Power Electronics Circuits Devices and Applications 4th Edition Rashid Solutions Manual

Power Electronics Circuits Devices and Applications 4th Edition Rashid SOLUTIONS MANUAL Full download: https://testbanklive.com/download/power-electronics-circuits-devicesand-applications-4th-edition-rashid-solutions-manual/ Chapter 2 – Diodes Circ uits Prob 2.1

6

di_dt := 80⋅10

−6

trr := 5⋅ 1 0 (a)

2

Eq. (2.10)

QRR := 0.5⋅ di_dt⋅ trr (b)

6

QRR⋅ 10 = 1 × 10

3

μC

Eq. (2-11)

IRR :=

2⋅ QRR⋅ di_dt

IRR = 400

A

Prob 2.2 −6

trr := 5⋅ 10

s

Ifall_rate := 800⋅ 10

6

A s

SF := 0.5

trr

ta := 1 + SF

−6

ta = 3.333 × 10

10 tb = 1.667 ×

tb := SF⋅ ta IRR := Ifall_rate⋅ ta

Using Eq. (2-7), (a)

1 2

−6

IRR = 2.667 × 10

3

QRR :=

(

)(

)

⋅ Ifall_rate⋅ ta ⋅ ta + tb

QRR⋅ 106 = 6.667 × 103

μC

1 2 QRR :=

(

)

⋅ IRR⋅ ta + tb

6

QRR⋅ 10 = 6.667 × 10

μC

Using Eq. (2-6), (b)

IRR := Ifall_rate⋅ ta

3

3

IRR = 2.667 × 10

Prob 2.3 −6

trr := 5⋅ 1 0

SF := 0.5

trr ta := 1 + SF

−6

ta = 3.333 × 10

10 −6

tb = 1.667 ×

tb := SF⋅ ta 1

⋅ ta⋅ trr

m :=

m

8.333 =

2

12

10 ×

−

QRR (x) := m⋅ x

Plot of the charge storage verus di/dt

Charge storage

0.008

0.006 QRR ( x) 0.004

0.002

0

8

2 .10

8

4 .10

6 .10

8

8

8 .10

9

1 .10

x di/dt

IRR (x) := ta⋅ x Plot of the charge storage verus di/dt 4000

Charge storage

3000

IRR ( x)

2000

1000

0 8 1 .10

Prob 2.5

8

2 .10

8

3 .10

VT := 25.8⋅

4 .10

8

8

8

6 .10 x di/dt

8

7 .10

8

8 .10

10 ID2 := 1500

ID1 := 100

Using Eq. (2-3),

VD2 −VD1

(a) η :=

⎛ ID2⎞ VT⋅ ln⎜ ⎟

η = 5.725

I

(b)

x :=

VD1 η ⋅V

⎝ D1 ⎠ x = 8.124

8

9 .10

−3

VD1 := 1.2

VD2 := 1.6

5 .10

9

1 .10

T

Using Eq. (2-3), IS :=

⎛ ID1⎞ VT⋅ η ⋅ ln ⎜ ⎟ = 1.2 IS ⎝ ⎠

ID1 x

e

IS = 0.03

Prob 2-7 VD1 := 2200

VD2 := 2200 −3

IS1 := 20⋅ 10

R1 := 100⋅ 10

3

−3

IS2 := 35⋅ 10

(a)

VD1

IR1 := R1

IR1 = 0.022

Usi ng Eq. (2-13),

(b)

IR2 := IS1 + IR1 − IS2

IR2 = 7 × 10

−3

VD2

R2 :=

IR2

5

R2 = 3.143 × 10

Prob 2.11 IT := 300

VD := 2.8

IT I1 := 2

I1 = 150

I2 := I1

VD1 := 1.4 Prob 2-7

I2 = 150

VD −VD1

VD2 := 2.3 −3

R1 :=

I1 VD −VD2

R2 := IT I1 := 2

I2

R1 = 9.333 × 10

−3

R2 = 3.333 × 10

Prob 2-13 R1 := 50⋅ 10

3

R2 := 50⋅ 10

−3

Is1 := 20⋅ 10

Is2 := 30⋅

3

VS := 10⋅ 10

3

−3

10 Usi ng Eq. (2-14),

VS IS1 − IS2 + R1 VD2 := 1 1 + R1 R2

3

VD2 = 4.625 × 10

3

VD1 := VS − VD2

VD1 = 5.375 × 10

Prob 2-15 Ip := 500

T :=

−6

t1 := 100⋅ 10

f := 500

1 f

3

T⋅ 1

=2

t Ip ⌠ 1

0

IAVG := ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0

IRMS := Ip

t1 1 ⌠

IAVG = 3.895

2

Ipeak := Ip Prob 2-13

⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0

3

IRMS = 20.08

3

3

Ipeak = 500

Prob 2-16 IRMS := 120 T :=

−6

f := 500

t1 := 100⋅ 10

1

3

T⋅ 10 = 2

f IRMS

Ip :=

Ip = 2.988 × 103

t1

1 ⌠ 2 ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0

t

IRMS := Ip

1 1 ⌠ ( sin ( 2⋅ π ⋅ f ⋅ t) ) 2 dt ⎮ ⋅ T ⌡0

IRMS = 120

t

Ip ⌠ 1 IAVG := ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0

IAVG = 23.276

Prob 2-17 IAVG := 100 T :=

1

f := 500

−6

t1 := 100⋅10 3

T⋅ 10 = 2

f Ip :=

IAVG t1

⎛

⎞

4

T

⎜1 ⌠ sin ( 2⋅ π ⋅ f ⋅ t) dt ⎜ ⋅⌡ ⎮

Ip = 1.284 × 10

0

⎟ ⎟⎠

Ip t

⌠1 IAVG := ⋅ ⎮ sin ( 2⋅ π ⋅ f ⋅ t) dt T ⌡0

⎝

IAVG = 100

t

IRMS := Ip

1 1 ⌠ 2 ⋅ ⎮ ( sin ( 2⋅ π ⋅ f ⋅ t) ) dt T ⌡0

IRMS = 515.55

Prob 2-18 −6

t1 := 100⋅ 10

−6

−6

t2 := 200⋅ 10

−6

t3 := 400⋅ 10

t4 := 800⋅ 10

−3

t5 := 1⋅ 10

f := 250

Ia := 150

Ib := 100

(a) I AVG := Ia⋅ f ⋅ t3 + Ib⋅ f ⋅ t5 − t4 + 2⋅ Ip − Ia ⋅ f ⋅

(

(

)

(

)

Ip := 300

( t2 − t1) π IAVG = 22.387

)

Ir1 := Ip − Ia ⋅ (b)

Ir1 = 16.771

( t2 − t1) f⋅ 2 Ir2 := Ia⋅ f ⋅ t3

Ir2 = 47.434

(

)

Ir3 := Ib⋅ f ⋅ t5 − t4

Irms

:=

2

2

Ir3 = 22.361

2

+I +I Ir1 r2 r3

I = 55.057 rms

Prob 2-19 −6

t1 := 100⋅ 10

−6

−6

t2 := 200⋅ 10

t3 := 400⋅ 10

−3

Chapter 2-Diodes Circuits Page #2-7

−6

t4 := 800⋅ 10

t5 := 1⋅ 10

f := 250

Ia := 150

Ib := 100

(a) I AVG := Ia⋅ f ⋅ t3 + Ib⋅ f ⋅ t5 − t4 + 2⋅ Ip − Ia ⋅ f ⋅

(

(b)

(

)

Ir1 := Ip − Ia ⋅

f⋅

)

(

)

2

IAVG = 20

Ir2 = 47.434

(

Irms

π

Ir1 = 0

)

Ir3 := Ib⋅ f ⋅ t5 − t4

2

( t2 − t1)

( t2 − t1)

Ir2 := Ia⋅ f ⋅ t3

:=

Ip := 150

2

Ir3 = 22.361

2

+I +I Ir1 r2 r3

Chapter 2-Diodes Circuits Page #2-8

I = 52.44 rms

Prob 2-20 −6

−6

−6

t1 := 100⋅ 10

t2 := 200⋅ 10

−6

t3 := 400⋅ 10

t4 := 800⋅ 10

−3

t5 := 1⋅ 10

f := 250

Ia := 150

Ib := 100

Ip := 150

Irms := 180

Ir2 = 47.434

Ir2 := Ia⋅ f ⋅ t3

(

Ir3 = 22.361

)

Ir3 := Ib⋅ f ⋅ t5 − t4

Ir1

:=

2

Irms

2

Ir1

(a) Ip :=

( t2 − t1) f⋅

(

:=

Ir1 = 172.192

+ Ia

Ip = 1.69 × 10

3

2

)

Ir1 := Ip − Ia ⋅

Irms

2

−I −I r2 r3

2

Ir1

f⋅

( t2 − t1) 2

2

Ir1 = 172.192 2

+I +I r2 r3

Irms = 180

(b) Chapter 2-Diodes Circuits Page #2-8

IAVG := Ia⋅ f ⋅ t3

(

( t2 − t1) π

)

+ Ib⋅ f ⋅ t5 − t4 +

(

)

2⋅ Ip − Ia ⋅ f ⋅

IAVG = 44.512

Chapter 2-Diodes Circuits Page #2-9

Prob 2-21 −6

−6

−6

t1 := 100⋅ 10

t2 := 200⋅ 10

t3 := 400⋅ 10

−6

t4 := 800⋅ 10

−3

t5 := 1⋅ 10

f := 250

Ia := 150

Ib := 100

Ip := 150

IAVG := 180 (a)

Iav1 := Ia⋅ f ⋅ t3

Iav1 = 15

(

)

Iav2 := Ib⋅ f ⋅ t5 − t4

Iav2 = 5

Iav3 := IAVG − Iav1 − Iav2

Iav3 = 160

Iav3

Ip :=

t2 − t1) ⎤ ⎡ ( 2f ⋅ ⎥ ⎢ π ⎦ ⎣

+ Ia Ip = 1.02 × 10

4

( t2 − t1) (

)

(

)

IAVG := Ia⋅ f ⋅ t3 + Ib⋅ f ⋅ t5 − t4 + 2⋅ Ip − Ia ⋅ f ⋅

(b)

π IAVG = 180

( t2 − t1) 2

Chapter 2-Diodes Circuits Page #2-9

10

(

)

Ir1 := Ip − Ia ⋅ f ⋅

Ir1 = 1.124 ×

Ir2 := Ia⋅ f ⋅ t3

Ir2 = 47.434

(

)

Ir3 := Ib⋅ f ⋅ t5 − t4

Irms :=

2

3

2

Ir1 + Ir2 + Ir3

Ir3 = 22.361

2

Chapter 2-Diodes Circuits Page #210

Irms = 1.125 × 10

3

Prob 2-22 VS := 220

R := 4.7

−6

C := 10⋅ 1

t := 2⋅ 1

0 0

−

τ = 4.7 × 10

5

τ := R⋅ C Usi ng Eq. (2-20), VS (a)

(b)

Ip := R

Ip = 46.809

VO := VS W := 0.5⋅ C⋅ VO

2

W = 0.242

Usi ng Eq. (2-21), − t⎞ τ ⎟

⎛ ⎜

(c)

V c := V S⋅ ⎝ 1 − e

Vc = 9.165

⎠

Prob 2-24 VS := 110

R := 4.7

L := 6.5⋅

−3

R 10 τ :=

τ = 723.077

L

Usi ng Eq. (2-25),

(a)

−6

VS ID := R

ID = 23.404 Chapter 2-Diodes Circuits Page #2-10

(b)

IO := ID W := 0.5⋅ L⋅ IO

2

W = 1.78

Usi ng Eq. (2-27),

(c)

di :=

VS

di = 1.692 × 104

L

Chapter 2-Diodes Circuits Page #2-11

Prob 2-25 R := 4.7

VS := 220

L := 6.5⋅

−3

R 10 τ :=

τ = 723.077

L Usi ng Eq. (2-25), VS

ID := R

(a)

(b)

ID = 46.809

IO := ID W := 0.5⋅ L⋅ IO

2

W = 7.121

Usi ng Eq. (2-27),

(c)

di :=

VS

di = 3.385 × 10

L

4

Prob 2-29 VS := 110

C := 10⋅ 1

−6

L := 50⋅ 1

−

0

6

0 Usi ng Eq. (2-32),

(a)

(b)

C Ip := VS⋅ L

t1 := π ⋅ L⋅ C Chapter 2-Diodes Circuits Page #2-11

Ip = 49.193 10

t1 = 7.025 ×

−5

Usi ng Eq. (2-35),

(c)

V C := 2⋅ VS

Chapter 2-Diodes Circuits Page #2-12

VC = 220

Example 2.31 L

:= ⋅

(a)

Vs := 220

−6

3

4 10 −

C := 0.05⋅ 10

R := 160

α :=

R 2⋅ L

4

α = 2 × 10

Usi ng Eq. (2-41),

1

ω o :=

4

ω o = 7.071 × 10

L⋅ C 2

ω r :=

ωo − α

2

4

ω r = 6.782 × 10

Vs

A2 :=

π t1 := ωr

(b)

A2 = 0.811

ω r⋅ L

vc (t) := e

− α⋅t

t1⋅ 106 = 46.32

( )

⋅ A2⋅ sin ω r⋅ t

Probl 2-32 L

2 10

3

−6

Vs := 220

Chapter 2-Diodes Circuits Page #2-12

μs

−

:= ⋅

(a)

C := 0.5⋅ 10

R := 160

α :=

R 2⋅ L

4

α = 4 × 10

1

ω o :=

4

ω o = 3.162 × 10

L⋅ C

s1 := −α +

2

α − ωo

2

2

s2 := −α −

at t = 0 at t = 0

4

s1 = −1.551 × 10 2

α − ωo

i := 0 di := 0

α > ωo

4

s2 = −6.449 × 10 0 ≡ A1 + A2 V Vs L

≡ A 1⋅ s1 + A2⋅ s2

Chapter 2-Diodes Circuits Page #2-13

A1 :=

Vs

(

A1 = 2.245

)

L⋅ s1 − s2

A2 = −2.245

A2 := −A1

(b)

(

⋅ A1⋅ e

vc (t) := e

s1⋅ t

− α⋅t

s2⋅ t

−6

Probl 2-33 L

(a)

Vs := 220

3

2 10 := ⋅

)

−e

−

C := 0.05⋅ 10

R := 16

ω o := ω r :=

α := R 2⋅ L 1

2

5

ω o = 1 × 10

L⋅ C ωo − α

3

α = 4 × 10

2

4

ω r = 9.992 × 10

Vs

A2 :=

ω r⋅ L

A2 = 1.101

Chapter 2-Diodes Circuits Page #2-13

(b)

t1 :=

π ωr

vc (t) := e

Prob 2-34

t1⋅ 106 = 31.441

− α⋅t

( )

⋅ A2⋅ sin ω r⋅ t

VS := 110

L := 1⋅ 1

VS ⋅t IO := L 1

W := 0.5⋅ L⋅ IO

0

−

μs

3

10

t1 := 100⋅

IO = 11

2

Chapter 2-Diodes Circuits Page #2-14

W = 7.121

−6

Example 2.36 Vs := 220

−6

Lm := 450⋅10

N2 := 100

N1 := 10

t1 := 50⋅

−6

10

N2

a :=

a = 10 N1 Usi ng Eq. (2-52), (a)

3

vD = 2.42 × 10

vD := V s⋅ (1 + a)

Usi ng Eq. (2-55),

(b)

(c)

Io = 24.444

Vs Io := ⋅t Lm 1 Io Io_peak := a

Io_peak = 2.444

Usi ng Eq. (2-58),

(d)

t2 :=

a⋅ Lm⋅ Io

6

t2⋅ 10 = 500 μs

Vs 1

(e)

W :=

2

2

⋅ Lm⋅ Io

W = 0.134

J 10

Example 2.37 Vs := 220

Lm := 250⋅

−6

N1 := 10

N2

Chapter 2-Diodes Circuits Page #2-14

N2 := 10

t1 := 50⋅

−

10 a :=

a=1

N1

Usi ng Eq. (2-52),

(a)

vD := V s⋅ (1 + a)

Usi ng Eq. (2-55),

(b)

Vs Io := Lm

⋅ t1

vD = 440 Io = 44

Chapter 2-Diodes Circuits Page #2-15

Io Io_peak := a

(c)

Io_peak = 44

Using Eq. (2-58), (d)

a⋅ Lm⋅ Io

t2 :=

Vs 1 2 ⋅ Lm⋅ Io 2

W :=

(e)

6

t2⋅ 10 = 50

μs

W = 0.242

J

Example 2.38 Vs := 220

−6

Lm := 250⋅ 10

N2 := 1000

N1 := 10

t1 := 50⋅ 10

N2

a :=

(a)

a = 100

N1

vD := V s⋅ (1 + a)

4

vD = 2.222 × 10

Vs (b)

(c)

(d)

(e)

⋅t Io := Lm 1 Io

Io = 44

Io_peak := a

Io_peak = 0.44

t2 := W :=

a⋅ Lm⋅ Io Vs 1

6

⋅ Lm⋅ Io

2

3

t2⋅ 10 = 5 × 10

Chapter 2-Diodes Circuits Page #2-15

μs

−6

J

2

W = 0.242

Power Electronics Circuits Devices and Applications 4th Edition Rashid SOLUTIONS MANUAL Full download: https://testbanklive.com/download/power-electronics-circuits-devices-andapplications-4th-edition-rashid-solutions-manual/ People also search: power electronics circuits devices & applications (4th edition) pdf power electronics circuits devices and applications 3rd edition pdf power electronics circuits devices and applications 4th edition pdf free download power electronics by mh rashid 4th edition pdf power electronics: devices, circuits, and applications power electronics by mh rashid 2nd edition pdf power electronics rashid 4th edition power electronics circuits devices and applications solution manual

Chapter 2-Diodes Circuits Page #2-16