hitung baja lengkap.xls

PERHITUNGAN ATAP : ( ATAP BANGUNAN MULTIPURPOSE)

Kuda - kuda atap : WF Cas 600 x 200 x 8 x 13

Kuda - kuda atap : WF 20 x 12 x 6 x !

P"#$"$a%a% :

P"#$"$a%a% :

Beban pada atap Q = Jarak Kuda - kuda = Jarak Kuda - kuda =

57 kg/m2 2.5 m 2 m

Beban pada atap Q = Jarak Gording = Jarak Kuda - kuda =

57 kg/m2 1.5 m 2.5 m

&"$a% pada Kuda - kuda WF :

&"$a% pada Kuda - kuda WF :

Beban terbagi rata q = Q x L = 57 57 x 25

Beban terbagi rata q = Q x L = 57 57 x 15

q =

q =

1!2.5 kg/m"

#5.5 kg/m"

Beban terpu$at %1 = &57 x 25' x &! ( )25'

Beban terpu$at %1 = &57 x 25' x &! ( )25'

%1 =

%1 =

1*)).125 kg

1*)).125 kg

Beban terpu$at terpu$at %2 = &57 x 2*' x &)25 ( 275' 275' %2 =

+#! kg

Kuda Kuda - kuda kuda atap atap : WF 200 x 100 100 x ' ' x (

Kuda Kuda - kuda kuda atap atap : WF 30 30 x 1( 1( x ( x 11

P"#$"$a%a% :

P"#$"$a%a% :

Beban pada atap Q = Jarak Kuda - kuda =

57 kg/m2 2.5 m

Beban pada atap Q = Jarak Kuda - kuda =

57 kg/m2 ).) m

&"$a% pada Kuda - kuda WF :

&"$a% pada Kuda - kuda WF :

Beban terbagi rata q = Q x L = 57 57 x 25

Beban terbagi rata q = Q x L = 57 57 x ))

q =

q =

1!2.5 kg/m"

1##.1 kg/m"

PERHITUNGAN IKATAN ANGIN ATAP b

=

arc tan ( 5.75 /

6 )

=

43. 76

0

PEMBEBANAN A. Beban Tetap

( N)

= N/cos b

=

117 5.46

/c os

43.76

=

1 628. 09

k

B. Beban !e"entara

( N)

= N/cos b

=

194 4.60

/c os

43.76

=

2 693. 39

k

PERHITUNGAN BATANG TARIK  f

#

$/500

=

60 0

/

c os

43. 76

1 628. 09

/

1600 =

& = (4 'A/3. 14)%0 .5

=

1.1 4

2 693. 39

/

2080 =

& = (4 'A/3. 14)%0 .5

=

1.2 8

c"

16

""

/

500 =

1.6621 ,m

A. Beban Beban Tetap Tetap A = N/s =

1 .02

c" %2

c"

B. Beban Beban !e"entara !e"entara A = N/ s =

a&+ &+paka+ bes+ beton f

1 .29

c" %2

KONTROL TERHADAP SYARAT PPBBI (pasal 7.4.2) /$ #= (0.25'/(*'Atep+))%0.5 

=

6

$

=

(



=

n'-'$ '&k

Atep + 6 /

" 40

=

,

2' =

b ' ts

1.5 2 ' =

#=

/

3 0.33

125 '

44. 518 #= ( 0.25' 0.13

)

c os '

15

4 4.518 '

9 =

1 125

16 200.3 11 /

0.01

=

....  

44.518 " 6

"" %2 =

( 2.1' 10%6'

=

16200 .311 k

11 .25

c" %2

11 .25

)) %0.5

PERHITUNGAN GORDING DATA :

N  125.50.20.23

*NAN ATA

=

15

0



=

AA N

($) =

1.5

"

b

=

50

""

tb =

2.3

""

AA !A

($s) =

2

"

A

=

5.747

c"%2

+ =

4.88

c"

($) =

6

"

:

=

4.51

k/"

+; =

1.89

c"

k/"%2

 =

137

c"%4

: =

21.9

c"%3

"

; =

20.6

c"%4

:; =

6.22

c"%3

(a)

AA A B*AT ATA

=

7

$*BA B*NTAN

=

40

AA  <*TA$ *TAA

""

ts =

=

1.5

"

=

5.75

"

=

5.75

"

$A> N AA $1

=

2

b?a

$A> N AA $2

=

5

b?a

=

5

b?a

=

6

"

AA <*TA$

(AN)

125

*A

AA ANTA  <*TA$

&L1' &L2' &L)'

$A> N AA $3 TN $

(k)

2.3

""

PEMBEBANAN : A. Beban Beban at+ at+  @

Beban Atap

=

@

Berat !en&+r+ or&+n

=

@

Berat Aat en;a"b?n

=

7 0.1'(

'

1.5

10.5

,

4.51 )

"

=

10.5

k/"

=

4.51

k/"

=

1.50

k/"

=

16.51

k/"

=

28

(

B. Beban Beban >+&?p >+&?p @

Beban A+r >?an ()

=

@

Beban Terp?sat ()

=

[email protected]'

=

20

'

a 1.5 '

cos

a

k/"%2

=

28.98

=

100

k/"

=

@3.75

k/"

k

C. Beban Beban An+n An+n An+n &ar+ sa"p+n k+r+ = kanan @

+ p+ak an+n

=

@

+ beakan an+n

=

@ 0.4 ' 25 ' $

=

@15

k/"

=

@ 0.4 ' 25 ' $

=

@15

k/"

An+n &ar+ &epan

(0.02'[email protected]) ' 25 ' $

PERHITUNGAN MOMEN A. Ak+bat

Beban at+

" = 1/8 ' " ' cos a ' $%2

=

71.77

k "

"; = 1/8 ' " ' s+n a ' $s%2

=

2.14

k "

B. Ak+bat Ak+bat Beban >+&?p >+&?p @

Beba Beban n A+r A+r >?a >?an n  = 1/8 '  ' cos a ' $%2

=

; = 1/8 '  ' s+n a ' $s%2 = @

125.95 k " 3.75

k "

Beba Beban n eke eker ra a p = 1/4 '  ' cos a ' $

=

p; = 1/4 '  ' s+n a ' $s

=

144.88 k " 12.95

k "

C. Ak+bat Ak+bat Beban An+n An+n @

+ +ak An+n



a = 1/8 ' a ' $%2

=

@16.88 k "

@

+ Beakan An+n



a = 1/8 ' a ' $%2

=

@67.5

k "

@

An+n &ar+ &epan



a = 1/8 ' a ' $%2

=

@67.5

k "

..harus<=20 kg/m^

Ko!"#as" P$!$!a#a# : A. e"bebanan Tetap (Beban at+ , >+&?p)  =

71.77

,

; =

2.14

,

144.88 = 12.95

216.65 k "

=

15.088 k "

B. e"bebanan !e"entara (Beban Tetap , An+n !a"p+n)  =

71.77

,

0

=

71.77

k "

; =

2.14

,

0

=

2.14

k "

c. e"bebanan !e"entara (Beban Tetap , An+n epan)  =

71.77

,

@67.5

=

4.27

k "

; =

2.14

,

0

=

2.14

k "

Ko#%&ol T$'a#'a# : 1231.81 k/c"%2 s"a = /: , ;/ :; = Ko#%&ol L$#%a# : * Ak+bat Beban Terp?sat tera&ap !?"b? E

*

... >ar?s D= 1600 k/c"%2

F = 3.3 c" F; = ;'$s%3/(48'*';) = 0.0998 c" .... D 3.3 c" Ak+bat Beban at+ , >+&?p F = 1/180 ' $ = 3.33 c" @ Beban at+ , A+r >?an F = 5''$%4/(384'*') = 2.67 c" .... D 3.33 c" F; = 5';'$s%4/(384'*';) = 0.56 c" .... D 3.33 c" @ Beban at+ , ekera F = 5''$%4/(384'*') , '$%3/(48'*') 2.45 = F; = 5';'$s%4/(384'*';) , ;'$s%3/(48'*';) 0.12 =

c" .... D c" .... D

3.33 3.33

PERHITUNGAN GAYA NORMAL TEKAN PADA GORDING H!#'a# Go&"#' $#'a# Ra+%$& +rencanakan raFter

CA!T*$$A 375.125



=

375

""

tb =

6

""

b

=

125

""

ts =

9

""

k?&a@k?&a = Asa;ap ' s = (b'ts)'1600 = G = 0.01'k?&a@k?&a =

180

18000

k

k

H!#'a# Go&"#' $#'a# I,a%a# A#'"# H =

G,0.005'n'&k'&-'-

=

180

,

=

182.73

0.005'2'

.... 6 '

=

1.5

16.51 '

/

1.5 ,

20

' cos

30.33

k

P$#'a&- A#'"# Paa Go&"#' 1G

=

2G

=

3G

=

4G

=

= = =

0

k

0.5'0.5'$2/2'(2'k,$2/2'tan a)'0.9'25 206.53

k

0.5'0.5'($2,$3)/2'(2'k,$2/2'tan a,($2,$3/2)'tan a)'0.9'25 487.83

k

0.5'0.5'$3/2'(2'k,($2,$3/2)'tan a+($2,$3)tana)'0.9'25 281.31

k

Ko!"#as" P$!$!a#a# @

Ak+bat Beban Tetap 1 = 2 = 3 = 4 =

G 1.5 ' 3

G ,

=

180.00

k

H =

452.73

k

'

G ,

H =

722.73

k

1.5 '

G ,

H =

452.73

k

,

15

=

30.33

k/"%2

A

=

1808.19

a;a batan "a+"?" (N) @

=

k

A@1@2 =

1175.46

k

1944.60

k

Ak+bat Beban !e"entara 1 =

1

,

1G

=

180.00

k

2 =

2

,

2G

=

659.26

k

3 =

3

,

3G

=

1210.56

k

4 =

4

,

4G

=

734.04

k

=

2783.85

A

a;a batan "a+"?" (N)

=

,

A@1@2 =

PERSAMAAN INTERAKSI /tb = 54.35 D 75 .. ena"pan $/ = 16.00 D 1.25 ' b/ts = 27.17 ber?ba bent?k AG = Asa;ap , 1/6 Aba&an = 1.62 c"%2 = 2.52 c" l+; tep+ = (;/(2'AG)%(1/2) l; = $k;/ l+;tep+ = 79.33 ... I; = 1.6046 sk+p = s/I; = 997.13 k/c"%2

q = 5's/(sk+p'(8@3'1/2)) = = 600 / 4.88 = l = $k/+ = 200 / 1.89 = l; = $k;/+; -

1.00

.... ar?s #=1.

a&+ q =

.... s* =

1371.2 k/c"%2

105.82 .... s*; =

1851.3 k/c"%2

122.95

1 I"a =

2.9177

nt?k Beban Tetap n = A' s*/N

=

5.747

'

1371.2 /

1175.46

=

6.70

n; = A' s*;/N

=

5.747

'

1851.3 /

1175.46

=

9.05

I"a'N/A,q'n/(n@1)' b'/:,b;'n;/(n;@1)';/:; =

861.22

k/c"%2

.... ar?s D= 1600 k/c"%2

N/A,q'/:,;/:; = @

904.12

k/c"%2

.... ar?s D= 1600 k/c"%2

nt?k Beban !e"entara n = A' s*/N

=

5.747

'

1371.2 /

1944.60

=

4.05

n; = A' s*;/N

=

5.747

'

1851.3 /

1944.60

=

5.47

I"a'N/A,q'n/(n@1)' b'/:,b;'n;/(n;@1)';/:; =

966.09

k/c"%2

.... ar?s D= 2080 k/c"%2

N/A,q'/:,;/:; = a&+ proF+ or&+n CN

1231.81

k/c"%2

125.50.20.23

.... ar?s D= 2080 k/c"%2 A"an &+?nakan

PERHITUNGAN SAGROD PEMBEBANAN A

Beban at+

B

Beban >+&?p

=

1

= " ' s+n a ' $s 29.0 ' s+n a

@

Beban A+r >?an

=

2

=

-

Beban Terp?sat

=

3

= ' s+n a

a&a sat? s+s+ a&a  =

17

'

 =

17

'

(

17

8.55 8.55

16.51

' s+n

' $s = 29.0 '

s+n

100  s+n or&+n &an &+anap a&a 3 pekera

,

,

=

15.01

3 

) =

25.89

=

=

400.44

k

223.03

k

15

'

2 =

8

15

'

2 =

1

=

2

15

 "a

=

554.84

k

PERHITUNGAN BATANG TARIK  .... f # 150 Ateras = K/s = 554.84

f

&

#

=

$/500

(4'A/3.14)%0.5

=

/

500 =

0.30

c"

/ 1600 =

0.35

c"%2

0.66

c" .... &+paka+ bes+ beton poos f

8

""

PEMERIKSAAN GORDING PADA PUNAK RA/TER AKIBAT SAGROD B$!a# ; =

 ' tan a

saro&  =

=

554.84

148.73

'

2

' tan =

15

297.46

=

148.73

k

k "

Ko!"#as" B$!a# A. Beban Tetap  = ; =

21664.58

, 29746.319 =

51410.90 k c"

15.087521 k c"

Nt = B. Beban !e"entara  = ; = Nt =

Ko#%&ol T$'a#'a# A. Tera&ap Beban Tetap n = A's*/N

=

J*KL

'

0

/

0.00

=

J*KL

n; = A's*;/N

=

J*KL

'

0

/

0.00

=

J*KL

I"a'N/A,q'n/(n@1)'b'/:,b;'n;/(n;@1)';/:; =

J
k/c"%2

.... a 1600 k

N/A,q'/:,;/:; =

J

k/c"%2

.... ar?s D= 1600 k/c"%2

B. Tera&ap Beban !e"entara n = A's*/N

=

5.747

'

1371.2 /

0.00

=

JJJ

n; = A's*;/N

=

5.747

'

1851.3 /

0.00

=

JJJ

I"a'N/A,q'n/(n@1)'b'/:,b;'n;/(n;@1)';/:; =

J
k/c"%2

.... a 1600 k

N/A,q'/:,;/:; =

J

k/c"%2

.... ar?s D= 1600 k/c"%2

.55

k

.01

k

.89

k

r?s D=  

c"%2

r?s D=  

c"%2

PERHITUNGAN &AUT

TRUSS10 N)#)* &ata%

1+ 17 1# 10 2*

Ga+a N)*#a, N'  k 4 ( ( ( -

5 2*2 27* )+ )+

P*)., T"*paka.

/u#,a $aut

$aut 5#

7**.55 7**.55 7**.55 7**.55 7**.55

).** ).** ).** ).** ).**

*.!* *.!* *.!* *.!* *.!*

s iin baut = !*** kg/,m2 % ge$er baut = *.+ x  x s x n   = Lua$ baut n = um3a4 baut

P "s"* $aut k 0*!.) 0*!.) 0*!.) 0*!.) 0*!.)

N  P "s $aut

ok ok ok ok ok

DESAIN KEKUATAN SAMBUNGAN

Mutu Baja : Fe 360 Mutu Baut : Fe 360

Koe

!ro"i# Sa$%un&an

'eser

Mo$en (entur

B-(.K

)k&+

)k&*$+

Baut f %aut

=

2400 k&8*$2

Tijin =

1 600 k&8*$2

Ttarik =

1120 k&8*$2

Tshear=

960 k&8*$2

Ty

jarak %aut)*$+

ju$#ah

1

2

3

4

/

6





9

10

11

Tota#

Te&, &eser

Te&,tarik

2

 T shear 

T tarik

Te&,iii#

!.RT-( : B223

5F 3461469

920

12/0000

16

12

//,2

43,9

32,6

20,6

10,3

0,0

0,0

0,0

0,0

0,0

0,0

13134,92

403,06/

334,34

399

B110

5F 2/012/69

40

40000

16

6

36,0

1,0

0,0

0,0

0,0

0,0

0,0

0,0

0,0

0,0

0,0

310,00

403,9/

394,32

3/

B1/

5F 39619911

13620

21/2100

16

12

6/,2

/1,4

3,6

26,6

12,

0,0

0,0

0,0

0,0

0,0

0,0

13/6,32

/64,9

/433,96

//21

B222

5F 29149/7/

30

34100

16

10

4/,6

36,

2,

1/,

0,0

0,0

0,0

0,0

0,0

0,0

0,0

9,46

434,41/

303,/

3131

B333

5F /2300121 3339

/29100

16

1 102,2

90,

9,2

6,

/6,2

44,0

33,0

22,0

0,0

0,0

0,0

239,40

923,290

/310,4

//46

B10

5F 44619912

1/11

2302100

16

16

/,1

64,3

/3,/

42,

30,6

20,4

10,2

0,0

0,0

0,0

0,0

3133,20

4,623

360,9

39/2

B200

5F /002001016 1/1

36100

16

1

6,0

6,/

6,0

/,/

4,0

36,0

24,0

12,0

0,0

0,0

0,0

/02,00

4/,/2

461,39

44

B14

5F 600200111 224/

4232200

16

20 106,0

94,0

2,0

0,0

/,0

46,0

34,/

23,0

11,/

0,0

0,0

0//,00

/6,39

40/,6

4203

PERHITUNGAN SAMBUNGAN SAMBUNGAN RA/TER DAN KOLOM  

=

@797646

k c"



=

N

=

<

=

'cosa , N's+na =

@2059.723 k

>

=

's+na , N'cosa =

@1352.746 k

@1893.05 k @893.05

k

+paka+ &+a"eter ba?t f

18

"" .... A

?"a ba?t ;an &+?nakan (n)

=

12

arak antar ba?t 

D=

&

2.5 & 2.5 45

arak antar ba?t 1%2 =

100

c"%2

2%2 =

400

c"%2

3%2 =

900

c"%2

4%2 =

1600

c"%2

=

D= s '

18 ""

100 ""

=

2.5434 c"%2

b?a

D= s D= 7 ' D= s D=

126

18 ""

KT

PERHITUNGAN SAMBUNGAN SAMBUNGAN RA/TER DAN KOLOM  

=

@797646

k c"



=

N

=

<

=

'cosa , N's+na =

@2059.723 k

>

=

's+na , N'cosa =

@1352.746 k

@1893.05 k @893.05

k

+paka+ &+a"eter ba?t f

18

"" .... A

?"a ba?t ;an &+?nakan (n)

=

12

arak antar ba?t 

D=

&

2.5 & 2.5

D= s '

45 arak antar ba?t 1%2 =

100

c"%2

2%2 =

400

c"%2

3%2 =

900

c"%2

4%2 =

1600

c"%2

5%2 =

2500

c"%2

S%2 =

5500

c"%2

T"a =

=

18 ""

=

2.5434 c"%2

b?a

D= s D= 7 ' D= s D=

18

126

""

100 ""

,

'5/(2'S%2)

=

@3625.66 k

= @1425.52 k/c"%2 s"a = T"a/A t = /(n'A) = @62.02 k/c"%2 = (s"a%2,3't%2)%0.5 = 1429.56 k/c"%2 s+

.... D= 1600 k/c"%2... 

SAMBUNGAN PUNAK RA/TER  

=

@797646

k c"



=

N

=

<

=

'cosa , N's+na =

@2059.723 k

>

=

's+na , N'cosa =

@1352.746 k

@1893.05 k @893.05

k

+paka+ &+a"eter ba?t f

18

"" .... A

?"a ba?t ;an &+?nakan (n)

=

12

arak antar ba?t 

D=

&

2.5 & 2.5 45

arak antar ba?t 1%2 =

100

c"%2

2%2 =

400

c"%2

3%2 =

900

c"%2

4%2 =

1600

c"%2

5%2 =

2500

c"%2

S%2 =

5500

c"%2

T"a =

=

'5/(2'S%2)

D= s '

18 ""

=

2.5434 c"%2

b?a

D= s D= 7 ' D= s D=

18

126

""

100 ""

, =

@3625.66 k

= @1425.52 k/c"%2 s"a = T"a/A = /(n'A) = @62.02 k/c"%2 t = (s"a%2,3't%2)%0.5 = 1429.56 k/c"%2 s+

.... D= 1600 k/c"%2... 

SAMBUNGAN KOLOM DAN RANE 

=

@797646

k c"



=

N

=

<

=

'cosa , N's+na =

@2059.723 k

>

=

's+na , N'cosa =

@1352.746 k

@1893.05 k @893.05

k

+paka+ &+a"eter ba?t f

18

"" .... A

?"a ba?t ;an &+?nakan (n)

=

12

arak antar ba?t 

D=

&

2.5 & 2.5

D= s '

45 arak antar ba?t 1%2 =

100

c"%2

2%2 =

400

c"%2

3%2 =

900

c"%2

4%2 =

1600

c"%2

5%2 =

2500

c"%2

S%2 =

5500

c"%2

T"a =

=

18 ""

=

2.5434 c"%2

b?a

D= s D= 7 ' D= s D=

18

126

""

100 ""

,

'5/(2'S%2)

=

@3625.66 k

= @1425.52 k/c"%2 s"a = T"a/A = /(n'A) = @62.02 k/c"%2 t s+ = (s"a%2,3't%2)%0.5 = 1429.56 k/c"%2

.... D= 1600 k/c"%2... 

SAMBUNGAN ANTAR RA/TER  

=

@797646

k c"



=

N

=

<

=

'cosa , N's+na =

@2059.723 k

>

=

's+na , N'cosa =

@1352.746 k

@1893.05 k @893.05

k

+paka+ &+a"eter ba?t f

18

"" .... A

?"a ba?t ;an &+?nakan (n)

=

12

arak antar ba?t 

D=

&

2.5 & 2.5 45

arak antar ba?t 1%2 =

100

c"%2

2%2 =

400

c"%2

3%2 =

900

c"%2

4%2 =

1600

c"%2

5%2 =

2500

c"%2

S%2 =

5500

c"%2

T"a =

=

'5/(2'S%2)

s"a = T"a/A = /(n'A) t

D= s '

18 ""

=

2.5434 c"%2

b?a

D= s D= 7 ' D= s D=

126

100 ""

, =

@3625.66 k

=

@1425.52 k/c"%2

=

@62.02

k/c"%2

18 ""

s+

=

(s"a%2,3't%2)%0.5

=

1429.56

k/c"%2

.... D= 1600 k/c"%2... 

PERHITUNGAN SAMBUNGAN SAMBUNGAN RA/TER DAN KOLOM   =

68829

( 01 $#'a# !11 )

k c"



=

602

k

N

=

151

k

<

=

'cosa , N's+n a =

614

k

>

=

's+na , N'cos a =

210

k

+paka+ &+a"eter ba?t f

16

"" ....

?"a ba?t ;an &+?nakan (n) arak antar ba?t 

=

2.5 &

D= s

2.5

'

16

40 arak antar ba?t

=

1%2 =

81

c"%2

2%2 =

324

c"%2

3%2 =

729

c"%2

4%2 =

1296

c"%2

S%2 T"a s"a t s+

2430

c"%2

=

90

10

=

D= 7 & D=

s

D= 7 '

D=

s

D=

, 637.31

k

=

T"a/A

=

317.13

k/c"%2

=

/(n'A)

=

29.96

k/c"%2

=

(s"a%2,3' t%2)%0.5

=

=

RA/TER 

321.35

k 16

"" ....

?"a ba?t ;an &+?nakan (n) arak antar ba?t 

=

2.5 &

D= s

2.5

'

40 arak antar ba?t

=



;

2

c"

c"

c"2

70

c"2

0

0

0

2

7

0

49

0

3

0

7

0

49

4

7

7

49

49

3 =

""

;2

0

4(98,98)

16 ""

1

=

.... D= 1600

& B 11 '

+paka+ &+a"eter ba?t f

x2+24

k/c"%2

k c"

602

no

""

""

=

68800

16

112

'5/(2' S%2)

 =

2.0096 c"%2

b?a

=

SAMBUNGAN BADAN 

""

A

3 784 c"2



=

 x 6 max S&x2(62'

= +##** x 7 7#!

=

+1! kg

;1

=

 x x max S&x2(62'

= +##** x 7 7#!

=

+1! kg

A 9

=

2.0096 c"%2

b?a

D= 7 & D=

s

D= 7 '

D=

s

D=

112

16 ""

;2

=



=

+*2

n baut

=

++.0 kg

=

+#1 kg

0

;

=

K61 ( K62



=

& Kx2 ( K62'8*.5

= +1! ( ++.0 =

& +1!82 ( +#182 '8*.5

n = 0.25  3.14  & 2  0.6  1600 = 2573 k

n$ = t x d x 1! x 1+** = 2)20 kg & menentukan '

=

017

k

D

2329 k

k/c"%2... 

PERHITUNGAN 7A&UNGAN &AUT  PIN /9INT 4

siin= N)

5*** T+p" &a,)k

kg/,m2 P*).,

&9B' Ga+a "s"*  k 4

.a &aut 5#4

/u#,a

;uas  5#24

k<5#24

.=.% 0>6? .=.%  k<5#24

KET

1

:B1

;< 25*.125

!)5*

1.0

2

5.+7

7+7.51

)***

ok

2

:B2

;< )**.15*

55++

2.2

)

11.!*

!##.)2

)***

ok

)

:B)

;< !5*.2**

71+!

2.2

!

15.2*

!71.)0

)***

ok

!

:B!

;< )5*.175

)+7*

2.2

)

11.!*

)21.0#

)***

ok

5

:B5

;< !**.2**

!27!

2.2

)

11.!*

)7!.07

)***

ok

PERHITUNGAN RAFTER .paka. p*)., :

;< !**.2**.#.1)   = x = ix =

#!.1 ,m2 110* ,m) 1+.# ,m

Ga+a a,a#  9utput 7AP@!0 4  = > =

155*+** kg,m +!+0 kg

T"a%a% Rat"*  B>N
1#.5 m 11*.110*!# 8-----------? 183>018(!

@

=

kg/,m2

2.)! A

1600 k<5#2

 )k 4

1600 k<5#2

 )k 4

PERHITUNGAN K9;9 &A/A .paka. p*)., :

;< !**.2**.#.1)   = x = ix =

#!.1 ,m2 110* ,m) 1+.# ,m

Ga+a a,a#  9utput 7AP@!0 4  =

17*)2** kg,m

> =

51*2 kg

T"a%a% Rat"*  B>N
+ m )5.71!2#57 8-----------? 1!8>!!62

@

= kg/,m2

1.11 A

PERHITUNGAN ANGKER PER;ETAKAN K9;9 diren,anakan p3at baa 

5** x )** x 1* N
#ax  

= =

N
= =

N
#.%  

> =

51*2 kg

T"a%a% Rat"*  B>N
+ m )5.71!2#57 8-----------? 1!8>!!62

@

=

1.11

kg/,m2

A

1600 k<5#2

 )k 4

PERHITUNGAN ANGKER PER;ETAKAN K9;9 diren,anakan p3at baa 

5** x )** x 1* N
#ax  

= =

N
= =

N
#.%  

9egangan minimum 4aru$ dipiku3 angker  x / !5 - x

=

1)2 / 1)0

x C

= = =

2!.) ,m 2!.) x )* x 1)2 x *.5 !#1!! kg

<

ipakai

# f 22

=

C/s !#1!!/1+**

=

)* ,m2

& < = )*.! ,m2 '

PERHITUNGAN P9NA7I iren,anakan dengan 2 ma,am ponda$i 6aitu  1. %onda$i
Kondi$i tana4 dianggap ,ukup baik .*"%5a%aka% : 1. :trau$$ f )* ,m  L = - 1).5 m % a33o@ = 1* 1. %onda$i
ton kg/m2

Beban 6ang bekera diterima o3e4 ponda$i dangka3 $ampai tegangan 25**kg/m2 $i$an6a diterima $trau$$

x C

<

ipakai

= = = =

# f 22

2!.) ,m 2!.) x )* x 1)2 x *.5 !#1!! kg

C/s !#1!!/1+**

=

)* ,m2

& < = )*.! ,m2 '

PERHITUNGAN P9NA7I iren,anakan dengan 2 ma,am ponda$i 6aitu  1. %onda$i
Kondi$i tana4 dianggap ,ukup baik .*"%5a%aka% : 1. :trau$$ f )* ,m  L = - 1).5 m % a33o@ = 1* 1. %onda$i
ton kg/m2

Beban 6ang bekera diterima o3e4 ponda$i dangka3 $ampai tegangan 25**kg/m2 $i$an6a diterima $trau$$

PERHITUNGAN

KOLOM

 5/ 26  126  8  3 - 9

26.

0

%! 9

.8

0

 ! 9

12.6

0

%s 9

.3

0 

 A 9

7.88

02

"; 9

2.73

0 

I< 9

46.

04

=< 9

24.

0

I; 9

234.

04

=; 9

47.

0

"< 9

1.4

L 9

3

0

18

 

,'>02

KIP : ***** ->%! ? 76 L>-

0  

**********************

@ 1.26 !>%s

***************

->%!

9

41.87

L>-

9

8.

1.26 !>%s 9 P$#apa#' !$&!a- !$#%,  *********  A

9 A sa;ap C 1>8 A !aa#

 A

9

"A

9

(1>2 I;)>A

9

L,;>"A

;a

9

********@

L,; 9

1.67

02

.231

0  

6

9

0 

161.32 ,"p 9

>

9

114.

1.6 ,'>02

17.8

PERHITUNGAN

KOLOM

 5/ 26  126  8  3 - 9

26.

0

%! 9

.8

0

 ! 9

12.6

0

%s 9

.3

0 

 A 9

7.88

02

"; 9

2.73

0 

I< 9

46.

04

=< 9

24.

0

I; 9

234.

04

=; 9

47.

0

"< 9

1.4

L 9

3

0

18

 

,'>02

KIP : ***** ->%! ? 76 L>-

0  

**********************

@ 1.26 !>%s

***************

->%!

9

41.87

L>-

9

8.

1.26 !>%s 9 P$#apa#' !$&!a- !$#%,  *********  A

9 A sa;ap C 1>8 A !aa#

 A

9

"A

9

(1>2 I;)>A

9

L,;>"A

;a 1.67

02

.231

0  

9

********@

L,; 9

6

9

0 

161.32 ,"p 9

>

9

114.

1.6 ,'>02

<1 9



,'

<2 9

414

,'

9 < <

9

.4 L,< > "<

9

   

**@ *************@

9

4.

********

1. L,< 9

6

x 9

1.7

E ;

9

;

9

#<

9

#<

9

17.8

223

0   ,'>02

L,; > ";

#< > (#< * 1)

173.2 (A .

E

; 9

1.46

E;

46

,'>02

)> N **************@

N

87

,'

)> N *************@

N

87

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RA/TER

PROYEK : RIKEN ASAHI PLASTIS INDONESIA  SUBYEK : 5ARE HOUSE RA/TER : SB1 ( $l$$# 4*1F +"l$ : ASAHI2.// )

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ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok

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N)#)*

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2

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2.7# 2.7# 2.7# 2.7# 2.7# 2.7# 2.7# 2.7# 2.7# 2.7# 2.7# 2.!* 2.!* 2.!* 2.!* 2.!* 2 !*

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TA&E; PERHITUNGAN TEGANGAN ATAP

TR14

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127.5 127.5 127.5 127.5 70.! 7*.5 7*.5 #* 127.5 127.5 127.5 77 #+.+ 0+.0 00.! 00.! 00.! 00.! 00.!

s iin = +*** kg/,m2

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P*)., T"*paka.

2

N'  k 4 ( ( ( ( ( ( -

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TA&E; PERHITUNGAN TEGANGAN TRU77

Ak.$at &"$a% Ta#$aa% 
Pa%=a%

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200<1>

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1600 k<#2

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23 T (10(10 10 5#

ata P*)., : 4= 7.5 b= 15.*   = 15.75 Cx = ++.** C6 = 2#2.** ix =

Lkx > 

TRU77 ATAP TR1

= =

,m ,m ,m2 ,m! ,m!

1.#1 ,m

tb = t$ = i6 = x = 6 =

*.7* 1.** ).75 1*.#* )7.+*

s =

1+** kg/,m2

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,m ,m ,m ,m) ,m)

A

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PERHITUNGAN TEGANGAN

N)#"* &ata% : P*)., : ; :

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ata P*)., : 4= 7.5 b= 15.*   = 15.75 Cx = ++.** C6 = 2#2.** ix =

Lkx >  l

= = = =

,m ,m ,m2 ,m! ,m!

1.#1 ,m

L / ix

N)#"* &ata% : P*)., : ; :

=

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,m ,m ,m ,m) ,m)

s =

1+** kg/,m2

D

1

D

1.110

103>6 k<5#2

3 T (10(10 10 5#

ata P*)., : 4= 7.5 b= 15.*   = 15.75 Cx = ++.** C6 = 2#2.** ix =

= = = =

,m ,m ,m2 ,m! ,m!

1.#1 ,m

L / i6

=

D N)#"* &ata% : P*)., : ; :

tb = t$ = i6 = x = 6 =

1!* ,m 1+)1 kg & tarik ' !7 kgm *.* -------------? dari tabe3 %%BBC ---?

D

Lkx >  l

TRU77 ATAP TR1

tb = t$ = i6 = x = 6 =

*.7* 1.** ).75 1*.#* )7.+*

,m ,m ,m ,m) ,m)

s =

1+** kg/,m2

1!* ,m 1*)1) kg & tekan ' 2! kgm )7.) -------------? dari tabe3 %%BBC ---? (32>(1 k<5#2

2! T (10(10 10 5#

ata P*)., : 4=

7.5 ,m

tb =

*.7* ,m

b=   = Cx = C6 =

15.* 15.75 ++.** 2#2.**

ix =

Lkx >  l

= = = =

,m ,m2 ,m! ,m!

1.#1 ,m

L / i6

=

,m ,m ,m) ,m)

s =

1+** kg/,m2

D

1.110

D

1.110

!!6>23 k<5#2

6 T (10(10 10 5#

ata P*)., : 4= 7.5 b= 15.*   = 15.75 Cx = ++.** C6 = 2#2.** ix =

Lkx >  l

1.** ).75 1*.#* )7.+*

1!* ,m 1!*22 kg & tekan ' 25 kgm )7.) -------------? dari tabe3 %%BBC ---?

D

N)#"* &ata% : P*)., : ; :

t$ = i6 = x = 6 =

= = = =

,m ,m ,m2 ,m! ,m!

1.#1 ,m

L / i6

*.7* 1.** ).75 1*.#* )7.+*

,m ,m ,m ,m) ,m)

s =

1+** kg/,m2

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=

D

N)#"* &ata% : P*)., : ; :

tb = t$ = i6 = x = 6 =

13>03 k<5#2

12 T (10(10 10 5#

ata P*)., : 4= 7.5 b= 15.*   = 15.75 Cx = ++.** C6 = 2#2.** ix =

,m ,m ,m2 ,m! ,m!

1.#1 ,m

tb = t$ = i6 = x = 6 =

*.7* 1.** ).75 1*.#* )7.+*

,m ,m ,m ,m) ,m)

s =

1+** kg/,m2

Lkx >  l

= = = =

L / i6

1!* ,m 12##5 kg & tarik ' 1*)) kgm *.* -------------? dari tabe3 %%BBC ---?

=

D

N)#"* &ata% : P*)., : ; :

D

1

D

1.1)5

18 T (10(10 10 5#

ix =

= = = =

,m ,m ,m2 ,m! ,m!

1.#1 ,m

L / i6

N)#"* &ata% : P*)., : ; :

tb = t$ = i6 = x = 6 =

*.7* 1.** ).75 1*.#* )7.+*

,m ,m ,m ,m) ,m)

s =

1+** kg/,m2

1!* ,m +0#0 kg & tarik ' 1*++ kgm *.* -------------? dari tabe3 %%BBC ---?

=

D

3>( k<5#2

 2; 0>0> 120 5#

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5.* 5.* !.#* 11.** 11.**

ix =

Lkx >  l

1

818>10 k<5#2

ata P*)., : 4= 7.5 b= 15.*   = 15.75 Cx = ++.** C6 = 2#2.**

Lkx >  l

D

= = = =

,m ,m ,m2 ,m! ,m!

1.51 ,m

L / i6

=

tb = t$ = i6 = x = 6 =

*.5* *.5* 1.51 ).*5 ).*5

,m ,m ,m ,m) ,m)

s =

1+** kg/,m2

12* ,m )55# kg & tekan ' * kgm )0.7 -------------? dari tabe3 %%BBC ---?

D

N)#"* &ata% : P*)., : ; :

20>66 k<5#2

61 2; 0>0> 1(0 5#

ata P*)., : 4= b=   = Cx = C6 =

5.* 5.* !.#* 11.** 11.**

ix =

Lkx >  l

= = = = D

,m ,m ,m2 ,m! ,m!

1.51 ,m

L / i6

=

tb = t$ = i6 = x = 6 =

*.5* *.5* 1.51 ).*5 ).*5

,m ,m ,m ,m) ,m)

s =

1+** kg/,m2

17* ,m 5**0 kg & tarik ' * kgm *.* -------------? dari tabe3 %%BBC ---? 21>(( k<5#2

D

1

& tarik '

& tarik '