TESTPAPER – I Duration : 30 min
Marks : 25 Q1 to Q5 carry one mark eac
1.
If one one of of the the input input to an ____ ______ __ gate gate is is invert inverted ed then then it become becomess an INHI INHIBIT BITOR OR.. (A AN!
$.
(B NAN!
2.
(B A
(" )
(! 1
+hich +hich one of the fo,,ofo,,o-ing ing is euiva euiva,en ,entt to OR/AN! OR/AN! rea,i0a rea,i0atio tion n (A NAN!/NOR rea,i0ation
(B NAN!/NAN! rea,i0ation
(" NOR/NOR rea,i0ation
(! None of these
+hic +hich h of of the the fo, fo,,o ,o-i -ing ng gat gates es is is a ser serie iess circ circui uitt gate gate (A AN! gate
3.
(! #OR
%(A %(A & AB AB(A (A & AB AB'% '%(" ("! ! & "! "! & (" ⊕ !' !' (A B
*.
(" NOR
(B OR gate
(" #OR gate
(! #NOR gate
(" 1*
(! None of these
The The ma4t ma4ter erm m des desig igna nato torr of of the the term term55 -it -ith h ! as 67B 67B A & B & " & ! is (A 1)
(B )3
Q! to Q13 carry t"o mark eac
8.
;.
The Boo,ea Boo,ean n e4pre e4pressio ssion n for for shade shaded d area area in the the 9enn diagra diagram m is is
(A (4 & : & 4:0
(B 4 & 0 & (4 & : & 0
(" (4 & 0 & (4 & : & 0
(! (4 & : & (4 & : & 0
The The f,oa f,oati ting ng poi point nt bina binar: r: num numbe berr is give given n as as
7
<
6
1
1))1)))1
1)))111)))1))))))))))))
=ind the binar: va,ue of given number.
>.
.
(A 11)))11)))11)))))))
(B /11)))11)))11)))))))
(" /11)))111)))1))))))
(! 11)))111)))1)))))))
=or =or the the fo,, fo,,oo-in ing g ?/ma ?/map5 p5 @O7 @O7 for form m eu euat atio ion n is is
(A 6(15 *5 25 85 5 115 1$5 12
(B 6()5 $5 35 ;5 >5 1)5 115 13
(" 6(15 *5 25 ;5 >5 1)5 115 13
(! 6()5 $5 25 ;5 5 115 1$5 12
Ho- man: man: minim minimum um NAN! NAN! gates gates are are reu reuired ired to imp,em imp,ement ent fo,,o fo,,o-in -ing g Boo,e Boo,ean an func function tion : (A & B B ×(A & " " (A 3
1). 1).
(! >
(B NAN!
(" #OR
(! #NOR
(" A & B
(! B & "
7imp,if 7imp,if: : this this e4pr e4press ession ion AB & (B & "A "A & B(B B(B & " " (A B & A"
1$.
(" ;
(NO (NOR.( R.(#O #OR R.(N .(NAN AN! ! (A NOR
11. 11.
(B 8
(B A & B"
The sing,e/pr sing,e/precision ecision f,oatin f,oating g point binar: binar: number number of the binar: binar: no. 111 11111 111)1 1)111 11)))) ))))) ) is
1*.
(A
)
1)))11)1
11111)111))))))))))))))
(B
1
1)))1))1
111111)111)))))))))))))
("
)
1)11)1)1
11111)111))1)))))))))))
(!
1
11))1)1)
11)11))111))1))))))))))
A 4 : 0 & 4 : 0 & 4 : 0 & 4 : 0 To imp,ement the above Boo,ean e4pression5 minimum no. of gates reuired are (A 1
(B $
(" *
(! 2
Q1#$a% to Q1#$&% carry t"o mark eac 'inke( Ans"er Questions
12(a.The 1)Cs comp,ement of a no. is (2;2>) 1) =ind the no. in decima, euiva,ent. (A 3$3*$)
(B *;2>)
(" 2;*>)
(! 8*8$)
(" (1*23;) >
(! None of these
12(b.The octa, euiva,ent of the ans-er of part a is (A (12823) >
(B (1*123) >
TESTPAPER – II Duration : 30 min
Marks : 25 Q1 to Q5 carry one mark eac
1.
(A 18 ns $.
(B > ns
(B 8*F
3.
(" $3F
(! 3)F
(" @6O7
(! "6O7
+hich of the fo,,o-ing ,ogic fami,: has ma4imum fan/in (A TTD
2.
(! $ ns
@ropagation de,a: is the time taEen bet-een ________ of peaE points on the input and output transistors. (A *;F
*.
(" 2 ns
(B !TD
The main advantages of TTD -ith totem po,e output as compared to other TTD is (A higher fan/in and higher fan/out
(B higher noise margin and ,o- cost
(" fast s-itching and ,o- po-er dissipation
(! None of these
In high/speed TTD5 basic prob,em is (A increase in po-er dissipation
(B increase in propagation de,a:
(" high speed po-er product
(! none of these
Q! to Q13 carry t"o marks eac
8.
7tatement 1G Totem po,e outputs of TTD can be connected together. 7tatement $G Deve, shifting circuits are not reuired for interfacing bet-een <"D and TTD (A 1/True $/True
;.
(B 1/=a,se $/=a,se
(! 1/=a,se $/True
!etermine the ma4imum va,ue of pu,, up resistance for an open co,,ector TTD gate to active a fan out of 1) given that IOH 2)mA. The ,eaEage current f,o-ing through the co,,ector of TTD output transistor is 3) mA and 9OH(min $.29 (A 11.11 E
>.
(" 1/True $/=a,se
(B 11.11
(" *.3 E
(! 3.> E
"onsider the transmission gate of fig. be,o-. The contro, vo,tage is 9() /39 and 9(1 &39. A sinusoid of peaE vo,tage 39 is app,ied at the input. Jiven that 9 T )9.
The entire sinusoid -i,, get through the gate if5 (A " 9() .
(B " 9(1
(! None of these
=or the "6O7 circuit5 determine the output for inputs of 19 and 95 Jiven K9 TK $.*9
(A $9 >9 1).
(" " 9 T
(B 19 9
(" )9 1)9
6atch the fo,,o-ing Output type
Function
(1 totem/po,e output
(a maEes possib,e -ired/AN! connection
($ open/co,,ector output
(b decreases speed/po-er product
(* tri/state output
(c suitab,e for bus operation (d increases noise immunit:
1
$
*
(A d
b
a
(! 1)9 )9
11.
(B b
a
c
(" a
b
c
(! a
c
d
7tate -hether if the fo,,o-ing statements are true. (i The n/channe, 6O7 gates usua,,: emp,o: positive ,ogic (ii The p/channe, 6O7 gates usua,,: emp,o: negative ,ogic (A (i/True5 (ii/=a,se
1$.
(B (i/=a,se5 (ii/True
(" (i/True5 (ii/True
(! (i/=a,se5(ii/=a,se
"onsider the fo,,o-ing statements. 71 G <"D circuits generate noise spiEes during state transitions. 7$ G "6O7 s-itching speed increases -ith operating freuenc: and decreases -ith supp,: vo,tage. "hoose the correct options using the codes given be,o-G/
1*.
(A 71 L True5 7 $ L True
(B 7 1 L True5 7 $ L =a,se
(" 7 1 L =a,se5 7 $ L True
(! 71 L =a,se5 7 $ L =a,se
+henever ne- information is entered in a memor: ,ocation previous data is erased. This happens in _____ (A RA6
(B "A6
(" 7A6
(! Both(A and (B
Q1#$a% ) $&% carry t"o marks eac 'inke( Ans"er Questions
12(a. =or ,o- po-er schottEe: TTD5 the parameters and their va,ues are specified. "a,cu,ate the propagation de,a:5 po-er dissipation5 and the fan out.
@arameter
9a,ue
9""
39
I"H
1.8 mA
I"D
$.> mA
9o,, (min
$.; 9
9oD (min
).29
9iH (ma4
$.)9
9iD (ma4
).>9
IoH (ma4
2.)mA
IoD (ma4
>.)mA
IiH (ma4
).)$mA
IiD(ma4
).2mA
T@DH
1) ns
T@HD
1) ns
(A 1) ns5 $.;3 m+5 $)
(B 1) Ms5 $.;3 +5 1)
(" $) ns5 11 m+5 1)
12(b.=or the above ca,cu,ate the figure of merit and noise margin high and ,o-. (A $;.3 m+ns5 ).295 ).;9
(B $;.3 m+ns5 1.195 ).29
(" $;.3 m+ns5 ).;95 ).29
(! $;.3 m+ns5 1.195 ).;9
(! $) Ms5 11+5 $)
TESTPAPER – III Duration : 30 min
Marks : 25 Q1 to Q5 carry one mark eac
1.
$.
In three/bit subtractor5 the difference is _____ -here 45 :5 0 are inputs of the subtractor. (A ! 4 : 0 & 4 : 0 & 4 : 0 & 4 : 0
(B ! 4 : 0 & 4 : 0 & 4 : 0 & 4 : 0
(" ! 4 : 0 & 4 : 0 & 4 : 0 & 4 : 0
(! None of these
The fina, step in designing the combinationa, circuit is (A to dra- the truth tab,e (B to minimi0e the Boo,ean function for each output obtained (" to determine the input and output variab,es (! to dra- the minimi0ed ,ogic diagram
*.
=or a 2/variab,e ?/map5 the tota, number of ,ogic e4pression that can be obtained are (A *
2.
(" $ 18
(B 18
6atch Dist/I -ith Dist/II and se,ect the correct ans-er b: using codes given be,o-.
Dist I
3.
(! >
Dist II
(a
6u,tip,e4er
1.
7euentia, memor:
(b
!e/6u,tip,e4er
$.
"onverts decima, number of binar:
(c
*.
!ata se,ector
2.
Routes out man: data output -ith sing,e input.
(A a L $5 b L 15 c L 2
(B a L 15 b L $5 c / *
(" a / 25 b L *5 c L 1
(! a L *5 b L 25 c L $
A combinationa, circuit is one in -hich the output depends on the (A input combination and the previous output (B present output and the previous output (" input combination at that time (! input combination at that time and the previous input combination.
Q! to Q13 carry t"o mark eac
8.
To imp,ement =u,, adder using > G 1 6#5 the no. of > G 1 6# reuired are (A 1
;.
(" *
(! 2
Borro- (B of fu,, subtractor is represented b: fo,,o-ing ,ogic function5 -here # is 67B input bit and P is D7B input bit. (A (# ⊕ QP&#Q
>.
(B $
(B Q(# ⊕ QP&#Q
(" Q(# ⊕ QP&#Q
(! (# ⊕ QP&#Q
"onsider the fo,,o-ing ,ogic diagram5
To represent above ,ogic diagram using NAN! gates on,:5 ho- man: minimum NAN! gates are reuired (Assuming both inverted non inverted inputs are avai,ab,e (A *
(B 2
(" 3
(! 8
.
!ra- the E/map for the fo,,o-ing euations f f 1 & f $ f1 (A ⊕ B" f$ (A e B"
1).
11.
1$.
(A
(B
("
(!
The ,ogic circuit sho-n converts :1 L :$ into
(A Jra: code
(B e4cess/* code
(" B"!
(!
The fo,,o-ing ?/map imp,ement
(A B"! to !ecima, !ecoder
(B !ecima, to B"!
(" 1 of 1) !ecoder
(! "hoice (A and (" both
The circuit sho-n in figure has 2 bo4es each described b: inputs @5 5 R and outputs Q5 P -ith P R & @R& @
The circuit acts as a
1*.
(A 2 bit adder giving @ &
(B 2 bit subtractor giving @ L
(" 2 bit subtractor giving L @
(! 2 bit adder giving @ & & R
The circuit given in figure is to be used to imp,ement the function P f(A5 B A & B +hat va,ues shou,d be se,ected for I and S
(A I )5 S B
(B I 15 S B
(" I B5 S 1
(! I B 5 S )
Q1#$a% ) $&% carry t"o marks eac 'inke( ans"er Questions
The figure sho-s a $/decade B"! L to L binar: converter.
12(a.The output of I"1 for an input of $ -i,, be5 (A )1111
(B 1)111)1
(" ))1)1)1
(! ))11111
(" ))1)1)1
(! ))11111
12(b.=or the above part(a5 the fu,, binar: output is5 (A ))111)1
(B 1)111)1
TESTPAPER – I* Duration : 30 min
Marks : 25 Q1 to Q5 carry one mark eac
1.
=or a divide b: 2 counter5 the present input @ is eua, to _____ (A 18
$.
(! 2
(B S & ?
(" S & ?
(! S & ?
(" 6aster/s,ave S/? ==
(! T ==
! f,ip f,op is formed b: combining the inputs of (A S/? ==
2.
(" >
The characteristic euation for S/? f,ip f,op is (A S & ?
*.
(B 1$
(B 7/R f,ip f,op
"onsider the fo,,o-ing diagram
=or the proper functioning of ==5 the present and c,ear inputs must be (A ,ogic )C 3.
(B ,ogic 1C
(" not connected
(! tied together
The output of !/== depends upon (A the data avai,ab,e on ! input ,ine
(B c,ocE signa,
(" 7tate of input ,ine on the triggering edge of c,ocE
(! none of the above
8 to 1* carr: t-o marEs each 8.
7uppose propagation de,a: time of f,ip f,op is ).$ nsec and it is fo,,o-ed b: $ decoders -ith a propagation de,a: time of ).1 nsec each. The time reuired for data input to sett,e before the triggering edge of c,ocE is $ nsec and the time for -hich data remains stab,e is Uust 1 nsec. Then ma4imum operating freuenc: of f,ip f,op -i,, be _____ (A $2 6H0
;.
(B 2)) 6H0
(" 23) 6H0
(! 2*2 6H0
7tatement 1G 7:nchronous counter is ,ess ,iEe,: to end up in erroneous state than as:nchronous counter. 7tatement $G 7:nchronous counter consumes ,es s po-er than as:nchronous counter. "hoose the correct optionG
>.
(A 1 L True5 $/True
(B 1 L True5 $ L =a,se
(" 1 L =a,se5 $ L True
(! 1 L =a,se5 $ L =a,se
@ractica,,: =,ip/=,ops can be designed using (1 NAN! gates
($ NOR gates
(* AN!/OR gates
(2 AN!/NOT gates
"hoose the correct option G (A 1 L True5 $ L True5 * L True5 2 / True (B 1 L True5 $ L =a,se5 * L =a,se5 2 L True (" 1 L =a,se5 $ L True5 * L True5 2 L =a,se (! 1 L True5 $ L True5 * L =a,se5 2 L =a,se .
1).
In c,ocEed 7R f,ip/f,op5 if c,ocE is not present at the instant 7 ) and R 15 then (A =,ip/f,op -i,, be reset
(B =,ip/f,op -i,, have comp,ementar: output
(" =,ip/f,op -i,, have prohibited input condition
(! =,ip/f,op -i,, be in its previous state
"ounter sho-n be,o- is supp,ied -ith a constant c,ocE freuenc: of f c5 then output ) 1$ -i,, have freuenc: of
(A f c* 11.
(B fc8
(" fc>
(! Insufficient !ata
(" 3
(! 2
=o,,o-ing state diagram sho-s c,ocEed seuentia, circuitG
Ho- man: states the seuentia, circuit has (A 8 1$.
(B ;
=igure be,o- sho-s ! t:pe =,ip/=,ops connected as shift register5 then outputs !5 "5 B5 A are given b:G
(i
)))1
))11
(iii
111)
))1)
)))1
1111
)1))
1)))
)111
)))1
)1))
))11
(A i and ii on,: 1*.
(ii
(B ii and iii on,:
(" i5 ii and iii
(! None of these
6a4imum propagation de,a: for a s:nchronous counter and an as:nchronous counter5 each -ith 2 f,ip/f,ops is ____ and _____ respective,:. The propagation de,a: of one f,ip/f,op is $) nsec. (A $ nsec5 $) nsec
(B $) nsec5 >) nsec
(" >) nsec5 >) nsec
(! >) nsec5 $) nsec
Q1#$a% ) $&% carry t"o marks eac 'inke( Ans"er Questions
12(a.Ho- man: f,ip/f,ops are reuired to bui,d a binar: counter circuit to count from ) to $)2> (A 1)
(B
(" 11
(! >
12(b.=or the above part(a5 -hat is the freuenc: of the output of ,ast == for an input c,ocE freuenc: of 8 6HP (A 2.>>* EH0
(B * EH0
(" 8 6H0
(! 3 EH0
TESTPAPER – * Duration : 30 min
Marks : 25 Q1 to Q5 carry one mark eac
1.
$.
The magnitude of ana,og euiva,ent vo,tage in R/$R ,adder net-orE changes if the converter is operated at ver: high freuenc:5 c,ose to ma4imum operating freuenc:. The change -i,, be ______ (A increase in magnitude
(B decrease in magnitude
(" constant magnitude
(! cannot be determined
=or a 1)/bit resistor divider net-orE5 the D7B has a -eight of _____ (A ).;3; V 1) /*
*.
2.
(" ).;;3 V 1) /*
(! None of these
The amount of time reuired to sett,e to a particu,ar desired accurac: of a !A converter is (A !A sett,ing time
(B !A speed
(" !A monotonicit:
(! !A osci,,ation time
=or a digita, input of 1)))5 the ana,og output is 2 m95 then the ma4imum fu,, sca,e output vo,tage for this !A converter -i,, be ______ (A ;.3 m9
3.
(B ).38 V 1) /*
(B 11 m9
(" > m9
(! 13 m9
7tatement 1G In f,ash A! converters5 the number of comparators decreases -ith increases in number of bits. 7tatement $G The dua, s,ope A! converter consists of integrator5 comparator and binar: counter. (A 1/True $/True
(B 1/=a,se $/True
(" 1/True $/=a,se
(! 1/=a,se $/=a,se
Q! to Q13 carry t"o marks eac
8.
In -eighted resistor !A net-orE5 -hich is 2 bit uses 1 E resistor for $ nd D7B5 then the resistor va,ue at 67B -i,, be_______ (A ).1 E
;.
(! None of these
(B 1).8$ns
(" 3.*1 ns
(! 3.*1 Ms
(B W$3F
(" W1)F
(! W3F
(B 1)
(" 11
(!
=or the -eighted resistor net-orE sho-n determine 9A5 assuming ) )9 and 1 &39
(A 3)9 1$.
(" 1$
+hat -i,, be the number of bits reuired at the input of a converter if it is necessar: to reso,ve vo,tages to 8 m9 and the ,adder has &1$9 fu,, sca,e (A >
11.
(B 11
In the circuit sho-n5 the input bits ) and 1 are represented b: ) and 39 resp. The O@/amp is idea,5 but a,, the resistances and the 39 inputs have to,erance of W1)F. The specification for the to,erance of !A" is
(A W*3F 1).
(! None of these
!etermine the aperture time for $ EH0 signa, using a 2 bit A!" -here input sine -ave amp,itude eua,s the ma4imum input for A!". (A $.88 Ms
.
(" 1.) E
Ho- man: bits are reuired at the input of !A ,adder converter so as to get reso,ution of $ m9 -ith fu,, sca,e output vo,tage of 39 (A >
>.
(B ).$3 E
(B *.**9
(" 8.$39
(! 39
7tatement 1G The d:namic memories have ,o-er pacEing densit: than static memories. 7tatement $G !arE current is the phenomenon re,ated to static memories. (A 1/True $/True
1*.
6atch the Dist/I -ith Dist/II
(B 1/True $/=a,se
(" 1/=a,se $/True
(! 1/=a,se $/=a,se
Dist I
Dist II
(a
=,ash converter
1.
Reuires digita, to ana,og converter
(b
!ua, s,ope converter
$.
Reuires a ver: comp,e4 hard-are
(c
7uccessive converter
*.
6inimi0es the effect of po-er supp,: interference
2.
It is a tracEing A! converter
(A a/$ b/* c/2
appro4imation
(B a/2 b/* c/1
(" a/* b/2 c/1
(! a/2 b/$ c/1
Q1#$a% ) $&% carry t"o marks eac 'inke( Ans"er Questions
12(a.=or a binar: -eighted !A converter sho-n determine R f assuming the output vo,tage due to offset as /$9
(A 3))
(B 1)))
(" 13))
(! 3 E9
12(b.=or the above determine the output vo,tage for the combination sho-n.
(A /3.2*;39
(B /).>1$39
(" /1.2*;39
(! None of the above
TESTPAPER – *I Duration : 30 min
Marks : 25 Q1 to Q5 carry one mark eac
1.
$.
In >)>35 microprocessor identifies the opcode fetch b: (A
IO 6 )
7) )
71 )
(B
IO 6 )
7) )
71 1
("
IO 6 )
7) 1
71 )
(!
IO 6 )
7) 1
71 1
The instruction #"HJ e4changes the contents of ____ register pair -ith the contents of ____ register pair. (A B" and !<
*.
(B B" and HD
(" !< and HD
(! @" and HD
After "@I instruction is e4ecuted5 if carr: f,ag is set and 0ero f,ag is reset5 then (A !ata is ,ess than accumu,ator content (B !ata is greater than accumu,ator content (" !ata is eua, to accumu,ator content (! None of the above
2.
3.
In memor: mapped IO of >)>35 the space provided b: memor: and IO device is (A $> and $ 18
(B $18 and $ >
(" $13 and $ 13
(! $18 to be shared bet-een memor: and IO
@rogram counter is a,so ca,,ed as memor: pointer because (A It points to the memor: ,ocation from -here program starts (B It points to the memor: ,ocation -here program ends (" It points to the memor: ,ocation of current instruction (! It points to the memor: ,ocation of ne4t instruction
Q! to Q13 carry t"o marks eac
8.
It is necessar: to mu,tip,: numbers )A H b: )B H and store the resu,t in A. The numbers are avai,ab,e in registers B and " respective,:. A part of >)>3 program for this purpose is given. 69I A5 ))H DoopG
_______ _______ _______ HDT
The seuence of instructions to comp,ete the program -ou,d be (A
("
;.
SNP DOO@
(B
A!!B
A!! B
!"R "
!"R "
SNP DOO@
!"R "
(!
A!! B
SNP DOO@
SNP DOO@
A!! B
!"R "
In case of "6O7 devices5 if inputs is a,,o-ed to f,oat then
>.
(A b: defau,t it is considered as ,ogic )
(B b: defau,t it is considered ,ogic 1
(" I" -i,, get damaged
(! it -i,, not affect I" operation
After the e4ecution of instruction RI65 the accumu,ator contains 8!H. Then -hich of the fo,,o-ing statements is correct 1. !ata is avai,ab,e on 7I! pin $. Interrupt enab,e f,ip f,op is set *. R7T 8.3 and R7T 3.3 are masEed 2. R7T ;.3 is masEed (A None of above
.
(B $ and 2
(" 1 on,:
(! 15 $ and *
"onsider the assemb,: ,anguage program 69I B5 >; H 6O9 A5 B 7TARTG
S6@ N<#T 69I B5 ))H #RA B OT @ORT1 HDT
N<#TG
#RA B S@ 7TART OT @ORT $ HDT
The e4ecution of the above program -i,, resu,t in (A An output of >;H at @ORT 1 (B An output of >;H at @ORT $ (" Infinite ,ooping of program e4ecution -ith accumu,ator data remaining at ))H (! Infinite ,ooping of program e4ecution -ith accumu,ator data a,ternating bet-een ))H and >;H 1).
7tatement 1G In !AA instruction5 if ,o-er nibb,e of accumu,ator is greater than or the au4i,iar: f,ag is set5 then 8 is added to higher nibb,e. 7tatement $G In !AA instruction5 if higher nibb,e of accumu,ator is ,ess than or carr: f,ag is set then 8 is added to higher nibb,e
11.
(A 1/True $/True
(B 1/True $/=a,se
(" 1/=a,se $/True
(! 1/=a,se $/=a,se
6atch the fo,,o-ing Instruction
(i
A((ressin+ Mo(es
D!A $)3) H
(a
direct
(ii 6O9 B5 A
(b
indirect
(iii 6O9 B5 6
(c
register
i
ii
iii
(A
a
b
c
(B
a
c
b
("
b
c
a
(!
b
a
c
1$.
If the operating freuenc: of >)>3 is $ 6H05 find the time reuired to e4ecute 6O9 A5 6. (A 2 Ms
1*.
(B *.3 Ms
(" * Ms
(! 2.3 Ms
(" $
(! 1
The no. of times the ,oop -i,, be e4ecuted is5 D#I
B5 ))); H
DOO@
!"#
B
6O9
A5 B
ORA
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SP
DOO@
(A ;
(B 8
Q1#$a% ) $&% carry t"o marks eac ,ommon Data Questions:
"onsider the fo,,o-ing programG D#I H5 $);)H 69I B5 )3H 69I A5 )1H 7TOR
(B )1 H
(" )$ H
(! )* H
12(b.7pecif: the contents of memor: ,ocation of $);2H after e4ecution of the above programG (A )* H
(B )2 H
(" )3 H
(! )8 H
