Pemahaman tentang mekanisme perpindahan momentum, energi termal dan massa dalam fluida yang mengalirFull description
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petunjuk memahami konsep dasar momentumFull description
test
Le Fevre High School
(a) Assuming that the nucleus was initially at rest, find the momentum of recoil of the nucleus. the total momentum is conserved p
T(after)
p
But
=
T(after)
p
T(before)
=p e + =0
p
= 0 as nucleus initially at rest. p
+
neutrino
recoiled nucleus
Three momenta after must add up as vectors to give zero. This will occur if the three vectors complete the three sides of a triangle so that the resultant is of zero length = 1.2 x 10
e
-
k p neutrino -22 = 0.6 x 10 k
o
90
nucleus
So
p
nucleus =
(1.2
2
2 + 0.6 )
-22
x 10
= 1.34 x 10-22 kg m s at angle -1
tan
.6 x 10-22 1.2 x 10-22
= 1 = 2
o = 26.6 pe nucleus
153
neutrino
p
nucleus
= 1.3 x 10
-22
-1
o
kg m s at 150 (2sf) to direction of recoil electron
(b) With what velocity does the nucleus begin to recoil? -25 (mass of nucleus = 3.35 x 10 kg). v
=
1.34 x 10 22 3.35 x10 25
= 400 m s i.e. v = 400 m s
-1
-1
o
(2 s.f.) at an angle 153 to direction of recoil electron
