Información del pozo Coordenadas de superficie Coordenada Objetivo
9987272.047 N 349831.46 E 9987547 N 349961 E
KOP= 500’ BUR=2.5°/100’ Profundidad total al objetivo= 9000’ (TVD)
1. Calculo de dirección y desplazamiento horizontal N= + 274.95 E= + 129.54 DH= [] [] = 303.94 mts * 3.28 = 996.92’
Θ = arctang (E-W/N-S) = arctang (129.54/274.95)= 25.23° Direccion = N 25° E = 25° AZM
2. Calculo de radio de curvature (R) R=
= = = 2291.6 ‘
3. Calcular DC
Si D2 > R entonces DC = D2 – R
Si D2 < R entonces DC = R – D2
D2=DH=996.92’ DC=R – D2= 2291.6’ – 996.92’= 1294.68’
4. Calculo del DO DO=V3 –V1= 9000’ – 500’= 8500’
5. Calcular angulo DOC Angulo DOC = arctang (DC/DO)= arctang(1294.68’/8500’)= 8.66°
6. Calcular OC OC =
= = 8598’
7. Calcular angulo BOC Angulo BOC = arccos (R/OC)= arccos(2291.6’/8598’)= 74.55°
8. Calcular angulo BOD
Si R < D2 entonces BOD = BOC - DOC
Si R > D2 entonces BOD = BOC + DOC
Angulo BOD = 74.55°+ 8.66° = 83.21°
9. Calcular máximo Angulo ( Θ) Θ = 90° - Ang BOD = 90° - 83.21° = 6.79°
10.
Calcular EOB (TVD)
V2 = V1 + R sen Θ = 500’ +(2291.6’ sen 6.79°)= 770.94’
11. EOB = V1 +
12.
Calcular EOB (MD) = 771.6’ = 500’ +
Calcular EOB (DH)
D1 = R – R cos = 2291.6’ - (2291.6’ x cos 6.79°) = 16.07’
13.
Calcular profundidad total al objetivo (MD)
PROF (MD) = V1 + (
) + BC
OB= R BC = (
) = ( ) = 8287’
PROF (MD) = 500’ + 271.6’ + 8287’= 9058.6’
Target location KOP (V1) Target’s TVD (V3) Build Radius (R)
Given information S1638.3 ft , W 1147.15ft 1981.00 ft 8500.00 ft 2291.83 ft
Unknown Profile Variables Variables Respuestas Polar coordinate S 35° W BUR 2.5°/100 ft MAX Hold Angle (θ) 18° EOB (TVD) (V2) 2689.21 ft EOB (MD) 2701.00 ft EOB displacement (D1) 112.17 ft Total MD to Target 8810.80 ft
Calculations Formula
respuesta
Polar coordinate Direction
V2 = V1 + R sen Θ
EOB TVD (V2) V2= 2689.21 ft EOB MD EOB MD =2701.00 ft
EOB displacement (D1) D1 = R – R cos D1 = 112.17 ft Total MD to Target BC= 6109.80 ft BC = ( ) TOTAL(MD)= V1 + ( ) TOTAL(MD) = 8810.80 ft + BC EOB = V1 +
Given the following profile variables, choose the correct answer below after calculating the maximum hold angle for a build and hold directional well.
Target Displacement = 2500 ft Target TVD = 10500 ft Build Up Rate = 3° per 100 ft Kickoff Point = 6925 ft Select the correct answer. a) 120.91° b) 136°34’ c) 41.18° d) 26.72° CALCULOS
R=
= = = 1909.67 ft 180 100
Calculo de DC Si D2 > R entonces DC = D2 – R Si D2 < R entonces DC = R – D2 D2=DH=2500 ft DC=D2 – R = 2500’ – 1909.67’= 590.33 ft DO=V3 –V1= 10500’ – 6925’= 3575 ft
Angulo DOC = arctang (DC/DO)= arctang(590.33’/3575’)= 9.38° OC =
= = 3623.45 ft
Angulo BOC = arccos (R/OC)= arccos(1909.67’/3623.45’)= 58.19 ° Angulo BOD Si R < D2 entonces BOD = BOC - DOC Si R > D2 entonces BOD = BOC + DOC Angulo BOD = 58.19°- 9.38°= 48.81° Θ = 90° - Ang BOD = 90° - 48.81° = 41.19°
Given the following profile variables, choose the correct answer below after calculating the end of build TVD for a build and hold directional well:
Target Displacement = 2,500 ft Target TVD = 10,500 ft Build Up Rate = 3o per 100 ft Kickoff Point = 6,925 ft Maximum Hold Angle = 41.18o Select the correct answer. a) b) c) d)
8,297.67 ft 6,783.4 ft 472.41 ft 8,182.5 ft
CALCULOS
V2 = V1 + R sen Θ = 6925’ +(1909.67’ sen 41.18 °) = 8182.38 ft
Given the following profile variables, choose the correct answer below after calculating the end of build (EOB) displacement for a build and hold directional well:
Target TVD = 10500 ft Build Up Rate = 3° per 100 ft Kickoff Point = 6925 ft Maximum hold angle ( ) = 41.18° Select the correct answer. a) 1378.84 ft b) 376.22 ft
c) 472.41 ft d) 5276.84 ft CALCULOS
EOB (DH) = R – R cos = 1909.67’ - (1909.67’ cos 41.18°) = 472.47 ft
Given the following profile variables, choose the correct answer below after calculating the end of build (EOB) measured depth (MD) of a build and hold directional well:
Target Displacement = 2,500 ft Target Direction = S28°E Target TVD = 10,500 ft Build Up Rate = 3° per 100 ft Kickoff Point = 6,925 ft Maximum Hold Angle = 41.18° Select the correct answer. a) b) c) d)
8,297.67 ft 11,376.84 ft 8,182.5 ft 472.41 ft
CALCULOS
EOB (MD) = V1 +
= 6925‘+ 1372’ = 8297.67 ft = 6925’ +
Given the following profile variables, choose the correct answer below after calculating the maximum hold angle for an "S"-type directional well:
Target Displacement = 3,439.84 ft Target TVD = 11,000 ft Build Up Rate = 2.5° per 100 ft Drop Off Rate = 1.5° per 100 ft Kickoff Point = 1,500 ft Select the correct answer. a) b) c) d)
136°34’ 26.72° 120.91° 22.55°
CALCULOS
R1=
= 2291.6 ft
R2= = 3819.3 ft
FE=R1 - (D3 – R2)= 2291.6 - (3439,84 – 3819.3)= 2671.1 ft EO=V4 – V1= 9500 ft Angulo FOE = arctag (FE/EO)= 15.7º OF= (
) = 9868.5 ft
FG = R1 + R2 = 6110.9 ft Angulo FOG = arcsen (FG/OF)= 38.26º Θ = Max Angulo = Angulo FOG - Angulo FOE= 38.26º - 15.7º = 22.56 º
Ejercicio 8 Given the following profile variables, choose the correct answer below after calculating the end of build’s measured depth for an "S" -type directional well:
Target Displacement = 3,439.84 ft Target TVD = 11,000 ft Build Up Rate = 2.5° per 100 ft Drop Off Rate = 1.5° per 100 ft Kickoff Point = 1,500 ft Maximum Hold Angle = 22.55° Select the correct answer. a) b) c) d)
3,439.84 ft 175.22 ft 2,378.89 ft 2,402 ft
CALCULOS
EOB (MD) = V1 +
= 1500 + = 1500 + 902 = 2402 ft
Ejercicio 9 Given the following profile variables, choose the correct answer below after calculating the start of drop true vertical depth for an "S"-type directional well:
Length of tangent section = 7748.36 ft Build Up Rate = 2.5° per 100 ft Drop Off Rate = 1.5° per 100 ft Kickoff Point = 1,500 ft Maximum Hold Angle = 22.55° Select the correct answer. a) b) c) d)
9535.18 ft 7378.89 ft 3439.84 ft 175.22 ft
CALCULOS
SOD(TVD) = V2 + (sección tg cos θ) = 2379.17 + (7748.36 cos 22.55) = 9534.76 ft
Given the following profile variables, choose the correct answer below after calculating the end of build (EOB) true vertical depth of an "S"-type directional well:
Target Displacement = 3,439.84 ft Target TVD = 11,000 ft Build Up Rate = 2.5° per 100 ft Kickoff Point = 1,500 ft Maximum Hold Angle = 22.55° Select the correct answer. a) b) c) d)
3653.69 ft 175.22 ft 1404 ft 2378.89 ft
CALCULOS
V2 EOB (TVD) = V1 + R1 senθ = 1500 + (2291.6 sen 22.56) = 1500 + 879.17 = 2379.17 ft
Given the following profile variables, choose the correct answer below after calculating the maximum hold angle for a horizontal well:
Target Displacement = 2100 ft Target Direction = 35° AZM Target TVD = 3300 ft 1st Build Up Rate = 6° per 100 ft 2nd Build Up Rate = 8° per 100 ft Kickoff Point = 1000 ft Select the correct answer.
a) 26.72° b) 70.91° c) 2.66°34’ d) 42.88° CALCULOS
R1=
= 954.83 ft
= 716.13 ft
R2=
EG= V4 – V1 – R2 = 3300-1000-716.13= 1783.87 ft EO = DH – R1 = 2100 – 954.83= 1154.17 ft Angulo GOE = arctang (EG/EO)= 57.18° OG = (
)= 2124.69ft
OF= R1 – R2= 238.7ft Angulo GOF = arctang (OF/OG)= 83.54 Max Angulo = 180 - Angulo GOF - Angulo GOE = 180° - 83.54° - 57.18° = 39.3°
Given the following profile variables, choose the correct answer below after calculating the first end of build’s displacement for a horizontal well:
Target Displacement = 2100 ft Target TVD = 3300 ft 1st Build Up Rate = 6° per 100 ft Kickoff Point = 1000 ft MAX Inclination Angle ( ) = 42.88° Select the correct answer. a) b) c) d)
289.11 ft 300 ft 763.8 ft 255.21 ft
CALCULOS
EOB (DH) = R1 – R1 cos θ = R1 (1 – cos θ)= 954.83 (1-0.733)= 254.94 ft
Given the following profile variables, choose the correct answer below after calculating the start of second build measured depth of a horizontal well:
Target Displacement = 2100 ft Target TVD = 3300 ft 1st Build Up Rate = 6° per 100 ft Tangent Section = 1939.74 ft Kickoff Point = 1000 ft Maximum Hold Angle = 44.88° Select the correct answer. a) b) c) d)
3869.11 ft 4000 ft 3654.46 ft 2763.8 ft
CALCULOS
MD = V1 +
+ BC= 1000 + + 1939.74 = 3653.9 ft
Given the following profile variables, choose the correct answer below after calculating the target’s total measured depth of a horizontal well:
Target Displacement = 2100 ft Target TVD = 3300 ft 1st Build Up Rate = 6° per 100 ft 2nd Build Up Rate = 8° per 100 ft Tangent Section = 1939.74 ft Kickoff Point = 1000 ft Maximum Hold Angle = 44.88° Select the correct answer. a) b) c) d)
4000 ft 4243.43 ft 3869.11 ft 2763.8 ft
CALCULOS
Prof total en MD = V1 +
+ BC +
Prof total en MD = 1000 +
1939.74 + = 4243.46 ft
Información del pozo Localización del objetivo = 1800 pies @ 135° AZM Profundidad del objetivo (TVD) = 3800’ KOP = 2000’
BUR1 = 5.73° BUR2= 9.54°
14. R1=
Calculo de radios de curvatura (R1 y R2)
= 999.83 ft
= 599.80 ft
R2=
15.
Calcular máximo Angulo de inclinación (θ)
EG= V4 – V1 – R2 = 3800 – 2000 – 599.80 = 1200.1ft EO = DH – R1 = 1800 – 999.83= 800.18 ft Angulo GOE = arctang (EG/EO) = 56.31° OG = (
)= 1442.4ft
OF= R1 – R2= 399.93 ft Angulo GOF = arctang (OF/OG) = 73.90° Max Angulo = 180 - Angulo GOF - Angulo GOE = 180° - 56.31° - 73.90°= 49.79°
16.
Calcular EOB1 en TVD/MD/DH
EOB1 (TVD) = V1 + R1 sen θ = 2763.31 ft EOB1 (MD) = V1 +
= 2868.84 ft
EOB1 (DH) = R1 – R1 cos θ = 354.38 ft
17.
Calcula EOH en en TVD/MD/DH
FG = (
) = 1385.85 ft
EOH (MD) = V1 +
+ BC= 4238.71 ft
BC’ = BC cos θ = 893.35 ft EOH (TVD) = V2 + BC = 3656.9 ft EC’ = (
) = 1056.78 ft
EOH (DH)= D1 + EC’ = 1411.34 ft
18.
Calcular EOB2 MD
EOB2 MD = V1 +
+ BC +
EOB2 MD = 4675.85 ft
19.
Calcular profundidad total TOE (MD)
TOE (MD) = Total MD + Longuitud de navegación TOE (MD) = 4675.74 + 500 = 5173.74 ft
20.
Calcular profundidad total al TOE
Profund total = D3 + longitud de navegación Profund total = 1800 + 500 = 2300 ft
Información del pozo Localización del objetivo = 1800 pies @ 135° AZM Profundidad del objetivo (TVD) = 4000’ KOP = 1800’ BUR1 = 1° BUR2= 10°
1. Calculo de radios de curvatura (R1 y R2) R1=
= 5729 ft
= 572.9 ft
R2=
2. Calcular máximo Angulo de inclinación (θ) EG= V4 – V1 – R2 = 4000 – 1800 – 572.90 = 1627.1ft EO = DH – R1 = 1800 – 5729 = -3929 ft NOTA: este ejercicio no se puede realizar ya que la línea EO sale negativo porque el radio de curvatura 1 (R1) es mucho mayor que el desplaz amiento horizontal
