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Aptitude - Problems on Ages ------------------------------------In this section you will find aptitude questions and answers of various difficulty levels on Problems on Ages with explanation for various interview, competitive examination and entrance test in an easy to understand way. You can also checkout Tips and Tricks, Videos related to the topic.Use Green Board or space provided for Rough work whenever you need.
Formulae : In these kind of problems, Ratios of ages of two persons at twodifferent points of time are given and we need to calculate their ages at givenpoint of time . Refer to Helpful rules mentioned in Ratio and Proportion topicto solve these problem without even making equations. Formulae: Ages of A and B are in the ratio of a:b . After “y” years , the ratio of ages becomes m:n . Then their present ages are “ax” and “bx” years, where X =y(m-n)/(an-bm) = Difference in Time * Difference in new ratio / Difference inmultiplication of new and old ratios
Questions and Answers : PadhleBeta.net - Aptitude - Problems on Ages 1) 5 years ago, A was 10 year younger than B. What will be the differencebetween differencebetween their ages after2 years from now?
1) 10 years
3) 9 years
2) 8 years
4) 7 years
Solution : Difference between their ages will always remain same i.e. 10years. PadhleBeta.net - Aptitude - Problems on Ages 2) Ajay got married 9 years ago . Today his age is 1 3 time of his age atthe time of his marriage . Find his present age.
1) 30 years
3) 28 years
2) 36 years
4) 29 years
Solution : Let his age at the time of marriage = X 9 years = ( 1/3 ) * X So,Ajay’s age at the time of marriage = > X = 3 x 9 =27 years Therefore his present age = 27 + 9 = 36 years PadhleBeta.net - Aptitude - Problems on Ages 3) The sum ages of kartik and his father is 78 years . 6 years hence ,father’s age will be twice of
kartik’s age . Find present age of father.
1) 60 years
3) 58 years
2) 46 years
4) 54 years
Solution : Sum of ages ofkartikand hisfather ,6 years from now = 78 + 2 * 6 = 90 years Therefore , father’s age after 6years = (2/3) * 90 = 60 years
= > Father’s present age = 60 –6 = 54 years. PadhleBeta.net - Aptitude - Problems on Ages 4) Ratio of present ages of P and Q is 2:3 . After 6 years, ratio of theirages is 3:4 . Find the present age of P.
1) 10 years
3) 11 years
2) 12 years
4) 18 years
Solution : After 6 years both the ratios are increased by 1 . Therefore , Present age of P = 2 * 6 years = 12 years. PadhleBeta.net - Aptitude - Problems on Ages 5) The sum of ages of Kartik and his father is 35 years. WhenKartik’s agewill beequal to present age of his father , then sum of their ages will be 85years. Find present age ofKartik’s father.
1) 30 years
3) 29 years
2) 22 years
4) 28 years
Solution : Let Kartik’s age be X and his father’s age be Y. Given , at present , X+ Y = 35 years Sum of their ages will be 85 years after = (85 – 35) / 2 = 25 years So,Kartik’scurrentage = ( 35 – 25 ) / 2 = 5 years Therefore, presentage of father = 35 – 5 = 30 years PadhleBeta.net - Aptitude - Problems on Ages
6) Thesum of ages of Sarvesh and his father is 46 years. 3 years back father’s age was4 times more than Sarvesh’s age . Find present age ofSarvesh.
1) 11 years
3) 8 years
2) 12 years
4) 16 years
Solution : Sum of Sarvesh and his father’s age , 3 years ago = 46 – ( 2 * 3 )= 40 years. Therefore ,Sarvesh’s age= 40 * ( 1/5 ) = 8 years. So ,Sarvesh’s present age = 8 + 3 = 11 years. PadhleBeta.net - Aptitude - Problems on Ages 7) In30 years, age of Kartik becomes 3 times of his present age . What is hispresent age?
1) 15 years
3) 18 years
2) 12 years
4) 16 years
Solution : Let Kartik’s present age be x years. Then his age after 30 years will be = 3x years i.e. x + 30 =3x Therefore , 2x = 30 = > x = 30/2 = 15 years. Trick: In 30 years,Kartik’sage will be 3 times, i.e. 2 times morethan his present age . Therefore his presentage = 30/2 = 15 years. PadhleBeta.net - Aptitude - Problems on Ages
8) Sumof present ages of P and Q is 60 years. 5 years hence their ages will be in theratio of 3:4 . Find P’s present age.
1) 20 years
3) 28 years
2) 25 years
4) 26 years
Solution : Sum of the present ages of P and Q = 60 years So, Sum of their ages after 5 years = 60 + (5 * 2) = 70years After 5 years, ratio of Ages of P and Q will be 3:4 Therefore , P’s age after 5 years = (3/7) * 70 = 30 years And , P’s present age = 30 -5 = 25 years PadhleBeta.net - Aptitude - Problems on Ages 9) Atthe time of marriage , a man was 6 years elder to his wife. 12 years aftertheir marriage , his age is 6/5 times the age of his wife. What was wife’s ageat the time of marriage ?
1) 20 years
3) 16 years
2) 22 years
4) 18 years
Solution : Ratio of their ages after 12 years = 6:5 Difference in ages = 6 years Wife’s age = 5 * 6 = 30 years Therefore , Wife’s age at the time of marriage = 30 - 12 = 18years. PadhleBeta.net - Aptitude - Problems on Ages 10) Aand B are 3 years and 2 years old respectively . Their father is 40 years old.After how many years father’s age would be twice of combined age of A and B ?
1) 8 years
3) 11 years
2) 12 years
4) 10 years
Solution : Father’s age = 40 years Children’s combined age = 3 + 2 = 5 years Double of their ages = 5 * 2 = 10 years Difference between father’s age and combined age of children = 40 – 10 = 30 years Therefore , resulting years = {1 / (2 +1 )} * 30 = 10 years PadhleBeta.net - Aptitude - Problems on Ages 11) P’sage is 50 years and Q’s age is 18 years.In how many years will P be twice as old as Q ?
1) 20 years
3) 12 years
2) 14 years
4) 18 years
Solution : Double of Q’s age = 18 * 2 = 36 years Difference between P and Q’s ages = 50 – 36 = 14 years Therefore , P will be twice of Q’s age after 14 years. PadhleBeta.net - Aptitude - Problems on Ages 12) Theages of A and B are in the ratio of 8:5 . If the sum of their ages is 39 years,what will the ratio of their ages after 9 years ?
1) 10 : 8
3) 11 : 6
2) 11 : 8
4) 10 : 6
Solution : Sum of the ratios = 8+5 = 13 Sum of the ages = 39 years Therefore 13 39 years= > 1 3 years Therefore , 9 years 3 New ratio = (8+3) : (5+3) = 11 : 8 PadhleBeta.net - Aptitude - Problems on Ages 13) Sumof present ages of A,B and C is 72 years. If 4 years ago , the ratio of theirages were 1:2:3 respectively, find A’s present age.
1) 18 years
3) 14 years
2) 10 years
4) 20 years
Solution : Sum of present ages of A, B and C is = 72 years Therefore , Sum of their ages 4 years ago = 72 – (4 * 3)= 60 years. 4 years ago ratio of the ages of A , B and C was = 1:2:3 Therefore, A’s age four years ago = (1/6) * 60 = 10 years. So , A’s present age =10 + 4 = 14 years PadhleBeta.net - Aptitude - Problems on Ages 14) Presentage of Kartik’s father is 4 timesKartik’sage . 5 years from now , father’sage willbecome 3 times ofKartik’sage. What is the present age ofKartik’sfather?
1) 45 years
3) 40 years
2) 55 years
4) 50 years
Solution : Older ratio of Father’s andKartik’sage = 4 : 1
New ratio of Father’s andKartik’sage = 3 : 1 Therefore , Father’s age = 4 * [ {5 * (3-1)} / {(4*1) – (3*1)}] = 4 * {(5 * 2) / 1} = 40 years. PadhleBeta.net - Aptitude - Problems on Ages 15) 2years ago A’s age was 6 times of B’s age . 6 years after the ratio between theages of A and B becomes 10 : 3. What is A’s present age
1) 44
3) 38
2) 42
4) 34
Solution : Older ratio = 6:1 Newer ratio = 10:3 Let 2 years ago , ages of B and A were x and 6xrespectively. X = [ {(2+6) * (10-3) }/ {(6*3) – (1 * 10)} ] = 8 * 7 / 8 =7 years Therefore , 2 years ago , A’s age was 6 * 7 = 42 years Therefore, A’s present age = 42 + 2 = 44 PadhleBeta.net - Aptitude - Problems on Ages 16) Ifratio of Kartik’s age to that of his father is 1:5 . After 10 years their ageswill be in the ratio of 1:3 . What is the current age of father?
1) 44years
3) 50 years
2) 42years
4) 34years
Solution : Older ratio of ages father’s andKartik’sages = 5:1 New ratio of agesfather’s andKartik’sages = 3 :1 Therefore Father’s Age =5 * [ {10 * (3-1) } / {(5*1) –(3*1)} ]
= 5 * 10 * 2 / 2 = 50 years Trick: Old ratio = 1:5 New Ratio = 1:3 or 2:6 , That means both the ratios areincreased by 1 Therefore father’s age = 5 * 10 = 50 years PadhleBeta.net - Aptitude - Problems on Ages 17) Ratiobetween present ages of A and B is 3:4 . What is the present age of A if 4years ago , the ratio was 5:7?
1) 24years
3) 20 years
2) 22years
4) 34years
Solution : Older ratio of A and B’s age = 5:7 New ratio of A and B’s ages = 3:4 Difference in years = 4 years Therefore , A’s age 4 years ago = 5 * [{4 * (3-4) }/ {(5*4)–(7*3)}] = 5 * 4 = 20 Therefore, A’s current age =20 + 4 = 24 years PadhleBeta.net - Aptitude - Problems on Ages 18) 3years ago , father’s age was twice age the ages of his 4 sons. After threeyears, father’s age will be equal to sum of ages of the sons. Find the presentage of the father .
1) 24years
3) 40 years
2) 39 years
4) 34years
Solution : 3 years ago let the sum of ages of 4 sons = x
Then father’s age = 2x years Father’s age after 6 years = 2x + 6 Sum of ages of sons = (x+6*4 ) = x + 24 2x + 6 = x + 24 X = 18 Father’s age = 2 * 18+ 3 = 39 years PadhleBeta.net - Aptitude - Problems on Ages 19) Ratioof present ages of father and son is 8:3 . If 10 years from now , the ratiobecomes 2:1 , find present age of son.
1) 14years
3) 15 years
2) 19 years
4) 24years
Solution : Older ratio of ages of Father and son = 8:3 New ratio of ages of father and son = 2:1 Present age of son = 3* [ {10 * (2-1) } / {(8*1) –(3*2)} ] = 3 * 5 = 15 years Trick: Old ratio = 8 : 3 New ratio = 2:1 or 10:5 , i.e. both ratios are increased by2 . Therefore , 2 10 years = > 1 5 years Present age of son = 3 * 5 = 15 years PadhleBeta.net - Aptitude - Problems on Ages 20) 5years ago father’s age was 3 times of his son’s age . 5 years from now , theratio between the ages of father and son becomes 11:5 . Find father’s presentage .
1) 30 years
3) 50 years
2) 40 years
4) 48 years
Solution : Older ratio of father and son’s ages = 3 : 1 Newer ratio of father and son’s ages = 11 : 5 Let 5 years ago father’s age be = 3x years , where X =[{(5+5) * (11- 5) }/ {(3*5) –(1*11)}] =10 * 6 / 4 = 15 Therefore , father’s age 5 years ago = 3 * 15 = 45 years So, present age of father = 45 + 5 = 50 years Trick: Old ratio = 3:1 = 9:3 New ratio = 11 : 5 , that means increase in the ratio is 2 Difference in years = 10 2 10 = > 1 5 years Therefore father’s age5 years ago = 5 * 9 = 45 years So , present age = 45 + 5 = 50 years. PadhleBeta.net - Aptitude - Problems on Ages 21) 3years ago , the age of the father was 7 times of his son’s age . If father’spresent age is 5 times his son’s age . Find the present age of the father ?
1) 45 years
3) 50 years
2) 40 years
4) 48 years
Solution : Older ratio of ages of father and son = 7:1
New ratio of ages of father and son = 5:1 Let 3 years ago , the father’s age was 7x years , where X= 3 * (5-1) / (7-5)= 3*4 / 2 = 6 Therefore, father’s age was = 7 * 6 = 42 years Therefore, his present age = 42 + 3 = 45 years
