Planilha Calculo Muro Gabião Inclinado Com Sobrecarga Impressao

MURO DE GABIÃO Dados: ɣsolo: c': !: &: ) *

= = = = = =

1.80 t/m³ 0 2" ° 0 ( 6 ° 0

ɣp,rocha: ᾳ #$%rr%&o

= =

2.50 t/m³ 82 ° 20.00 t/m

h B

2.50 t/m

+B--

0,14 7 h

a

=



=a 9

=

h

+ 1 3 0.644 =

=

2.5

=

9

)

=

1.00 m .00 m

 

= ar$ $a&; 7 h B
66.5014424

"2.50° 1.16066886

Obs.: Calcular um novo valor de H porque existe um carregamento vercal distriuído

>

=

?a

=

h 7 s%& s%&3 < ) 66.50 0.448

=

4."8 m

já calculado calculado com caract. caract. De muro com com carregament carregamento o vercal

@ D A@ C+D-CD --AC D+-B@ED a

=

1 7 ɣs ɣs 7 h 7 ?a

9

F 7 > 7 ?a

7

. 2 .2

s%& s%&3 9 *

5.6 C D GH a

>%a

= ɣs 7 > 9  7 F 7 > =  7 ɣs 7 > 9 6 7 F

1.8 m

+ D +-@@- ɣ;

=

ɣp 7 3 1 < & 

=

1."5 t/m³

I- D +GH -C+J-+ +

= B 9a . 2

7 h

=

.20 m

+ D - D+--CD C K@CDGH P

=

ɣ; 7 +

=

16.10 t/m

= 1

14.5 t/m

= =

4.60 m .  .0 0 m

+GH D C- D -JDD 'a

= 3 a /2 7 h

9

3h/6 +

7 3B9 a 7 B < 2 7 a =

1.08 m

L'a

= 3 a /2 7 h

9

3h/6 +

7 3 B
0.2 m

=

-DCD+ D C- D -JDD 

=

7'a M cos ) 9 1.0""8"2

L

=

7'a M s%& ) 9 N'a M cos ) = 1.02 m 0.1121685 0.116450"08 +@-CG  ABAC

%a

=

B 7 cos ) < 2.84

L%a

=

>%a

<

N'a M s%& ) = 0.0581""58

>%a

7 1.8

B 7 s%m )

=

1.1" m

$; 7 3 0 <   = 0.00681244 1".50 1.5" m

2.42 m

+@-CG  D+OAC 

=  7 cos ) 9 a

7 16.01

d

=

K;

=

14.5

C 7 $a&; !

cos 3 <)
=

2".2" t/m .50

1.8 t/m

d a 7 s%&3
=

1.8

16.10

0.10

Verifcação:

1.8

P

1.50

AAC @C A%ah

=

a 7 s%&3
L%a

=

16." t.m/m

AAC -++C Ap

=

A%aQ

=

 7 ;

=

a 7 cos3
18.8 t.m/m %a

=

25.1 t.m/m

++

KC D +@-CG  ABAC K$

=

Ap 9 A%aQ A%ah

=

2.6 Verifcação:

2.6

P

1.50

++R

D+SC D GH D3 C   C D ABAC d

= Ap9A%p9A%aQ = C

1.61 m

os.: mpZ7o pass*Qo \ &Zlo, po*s, o mZro &Yo %s$V aa*7o da co$a do $%rr%&o. CYo hV solo co&$r*Z*&do a ]aQor

I@ D C-DD %

=

B .

< 2

=

<0.11 m

T

B 6 0.5

2 <0.11 <0.11

T

Obs.: Como a excentricidade n!o "oi maior que #$%#m$ adotar "ormula abaixo para calculo da tens!o máxima.

-++U+ C B+ #mV7

#m*&

=

=

C B

7 1 96 7 % = . B .0 0.""082614 J%r*WcaXYo: ".01 t/m T C B

7 1 <6 7 % = . B .0 1.221"0086 J%r*WcaXYo: 11.1" t/m T

".01 t/m

20.00 t/m

++R

11.1" t/m

20.00 t/m

++R

a*^%s d% 1,0m d% al$Zra % malha 8710, 0 p%so da r%d% m%$Vl*ca 3pZ \ 8,6?;]/m %, ass*m, a co%sYo d*spo&_Q%l &a s%XYo *&$%rm%d*Vr*a s%rV: +H c;

=

0,0 7 pZ

=

2.08 t/m

AIA K-G D +>AC DA++EJ C +GH [adm

= Cc 7 $a&; ; 9 c; 7 B 0.6681"86" S&;Zlo d% a$r*$o ao lo&;o da s%XYo *&$%rm%d*Vr*a: ;

= 25 7 ɣ; < 10°

= 4."5

4°

24.46 t/m

K-G D +>AC `@ @ C +GH [

=

 7 s%m ) 9 0.10452846

a

7

s%& 3ᾳ
12.6 t/m

Verifcação:

24.46 t/m [adm

P

12.6 t/m [

++R

C+H C-A DA++EJ C +GH C-ADI- #adm

=

50 7 L; < 0

21.24 t/m

C+H AIA C-A `@ @ C +GH C-ADI- #mV7

=

C 27d

=

8.44 t/m Verifcação:

Secão 1

21.24 t/m #adm

P

8.44 t/m #mV7

T (t/m) 12.6 t/m

Tadm (t/m) 24.46 t/m

σmáx (t/m²) 8.44 t/m

++R

σadm (t/m²) 21.24 t/m


= = = = = =

1.80 t/m³ 0 0 ° 0 ( 6 ° 0


= =

2.50 t/m³ 82 ° 20.00 t/m

h B

2.50 t/m

+B--

+ 1 3 0.504 =

0,14 7 h

=

h 

=

2.20

=

9

)

=

a

=



=a 9



= ar$ $a&; 7 h B
6".8015052

1.00 m 2.50 m

".8° 1.1"600520"1


>

=

?a

=

h 7 s%& s%&3 < ) 6".8 0.448

=

."4 m

já calculado com caract. De muro com carregamento vercal

@ D A@ C+D-CD --AC D+-B@ED a

=

1 7 ɣs 7 h 7 ?a

9

F 7 > 7 ?a

7

.2 5.6

s%& s%&3 9 *

4.1 C D GH a

>%a

= ɣs 7 > 9  7 F 7 > =  7 ɣs 7 > 9 6 7 F

1.51 m

+ D +-@@- ɣ;

=

ɣp 7 3 1 < & 

=

1."5 t/m³

I- D +GH -C+J-+ +

= B 9a . 2

7h

=

6.0 m

+ D - D+--CD C K@CDGH P

=

ɣ; 7 +

=

11.0 t/m

= 1

.82 t/m

= =

.60 m 2.50 m

+GH D C- D -JDD 'a

= 3 a /2 7 h

9

3h/6 +

7 3B9 a 7 B < 2 7 a =

0. m

L'a

= 3 a /2 7 h

9

3h/6 +

7 3 B
0." m

=

-DCD+ D C- D -JDD 

=

7'a M cos ) 9 0.248461"1

L

=

7'a M s%& ) 9 N'a M cos ) = 0.88 m 0.0"0621445 0."814100606 +@-CG  ABAC

%a

=

B 7 cos ) < 2.486

L%a

=

>%a

<

N'a M s%& ) = 0.08212506

>%a

1.01 m

7

$; 7 3 0 <   = 0.28602060 16.62 1.25 m

1.51 B 7 s%m )

=

2.05 m

+@-CG  D+OAC 

=  7 cos ) 9 a 7 10.6

cos 3 <)
18."" t/m ".8

AAC @C A%ah

=

a 7 s%&3
L%a

=

8.4 t.m/m

AAC -++C Ap

=

A%aQ

=

 7 ;

= 11.0 t.m/m

a 7 cos3
%a

=

1.85 t.m/m


= Ap9A%p9A%aQ = C

1. m


+H &abi'es de ($#m de altura e mal)a *x(#$ # peso da rede metálica +pu, - *$/g"0m e$ assim$ a coes!o disponível na se1!o intermediária será:

c;

=

0,0 7 pZ

=

2.08 t/m


Cc 7 $a&; ; 9 c; 7 B 0.6681"86" S&;Zlo d% a$r*$o ao lo&;o da s%XYo *&$%rm%d*Vr*a: ;

=

= 25 7 ɣ; < 10°

=

1"."4 t/m

4°

4."5 K-G D +>AC `@ @ C +GH [

=

 7 s%m ) 9 0.10452846

a

7

s%& 3ᾳ
8.21 t/m

Verifcação:

1"."4 t/m [adm

P

8.21 t/m [

++R


=

50 7 L; < 0

1.2 t/m


=

C 27d

=

".06 t/m Verifcação:

Secão 2

1.2 t/m #adm

P

".06 t/m #mV7

T (t/m) 8.21 t/m

Tadm (t/m) 1"."4 t/m

σmáx (t/m²) ".06 t/m

++R

σadm (t/m²) 1.2 t/m


= = = = = =

1.80 t/m³ 0 0 ° 0 ( 6 ° 0


= =

2.50 t/m³ 82 ° 20.00 t/m

h B

2.50 t/m

+B--

0,14 7 h

=

h 

=

+ 1 3 0.64 =

a

=



=a 9



= ar$ $a&; 7 h 9 ) = B
1.8"

1.00 m

=

2.00 m

"4.6° 1.206224


>

=

?a

=

h 7 s%& s%&3 < ) 68.6 0.448

=

2.6 m


@ D A@ C+D-CD --AC D+-B@ED a

=

1 7 ɣs 7 h 7 ?a

9

F 7 > 7 ?a

7

.2 2.2

s%& s%&3 9 *

.01

= 1

C D GH a >%a

= ɣs 7 > 9  7 F 7 >=  7 ɣs 7 > 9 6 7 F

1.12 m

+ D +-@@- ɣ;

=

ɣp 7 3 1 < & 

=

1."5 t/m³

I- D +GH -C+J-+ +

= B 9a . 2

7 h

=

.0 m

+ D - D+--CD C K@CDGH P

=

ɣ; 7 +

=

6.8 t/m

5. t/m

= =

2.60 m 2.00 m

+GH D C- D -JDD 'a

= 3 a /2 7 h

9

3h/6 +

7 3B9 a 7 B < 2 7 a =

0."8 m

L'a

= 3 a /2 7 h

9

3h/6 +

7 3 B
0.6" m

=

-DCD+ D C- D -JDD 

=

7'a M cos ) 9 N'a M s%& ) = 0.""51"02" 0.06685642

L

=

7'a M s%& ) 9 N'a M cos ) = 0."4 m 0.081215 0.660145" +@-CG  ABAC

%a

=

L%a

=

B 7 cos ) < 1.8 >%a

<

>%a

7 1.12

B 7 s%m )

=

0.84 m

$; 7 3 0 <   = 0.25451"24 15.04 0.2 m

1."0 m

+@-CG  D+OAC 

=  7 cos ) 9 a 7 cos 3 <)
11.40 t/m 8.6

AAC @C A%ah

= a 7 s%&3
L%a

=

.84 t.m/m

AAC -++C Ap A%aQ

=

 7 ;

= 5."5 t.m/m

= a 7 cos3
%a

=

".11 t.m/m


= Ap9A%p9A%aQ = C

1.1 m



c;

=

0,0 7 pZ

=

2.08 t/m



= 25 7 ɣ; < 10° = 4."5

11."8 t/m

4°

K-G D +>AC `@ @ C +GH [

=

 7 s%m ) 9 0.10452846

a

7

s%& 3ᾳ
4.8 t/m

Verifcação:

11."8 t/m [adm

P

4.8 t/m [

++R


=

50 7 L; < 0

".22 t/m


=

C 27d

=


Secão 

".22 t/m #adm

P

5.05 t/m #mV7

T (t/m) 4.8 t/m

Tadm (t/m) 11."8 t/m

σmáx (t/m²) 5.05 t/m

++R

σadm (t/m²) ".22 t/m


= = = = = =

1.80 t/m³ 0 0 ° 0 ( 6 ° 0


= =

2.50 t/m³ 82 ° 20.00 t/m

h B

2.50 t/m

+B--

0,14 7 h

=

h 

=

+ 1 3 0.224 =

a

=



=a 9



= ar$ $a&; 7 h 9 ) = B
1.5

1.00 m

=

2.00 m

6.° 1.0121"0115


>

=

?a

=

h 7 s%& s%&3 < ) 5". 0.448

=

1."0 m


@ D A@ C+D-CD --AC D+-B@ED a

=

1 7 ɣs 7 h 7 ?a

9

F 7 > 7 ?a

7

.2 1.16

s%& s%&3 9 *

1.0

= 1

C D GH a >%a

= ɣs 7 > 9  7 F 7 >=  7 ɣs 7 > 9 6 7 F

0."4 m

+ D +-@@- ɣ;

=

ɣp 7 3 1 < & 

=

1."5 t/m³

I- D +GH -C+J-+ +

= B 9a . 2

7 h

=

2.40 m

+ D - D+--CD C K@CDGH P

=

ɣ; 7 +

=

4.20 t/m

.06 t/m

= =

1.60 m 2.00 m

+GH D C- D -JDD 'a

= 3 a /2 7 h

9

3h/6 +

7 3B9 a 7 B < 2 7 a =

0."8 m

L'a

= 3 a /2 7 h

9

3h/6 +

7 3 B
0.6" m

=

-DCD+ D C- D -JDD 

=

7'a M cos ) 9 N'a M s%& ) = 0.""51"02" 0.06685642

L

=


%a

=

L%a

=

B 7 cos ) < 1.8 >%a

<

>%a

7 0."4

B 7 s%m )

=

0.84 m

$; 7 3 0 <   = 0.48455508 26.01 0.5 m

1.66 m

+@-CG  D+OAC 

=  7 cos ) 9 a 7 cos 3 <)
6.88 t/m 2".

AAC @C A%ah

= a 7 s%&3
L%a

=

0.1 t.m/m

AAC -++C Ap A%aQ

=

 7 ;

= .54 t.m/m

= a 7 cos3
%a

=

2.85 t.m/m


= Ap9A%p9A%aQ = C

0. m



c;

=

0,0 7 pZ

=

2.08 t/m



= 25 7 ɣ; < 10° = 4."5

8."6 t/m

4°

K-G D +>AC `@ @ C +GH [

=

 7 s%m ) 9 0.10452846

a

7

s%& 3ᾳ
2.64 t/m

Verifcação:

8."6 t/m [adm

P

2.64 t/m [

++R


=

50 7 L; < 0

".22 t/m


=

C 27d

=

."0 t/m Verifcação:

Secão 4

".22 t/m #adm

P

."0 t/m #mV7

T (t/m) 2.64 t/m

Tadm (t/m) 8."6 t/m

σmáx (t/m²) ."0 t/m

++R

σadm (t/m²) ".22 t/m


= = = = = =

1.80 t/m³ 0 0 ° 0 ( 6 ° 0


= =

2.50 t/m³ 82 ° 20.00 t/m

h B

2.50 t/m

+B--

0,14 7 h

=

h 

=

+ 1 3 0.084 =

a

=



=a 9



= ar$ $a&; 7 h 9 ) = B
1.20

1.00 m

=

2.00 m

6.6° 0.54041500


>

=

?a

=

h 7 s%& s%&3 < ) 0.6 0.448

=

0."0 m


@ D A@ C+D-CD --AC D+-B@ED a

=

1 7 ɣs 7 h 7 ?a

9

F 7 > 7 ?a

7

.2 0.20

s%& s%&3 9 *

0."

= 1

C D GH a >%a

= ɣs 7 > 9  7 F 7 >=  7 ɣs 7 > 9 6 7 F

0. m

+ D +-@@- ɣ;

=

ɣp 7 3 1 < & 

=

1."5 t/m³

I- D +GH -C+J-+ +

= B 9a . 2

7 h

=

0.0 m

+ D - D+--CD C K@CDGH P

=

ɣ; 7 +

=

1.58 t/m

0.8 t/m

= =

0.60 m 2.00 m

+GH D C- D -JDD 'a

= 3 a /2 7 h

9

3h/6 +

7 3B9 a 7 B < 2 7 a =

0."8 m

L'a

= 3 a /2 7 h

9

3h/6 +

7 3 B
0.6" m

=

-DCD+ D C- D -JDD 

=

7'a M cos ) 9 N'a M s%& ) = 0.""51"02" 0.06685642

L

=


%a

=

L%a

=

B 7 cos ) < 1.8 >%a

<

>%a

7 0.

B 7 s%m )

=

0.84 m

$; 7 3 0 <   = 0."01601 5.04 0.12 m

1." m

+@-CG  D+OAC 

=  7 cos ) 9 a 7 cos 3 <)
2.55 t/m 0.6

AAC @C A%ah

= a 7 s%&3
L%a

=

0.01 t.m/m

AAC -++C Ap A%aQ

=

 7 ;

= 1. t.m/m

= a 7 cos3
%a

=

0.21 t.m/m


= Ap9A%p9A%aQ = C

0.60 m



c;

=

0,0 7 pZ

=

2.08 t/m



= 25 7 ɣ; < 10° = 4."5

5.86 t/m

4°

K-G D +>AC `@ @ C +GH [

=

 7 s%m ) 9 0.10452846

a

7

s%& 3ᾳ
0.8" t/m

Verifcação:

5.86 t/m [adm

P

0.8" t/m [

++R


=

50 7 L; < 0

".22 t/m


=

C 27d

=


Secão 5

".22 t/m #adm

P

2.12 t/m #mV7

T (t/m) 0.8" t/m

Tadm (t/m) 5.86 t/m

σmáx (t/m²) 2.12 t/m

++R

σadm (t/m²) ".22 t/m

Planilha Calculo Muro Gabião Inclinado Com Sobrecarga Impressao

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