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PENGGAL 2 960/2
STPM 2015
JABATAN PENDIDIKAN NEGERI KELANTAN
SIJIL TINGGI PERSEKOLAHAN MALAYSIA
MARKING SCHEME
PHYSICS 2 (960/2) MODULE 1
1
Marking Scheme
16.
(a)
1. A
6.B
11.A
2.B
7.A
12.A
3.D
8.A
13.B
4.B
9.A
14.D
5.A
10.C
15.D
(i) Sphere X, E 1
Q1 1 2 0 4 0 r1
Sphere Y, E 2
Q2 2 2 0 4 0 r2
The ratio
E1 1 E2 2
(ii) Charge flow until the electric potential of the spheres are the same. Hence (b)
V1 1 V2
1M
1M 1M 1M 1M
V Er Since
So
V1 1 V2
E 1r1 1 E 2 r2
E1 1 E2 2 r Then 1 1 1 2 r2
from
So
1 r2 2 r1
1M
1M Total 7 M
2
17
(a)
E L
dI dt
Symbol explained E = induced e.m.f. in a coil dI = rate of change of current in the/a same coil dt
Alternative 1: N = LI N is the number of turns/loops is the magnetic flux through a coil L is the self-inductance I is the current flowing in the the/a same conductor/coil Alternative 2: = LI
2M/0
is the magnetic flux linkage L is the self-inductance I is the current flowing in the the/a same conductor/coil Alternative 3: N = LI N is the number of turns/loops is the magnetic flux through a coil L is the self-inductance I is the current flowing in the the/a same conductor/coil Alternative 4: The ratio of (magnitude) of induced/back e.m.f in a coil to the rate of change of current in the coil. (b) dI (i) L dt dI I f I i dt t
1M 1M
If = 13 – 4(2) = 5.0 A
1M
Alternative 1:
L
dI dt I f Ii
dI dt t = 21.0 A
(ii)
= LI = (0.26)(5.0) = 1.3 Wb or 5.5 Wb
OR 1M 1M 1M 1M 1M 1M Total 8 M
3
18
(a) (i)
2f 314 frequency ,f 50Hz
(ii)
1M
2.0 V 2 1.14V
Vrms
(b) (i)
1M
When ac flows in the inductor: magnetic flux linkage through the inductor varies sinusoidally.
1M
the change in magnetic flux linkage produces a back-e.m.f. // electromagnetic induction occurred inside the inductor.
1M
According to Len's law: the direction of the back-e.m.f. opposes the supply e.m.f
(ii)
1M
Eback Vapplied 1.0V
(iii)
IRMS
VRMS XL
VRMS 2fL
1M
1M
1M
1.41 A (2 50 5 10 3 ) 0.9 A
(c)
(i)
1M
3M
Axis : 1M Magnitude : 1M (by comparindg) Shape within Period : 1M (ii)
During t = 0 to
1 T : Power P is negative 4
1M 4
– power is returned completely by the inductor to the supply.
1 4
1M
1 2
During t = T to T : Power P is positive -power supplied to inductors.
1M
Hence mean power = 0.
Total 15 M 19
(a) The normal operating voltage is 240 V.
1M
When a voltage of 240 V is supplied, the power dissipated by the electric iron is 1.2 kW (b) (i) The average/mean velocity of the charge carrier/electron/ taking into
1M 1M
consideration the collision with positive ions
1
along/opposite direction of/in an electric field/potential difference applied (ii)
V
m
n
NA V
NA m
1M
1
1M
1M
NA 63.5 103
(NA)
1M
8900
I nAve v
v
1M
I nAe
0.15 8.44 10 (1.0 103 )2 1.6 1019 28
Cross sectional area
= 3.54 × 10-6 ms1 or 3.5 × 10-6 ms1 (c)
1M 1M
1
(i) Current density
J =
I A 15 (4 103 ) 2
1M Area
= 9.375 × 105 A m2 or 9.4 × 105 A m2
1M 1M
1
5
(ii) The resistance of the copper rod
R
l
1M
A 1.69 108 60 (4.0 103 )2
1M
= 6.34 102 Ω
Total 15 M
20
(a) (a) The hall effect is the phenomenon in which a transverse voltage is set up in a conductor carrying a current in a magnetic field Place a piece of n-type or p-type semiconductor in a magnetic field B Let a current I flow in the semiconductor, A millivoltmeter connected across XY of the semiconductor records the Hall voltage Or
2M
1M 1M 1M Or 3M
(b)
(i)
VH Hall Voltage FE FM eE eB VH I , A ac where E , c neA V I e H e B c nea
1M 1M
1M 1M
6
VH
(ii)
IB nea 2M OR
Polarities of VH ; Front edge is negative, Back edge is positive Or
2M
(iii)
The Hall effect Potential Different VH : Magnitude of VH
1 n
1M
Large VH implies ihai volume density of charge carriers is small //
1M
Small VH implies that volume density of charge carriers is large. 1M
Direction of VH perpendicular to the current in a conductor. If direction of VH , is as shown in the above figure, it implies that charge
1M
carriers are negatively charged // If direction of VH is in the opposite direction, its implies that carriers are positively charged. Total 15 M