√
√
N° 1 2 3 4 5
TYLER M AL AL LA LA A BE BER TU TU RA RA 3/8" 9423 5/16" 7925 0,265" 6680 3m 5613
U.S.(A.S.T.M) M AL AL LA LA A BE BER TU TU RA RA 3/8" 9510 5/16" 8000 0,265" 6730 1/4" 6350 3m 5660
6 7 8 9
4m 5m 6m
4m 5m 6m
4699 3962 3327
12 13 14 15
7m 8m 9m 10m 12m
2794 2355 1981 1665 1397
7m 8m 10m 12m 14m
1178 991 833
16m 18m 20m
18 19
701
25m
2830 2380 2000 1680 1410
16 17
4760 4000 3360
10 11
14m 16m 20m
1190 1000 841
20 21
24m
24 25
28m 32m 35m
589 495 417
30m 35m 40m
595 500 420
42m
351
45m
354
26 27 28 29 30 31
48m 60m 65m
295 248 208
50m 60m 70m
297 250 210
80m
175
80m
177
32 33 34 35 36 37
41
4000
37
4000
3150
36
3150
2500 2000 1600
35 34 33
2500 2000 1600
1250
32
1250
1000
31
1000
800
30
800
630
29
630
500
28
500
400
27
400
315
26
315
250
25
250
200
24
200
160
23
160 125 100
88
98
100 90 80
21
170m
20
80
200m
74
200m
74
230m
61
230m
63
270m
53
270m
53
325m
43
325m
44
400m
38
400m
37
48 49
5000
22
46 47
125
44 45
38
150 125 105
42 43
5000
100m 120m 140m
40
BRITÁNICA M AL ALLA A BE BER TU TU RA RA
6300
147 124 104
170m
8000
100m 115m 150m
38 39
Francesa AFNOR M AL ALLA A BE BER TU TU RA RA
707
22 23
Alemana DIN M AL ALLA A BE BER TU TU RA RA
71 63 56 50 45 40
19
63
18
50
17
40
5
3353
6 7 8 10 12
2812 2411 2057 1678 1405
14 16 18
1204 1003 853
22
699
25 30 35
599 500 422
44
353
52 60 72
295 251 211
85
178
100 120 150
152 124 104
170
89
200
70
240
66
300
53
Representación de datos de un análisis granulométrico
Se cumple: G(x) +F(x) = 100
Los resultados de los análisis granulométrico son expresados mediante funciones que gobierna el tamaño de las partículas en función a la abertura del tamiz. Para la determinación de la función distribución se utilizan el porcentaje en peso como expresión de frecuencia de un tamaño “x” aparece en la muestra a la cual se realizo el análisis granulométrico. De esta manera es el porcentaje en peso de las partículas entre tamaños y
……(1)
……(2)
……(3)
G(x) =
……(4)
……(5)
……(6)
……(7)
……(8)
( ) = 100( ) =´
=
……(9)
……(10)
µ=
σ =(
( )
)(
)
……(11)
( ) = 100( )
log
= α log
+ =
a=
∑
∑ ∑
∑
∑
(∑
)
α = b=
∑
r= (
∑
∑
∑ )(
∑ ∑
∑ ∑
(∑
) )
+
∑ ∑ (∑ )
Malla
Abertura (um)=X
Peso(gr)
%Peso
G(x )
F(x )
1/2"
13200
8.1
2.7
2.7
97.3
3/8"
9500
20.7
6.9
9.6
90.4
3m
6730
29.1
9.7
19.3
80.7
4m
4760
37.8
12.6
31.9
68.1
6m
3360
28.5
9.5
41.4
58.6
8m
2380
17.4
5.8
47.2
52.8
10m
1680
17.7
5.9
53.1
46.9
14m
1190
15
5
58.1
41.9
20m
841
11.4
3.8
61.9
38.1
28m
595
11.4
3.8
65.7
34.3
35m
420
10.5
3.5
69.2
30.8
48m
297
8.4
2.8
72
28
65m
210
7.2
2.4
74.4
25.6
100m
149
4.2
1.4
75.8
24.2
150m
105
7.2
2.4
78.2
21.8
200m
74
5.4
1.8
80
20
41
8.1
2.7
82.7
17.3
31
6.6
2.2
84.9
15.1
21
5.1
1.7
86.6
13.4
14
4.2
1.4
88
12
10
5.1
1.7
89.7
10.3
Menos
30.9
10.3
100
0
300
100
Malla
Abertura (um)=X
1/2" 3/8"
X
Y
Log(x)
Log(F(x))
Peso(gr)
%Peso
G(x)
F(x)
13200
8.1
2.7
2.7
97.3
4.1205739
1.988113
16.9791295
8.1921659
3.9525927
9500
20.7
6.9
9.6
90.4
3.9777236
1.956168
15.8222851
7.7810973
3.8265949
3m
6730
29.1
9.7
19.3
80.7
3.8280151
1.906874
14.6536993
7.2995406
3.6361667
4m
4760
37.8
12.6
31.9
68.1
3.677607
1.833147
13.5247929
6.7415946
3.3604283
6m
3360
28.5
9.5
41.4
58.6
3.5263393
1.767898
12.4350687
6.2342068
3.125462
8m
2380
17.4
5.8
47.2
52.8
3.376577
1.722634
11.4012719
5.816606
2.9674676
10m
1680
17.7
5.9
53.1
46.9
3.2253093
1.671173
10.40262
5.3900493
2.7928187
14m
1190
15
5
58.1
41.9
3.075547
1.622214
9.45898911
4.9891954
2.6315783
20m
841
11.4
3.8
61.9
38.1
2.924796
1.580925
8.55443162
4.623883
2.4993238
28m
595
11.4
3.8
65.7
34.3
2.774517
1.535294
7.69794439
4.2596996
2.357128
35m
420
10.5
3.5
69.2
30.8
2.6232493
1.488551
6.88143684
3.9048396
2.2157832
48m
297
8.4
2.8
72
28
2.4727564
1.447158
6.11452446
3.5784694
2.0942664
65m
210
7.2
2.4
74.4
25.6
2.3222193
1.40824
5.39270245
3.270242
1.9831398
100m
149
4.2
1.4
75.8
24.2
2.1731863
1.383815
4.72273856
3.0072886
1.914945
150m
105
7.2
2.4
78.2
21.8
2.0211893
1.338456
4.08520618
2.7052739
1.7914658
200m
X^2
XY
Y^2
74
5.4
1.8
80
20
1.8692317
1.30103
3.49402722
2.4319265
1.692679
41
8.1
2.7
82.7
17.3
1.6127839
1.238046
2.60107177
1.9967008
1.5327582
31
6.6
2.2
84.9
15.1
1.4913617
1.178977
2.2241597
1.7582811
1.3899866
21
5.1
1.7
86.6
13.4
1.3222193
1.127105
1.74826386
1.4902797
1.2703652
14
4.2
1.4
88
12
1.146128
1.079181
1.31360947
1.2368799
1.1646322
10
5.1
1.7
89.7
10.3
1
1.012837
1
1.0128372
1.0258392
Menos
30.9
10.3
100
0
54.56133
31.58784
160.50797
87.72106
300
100
49.22542
= 54.56133
= 31.58784
= 160.50797
= 49.22542
0.721110813
b = α = 0.3014
0,722 = log
= 87.72106 r = 0.9975
,
= 18200µm
( ) = 100(
)
,
Malla Abertura (um)=X Peso(gr)
%Peso
G(x)
F(x)
20m
841
0
0
0
100
28m
595
0.9
0.3
0.3
99.7
35m
420
2.4
0.8
1.1
98.9
48m
297
5.1
1.7
2.8
97.2
65m
210
8.4
2.8
5.6
94.4
100m
149
24.6
8.2
13.8
86.2
150m
105
38.7
12.9
26.7
73.3
200m
74
59.7
19.9
46.6
53.4
270m
53
36
12
58.6
41.4
325m
44
21
7
65.6
34.4
400m
37
16.2
5.4
71
29
Malla
Abertura (um)=X
Peso(gr)
%Peso
G(x)
F(x)
Log(x)
20m
841
0
0
0
100
2.924796
2
8.55443162
5.849592
4
28m
595
0.9
0.3
0.3
99.7
2.774517
1.998695
7.69794439
5.5454136
3.9947823
35m
420
2.4
0.8
1.1
98.9
2.6232493
1.995196
6.88143684
5.2338973
3.9808082
48m
297
5.1
1.7
2.8
97.2
2.4727564
1.987666
6.11452446
4.9150146
3.9508172
65m
210
8.4
2.8
5.6
94.4
2.3222193
1.974972
5.39270245
4.5863181
3.9005144
100m
149
24.6
8.2
13.8
86.2
2.1731863
1.935507
4.72273856
4.2062178
3.7461884
150m
105
38.7
12.9
26.7
73.3
2.0211893
1.865104
4.08520618
3.7697282
3.4786128
200m
74
59.7
19.9
46.6
53.4
1.8692317
1.727541
3.49402722
3.2291749
2.9843988
270m
53
36
12
58.6
41.4
1.7242759
1.617
2.97312727
2.7881547
2.6146901
325m
44
21
7
65.6
34.4
1.6434527
1.536558
2.7009367
2.5252611
2.3610118
400m
37
16.2
5.4
71
29
1.5682017
1.462398
2.45925665
2.2933351
2.1386079
87
29
300
100
24.11708
20.10064
55.076332
44.94211
37.15043
-400m
Log(F(x))
X^2
XY
Y^2
= 24.11708
= 20.10064
= 55.076332
= 37.15043
0.958314791
r = 0.9074
b = α = 0.3964
,
=
= 44.94211
,
=
( )=
(
,
)
,
,
µm
Malla Abertura (um)=X Peso(gr)
%Peso
G(x)
F(x)
20m
841
0
0
0
100
28m
595
0.9
0.3
0.3
99.7
35m
420
2.4
0.8
1.1
98.9
48m
297
5.1
1.7
2.8
97.2
65m
210
8.4
2.8
5.6
94.4
100m
149
24.6
8.2
13.8
86.2
150m
105
38.7
12.9
26.7
73.3
200m
74
59.7
19.9
46.6
53.4
270m
53
36
12
58.6
41.4
325m
44
21
7
65.6
34.4
400m
37
16.2
5.4
71
29
=
( )
α
b
+α
+
(
)
)
=
Y Malla Abertura (um)=X Peso(gr) %Peso
G(x)
Log(ln(100/G(x)))
X F(x)
Log(x)
100
2.924796
2
20m
841
0
0
0
28m
595
0.9
0.3
0.3
0.764112067
99.7
2.774517
35m
420
2.4
0.8
1.1
0.654163061
98.9
48m
297
5.1
1.7
2.8
0.553342949
65m
210
8.4
2.8
5.6
100m
149
24.6
8.2
150m
105
38.7
200m
74
270m
Log(F(x))
X^2
Y^2 0
0
1.998695
7.69794439 2.1200419
0.5838673
2 .6232493
1.995196
6.88143684 1.7160328
0.4279293
97.2
2 .4727564
1.987666
6.11452446 1.3682823
0.3061884
0.45975479
94.4
2.3222193
1.974972
5.39270245 1.0676514
0.2113745
13.8
0.296775196
86.2
2.1731863
1.935507
4.72273856 0.6449478
0.0880755
12.9
26.7
0.120740583
73.3
2.0211893
1.865104
4.08520618 0.2440396
0.0145783
59.7
19.9
46.6
-0.117151345
53.4
1.8692317
1.727541
3.49402722 -0.218983
0.0137244
53
36
12
58.6
-0.27210471
41.4
1.7242759
1.617
2.97312727 -0.469184
0.074041
325m
44
21
7
65.6
-0.375105074
34.4
1.6434527
1.536558
2.7009367 -0.616467
0.1407038
400m
37
16.2
5.4
71
-0.465351713
29
1.5682017
1.462398
2.45925665 -0.729765
0.2165522
87
29
300
100
-400m
8.55443162
XY
0
1.619175804
0
24.11708 20.10064
55.076332 5.126596
2.077035
= 24.11708
= 20.10064
= 55.076332
= 37.15043 b = α = 0.7165
( )
=
−(
)
= 44.94211 r = 0.7838
.
=
( )
=
−(
.
.
)
.
µm
Malla 200m 270m 325m 400m -400m
Abertura (um)=X 74 53 44 37
Peso(gr) 2.9 16.3 7.8 6.7 66.3
Malla Abertura (um)=X Peso(gr)
%Peso
G(x)
F(x)
X
Y
Log(x)
Log(F(x))
X^2
XY
Y^2
200m
74
2.9
2.9
2.9
97.1
1.8692317 1.987219 3.49402722 3.7145732 3.9490403
270m
53
16.3
16.3
19.2
80.8
1.7242759 1.907411 2.97312727 3.2889034 3.6382181
325m
44
7.8
7.8
27
73
400m
37
6.7
6.7
33.7
66.3
66.3
66.3
100
0
-400m
100
1.6434527 1.863323
2.7009367 3.0622829 3.4719721
1.5682017 1.821514 2.45925665 2.8565007 3.3179115
6.805162 7.579467 11.627348 12.92226 14.37714
=
=
=
=
0.959145972
= r = 1.0000
b = α = 0.5500
,
=
,
=
( )=
(
,
)
,
,
µm
( )= ( )
=
( ,
)
,
,
( )=
(
,
)
,
% ( )
=
%
,
=
,
µm
a)
Hallamos los W = KW-h/TC (
−
)
=
,
∗
−
∗
=
=218HP
b)
El máximo tonelaje tratado sería utilizando los 250 HP instalados, luego:
.
=
∗
í
