Shortcuts in Quantitative Aptitude for Competitive Exams disha expertsFull description
maths formulasFull description
Coding and Decoding Questions Shortcut Tricks in Reasoning of AptitudeFull description
Quantitative Aptitude ShortcutsFull description
yyyFull description
Full description
nice fileFull description
You don’t always get what you wish for; you get what you work for. So my dear students here is the last package for your expedition: The most important topics for the upcoming examination — …Full description
Full description
Descripción completa
Full description
pte important grammerFull description
Descrição completa
Part of the Mind Control Archive. Share this with a friend and send them to http://www.scribd.com/groups/view/2546-mind-control
Full description
Description complète
short cut maths fractions
www.ibpsguide.com
Simplification -large, complex numerical expression into a simpler form by performing various mathematical operations, in accordance with the B
Stands
for bracket and operation of brackets in the order
,
rule. , { and
Stands for ‘of ‘( usage is x)
O
D
Stands
for division (/)
M Stands for multiplication (x) A
Stands
for addition (+)
S
Stands
for subtraction (-)
: Know about BODMAS Rule. Following are the list of priority given for brackets and signs. : If an expression Contains brackets, the expression within the
should
be simplified first. : If an expression contains ‘ then
, multiplication, division, addition and subtraction,
should be performed first then followed by multiplication or division.
Proceeding from left to right, addition and subtraction are carried out in the order in which the sign of addition and subtraction are given.
From the above question if we know the square value of 21 2, then this question will be easily solved 212 = 441 441/49= 9 9 6 = 54 Hence the answer for above series is
: Know the values of 60% =0.6 and 25 % = 0.25 : Now directly multiply 0.6 ×250 + 0.25×600 0.6×250= 150 0.25×600=150 : 150+ 150 = 300 Hence the answer for above series is
2×(3/5) × 8×(1/3) = (13/5) × (25/3) = 65/3
+ 7 ½ ×2×(2/3)= 43/6 × 12/5 = 86/5 65/3 + 86/5 = 38 ×(15/13) hence the answer for above series is
www.ibpsguide.com 19×(3/5) + 23×(2/3) – 24×(1/5) Take all the whole number outside the bracket i.e. 19+23 -24 = 18 Add fractions within bracket 18 ×[(3/5) + (2/3) – (1/5)] = 18(16/15) Hence the answer for above series is