Flow Through Triangular Notch 888

FLOW THROUGH TRIANGULAR NOTCH

AIM: - To calibrate to given notch and to determine it’s co-efficient of discharge Cd of 600 or 900 notches. Instruments: . !otc !otchh A""ar ""arat atus us #. $ie% $ie%om omet eter er or or "oin "ointt &aug &augee '. (to" (to" )atc )atchh * (cal (calee Theory:- The discharge



through +-notch +-notch is given b,.

 /1 Cd 2#g tan 3# 41#

$utting 5

 /1 Cd 2#g tan 3# 5  =

ischarge   541#

or

4

1 #

7, measuring the head of )ater 84 over the sill of the notch If

4 4# 4 d t A

 Initial reading at the sill of notch  inal reading at the sill of notch  4e 4ead of of )a )ater ov over si sill of of no notch; 4 44#-4  e"t e"thh of coll collec ecti tion on of )at )ater in meas measur uriing tan< tan<  Time for ==== ====.. ====  Area of measuring tan< 

-act

Ad =

Then   54 1# 5 

=

4

1#

t

cm

'

sec

)e have < /1Cd #g tan 3# Cd =

1 5  / # g tan 3 #

or 900 notch tan #  tan 90# tan >10  Cd =

1 5  / #g

(o )e have  /1 Cd 2#g tan 3# 41# Cd =

1 / # g tan 3 # 4 1  #

To get discharge e?uation for a given notch   5.4n 7, ta
@og 5 + @og 5  @og 4

 

-----------doubt

$utting grou" of log  vs log 4 rom e?uation if 40 means no flo) ta
=

@og - − @og 5  @og 4

If 7, &ra"h 4  o log   log 5 5  Antilog of log 5  EFam"le  if 5  9.G/ n  #.1' Then   9.G/4#.1' This is notch e?uation for given notch

  = 8/15 Cd 2g tanθanH 5/2

!  = 8/15 Cd 2g tan θ/2 H

5/2

Cd =

  54 5  =

1 5  / # g tan 3 #

1#

41  #

 !o) again start the motor till )ater level rise aboveu" to the sill "oint; no) ta
O"#er$at%on

 Angle of notch 600    600 # Initial "ie%ometer reading I  6.>0 cm ' Area of measuring tan< A  @F7  6'F>>  #GG#cm# Ta"&'ar Co'o&(n )or Tr%ang&'ar not*h o) +, , -'. No

Head o) ater

H5/2

Log H

0ea#&r%ng tan1



FR 

.

#./0

H FR3IR 

1.>

Ad =

t

Log 

!  =

#.G/

/./9

 H

5/2

Cd =

15!  8 2g tan θ/2

e"th d Timet 6G.G6

0.G1

1 1 1 1

#'J #>J ##J #'J

60#.6

0.61

#.

#.>0

1.00

11.90

0.G0

1 1 1 1

#/J #9J #/J #/.''J

>/9.#'

#.69

/.G1

Avg  6>.1

'.

(am"le Calculation .

4

 - I    #./-6.>  1.>  6G.G6 @og 4  0.G1

41# -=

Ad t

#. 5  =

'.

#GG# × 1

=

#'

4

Cd =

=

1 #

=

60#.6 cm

=

/./9

60#.6 6G.G6

1 5  / tan 3 # g

=

1 × /./9 #0>.6

d1

'

sec

=

0.61

>.

&ra"h Calculation rom  41#  #1

 ##1 5  =

Cd =

41  #

=

##1 #1

1 5  / tan 3 # g

rom #

=

=

9

1 × /./9 60 / tan # × 9/ #

=

0.6>

'1 / × 0.1GG × >>.'

=

0.6G

t  #'

@og 5  0.9# n=

@og   >.1 @og 4  .>

@og- − @og5  @og4

=

>.1 − 0.9# .>

=

#.16

  54n  94#.16 Tri"e%oidal notch Tri"e%oidal notch Cd  Cd ect D Cd Tri

FRICTION THROUGH 4I4 FLOW  Minor losses in "i"e fitting a""aratus

AIM:- To determine the various losses of head the to determine the constant . (udden enlargement #. (udden Contraction * '. At 900  bend In#tr&(ent:3

$i"e riction a""aratus )ith a "i"e having fitted )ith enlarger and reducer of 900 bend and elbo). Theory:3  +ariable velocit, head loss

the head loss due to variable vetral, ta