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CE 323: ENGINEERING SURVEYS LECTURE UNSYMMETRICAL PARABOLIC CURVES Unsymmetrical or Asymmetrical Parabolic Curves. Curves with unequal tangents or a compound curve where one parabola extends from the P.C. to the point directly below the vertex and a second parabola which extends from this point to the P.T. ππ―π³π π³π (ππ β ππ ) β ππ―
π³π =
Location of Highest or Lowest Point of the Curve: When
π³π ππ π
> π―, the highest or lowest point of the curve
is located on the right side of the curve. When
π³π ππ
When
π³π ππ
π
π
> π―, use πΊπ =
ππ π³π π
< π―, use πΊπ =
ππ π³π π
ππ―
ππ―
(from the P.T.) (from the P.C.)
Illustrative Examples 1. An unsymmetrical parabolic curve has a forward tangent of -8% and a back tangent of 5%. The length of curve on the left side of the curve is 40m long while that of the right side is 60m long. The P.C. is at station 6 + 780 and has an elevation of 110m. An outcrop is found at station 6 + 800 and has an elevation of 108.40m. a. Compute the height of the fill needed to cover the outcrop. b. Compute the elevation of curve at station 6 + 820. c. Compute the elevation of the highest point of the curve. 2. A forward tangent of +6% was designed to intersect a back tangent of -3% at a proposed underpass along EDSA so as to maintain a minimum clearance allowed under a bridge which crosses perpendicular to the underpass. A 200m curve lies on the side of the back tangent while a 100m curve lies on the side of the forward tangent. The stationing and elevation of the grade intersection is 12 + 530.20 and 100m, respectively. The centerline of the bridge falls at station 12 + 575.20. The elevation of the underside of the bridge is 117.48m. a. Determine the clearance of the bridge at the left side if it has a width of 10m. b. Determine the clearance of the bridge at the right side. c. Determine the clearance of the bridge at the center.