Shinas College of L A Technology U
1 S E R U T C U R T S F O N G I S E D
N A M Y R O T A R O B A L
Course Code:
AY 2016-2017
Semester: 2
CECE 2240 ID No.:
Name of the Student:
Section No.
Lee!:
S"ecia!i#ation:
Engineering Department
Diploma – Civil Engineering
CONTENTS Experiment. No.
Name of the experiment
Page No.
Table of contents
2
Course objectives, outcomes
3
Auto CAD Software
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Introuction
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!aborator" rules
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DESI%& A&D DETAI!I&% '( C'!+-& 1IT3 S0I*A! STI**+0S
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Date of revision :
CECE2240-Design CECE2240-Design of structures- 1
2|Page
Engineering Department
Diploma – Civil Engineering
CECE 2240
Design of Structure I
0rere8uisites9 %oal
CECE 222
3 Credit Hours
To e8uip t:e stuent wit: an unerstaning of primar" mec:anisms ofbe:avior an t:e basic criteria for esign of simple reinforce concretestructures to enable :im;:er to present t:e final esign for reinforceconcrete structural elements<
Objectives
Outcomes
T:is course s:oul enable t:e stuent to9
T:e stuents s:oul be able to9
1. Establis: esign loas 2. +nerstan t:e esign coe w:ic: is use to esign structures 3. Discuss t:e use of basic approac:es an more uni8ue met:os to anal"=e structures b" :an 4. +nerstan t:e esign of components an complete structures from initial conceptual esign to t:e final esign #< Ientif" t:e responsibilit" of t:e engineer to be et:ical in ealing wit: ot:ers an in t:e presentation of results from anal"sis an esign
1. +se t:e esign coes in orer to prouce t:e esign of structures 2. Appl" iteration met:os to t:e initial esign to converge on an efficient final structure 3. -aintain et:ics wit:in t:e framewor> of professional conuct 4. Design an anal"=e of basic structural elements of reinforce concrete incluing9 a. Singl" an oubl" reinforce beams . 'ne?wa" slabs c. Columns an footings !. Calculate t:e reinforcement etails w:ic: inclue9 a. -a@imum an minimum reinforcement areas< . Spacing of reinforcement c. Curtailment an anc:orage of reinforcement< ". !apping of reinforcement< .< 0resent t:e esign etails to s:ow reinfo reinforce rceme ment nt an si=e si=e re8uir re8uireme ements nts for basic members b" using manual rawing or CAD<
Auto CAD Software:
CECE2240-Design CECE2240-Design of structures- 1
3|Page
Engineering Department
Diploma – Civil Engineering
#utoC#D is a co$$ercia% co$&uter-ai"e" "esign 'C#D( an" 'C#D( an" "rafting soft)are "rafting soft)are a&&%ication. De*e%o&e" 1/ an" $ar+ete" , #uto"es+ , #uto"es+ #utoC#D )as first re%ease" in Dece$er 12 as a "es+to& a&& running on $icroco$&uters on $icroco$&uters )it )it interna% gra&ics interna% gra&ics contro%%ers. contro%%ers.2/ Prior to te intro"uction of #utoC#D $ost co$$ercia% C#D &rogra$s ran on $ainfra$e co$&uters or co$&uters or $inico$&uters $inico$&uters )it eac C#D o&erator 3/ 'user( )or+ing at a se&arate gra&ics ter$ina%. ter$ina%. Since 2010 #utoC#D )as re%ease" as a $oi%e- an" $oi%e- an" )e )e a&& as a&& as )e%% $ar+ete" as #utoC#D 30. #utoC#D is use" across a )i"e range of in"ustries , arcitects &roect $anagers engineers gra&ic "esigners an" $an, oter &rofessiona%s. It )as su&&orte" , 5 !0 training centers )or%")i"e in 14.
Introduction 6ea$s a*e een use" since "i$ anti7uit, to su&&ort %oa"s o*er e$&t, s&ace as roof ea$s su&&orte" , tic+ co%u$ns or as ri"ges tro)n across )ater for e8a$&%e. Te Eg,&tians in*ente" te co%onna"e" ui%"ing tat )as te ins&iration for te c%assic 9ree+ te$&%e. E*en )it te scarcit, of ti$er in Eg,&t )oo"en ea$s su&&orte" te roofs. Ear%, ri"ges )ere ea$s su&&orte" at eac en" , te strea$ an+s or on &i%es on )ic a "ec+ )as constructe" for traffic. In eiter case te trun+ of a tree )as te usua% ea$ tri$$e" an" eiter %eft roun" or s7uare". Our )or" ea$ is in fact cognate )it 9er$an Baum 9er$an Baum or or Dutc boom. boom. # tree $a+es a *er, satifactor, ea$ in"ee" an" &ractica%%, a%% ea$s )ere origina%%, ti$er ea$s. Stone ea$s as in "oor %inte%s cou%" e use" on%, for *er, sort s&ans an" %igt %oa"s ecause of te ritt%eness of stone. 6ritt%e $ateria%s "o not $a+e goo" ea$s. Troug te $i%%ennia ea$s )ere "esigne" , e$&irica% $eto"s a&&%ica%e on%, to s&ecific cases an" inca&a%e of genera%i;ation. 9a%i%eo stu"ie" ea$s an" a%toug e "i" not get it 7uite rigt e so)e" o) te suect sou%" e a&&roace". Te teor, of ea$s )as on%, &erfecte" in te %ate 15t centur, )it te rise of te science of e%asticit, an" )as so)n to e a suect of great co$&%e8it, for )ic a fu%% an" accurate so%ution )as *er, "ifficu%t. Tis re$ains true e*en )it $o"ern co$&utationa% $eto"s suc as te $eto" of finite e%e$ents )ic &ro"uces on%, nu$ers 'not "esigns( ut *er, %itt%e insigt an" "e&en"s on &ara$eters tat are not )e%% +no)n an" $o"e%s tat $a, contain errors. Tese $eto"s a*e great *a%ue ut are not a co$&reensi*e so%ution. Te teor, of ea$s so)s re$ar+a%, )e%% te &o)er of te a&&ro8i$ate $eto"s ca%%e" strengt of $ateri $ateria%s a%s $eto"s $eto"s. . Tese Tese $eto"s $eto"s "e&en" "e&en" on te use of static statics s su&er& su&er&osi ositio tion n an" si$&%i si$&%if,i f,ing ng assu$&tions tat turn out to e *er, c%ose to te trut. Te, gi*e a&&ro8i$ate not e8act resu%ts tat are usua%%, $ore tan a"e7uate for engineering )or+. Ca%cu%us an" a %itt%e "ifferentia% e7uations are a%% te $ate$atics re7uire" for tis a&&roac not te &artia% "ifferentia% e7uations or tensor ana%,sis tat are t,&ica% too%s in e%asticit,. Strengt of $ateria%s $eto"s can e use" for ea$s of aritrar, cross sections for ea$s )ose sa&e *aries a%ong te %engt for %oa"s a&&%ie" in an, "irection at an, &oint "istriute" or concentrate".
CECE2240-Design CECE2240-Design of structures- 1
4|Page
Engineering Department
Diploma – Civil Engineering
# concrete slab is a co$$on structura% e%e$ent of $o"ern ui%"ings. =ori;onta% s%as of stee% reinforce" concrete concrete t,&ica%%, et)een 4 an" 20 inces '100 an" !00 $i%%i$eters( tic+ are $ost often use" to construct f%oors an" cei%ings )i%e tinner s%as are a%so use" for e8terior &a*ing. So$eti$es tese tin tinne nerr s%a s%as s rang rangin ing g fro$ fro$ 2 ince incess '!1 '!1 $$( $$( to ince incess '1!0 '1!0 $$( $$( tic tic+ + are are ca%% ca%%e" e" mud slabs slabs 1/ 2/ &articu%ar%, )en use" un"er te $ain f%oor s%as or in cra)% s&aces. In $an, "o$estic "o$estic an" in"ustria% in"ustria% ui%"ings a tic+ concrete s%a su&&orte" on foun"ations or foun"ations or "irect%, on te susoi% susoi% is use" to construct te groun" f%oor of a ui%"ing. Tese can eiter e groun"-earing or sus&e sus&en"e" n"e" s%as. s%as. In ig ig rise rise ui%"i ui%"ings ngs an" s+,scra&ers an" s+,scra&ers tinner tinner &re-cas &re-castt concrete concrete s%as s%as are s%ung s%ung et)een te stee% fra$es stee% fra$es to for$ te f%oors an" cei%ings on eac %e*e%. On te tecnica% "ra)ings reinforce" concrete s%as are often are*iate" to r.c.c.s%a or si$&%, r.c. Reinforced Concrete Columns
# co%u$n is a *er, i$&ortant co$&onent in a structure. It is %i+e te %egs on )ic a structure stan"s. It is "esigne" to resist a8ia% an" %atera% forces an" transfer te$ safe%, to te footings in te groun". >ou can $anua%%, ca%cu%ate te su&eri$&ose" %oa"s on a co%u$n in a structure using a si$&%e &rocess out%ine" in tis %in+e" artic%e. > artic%e. >ou ou $igt a%so a %so %i+e tis ?CC Co%u$n "esign a&& "esign a&& )ic can ten e use" to ca%cu%ate %ongitu"ina% stee% reinforce$ent in a co%u$n for a gi*en a8ia% %oa". Co%u$ns su&&ort f%oors in a structure. S%as an" ea$s transfer te stresses to te co%u$ns. So it is i$&ortant to "esign strong co%u$ns. Principles of foundation design
Te $ain ro%e of foun"ations is to structura%%, su&&ort te ui%"ing , transferring te %oa"s of te ui%"ing troug te )a%%s into te surroun"ing soi%. In ter$s of a stic+ fra$e structure te foun"ations $ust a%so &rotect te ti$er fro$ $oisture ingress , %ifting te $e$ers ao*e te groun". Te t,&e of soi% on te site )i%% a*e a strong i$&%ication to te foun"ation "esign. Different regions )i%% a*e "ifferent soi% t,&es te ta%e e%o) rief%, "e$onstrates te t,&es of soi% an" its suitai%it, as a foun"ation $ateria%.
LABORAOR! R"L#S
1. No stu"ent )i%% e &er$itte" to )or+ in te %aorator, un%ess a "e$onstrator or instructor is &resent. 2. On co$&%etion of an e8&eri$ent te, a*e to ta+e &rint out an" su$it te ar" co&ies to te concerne" %ecturer. %ecturer. 3. 6efore %ea*ing te c%ass te, a*e to sut"o)n te co$&uter. co$&uter. 4. Don@t use o&en an, oter soft)are e8&ect #uto C#D. !. 6efore ta+ing te &rint out stu"ents a*e to infor$ infor$ to tecnician. . #n, &ro%e$ in te #uto C#D soft)are te, a*e to infor$ to te concern course co urse teacer.
DESI%& &' $9
CECE2240-Design CECE2240-Design of structures- 1
!|Page
Engineering Department
Diploma – Civil Engineering
DESI%& A&D DETAI!I&% '( SI&%!) *EI&('*CED *ECTA&%+!A* C'&C*ETE EA-
CECE2240-Design CECE2240-Design of structures- 1
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Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
5|Page
Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
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Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
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Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
10 | P a g e
Engineering Department
Diploma – Civil Engineering
Detailing of singl reinforced beam
CECE2240-Design CECE2240-Design of structures- 1
11 | P a g e
Engineering Department
Diploma – Civil Engineering
DESI%& &'9 2 DESI%& A&D DETAI!I&% DETAI!I&% '( D'+!) *EI&('*CED *EI&('*CE D *ECTA&%+!A* *ECTA&%+!A* EA-
CECE2240-Design CECE2240-Design of structures- 1
12 | P a g e
Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
13 | P a g e
Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
14 | P a g e
Engineering Department
Diploma – Civil Engineering
DESI%& &' 9 / DESI%& A&D DETAI!I&% '( SI-0!) S+00'*TED '&E 1A) S!A Example: - Design a simply supported rcc slab for a roof of hall 4m x 10m (inside dimension) with 230mm
wall all around. ssume a li!e load of 4 "#$ m 2 and %nish 1 "#$ m 2 . &se '2 and e 41
Soluton: - data gi!en
*oom si+e , 4 x 10 m -all thicness , 230 // , 4 "#$ m 2 , 1 "#$ m 2 *euired %nd depth st.
Sep 1. Calculaton of load.
ssume d ,
span 2
,
4000 2
, 142.
143 mm
(2,20x1.4,2) otal depth , 1435520,16 170 Dead load , 0.17 x 2 , 4.2 "#$ m 2 , 1.0 "#$ m 2 otal D./ , .2 "#$ m 2 // , 4.0 "#$ m 2 actored actored design load , 1.(.254) , 13.7 "#$ m 2 Span lengh of slab
8pan , e9ec:!e span 5 d , 450.143 ,4.143 m Ultmae momen and shear:-
CECE2240-Design CECE2240-Design of structures- 1
1! | P a g e
Engineering Department
M
M
wl 2
wl
2
Diploma – Civil Engineering
13.5! 4.1432
2.55 KNm
13.5! 4.143
2.54 KNm
2
3. Check he deph for he bending:-
',0.13 c b d 2
2.55 10 0.13 2! 1000 d 2 d 2. mm d 143
;"
1. ough calculaton for shear:-
v
v bd
2.54 1000 1000 143
0.2 c '0.3(
c or grade of concrete '2 is 0.36
!. Calculaton of seel area:-
mu
Ast fy 0.5 fy Ast d 1 bd fck
2=.77 x 10
Ast 41! 0.5 41! Ast 1431 1000 143 2! ,
1630.1 st >. >.==343 Ast 2
CECE2240-Design CECE2240-Design of structures- 1
1 | P a g e
Engineering Department
Diploma – Civil Engineering
Ast 2 > 614.47 st 5 4=6710.647,0
Ast
14.4!5
14.4!5 2 4 4510!.45 2
Ast 22 mm2 ". #ain seel:-
&sing 10 bar.
8pacing ,
5!00 22
12! c A c
st pro!ided , 62 mm 2
B Ast 0.43B 0.42B
3. C heck for cenral of crack:-
'in pt , 0.12
As
0.12 1000 150 100
204m 2
Dia ,
150
,21.2?10mm pro!ided o.
'ax spacing not more than 300. o
$. echeck for shear
p,
2 100 1000 143
0.4 @
CECE2240-Design CECE2240-Design of structures- 1
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Engineering Department
*eference table 1=
c
Diploma – Civil Engineering
0.42 N A mm 2
!. Check for de%ecton
Aasic span to depth ra:o ,20 'ul:plying factor for st ,0.42@ ,1.40 llowable /$d ,1.40 x 20 ,2 ssumed is also 2 hence o
s ,
0.12 b D 100
0.12 1000 150 100
204 mm 2
8pacing less than , d or 40 mm ,71 or 40 mm
CECE2240-Design CECE2240-Design of structures- 1
1 | P a g e
Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
1 | P a g e
Engineering Department
Diploma – Civil Engineering
DETAI!I&% '( CA&TI!EE* CA* 0'*C3 DC8E# #; F 4 DESI%& A&D DETAI!I&% Example:- Design a can:le!er porch porch of si+e 200 mm wide and 000 mm long is to be pro!ided at a
height of 3 m from Boor le!el. he porch slab which o!erhangs 200 mm beyond the face of the beam into be cast in Bush with the top face of the beam
ssume li!e load , 0.7 KN A m 2 loor %nish , 0. KN A m 2 Goncrete '20 and e 41
Soluton:-
200 100 20 2 .1 C9ec:!e span , 2!00 , 26 2 he trial depth /$d ,7 'odi%ca:on factor is 2 or e20 fs,0. x fy ,0. x 20 ,14 Ht @ is 0.4
d , 200>20,10 mm
/et the o!erall depth of the slab be reduced to 100 mm at the can:le!er and where bending moment is +ero. 2. 'oads Gonsider 1 m width of slab
CECE2240-Design CECE2240-Design of structures- 1
20 | P a g e
Engineering Department
Diploma – Civil Engineering
8elf weight of slab , (0.250.1)$2 x 2 , 3.7 "#$m -eight due to %nish
, 0.0 "#$m
/i!e load
,0.7 "#$m
otal
, .30 "#$m
&l:mate &l:mate load per meter -u , .3 x 1. , 7.= "#$m 'aximum bending moment (>!e) at the face of support 'u , -u x L A 2 5.! 2 1
2.! 2 2
24.4 KNm
4. (eph from bending momen consideraton
M ur $a8
2.5 1000 10 2 10 .2 KNm 24.4 KNm
'0.14 f ck bd 2 (
;r
24.4 10
2.5 1000 d 2
d , =1.4II d consider (10)
Ast 2
0.! 20 4. 24.4 10 1 1 2!0 20 1000 10 2
CECE2240-Design CECE2240-Design of structures- 1
1000 10
21 | P a g e
Engineering Department
Diploma – Civil Engineering
mm mm 2 &sing 10 bar
spacing spaci ng Hro!ide
1000 5.!
115 mm
10 J 110 c$c
rea pro!ided,1000 pro!ided,1000 x 7.$110 ,713
mm 2
Curailmen of seel
t is proposed to curtail 0@ of the steel reuired at the support since the depth of the slab is tapering and bending moment !aria:ons parabolic the area of reinforcement will get reduced to half at a distance greater than half the span from the free end. Aending moment at 1.6 m
1 . 2 Mu 5.4! 10.15 2 otal depth of slab at 1.6 m from free end , 100 5 1.6(200>100)$2., 164 mm d , 164 >20 ,144 mm
Ast 2
0.! 20 4. 10.15 10 1 1 2!0 2! 0 20 1000 144 14 4 2
1000 144
, 33 mm 2 I (713$2) pro!ided at support Distance Distance from support 200>1600,=00
CECE2240-Design CECE2240-Design of structures- 1
22 | P a g e
Engineering Department
Diploma – Civil Engineering
Gurtail 0@ of the bars at a distance greater of the following a) =00512 , =005120 ,1020 mm b) =005 =005 d , =005 =00514 144, 4, 104 1044 4 mm 8o curtail 0@ of steel at a distance 100 mm from support 6. (isributon seel rea reuired , 1. D , 1.(2005100)$2 ,22
mm 2
8pacing , 1000 x 2$22 , 124 mm Hro!ide 6
J 120 mm c$c
DESI%& &'9 # DESI%& A&D DETAI!I&% DETAI!I&% '( *ECTA&%+!A *ECTA&%+!A* * C'!+-&
CECE2240-Design CECE2240-Design of structures- 1
23 | P a g e
Engineering Department
Diploma – Civil Engineering
DESI%& &' 9 . DESI%& A&D DETAI!I&% '( CI*C+!A* C'!+-& 1IT3 S0I*A! STI**+0S
CECE2240-Design CECE2240-Design of structures- 1
24 | P a g e
Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
2! | P a g e
Engineering Department
Diploma – Civil Engineering
D iameter of t:e column 42 mm Dc iameter of t:e core 42 ?4?4 /4 mm 4? effective cover on bot: sies
Bsp – .mm Asp –; 4 F . 2 27<5# mm 2 Substitute all t:e values we get 0 /.< /5 mm sa" /# mm -a@imum pitc: – 5# mm or Dc;. w:ic: ever is less -inimum pitc: – 2# mm or / times t:e iameter of stirrups w:ic: ever is less
So /# mm is t:e pitc: for t:is problem s it is in safe< . mm iameter wit: /# mm pitc:<
DETAI!I&% '( S6+A*E IS'!ATED (''TI&% D#SI$% %O: & DESI%& A&D DETAI!I&% CECE2240-Design CECE2240-Design of structures- 1
2 | P a g e
Engineering Department
Diploma – Civil Engineering
# s7uare s7uare co%u$n !00$$ !00$$ carries an a8ia% %oa" of 1!00 N . Design s7uare footing for te co%u$n. Te safe earing ca&acit, of te co%u$n is 22! NA$ 2. se <20 an" Fe 41! stee%.
O
Design of t:e founation9 !oa on t:e column $# G& Appro@imate weig:t of t:e footing at $ H of t:e column loa $# G& Total loa $.# G& Safe bearing capacit" of t:e soil 22# G&;m 2 Area of founation $.#;22# 5// m2 F 5// reat: of founation 5// 2<5$ sa" 2<5# m So t:e area of t:e founation is 2<5# F 2<5# m &et upwar pressure loa on t:e column ; area of t:e footing $#;2<5# F 2<5# $J7/45<$$ &;m2< Dept: of t:e founation -inimum ept: of t:e founation p;rK$?sinL;$Msin LN2 22#;$7 K$?sin/;$Msin/N2 $<4 m Determination of t:e ept: of t:e concrete slab below t:e footing< Critical section for bening moment is 25#?#;2 $$2# $$2# mm $<$2# m -a@imum bening moment - $J7/45<$$ $J7/45<$$ @ 2<5# F $<$2# @ $<$2#;2 /4#$5 &m (actore moment -u $<# F $<# F /4#$5 #$55## &m< To fin t:e ept: of t:e slab in t:e founation< -u <$/7 fc> b 2 #$55## <$/7 F 2 F # wit: of column F 2 .$/ mm D .$/ M $2;2 M. .J$ mm $2? ia of bar , . – clear cover for footing T:e ept: of slab of t:e founation is increase b" / H D .J$ F F .J$ J mm J – $2;2? . 722 mm< Determination of 8uantit" of steel re8uire9 Ast 0t F b @ Determination of area of main reinforcement Ast As t 0erc 0ercen enta tage ge of stee steell F b F
O
0erc 0ercen enta tage ge of stee steell
CECE2240-Design CECE2240-Design of structures- 1
25 | P a g e
Engineering Department
Diploma – Civil Engineering
(actore moment -u $<# F $<# F /4#$5 #$55## &m (c> 2 &;mm 2 An (e 4$# &;mm2 b# mm An 722mm Substitute all t:e values in t:e above formula we get 0t <45 H Ast 0t F b @ <45;$ @ # @ 722 $J/2 mm 2 &o of bar Total Total area; area of one bar $J/2; /<$4;4@$2 2 Assume $2 mm ia bars so provie $7 bars of $2 mm iameter< iameter< 3ere t:e column is s8uare so provie t:e same reinforcement on bot: t:e irections<
CECE2240-Design CECE2240-Design of structures- 1
2 | P a g e
Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
2 | P a g e
Engineering Department
Diploma – Civil Engineering
DESI%& &' 9 7 DESI%& A&D DETAI!I&% '( *ECTA&%+!A* (''TI&%
DE!"#N O$ %EC&'N#()'% $OO&"N#
A rectangular column footing footing . mm F 4 mm carries an a@ial loa of 7 G& Design a rectangular footing to support t:e column < T:e safe bearing capacit" of t:e soil is 2 G&;m2 < +se -2 concrete an (e4$# steel< !oa on t:e column 7& Appro@imate weig:t of t:e founation ta>e $ H of t:e weig:t of t:e column column 7& Total loa 77& 77 & Safe bearing capacit" of t:e soil is given as 2 G&;m 2 2&;m2 Area of t:e founation Total Total loa ; Safe bearing capacit" of t:e t:e soil< 2 77;2 4<4 m To fin t:e lengt: an breat: of t:e founation P in case of square footing its easy because by taking square root we get all the values P Area 4<4 ! 4<4 4<4 ;! E8uating t:e projections on bot: sies be"on t:e footing Q ?<4 Q !?<. Sub alue Q K4<4;!N?<4 Q !?<. Solving t:e above e8uation we get ! 2<2 m Sub t:is is value we get 4<4;! 4<4; 2<2 2 m &ow fin t:e projections on bot: t:e a@is <7 m &et upwar pressure column loa ; Area of t:e footing 7;4<4 $7$72 &;m2 Determination of reinforcement in section @@ a@is an )) a@is< ening moment -"" $7$72 F 2<2F <7 F <7;2< $27 &m (actore -oment -u" $27 F $<# $J2 &m Determine t:e ept: -u" <$/7 (c> b 2 $J2 <$/7 @ 2 @ . @ 2 d* 3+, mm. ening moment -@@ $7$72 F 2 F <7 F <7;2< $$./.4<7 &m (actore -oment -u@ $$./.4<7 F $<# $54#45<2&m Determine t:e ept: -u@ <$/7 (c> b 2 $54#45<2 <$/7 @ 2 @ 4 @ 2 d* 3- mm. CECE2240-Design CECE2240-Design of structures- 1
30 | P a g e
Engineering Department
Diploma – Civil Engineering
(rom t:e above two ept: ta>e t:e greater one /J7 mm 0roviing $ mm ia bars at a clear cover of 5 mm D /J7 M $;2 M 5 45/ mm T:e overall ept: ma" increase b" /H 45/ M F45/ .$42&;mm2 (e4$# &;mm2 In t:e 0t formula an fin 0t 0t2 H Ast 2;$ F. @#4#$4.<4mm2
O
&o of bar Total Total area; area of one bar $4.<4; /<$4;4@$2 2 Assume $2 mm ia bar < 0rovie $2 mm ia bars of $ numbers< Determination of area of main reinforcement Ast As t 0erc 0ercen enta tage ge of stee steell F b F
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0erc 0ercen enta tage ge of stee steell
Ta>e -u@ an fin S:orter irection steel (actore -oment (actore -oment -u@ $$./.4<7 $$./.4<7 F $<# $54#45<2&m Determination of 8uantit" of steel re8uire9 Ast 0t F b @ Sub b 4mm #4#mm (c>2&;mm2 (e4$# &;mm 2 In t:e 0t formula an fin 0t 0t<4# H Ast <4#;$ F4 @#4#J7$mm2 &o of bar Total Total area; area of one bar J7$; /<$4;4@$2 2 CECE2240-Design CECE2240-Design of structures- 1
31 | P a g e
Engineering Department
Diploma – Civil Engineering
Assume $2 mm ia bar < 0rovie $2 mm ia bars of J numbers<
CECE2240-Design CECE2240-Design of structures- 1
32 | P a g e
Engineering Department
CECE2240-Design CECE2240-Design of structures- 1
Diploma – Civil Engineering
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