This is the Cape Physics unit 2 2014 paper 1Full description
JEE Advanced 2019 Paper-2 PhysicsFull description
Problem Solving Qualitative Physics SPM Paper 2 Electricity Waves Light
cape Physics unit 2 paper 1Full description
Discussion of Einstein's seminal paper on theory of relativity
Previous Year Question Paper of Physics Gate 2012.
Answer guide for O Level Physics (5054/2) – Paper 2 Theory June 2000
1(a)
speed in increases or or pa parachutist ac accelerates acceleration decreases or increase of speed decreases until until accele accelerat ration ion zero zero or or constan constantt speed/t speed/term ermina inall veloci velocity ty reache reached d
3
(b)
50 m/s and 5 m/s
1
(c)
a = ∆v/t = 4.5-5.0 m/s 2 no more than 3 s. f.
2
2(a)(i)
P=F/A in any form, symbols or words
1
(ii)
F=P.A F = 40 000 F = 100N (not 10kg alone)
3
Any two from: larger area of glass covered by cup/bigger cup /larger area of cup lower pressure inside cup larger atmospheric pressure
2
solid olid gets lar larger/ ger/lo long nger er/e /exp xpan ands ds when hen heat heateed or hot hot or at hig higher her temperature
1
atoms ar are fu further ap apart (n (not at atoms ex expand) atoms vibrate or move faster
2
the rim contra tracts or returns to norma rmal or compres resses wheel when cooled or in normal or everyday use or when heating stops
1
Any two from: faster moving or more energetic molecules escape leaving behind slower or less energetic molecules or mean molecular energy decreases temperature related to mean molecular energy energy is required to break bonds or latent heat is needed
Answer guide for O Level Physics (5054/2) – Paper 2 Theory June 2000
9(a) 9(a)(i (i))
any any appa appara ratu tuss to dete detect ct rad radio ioac acti tivi vity ty (GM (GM tub tubee and and coun counte terr, spar spark k counter etc) any reading taken (e.g. count, count rate mentioned) paper or a few cm air used as absorber or electric or magnetic field used shows decrease (to background) or correct field deflection for α nothing or background through paper or few cm air so no β or only
α
(ii)
or other experimental proof that these particles not present (e.g. no particles where β particles should be deflected)
5
take several readings (counts) (in time or if in space at same distance ) different values obtained (accept other detector ideas)
2
(iii (iii))
handl andlee with with forc forceeps/t ps/to ongs/ ngs/tw tweeezer ezerss or keep dista istan nce from from sour sourcce/ point source away from you or place absorbers in the way (e.g. keep source in lead box or wear lead apron) 1
(b)(i)
134
(ii)
α−particle top no 4 α−particle bottom no 2
1
Po bottom no 84 (iii)
3
formula E = mc2 1.14.10-29 x (3x108)2 1.0(26) x 10-12 J
3
basic complete outline shape vacuum labelled fluorescent screen labelled X and Y plates labelled filament and/or cathode correctly labelled anode as plate with hole or cylinder labelled
6
metal or filament or cathode heated electrons gain enough speed or energy to escape or to be boiled off or t or thermionic emission described
2
anode is is po positive or or ca cathode is is ne negative or or p. p.d. be between an anode an and cathode anode or positive attracts electron or cathode or negative negative repels electron
2
(c)(i)
5 squares used (e.g. 5 seconds as answer) 0.05s or 50ms
2
(ii)
f=1/T = 1/0.05 = 20 Hz
2
(iii)
twice as many waves on screen or length of one wave halved etc
Answer guide for O Level Physics (5054/2) – Paper 2 Theory June 2000
11(a 11(a)( )(i) i)
wate waterr exp expan ands ds on hea heatin ting g or dens densit ity y decr decrea ease sess on on heat heatin ing g hot hot wat water er (not heat) rises cold water falls or circulation described 3
(ii)
source of local heat clear (accept arrow on diagram) method of detecting circulation, e.g. smoke, dye, aluminium or soot particles convection current shown on diagram and complete and consistent with position of source 3
(b)(i)
energy = mcT change in temperature = 5 ˚C 3x4200x5 (= 63 000J)
2
time seen as 30 s P = E/t = 63000/30 = 2100W
2
number of hours = 3/60 =0.05 power in kw =2100/1000 Number of kWh = 2.1 x 0.05 = 0.1(05)
3
Any two from: evaporation conduction/convection conduction/convection to surroundings described radiation