Structural Engineering Rules of Thumb for designDescripción completa
Structural Engineering Rules of Thumb for designFull description
Useful collection of handy thumb rules for quick assessment of HVAC systems.Full description
HVAC rule of ThumbFull description
Foundation Thumb Rules
Rules of thumb for pilotsDescrição completa
FootingFull description
Tower Rules
Document
Rules ElectricalFull description
Electrical BasicsFull description
Thumb rule designFull description
Rules of Thumb Steel Design
rules of thumb-mechanical
aquaponics
Best Guidelines to select mechanical seals
To Calculate quantity of Steel in Slab , Beam, Column & Footing
Slab area is 400 square meter, thickness of the slab is 150 mm. Concrete quantity required to cast this slab is 400*0.15 = 60 Cubic meter. fter calculatin! concrete quantity, you can remember these thumb rules "ust for !ettin! a basic idea of ho# much quantity of steel is required in those structural members. Steel quantity in a con$entional slab %e&cludin! its beams' #ill be around 60 to 65 (! )er Cubic meter. n beams it #ill be around +00 to ++0 k! )er cubic meter. n columns itll be around +00 to +50 k! )er cubic meter. -or raft footin!s itll be around 100 to 1+0 k! )er cubic meter. Column footin!s 5 k!/m rade beams 100 k!/m 2linth beams 1+5 k!/m 3ain beams abo$e 6m +50 k!/m Columns ++5 k!/m intel beam 1+5 k!/m Sunshades 60 k!/m Cano)y slab u)to +.0 m s)an 1+5 k!/m Staircase #aist slab 150 k!/m oof slab %a' ne #ay slab 70 k!/m %b' 8#o 8#o #ay slab 100 k!/m %c' Square slab 9 4m to 6m si:e 150 k!/m
To Estimate for Number of Bricks , sand, cement Multiply the size of brick and get the volume or e.g. 4 inch brick = 9"x"x4" =!.# x !.$# x !. =!.!%&'# cubic foot (o) &*!.!%&'# = &% bricks +n any kind of ,-+/ 01-/ 2 mortar is assumed in one cubiic foot 3hat is in &!! &!! cubic foot foot 2 0ill 0ill be cubic foot onsider mortar mix ratio &%
3herefore for cement = * 5addition of & and %6 =4.&*&.$# 5& cement bag is &.$# cu.ft.6 =.%' 7.' bags 8and = 4.& = cu.ft
take brick)ork as &!! percent then deduct the mortar for e.g % " )all dimension &!: x &!: &! feet divided by numbers of mortar layer )hich )ill be decided by dividing it by brick laying format for stretcher bond it )ill be &!: ; . 54 inch = .<4;&$6 =! numbers > & = & 5 this )as for vertical 6 no) for horizontal &!:;.# = &>& = &4 ?oints no) &!: x .# x .!' 5 dimesion of mortar laid in horizontal direction6 = !.4 x & ?oints = &$.4 cu.ft @ &!: x . x .!' 5 dimension of mortar laid in vertical direction6 =!.$%4 x &4 ?oints = . add both i.e &$.4 > . = &%.& cu.ft if &!: x &!: x %" = #! cu.ft is &!! 2 the ho) much percent )ill be &%.& of #! cu.ft .. &%.&;#!x&!! = $.$ say 2 )ooah .. that )as Auite a lecture
Percentage of Bricks and Mortar in a Masonry Wall 2osted on 3arch 16, +015 by ;<>3 ? Comments @
Percentage of Bricks and Mortar in a Masonry Wall
Case 1: When thickness of the wall is 4.5” and that of mortar is 12mm ha!ing the following "lan.
n this case >ei!ht of the #all alon! #ith the mortar = %10 & ' D%E & 1+'/+5.4F = 4.+5+G n the abo$e equation 10 = Ho of ei!ht in inches Iidth= 4.5J en!th of the #all alon! #ith the mortar= %5.5 & E' D%5K1+'/+5.4F Lolume of the #all alon! #ith the mortar= #$W$% Lolume of the #all alon! #ith the mortar= EE.+ cubic inch &ol'me of the wall along with the mortar( 4.)2) cft Ho# Humber of
Case 2:When thickness of the wall is ” and that of mortar is 12mm ha!ing the following "lan.
n this case >ei!ht of the #all alon! #ith the mortar = %10 & ' D% E & 1+ '/+5.4F = 4.+5+G Iidth of the #all alon! #ith the mortar = %E1+/+5.4'J = E.4+G en!th of the #all alon! #ith the mortar= %5.5 & E' %5 & 1+/+5.4' = 51.76+G Lolume of the #all alon! #ith the mortar= #$W$% Lolume of the #all alon! #ith the mortar=167+6.67 cubic inch &ol'me of the wall along with the mortar( ./-/) cft Ho# Humber of
Case -: When thickness of the wall is 4.5” and that of mortar is 13mm ha!ing the following "lan.
n this case >ei!ht of the #all alon! #ith the mortar = %10 & ' %E & 10/+5.4' = .54G #idth = 4.5G en!th of the #all alon! #ith the mortar= %5.5 & E' %5 & 10/+5.4' = 51.467G Lolume of the #all alon! #ith the mortar= #$W$% &ol'me of the wall along with the mortar( 4.45 cft Ho# Humber of
Case 4:When thickness of the wall is ” and that of mortar is 13mm ha!ing the following "lan.
n this case >ei!ht of the #all alon! #ith the mortar = %10 & ' %E & 10/+5.4' = .54G #idth = %E 10/+5.4'J E.EG en!th of the #all alon! #ith the mortar= %5.5 & E' %5 & 10/+5.4' = 51.467G Lolume of the #all alon! #ith the mortar= #$W$% &ol'me of the wall along with the mortar( .-51- cft Ho# Humber of
Concl'sion
Ihere in it I= #all thickness in inches m= thickness of the mortar in mm 8he ans#er #ill be the Ma!e of mortar, and for better results round it off. ts &erification is !i$en belo# after the e&am)le from obser$ation. 678MP#6: f thickness of the #all is 4.5J and that of mortar is 1+mm, then #hat #ill the )ercenta!e of mortar used in the #allN 9ol'tion:
