Primer simulacro de más que policía. Puedes encontrarnos en instagram @masquepolicia, en blogger http://masquepolicia.blogspot.com.es/ No dejes de seguirnos, preguntas diarias ;)Descripción completa
Descripción: Primer simulacro de más que policía. Puedes encontrarnos en instagram @masquepolicia, en blogger http://masquepolicia.blogspot.com.es/ No dejes de seguirnos, preguntas diarias ;)
Commerce
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M Sc (Design Engineering) I Semester Examination March 2017 Advanced Mechanics of Materials Time 1!0 Min"tes
Max# Mar$s !0
%ote Ans&e an' IE f"ll *"estions# All *"estions carr' e*"al Mar$s Ass"me s"ita+le data &herever necessar' , 1)# From the generalised Hooks law for a material Explain how 81 constants are reduced to 21 constants.
(
σ =
, 2)# The state of stress at point is given b
10
0
3
0
3
0
3
0
2
)
!a
"etermine a# $ctahedral
%ormal stress b# $ctahedral shear stress stress c# aximum shear stress. &se Eigen Eigen value method.
[
σ =
, -) 't a point on the surface turbine engine the strsses are
50
−
20 0
20
0
20
0
0
0
−
]
!a. &sing
ohr(s circle and onl) considering in*plane stresses+ determine the following ,uantities. a# -tress -tresses es acting on an element element inclin inclined ed at an angle angle
∝=
40
degrees b# principal stresses c#
aximmum in*plane shear stress.
, .)# -tate of stress at point is given b)
[
σ =
20 40
−
0
40
0
40
0
− −
0
1 00
]
!a &sing the ohr(s /ircle
determine a# principal stresses b# $ctahedral $ctahe dral stresses c# aximum shear stress. , !)# -how that the following stress function satisf) the stress condition in a beam of rectangular cross section of width 2h and depth d under a total shear force W
, /#) The circular link shown in figure below has a circular crss section 0 cm in diameter.The iof the ring is cm. The load ! is 1 kg./alculate the the stress at ' and 3. /ompare the values with those found b) the straight beam formula. 'ssume 'ssume that the material is not stressed 1
above its elastic strength.
,# 7# ' tor,ue of 1 k%m acts on a bar with the shown cross section+ Fig.shown below. Find the magnitude of the maximum shear stress and the angle of twist per unit length. Take t"/ 4 t'3 4 mm+ t'" 4 t3/ 4 5 mm+ and 6 4 8 6!a.
7.8. rite short notes on an) two of the following. a# /ompatibilit) e,uations. b# 'ir) stress functins in 2" polar cordinates c# Expressions for radial and tangential stresses in a rotating disc of uniform thickness 2