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Chapter 3-Diodes Rectifiers Prob 3-1
Vm
:= 170
R := 5
f := 60
Using Usin g Eq. (3-11) (3-11) 2⋅ V m Vdc :=
Vdc = 108.23
π
Vdc := 0.6366⋅ Vm
Prob 3-2
Vm
Vdc = 108.22
:= 170
−3
R := 10
Lc := 0.5⋅ 10
f := 60
Using Eq. (3-11) (3-11) Vdc := 0.6366⋅ V m Vdc
Idc :=
Using Eq. (3-83) Vx
:= 2⋅ f ⋅ Lc⋅ Idc
Vo
Prob 3-3
Idc = 10.82
R
:=
Vdc − Vx
:= 170
Vm
Vx = 0.65 Vo = 107.57 R := 5
Using Eq. (3-25) Vdc := Vm⋅
Prob 3-4
Vm
6
π
f := 60
π ⋅ sin⎛ ⎞
Vdc = 162.34
⎝ 6 ⎠
:= 170
R := 5
f := 60
Using Eq. (3-25) Vdc := Vm⋅ Idc :=
6
π
π ⋅ sin⎛ ⎞
⎝ 6 ⎠
Vdc = 162.34
Vdc Idc = 32.47
R
Using Eq. (3-83) Vx := 6⋅ f ⋅ Lc⋅ Idc Vo
:=
Vx = 5.84
Vdc − Vx
Vo = 156.49
Chapter 3-Diodes Rectifiers Page # 3 -1
−3
Lc := 0.5⋅ 10
Prob 3-5
Vs := 280 Vm
R := 5
2
:= 280⋅
f := 60 Vm = 228.62
3
Using Eq. (3-33) 1.6542⋅ V m Vdc :=
Prob 3-6
Vs := 280 Vm
Vdc = 378.18 R := 5
f := 60
2
:= 280⋅
Lc
Vm = 228.62
3
Using Eq. (3-33)
Vdc = 378.18
1.6542⋅ V m Vdc := Vdc
Idc :=
Idc = 75.64
R
Using Eq. (3-83) Vx := 6⋅ f ⋅ Lc⋅ Idc
:=
Vo
Prob 3-7
Vdc := 240
Vm
0.6366
:=
Vdc
Idc
R
Vm
= 24
I p = 37.7
R
Id :=
= 377
Vs = 266.58
2
Idc :=
I p
Vm
Vm
Vs :=
Diodes
Vo = 364.57
R := 10 Vdc
:=
Vx = 13.61
Vdc − Vx
Idc
Id = 12
2
Chapter 3-Diodes Rectifiers Page # 3 -2
−3
:= 0.5⋅ 10
I p
IR := Transformer
Vm
Vs :=
Vs = 266.58
2 I p
Is :=
VI
IR = 18.85
2
Is = 26.66
2
:=
3 VI = 7.107 × 10
Vs⋅ I s
Using Eq. (3-1) Pdc :=
Using Eq. (3-2)
TUF :=
1 TUF Vdc := 750
Using Eq. (3-33) Vm
:=
Vs :=
Diodes
I p
:=
2 3 Pdc = 5.76 × 10
R
3 Pac = 7.11 × 10
Pac := Vs⋅ I s
Using Eq. (3-8)
Prob 3-8
(0.6366⋅ Vm)
Pdc
TUF = 0.8105
Pac
= 1.23 6000 Idc :=
Vdc
Vm = 453.39
1.6542 Vm
Vs = 320.6
2 Idc
Id :=
I p
Idc
IR :=
3
= 6 × 10
3 Id = 3 × 10
2 I p
3 IR = 4.24 × 10
2
Chapter 3-Diodes Rectifiers Page # 3 -3
Transformer
Vs :=
Vm
Vs = 320.6
2
Is := I p
6 VI = 1.924 × 10
Pdc := Vdc⋅ I dc
6 Pdc = 4.5 × 10
Pac := 3Vs⋅ I s
6 Pac = 5.77 × 10
Using Eq. (3-2) Using Eq. (3-8)
3
= 6 × 10
Vs⋅ I s
VI
Using Eq. (3-1)
Is
:=
Pdc
TUF :=
1 TUF
TUF = 0.78
Pac
= 1.28
Prob 3-9 Vm
:= 170
f := 60
R := 10
ω := 2⋅ π ⋅ f
ω = 376.99
0.04 RF :=
Guess L
−3
:= 5⋅ 10
Given
Using Eq. (3-67)
2
⋅ L ⎞ ⎛ 2⋅ ω − 0.481 RF⋅ 1 + ⎝ R ⎠ 3 Find( L ) ⋅ 10