www.ibpsguide.com
Model Question in Profit and Loss Method: 1.) ‘A’ sells a bicycle to ‘B’ at a profit of 20%, and ‘B’ sells it to ‘C’ at a profit of 25%. If ‘C’ pays Rs. 225 for it, then what is the Cost Price of ‘A’? Shortcut Method: X(Cost Prize of ‘A’) ×
120 ( +20% ℎ ′ ′ ′ ) 100 ( %)
×
125 ( +25 % ℎ ′ ′ ′ )
= 225
100 ( %)
Here, 225 is the C P of ‘C’. CP= Cost Price This is the rapid method for solving this type of problems. Solution: X×
120 100
×
125 100
= 225,
Simplify the above equation, then we will get, X = 150, So the Cost Price of ‘A’ is Rs. 150. More Model Questions: 2.) A’ sells a bicycle to ‘B’ at a profit of 4 0%, and ‘B’ sells it to ‘C’ at a loss of 20 %. If ‘C’ pays Rs. 140 for it, then what is the Cost Price of ‘A’? Shortcut Method: X(Cost Prize of ‘A’) ×
140 ( +40% ℎ ′ ′ ′ ) 100 ( %)
Here, 140 is the C P of ‘C’.
CP= Cost Price For More Aptitude Shortcuts and Tricks Visit: www.ibpsguide.com www.ibpsguide.com
×
80 (− 20 % ℎ ′ ′ ′ ) 100 ( %)
= 140
www.ibpsguide.com This is the rapid method for solving this type of problems. Solution: X×
140 100
×
80 100
= 140,
Simplify the above equation, then we will get, X = 125, So the Cost Price of ‘A’ is Rs. 125.
3.) ‘A’ sold a watch at gain of 15% to ‘B’ and ‘B’ sold it to ‘C at a loss of 20% and ‘C’ sold it to ‘D’ at a loss of 25%. If the Cost Price of ‘A’ is Rs. 500, find the price paid by ‘D’ ?
Shortcut Method: 500 (CP of ‘A’) ×
115 ( +15% ) 100 ( %)
×
80 (−20% ) 100 ( %)
×
75 (−25% ) 100 ( %)
= X
Assume that X as the price paid by ‘D’.
CP= Cost Price This is the rapid method for solving this type of problems. Solution: 500 ×
115 100
×
80 100
×
75 100
= X,
Simplify the above equation, then we will get, X = 345, So the Cost Price of ‘ D’ is Rs. 345. If you have any queries in the above shortcut method, reach us via below email: Email:
[email protected]
For More Aptitude Shortcuts and Tricks Visit: www.ibpsguide.com
