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Diameter of Roll Crusher Home -> Solved Problems -> Mechanical Operations ->
A pair of rolls is to take a feed equivalent to spheres of 3 cm in diameter and crush them to spheres having 1 cm diameter. If the coefficient of friction is 0.29, what would be the diameter of rolls? Calculations:
The following formula relates the coefficient of friction (), radius of rolls (r), radius of product (d), and radius of feed (R): cos = (r + d) / (r + R) 1 where is related to the coefficient of friction by b y the relation, =
tan
Angle of nip = 2 We have, = 0.29 -1
o
Therefore, = tan (0.29) = 16.17
And we have, d = 0.5 cm; R = 1.5 cm Substituting for the known quantities in equn.1, cos (16.17) = (r + 0.5)/(r + 1.5) 0.9604 = (r + 0.5)/(r + 1.5) 1. 5) r + 0.5 = 0.9604 (r + 1.5) r - 0.9604 r = 1.4406 - 0.5 r = 23.753 cm Radius of rolls = 23.753 cm Dia of rolls = rolls = 2 x 23.753 = 47.5 cm
