + H2O  C



























Clarify Question

What is the key concept addressed by the question? o The question asks about dehydration reactions. What type of thinking is required?



































































































































































































































































































































































































































































































































































































































































































































































































Blooms Level: 3. 3. Apply Gradable: automatic LO: 03.04.03 Understand Understand the relationship relationship between between amino acid acid sequence and their their three-dimensional structure. structure. Section: 03.04 Topic: Chemistry



























63. Which amino acid is most most soluble in water? A. Valine A. B. Glycine B. C. Leucine C. D. Serine



























Clarify Question

What is the key concept addressed by the question? o The question asks about the solubility of functional groups in water. What type of thinking is required? o You are being asked to apply your knowledge of functional groups to predict which would be most soluble in water. What key words does the question contain and what do they mean? o Most soluble in water – water – this this means that the amino acid dissolves well in water. Gather Content

What do you know about abo ut solubility in water? How does it relate to the question? o The more polar a molecule is, the better it can dissolve in water. The more non-polar functional groups a molecule has, the less soluble it will be in water. Consider Possibilities

What other information is related to the t he question? Which information is m ost useful? o All four of the amino acids will have the same backbone structure with an amino group, an -carbon, and a carboxyl group. The differences will be with the structure of the side chains. o Three of the amino acids have non-polar side chains: glycine (H), valine (C 3H7), and leucine (C4H9). While none of these has polar groups, leucine has the most carbons and will be the most non-polar and an d hydrophobic. This will make isoleucine the th e least soluble in i n water. Choose Answer

Given what you now know, what information and/or problem solving approach is most likely to produce the correct answer? o Serine is the only amino acid with a polar side chain (CH 2OH), the hydroxyl group (OH) will interact well with water, making serine the most soluble in water. Reflect on Process

Did your problem-solving problem -solving process lead you to the correct answer? If not, where did the process break down do wn or lead you astray? How can you revise your approach to pr oduce a more desirable result? o This question asked you to apply the structure of an amino acid to predict its solubility. If you got the correct answer, great job! If you got an incorrect answer, where did the process break down? Did you know the structures of the amino acid side chains? Did you know which structures would be the most polar?



























Blooms Level: 3. 3. Apply Gradable: automatic LO: 03.04.03 Understand Understand the relationship relationship between between amino acid acid sequence and their their three-dimensional structure. structure. Section: 03.04 Topic: Proteins: Molecules with Diverse Structures and Functions Functions



























64. The formula formula for glucose is C 6H12O6. What is the formula for a polymer made by linking ten glucose molecules together by dehydration synthesis? A. B. C. D.

C60H111O51 C 60H120O60 C 60H100O50 C60H102O51





























Clarify Question

What is the key concept addressed by the question? o The question asks about the net reaction for a dehydration synthesis. What type of thinking is required? o You are being asked to analyze choices for the product of a dehydration synthesis reaction and choose the correct answer. What key words does the question contain and what do they mean? o Dehydration synthesis – synthesis – a a reaction used to join monomers together to form a polymer. As each monomer is added, a molecule of water is lost, this is why it is considered a dehydration reaction. Gather Content

What do you know about dehydration synthesis? How does it relate to the question? o Dehydration Dehydrati on synthesis is used to make polymers out out of monomers. If 10 glucose molecules are joined together then it would make sense to simply multiply the number of each atom in glucose by 10 to calculate how many would be present in the polymer. Based on this you would obtain the answer C 6H12O6 x 10 = C60H120O60. Consider Possibilities

What other information is related to the t he question? Which information is m ost useful? o One additional thing to consider is that a water molecule is lost as each glucose is joined together. If there are 10 glucoses joined together, there ther e would be 9 t otal dehydration reactions that took place. Choose Answer

Given what you now know, what information and/or problem solving approach is most likely to produce the correct answer? o Water has the chemical structure H2O. If a water molecule is lost in each dehydration reaction a total of 9 H O would be lost for for a total loss of H18O9. The formula of the final



























would only be 9 dehydration reactions? Did you know to subtract subtract the 9 water water molecules from the formula to get the final answer?

Blooms Level: 4. 4. Analyze Gradable: automatic LO: 03.01.03 List List the different kinds kinds of biological biological macromolecules. macromolecules. Section: 03.01 Topic: Carbon: The Framework of Biological Molecules

65. The myoglobin protein, which carries carries oxygen in muscle cells, has only only the first three levels of protein structure. What can you infer about myoglobin? A. Myoglobin is made of nucleic acids B. Myoglobin lacks hydrogen bonds made of only one polypeptide chain C. Myoglobin is made D. Myoglobin is not helical or pleated pleated

Blooms Level: 2. 2. Understand Gradable: automatic LO: 03.04.01 Describe Describe the possible levels levels of protein structure. structure. Section: 03.04 Topic: Proteins: Molecules with Diverse Structures and Functions Functions



























66. A phosphorus shortage in soil soil would make it difficult for plants to produce: A. DNA B. starch B. C. amylose C. D. cellulose D.



























Clarify Question

What is the key concept addressed by the question? o The question asks about which biological molecules contain phosphorus. What type of thinking is required? o You are being asked to apply your knowledge of the atoms found in different biological molecules molecule s to predict which whi ch could not be made by plants pla nts in a shortage of phosphorus. What key words does the question contain and what do they mean? o Phosphorus shortage – shortage – a a lack of phosphorus means that molecules that contain phosphorus may not be made mad e by the plant. Gather Content

What do you know about molecules that contain phosphorus? How does it relate to the question? o The primary molecules in cells that contain phosphorus are nucleic acids. Consider Possibilities

What other information is related to the t he question? Which information is m ost useful? o The word carbohydrate has the roots carbo- (carbon) and hydrate (water). Carbohydrates all have the base structure CH 2O repeated many times, and do not contain phosphorus. Choose Answer

Given what you now know, what information and/or problem solving approach is most likely to produce the correct answer? o DNA is deoxyribonucleic acid and contains nucleotides connected together by phosphates. The other opti ons are all carbohydrates and an d do not contain phosphate. phosphate . Reflect on Process



























Blooms Level: 3. 3. Apply Gradable: automatic LO: 03.03.01 Describe Describe the structure of of nucleotides. nucleotides. Section: 03.03 Topic: Nucleic Acids: Information Molecules

67. This is a nucleotide containing molecule that is commonly used to carry electrons in the cell. A. ADP A. ADP B. ATP B. ATP C. NAD+ D. pyruvic D. pyruvic acid

Blooms Level: 1. 1. Remember Gradable: automatic LO: 03.03.04 Recognize Recognize other nucleotides nucleotides involved in energy metabolism. metabolism. Section: 03.03 Topic: Nucleic Acids: Information Molecules





























68. Benedict's reagent is a chemical that is used as a test for the presence of a free aldehyde functional group on glucose. glucose. The aldehyde is used when glucose and fructose bind together to form sucrose, and the Benedict's test is negative. Starch contains a great deal of glucose but gives a negative Benedict's test because: A. all of the aldehyde groups on the starch are oxidized and cannot react with the Benedict's reagent. B. glucose in starch has has lost a carbon atom and cannot react react with Benedict's reagent. have an exposed aldehyde alde hyde functional C. only the glucose at the end of a chain of starch will have group to react with Benedict's reagent. D. starch is not soluble in water and cannot react with Benedict's reagent.



























Clarify Question

What is the key concept addressed by the question? o The question asks about the role of the aldehyde groups in glucose in the formation of starch. What type of thinking is required? o You are being asked to analyze the results of an experiment to explain the structure of starch. What key words does the question contain and what do they mean? o Benedict’s test – detects detects aldehyde on glucose. o Aldehyde on glucose – glucose – this this reacts with Benedict’s reagent and is also used to join together with other glucose molecules to form starch and with fructose to form sucrose. Gather Content

What do you know about the structure of starch? How does it relate to the question? o Starch is formed from multiple glucose molecules joined together through the aldehyde on one glucose and a hydroxyl group on another. Thus the aldehyde group is no longer present on a glucose molecule when it is in starch. Consider Possibilities

What other information is related to the question? Which information is most useful?



























structure of starch, did you understand that the glucose on the end of the starch molecule still has a free aldehyde?

Blooms Level: 4. 4. Analyze Gradable: automatic LO: 03.02.01 Describe Describe the structure of of simple sugars with with three to six carbons. carbons. Section: 03.02 Topic: Carbohydrates: Energy Storage and Structural Molecules



























69. What characteristic would the R groups groups of amino acids have if they are located within the interior of biological membranes? A. The R groups would be able to form ionic bonds. B. The R groups groups would be polar. C. The R groups would hydrophobic. D. The R groups would be hydrophili hydrophilic. c.



























Clarify Question

What is the key concept addressed by the question? o The question asks about the nature of amino acids in a membrane. What type of thinking is required? o You are being asked to apply your knowledge of the properties of amino acid side chains to predict which would be found in a membrane. What key words does the question contain and what do they mean? o R groups – groups – these these are the side chains of amino acids. These can be polar or non-polar. o Interior of biological membranes – membranes – this this is a hydrophobic, non-polar environment. Gather Content

What do you know about abo ut proteins in membranes? How Ho w does it relate to the question? o Membranes contain lipids and are hydrophobic, non-polar environments. Amino acids with side chains that are non-polar or hydrophobic will be more soluble in this environment. Consider Possibilities

What other information is related to the t he question? Which information is m ost useful? o R groups that are hydrophilic, polar or able to form ionic bonds will all be soluble in water. These will not be soluble in a lipid membrane.





























Blooms Level: 3. 3. Apply Gradable: automatic LO: 03.04.03 Understand Understand the relationship relationship between between amino acid acid sequence and their their three-dimensional structure. structure. Section: 03.04 Topic: Proteins: Molecules with Diverse Structures and Functions Functions



























70. Sudan IV, a dye that that binds to nonpolar molecules, is used to detect the presence of macromolecules in food. Sudan IV would test positive in the presence of what macromolecule? A. Starch A. B. DNA B. C. Hemoglobin C. D. Chitin D. E. Fats



























Clarify Question

What is the key concept addressed by the question? o The question asks about nonpolar molecules. What type of thinking is required? o You are being asked to apply your knowledge of the polarity of different macromolecules to predict which would bind to a dye. What key words does the question contain and what do they mean? o Sudan IV – IV – a a dye that binds to nonpolar molecules and turns those samples a color. Gather Content

What do you know about nonpolar molecules? How does it relate to the question? o Nonpolar molecules are hydrophobic and do not dissolve in water. water. Lipids and fats fats are



























Blooms Level: 3. 3. Apply Gradable: automatic LO: 03.05.01 Describe Describe the structure of of triglycerides. Section: 03.05 Topic: Lipids: Hydrophobic Molecules



























71. How many water molecules are produced during the formation of a triglycerid e from fatty acids and glycerol? A. 0 B. 1 C. 2 D. 3 E. 4





























Clarify Question

What is the key concept addressed by the question? o The question asks about the number of water molecules produced in a dehydration synthesis reaction.



























Blooms Level: 4. 4. Analyze Gradable: automatic LO: 03.05.01 Describe Describe the structure of of triglycerides. Section: 03.05 Topic: Lipids: Hydrophobic Molecules



























72. Acyclovir is an antiviral chemical that resembles a nucleotide but lacks a 3' OH group and cannot form phosphodiester bonds. Why is Acyclovir useful in treating some viral infections? A. Acyclovir stops viral protein synthesis.



























Clarify Question

What is the key concept addressed by the question? o The question asks about the role a 3’ OH group in the formation of phosphodiester bonds.



























Blooms Level: 4. 4. Analyze Gradable: automatic LO: 03.03.01 Describe Describe the structure of of nucleotides. nucleotides. Section: 03.03 Topic: Nucleic Acids: Information Molecules





























































































































































































































Test Bank for Biology 11th Edition Raven

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