FE CBT Electrical Sample Exam II

NCEES CBTExam FE-ElectricalSample Exam-II Dr. Sri Susarla

1

QUESTION 1. The magnitude of the resultant of the three coplanar forces A, B and  is most nearl!"

A. B. . (.

#. $ # .% & .' 1$.)

QUESTION ' Accord According ing to the *odel *odel +ules, +ules, Sectio Section n '$.1-, '$.1-, +ules +ules of profes professio sional nal onduct onduct,, licens licensed ed professional engineers are oligated to"

A. Ensu Ensure re that that desi design gn docum document entss and and sur/ sur/e! e!ss are are re/ie re/ie0e 0ed d ! a panel panel of lice licens nsed ed engineers prior to affiing seal of appro/al B. Epres Epresss pulic pulic opinions opinions under the directio direction n of an emplo! emplo!er er or client client regardl regardless ess of 2no0ledge of su3ect matter . 4ractice 4ractice performing performing ser/ices ser/ices onl! onl! in the areas of of their competence competence and in in accordance accordance 0ith the current standards of technical competence (. Offer, Offer, gi/e, gi/e, or solicit solicit ser/ices ser/ices directl! directl! or indirectl! indirectl! in order to secure 0or2 0or2 or other /aluale or political considerations QUESTION )

FE-CBT-Electrical Sample Exam II

2

The annual interest rate on the unpaid portion of a contract is 1#5. If the interest is compounded 6uarterl!, the effecti/e interest rate is most nearl!"

A. B. . (.

15 175 1%5 '$5

QUESTION  A corrosion protection s!stem is to e designed to protect a cast iron pipe. 8hich one of the follo0ing metals 0ould corrodes efore the pipe9

A. B. . (.

4 Ni u :n

QUESTION 8hich of the follo0ing situations is most appropriate for using rea2;e/en anal !sis9

A. B. . (.

alculating alculating the interest interest rate rate that 0ill ensure ensure that costs and returns returns are e6ual (eterminin (etermining g the numer of units units to produce produce to ensure that that income co/ers co/ers epenses epenses Estalishi Estalishing ng the minimum minimum return return on an in/estment in/estment o/er a set numer numer of !ears !ears

3

QUESTION 7 2

8hich of the follo0ing occurs in the reaction

A. B. . (.

2

+¿

+ ¿ + Zn→Cu + Zn¿ 9 ¿ Cu

Onl! Onl! coppe copperr is oidi= oidi=ed ed Onl! Onl! =in =incc is oid oidi= i=ed ed Both Both copper copper and and =inc =inc are oid oidi=e i=ed d Neither Neither copper copper not =inc is oidi=ed oidi=ed

QUESTION # T0o T0o point charges of - couloms and ;1' couloms are separated separated in air !  ! a distance distance of )$cm. ;1' The permitti/it! of air is %.%-  1$ farads>m. farads>m. Assume Assume that the dielectric dielectric rea2do0n rea2do0n does not occur. The force of repulsion ?N@ et0een the spheres is most nearl!"

A. B. . (.

#.  1$ 1$;1' ;7  1$1' ;7  1$1$ 7  1$17

QUESTION % An electron 0ith mass ?&.1 1$;)1 2g@ is released from the cathode into a /acuum and accelerates to0ards the anode, 0hich tra/els to0ards the cathode. 8hen the electron reaches anode, its /elocit! is most nearl!"

A. B. . (.

-&  1$7 m>s %)  1$7 m>s '7-  1$7 m>s )-  1$' m>s


4

QUESTION & The thermal /oltage for a silicon 4;N 3unction 2ep t at a temperature of $ is most nearl!" nearl !"

A. B. . (.

'7 ').- '7m ').-m

QUESTION 1$ A );phase induction motor is operating at a speed of n ),-$$ rpm 0ith a line /oltage of '$ at 7$C=. The numer of poles this motor has is most nearl!"

A. B. . (.

'  7 %

QUESTION 11 T0o T0o comple numers A and B are as follo0s" A  1$D3) B  ;7 D3 The 6uotient A>B is most nearl!"

A. B. . (.

;$.& ;$.&' ' D31 D31.1 .1' ' $.&' $.&' 31. 31.1' 1' ;$.& ;$.&'; ';31 31.1 .1' ' $.&' $.&'D3 D31. 1.1' 1'


5

QUESTION 1' The indefinite integral of x

A. B. . (.

2

3 x

x x

4

3

x

−

x

2

2

+1 +C

2

− x + 1 2

4

3

− x + 1 is"

−1+ C

4

3

3

x

−

2

2

+ x +C

QUESTION 1) 3

The onl! point of inflection on the cur/e representing the e6uation y = x + x

2

−3 is at"

−2

A.

x=

B.

=−¿ 1>) x =−¿

.

x =0

(.

x =

3

1 3

QUESTION 1 The follo0ing e6uation descries a second;order s!stem" 2

d y dy + 6 +25 y = x ( t ) 2 dx dx The s!stem ma! e descried as" A. Nonl Nonliinear near B. O/er O/erda dam mped ped


6

. rit ritic ical all! l! dampe damped d (. Unde Underd rdam ampe ped d


7

QUESTION 1
A. B. . (.

1'.1'.$ 11.11.$

QUESTION 17. Fou ha/e a fair coin that !ou toss ten times. The proailit! of getting four heads in ten tosses is most nearl!"

A. B. . (.

$. 1 $ .' $ . $. -

QUESTION 1# An engineer testif!ing as an epert 0itness in a product liailit! case should"

A. B. . (.

A/oid A/oid ans0ering ans0ering 6uestions 6uestions from from the opposing opposing attorne! attorne! 4ro/ide 4ro/ide a complete and o3ecti o3ecti/e /e anal!sis anal!sis 0ithin 0ithin his or her area of competenc competencee 4ro/ide 4ro/ide an e/aluation e/aluation of of the characte characterr of the the defendant defendant 4ro/ide 4ro/ide information information on the profess professional ional ac2ground ac2ground of the the defendant defendant




QUESTION 1% The final /alue of Q in the follo0ing flo0 chart is most nearl!"

A. B. . (.

$ 1 ) -


!

QUESTION 1& A single;phase induction motor is rated at $rms, 1$hp, %-5 efficienc! and $.7 pf lagging. The magnitude ?amperes@ of the rms motor current is most nearl!"

A. B. . (.

)).' '%.) 1&.& 17.&

QUESTION '$ A alanced );phase load is rated at 1$$ 2A and $.7- pf lagging. A purel! capaciti/e load is added in parallel 0ith the inducti/e load to impro/e the po0er factor to $.& lagging. The capaciti/e load must suppl! supp l! a reacti/e po0er po 0er ?2A+@ ?2A+@ that is most nearl!" ne arl!"

A. B. . (.

#7 7)1

QUESTION '1 An ammeter, a /oltmeter and a 0attmeter 0ere installed in an ac circuit and read 1- Arms, 11rms rms and 1,-$$ 8, respecti/el!. respecti/el!. The po0er factor of the circuit is most nearl!" n earl!"

A. B. . (.

$. $ .# $.%# 1. $


1"

QUESTION '' One tesla represents a /er! strong magnetic flu densit!. The current ?amperes@ re6uired in a long straight 0ire to produce a 1;tesla flu densit! at $.-m from the 0ire in free space ?use GG$@ is most nearl!"

A. B. . (.

1.'-  1$7 '.-  1$ 1$7 -  1$7 '-  1$7

QUESTION ') A coa coaia iall cal calee tran transm smis issi sion on line line is 2no0n 2no0n to ha/e ha/e a char charact acter eris isti ticc imped impedanc ancee of -$H. -$H. *easurement of the capacitance et0een the center conductor and the outer shield indicates a capacitance per unit length of 1)) p<>m. The inductance per unit length of the coaial cale is most nearl!"

A. B. . (.

7.7 nC> nC>m )) nC>m $.)) GC GC>m ).) GC GC>m

QUESTION ' 8hen data is transmitted in a serial format, an error detection it called a parit! it ma! e appended to the it stream. A serial recei/er that uses e/en parit! has recei/ed the follo0ing nine its ?parit! it follo0ed ! eight data its@. $$$11$1$$ 8hich statement est descries the recei/ed code9

A. B. . (.

No errors errors occurre occurred d during during transmi transmission ssion An e/en numer numer of its its ha/e een een corrupted corrupted during during transmiss transmission ion An odd numer numer of its its ha/e een corrupt corrupted ed during during transmissi transmission on A it it transferred transferred as a one ?1@ has has een changed to to a =ero ?$@ during during transmissi transmission on


11

QUESTION 'In data transmission terminolog!, a station refers to a computer, terminal, telephone, or some other communication de/ice. The transmission path connecting a pair of stations is called a channel or lin2. The lin2s ma! e simple, half;duple, or full duple. Assume that there are fi/e stations, and each station is capale of sending or recei/ing. All stations are full! interconnected 0ith full;duple lin2s. The numer of lin2s re6uired to connect the net0or2 is"

A. B. . (.

 1$ '-

QUESTION '7. The transport of la!er of the OSI frame0or2 pro/ides a mechanism for the echange of data et0een end s!stems. Eamples of protocols that operate on the transport la!er include"

A. B. . (.

I4 and and T4 T4 I4 an and U( U(4 T4 T4 and and U( U(4 I4, I4, T4 T4 and U(4 U(4

QUESTION '# The inar! numer 1$11 corresponds to the decimal n umer"

A. B. . (.

) 1$ 11 1-


12

QUESTION '% A se6uential logic circuit has one input ?@, one output ?=@, and si states laeled A;<. The circuit is descried ! the state lael sho0n elo0. Entries in the t0o right;hand columns represent the net;s net;stat tate>o e>outp utput; ut;/al /alue ue comin cominati ation on for each presen present;s t;stat tatee condit condition ion and input input /alue. /alue.
If the circuit is initiall! in State  and the input se6uence 1$$ is applied, the output se6uence is est descried !"

4resent state

A B  ( E < A. B. . (.

Net State>output Input $ 1 >$ A>$ B>1 (>$ (>$ B>1 <>1 B>1 E>1 <>$ <>$ A>1

1$1 $1$ 1$$ 111


13

QUESTION '& An instruction pipeline is a computer design techni6ue that generall! impro/es performance for 0hich of the follo0ing reasons9

A. B. . (.

The time time to eecute eecute an instru instruction ction is is reduced reduced The time to access instru instructions ctions is reduced reduced since instruct instruction ion codes are prefetched prefetched *emor! *emor! acce access ss tim timee is redu reduced ced *ultiple *ultiple instruct instructions ions can e eecuted eecuted simult simultaneousl aneousl! !

QUESTION )$ The follo0ing function counts do0n starting at F. 8hat numer does the countdo0n return if it is called 0ith F 1$9
;1 $ 1 1$


14

QUESTION )1 T0o T0o 0a/e forms are represented ! the follo0ing e6uations" cos ( ωt )− i1=10 cos )−7cos ( 3 ωt )−3sin (5 ωt )

i 2=10sin ( ωt )+ 3cos ( 3 ωt )+ 7cos ( 5 ωt ) Co0 do their +*S /alues compare9

A. B. . (.

+*S +*S +*S +*S +*S +*S +*S +*S

/al /alue ue of i1?t@ and i'?t@ are non;=ero and e6ual /al /alue ue of i1?t@ is larger than that of i'?t@ /al /alue ue of i1?t@ is smaller than that of i'?t@ /al /alue ue of i1?t@ and i'?t@ are each =ero.

QUESTION )' In the resistor resistor circuit sho0n elo0, elo0, the e6ui/alent e6ui/alent resistance resistance +e6 ?H@ at Termin Terminals als a; is most nearl!"

A. B. . (.

'' '$  '


15

QUESTION )) The po0er ?8@ dissipated in the &$;H resistor of the circuit sho0n e lo0 is most nearl!"

A. B. . (.

% 1% $ #1

QUESTION ) In the circuit sho0n, /oltage $ ?@ is most nearl!"

A. B. . (.

1&.1%.17.). $

QUESTION )FE-CBT-Electrical Sample Exam II

16

A 1$$$;H resistor is in series 0ith a ';mC inductor. An ac;/oltage source operating at a fre6uenc! of 1$$,$$$ rads>s is attached to the impedance. The impedance ?H@ of the + comination is most nearl!"

A. B. . (.

'$$ '$$ D31, D31,$$ $$$ $ 1,$$ 1,$$$ $ D3 D3'$$ '$$ )%. )%. D31& D31&' ' 1,$$ 1,$$$ $  3'$$ 3'$$


17

QUESTION )7 The circuit sho0n in figure 1 is presented as the Norton e6ui/alent circuit in figure '. The /alue of +N ?H@ is most nearl!"

A. B. . (.

-$ 7$ 1$$ 1'$


1

QUESTION )# In the circuit sho0n elo0, the fre6uenc! of the /oltage source can e /aried o/er a road range of fre6uencies 0hile the amplitude of the input /oltage is 2ept constant. The fre6uenc! ?2C=@ at 0hich /$ has maimum amplitude is most nearl!"

A. B. . (.

1.-& ).1% 1-.& )1.%


1!

QUESTION )%

V out The circuit sho0n elo0 has a transfer transfer function function is gi/en !

V ¿

=

1.2 ( s +2 )

(s + 1)( s + 4 ) .  in is a unit

step function, and there is no n o initial charge on the capacitors. The final ?stead! state@ /alue of out ?t@?@ is most nearl!"

A. B. . (.

$ $.$ $.-$.7$


2"

QUESTION )& The figure sho0n an ideal operational amplifier circuit. The /oltage gain of the circuit out>in is most nearl!"

A. B. . (.

%. # .- .$ . $


21

QUESTION $ The as!mptotic Bode plot for the magnitude of the transfer function T?s@ is sho0n in the figure elo0. The transfer function T?s@ in terms of the as!mptotic Bode plot is most nearl!" nearl!"

A.

T ( s )= K

( s +100 ) ( s +10 )( s + 1000 )

B.

T ( s )= K

( s +100 ) s ( s + 10 )( s + 1000 )

.

T ( s )= K

s ( s + 100 ) ( s +10 )( s + 1000 )

(.

T ( s )= K

( s +10 )( s + 1000 ) ( s + 1 )( s +1000 )


22


23

QUESTION 1 The sifting propert! of the impulse ?delta@ function K ?t@ is defined as ∞

∫ f ( ( t ) δ ( t −a ) dt = f (a ) ∞

The /alue of the integral ∞

∫ cos ( ωt ) δ ( t −1 ) dt whereω =2 ∞

radians per second and t is in seconds is most nearl!"

A. B. . (.

$ $.&$&) ;$.171 1. $

QUESTION ' onsider the follo0ing signal"

x ( t )= A cos [ ω 2 t + η sin ω1 t ] 8here, L1 MM L' and  is the modulation inde. If  is a constant and sin L 1t is the message, the resulting signal ?t@ is"

A. B. . (.

4hase 4hase modula modulated ted ?4*@ ?4*@ Amplit Amplitude ude modula modulated ted ?A*@ ?A*@ 4ulse; 4ulse;0id 0idth th modul modulate ated d ?48*@ ?48*@ 4ulse; 4ulse;shi shift ft modula modulated ted ?4S*@ ?4S*@


24

QUESTION ) A portion of a /oice communication s!stem is sho0n elo0. The audio message m?t@ is in the range '$ C= to -$$ C=. The signal m?t@ is used to modulate a cosine carrier signal as illustrated elo0.

The center center fre6ue fre6uenc! nc! and and0i and0idth dth,, respect respecti/el i/el! !, of an ideal ideal andpas andpasss filter filter re6uir re6uired ed to suppress the lo0er sideand and the carrier ca rrier of !?t@ to produce =?t@ are most nearl!"

A. B. . (.

'-$ '-$ C=, C=, '-$ '-$ C= C= $ C=, C=, 1,$$ 1,$$$ $ C= C= -,'-,'-$ $ C=, C=, -$$ -$$ C= C= ,#,#-$ $ C=, C=, -$$ -$$ C=


25

QUESTION  A proportional proportional controller 0ith gain  is used to control a spring and mass s!stem as sho0n in the figure elo0.

Y ( ( s ) 50 = 2 If  is ad3usted ad3usted so that the second;order second;order closed;loop closed;loop s!stem model is R ( s ) s + 2 s + 150 , then the s!stem damping ratio is most nearl!"

A. B. . (.

$. % $.$% $.$$7# $


26

QUESTION The ;map elo0 0as generated from a logic function <.

The epression that est represents the logic function < is"

A.

A ´C + AB

B.

´ C + A´ B A

.

A ´C + A ´B

(.

´ + A ´ B A C


27

QUESTION 7 8hen a 4U fetches an instruction 0ord from memor!, the 0ord contains an operation code ?op code@ that indicates the t!pe of operation the 4U is to perform and information specif!ing 0here the instruction operands are located. A computer ma! use /arious addressing modes to specif! the operand location. One such addressing mode is sho0n elo0, 0here + designates some register 0ithin 4U and d is a constant con stant emedded in the instruction 0ord.

8hich of the follo0ing terms est descries the addressing mode u sed ! the instruction ao/e9

A. B. . (.

Immedia Immediate te addres addressin sing g (ire (irect ct add addre ress ssin ing g Inde Indeed ed add addre ress ssin ing g Indir Indirect ect addres addressin sing g


2

QUESTION # et + c  7$$H, and let + E  -$$H. 8hen + 1  '.$$ 2H and + '  1.$$ 2H, the /alue of Ic ?mA@ is most nearl!"

+g  1$$H 1  1$.$ G< '  1$.$ G<

A. B. . (.

e  -$.$ G< BE  $.# 

1$ 1& ' '#


2!

QUESTION % The follo0ing +outh arra! has een constructed for a simple control s!stem 0ith a gain of  in the feedac2 path.

The denominator of the closed;loop s!stem transfer function is" 3

2

4

3

A.

s + 7 s + 12 s + 10

B.

s + 7 s + 12 s + 10 s

.

s + 7 s + 12 s + ( 10 + 14 K ) s + 42 K 4

3

2

2

(. Not defi defined ned from from the the +outh +outh arra! arra!


3"

QUESTION & The gate;to;source /oltage of the depletion;mode, n;channel *OS
If   $.$' mA>' and p  ;, the /alue of i( ?mA@ is most nearl!" A. B. . (.

' .' 1 .% $


31

QUESTION -$ The function ?t@ sho0n elo0 is to e con/ol/ed 0ith h?t@, also sho0n elo0"

If !?t@ is the /alue of the con/olution con/o lution ?t@h?t@, for 1MtM', the /alue of !?t@ is most nearl!"

A. B. . (.

Option A Option B Option  Option (


32

SOUTIONS QUESTION 1 +efer to resolution of a force in the statics section of the reference oo2. R x = F xi  R y = F yi 

∑

∑

R x =2.12+ 5cos105  0.83 ! R y =2.12 +5cos105 =6.95 ! R= √ R R x + R y = √ ( 0.83 ) +( 6.95) = 6.999 ! 2

2

2

2

QUESTION ' The correct ans0er  QUESTION ) Use the non;annual compounding interest e6uation" " r ie =(1 + ) −1 " Pi/en r  $.1# and m, 0e ha/e

¿(1+

0.17 4

4

) −1= 0.1815∨18

QUESTION  See the standard oidation potentials for corrosion reactions tale in the chemistr! section of the
¿

( 5 )(−12) −12 4 $ 8.85 x 10

(

12

30 100

2

=−6 x 10 !

)

QUESTION % All of the potential energ! at rest is con/erted to 2inetic energ! at the anode ?i.e. 4E E@. 1

& ( ' ' V ) ) = " (

2

2


33 1.6 x 10 9.1 x 10

¿ ¿

1 (¿¿ −19) ( 2 x 10 )= ¿ 4

2

¿ ¿ ( =83.9 x 106

" s

#$ESTI%N ! 1.38 x 10

) ) x 273.15 K K =23.52 x 10−3 V −19 1.6022 x 10 C *T V T = = ¿ &

( ¿ ¿ −23

#$ESTI%N 1" 120 f n2= + F&r p'2(

n s=

120 x 60

F&r p'4(

n s=

120 x 60

2

4

=3,600 r+" =1,800 r+"

n =( s,i+ ) n s -where 0 < s,i+ < 1 - n . ns

N is )i*e+ as 3(5"" rpm( t,ere&re t,ere&re +umer & p&les is 2 #$ESTI%N 11 o A =10 + / 3∨10.44 ∠ 16.70 146.31 B =−6 + / 4∨7.21 ∠ 146.31

o

o

A 10.44 ∠ 16.7 16.7 0 o 129.61 = =1.448 ∠−129.61 o B 7.21 ∠ 146.31 146.31

¿− 0.92− / 1.12 #$ESTI%N 12 x

(¿¿ 3− x +1 ) dx =¿

x

4

4

−

x

2

2

+ x +0

¿ ∫¿ #$ESTI%N 13 FE-CBT-Electrical Sample Exam II

34 3

2

f ( ( x x )= x + x −3 f ( x )=3 x + 2 x 1

2

1 1

( x )= 6 x +2 =0∨ x = f x

−1

1 1

3

( x ) ne2ati(e3e,ow x = f x

−1 3

( x ) +ositi ∨ f 1 1 x +ositi(e (e a3o( a3o(ee x =

−1 3

Si+ce //0x ' " a+ //0x c,a+)es si)+ at x ' -13( t,e i+ecti&+ p&i+t is at x ' -13 #$ESTI%N 14 2 T,e c,aracteristic euati&+ euati&+ is 4 + 6 4 + 25= 0 eerri+) t& t,e sec&+ &rer li+ear ,&m&)e+e&us i8ere+tial euati&+ 9it, c&+sta+t c&e:cie+ts i+ t,e ,a+&&; a ' 6<  ' 25 a+ 4 ' 1"" 2 sin0 sin0ee a =36 is,essthan 4 3 =100, the the syste syste" " is 0riti0 0riti0a, a,,y ,y da"+e da"+ed d5 #$ESTI%N 15 Fr&m t,e ispersi&+( mea+( meia+ a+ m&e *alues i+ t,e ,a+&&;( 9e ,a*e Ei),t Ei),t measur measureme eme+ts +ts.. T,e &urt, &urt, a+ =t, =t, measur measureme eme+ts +ts are are 11 a+ 12 12.. Si+ce t,e +umer & items 0ei),t is e*e+( t,e meia+ is t,e a*era)e & t,e &urt, a+ =t, measureme+ts. measureme+ts. "edian =

11+ 12 2

=11.5

#$ESTI%N 16 $si+) t,e i+&mial istriuti&+ p ' ".5 0c,a+ce & )etti+) a ,ea  ' ".5 0c,a+ce & +&t )etti+) a ,ea + ' 1" 0+umer & trials x ' 4 0+umer & ,eas 10 7 610 ( 4 )= (0.5 )4 ( 0.5)6 =0.2051 4 767 #$ESTI%N 17 T,e c&rrect c&rrect a+s9er is B #$ESTI%N 1 First r&u+ # =1 + 2 =3∧ K =2 x 3=6

3>3( N&? Sec&+ r&u+ # =3 + 2 =5∧ K =6 x 5 =30 5>3( @es. ( t,e c&rrect a+s9er is D #$ESTI%N 1! FE-CBT-Electrical Sample Exam II

35

T,e euati&+ &r c&mplex p&9er ca+ e &u+ i+ c&mplex p&9er i+ t,e electrical a+ c&mputer e+)i+eeri+) secti&+ & t,e ,a+&&; V ¿ =V80os9 6out = 6¿ x effi0ien0y effi0ien0y = 6¿ x 0.85 6out =10 h+ x 745.7 6¿ = 8 =

7.5 *: 0.85

: =7.5 *: h+

=8.8 *:

6¿ 8.8 *: = =33.2 A V0os9 440 V x 0.6

#$ESTI%N 2" C&mplex p&9er is expresse −1 6= s cos 9 - #= ; sin9 sin9∧9 =cos ( +f )

as

S

'

A#

9,ere(

T,e &ri)i+al real real a+ reacti*e p&9er( p&9er( t,e+ are )i*e+ )i*e+ @ @ −1 cos

(¿ (0.6 ))= 76 *VARindu0ti(e 6=100 *VA x 0.65=65 *: ∧# =100 *VA *VA x sin ¿ ; ori2ina, =65 *: + / 76 *VAR

i+) a purel@ capaciti*e l&a 9ill +&t c,a+)e t,e t&tal real p&9er 0A( ut it 9ill ecrease t,e reacti*e p&9er 0# ; ( new )= 65 *: + / ( 76 −# 0 ) *VAR −1

tan ( 9 new )= tan ( cos

%r

( 0.6 ))=0.48=

76−# 0 65

# 0 = 44.5 *VAR

#$ESTI%N 21 T,e euati&+ &r c&mplex p&9er ca+ e &u+ i+ c&mplex p&9er i+ t,e electrical a+ c&mputer e+)i+eeri+) secti&+ & t,e ,a+&&; 6=V r"s 8 r"s 0os9 + 5 f 5=0os9 =

1500 6 = = 0.87 V r"s 8 r"s 115 x 15

#$ESTI%N 22 eer eer t& t,e ma)+etic =el secti&+ i+ t,e FE ,a+&&; 2 $rB <8 B = <= = ∨ 8 = < 2 $r


36

¿

2 $ ( 0.5 )( 1 ) −7

4 $ 10

= 2.5 x 106 A

#$ESTI%N 23 Z 0 =

√

> > ∨( 50 )2= C C

>=2,500 x 133

+F <= =0.33 " "

#$ESTI%N 24 Si+ce t,e s@stem uses e*e+ parit@( a+ e*e+ +umer & 1 its 0i+clui+) t,e parit@ it s,&ul e rem&*e. + & +umer & its ,a*e t& e c&rrupte t& etect a+ err&r. Si+ce a+ & +um +umer er & its its ,a*e ,a*e ee+ ee+ recei ecei*e *e( ( i.e. i.e.(( 1 &r 3 &r 5.. 5.. its its ,a*e ,a*e ee+ ee+ c&rrupte. T,e c&rrect a+s9er is C #$ESTI%N 25  ull@ c&++ecte +et9&r; reuires N0N-12 li+;s &r pat,s< t,us N0N-12 ' 1" &r =*e stati&+s. T,e c&rrect c&rrect a+s9er is C #$ESTI%N 26 I+ter I+ter+et +et Ar&t&c r&t&c&l &l 0IA 0IA &perat &perates es at t,e +et9&r +et9&r; ; la@er la@er.. B&t, B&t, Tra+sm ra+smiss issi&+ i&+ C&+tr C&+tr&l &l Ar&t& Ar&t&c&l c&l 0TCA 0TCA a+ $ser $ser Data)r Data)ram am Ar&t& Ar&t&c&l c&l0$D 0$DA A &perat &perate e at t,e tra+sp&rt la@er.. T,e c&rrect a+s9er is C #$ESTI%N 27 3 2 1 0 1011=( 1 x 2 )+ ( 0 x 2 ) +( 1 x 2 ) +( 1 x 2 )

¿ 8 + 0 + 2 + 1 =11 #$ESTI%N 2 Arese+t state x Next state G

C 1 B 1

B " B 1

B " B 1

T,e c&rrect c&rrect a+s9er is D #$ESTI%N 2! T,e i+structi&+ pipeli+e is a mem&r@ eleme+t 9it, muc, aster access.  pipeli pipeli+e +e c&+tr c&+tr&ll &ller er pree preetc, tc,es es i+stru i+structi cti&+s &+s t& t,e pipe pipe &r execu executi& ti&+. +. T,e c&rrect a+s9er is B #$ESTI%N 3" Y =10 → ,oo+wh ,oo+whi, i,ee is a0ti a0ti(e→Y (e→Y =9

Y = 9 → ,oo+ ,oo+ whi, whi,eis eis a0ti a0ti(e→ (e→ Y =8 Y =0 → ,oo+ whi,e whi,e !?Ta0t !?Ta0ti(e i(e - returnsY eturnsY =0


37

T,e c&rrect c&rrect a+s9er is B


3

#$ESTI%N 31 eer t& e8ecti*e &r HS *alues i+ t,e electrical a+ c&mputer e+)i+eeri+) secti&+ & t,e ,a+&&;

√

∞

2

@ r"s = @ d0 +

@ ∑ =

2

n

n

1

F&r i1( 2 10 / √ ¿

¿

2 −7 / √ ¿ 2

¿ −3

( )

¿+

2

√ 2

¿ ¿ ¿ 2 0 +¿ @ r"s =√ ¿ F&r i2 2

/ √ ¿ ¿

10

2 3

2

/ √ ¿ ¿

( ) 7

¿+

2

√ 2

¿ ¿ ¿ 0 +¿ @ r"s=√ ¿ 2

T,us &t, 9a*e&rms ,a*e t,e t,e same rms rms *alue. #$ESTI%N 32


3!

#$ESTI%N 33 T,e p&9er issipate i+ a resist&r ca+ e &u+ @ appl@i+) t,e euati&+ 2 V 6= R T,e *<a)e acr&ss acr&ss t,e !"-&,m resist&r is 1""-6" 1""-6" ' 4". 4". T,ere&re T,ere&re 2

6=

( 40 ) 90

=17.78 :

#$ESTI%N 34 ppl@ JCK t& t,e +&e mar;e " 1

1

( V −36 ) + 6 ( V −6 ) =0∨V =19.5 V 3 0

0

0

#$ESTI%N 35 eer eer t& t,e electrical a+ c&mputer e+)i+eeri+) secti&+ & t,e ,a+&&;


4"

T,e impee+ce & t,e resist&r resist&r is T,e impe+ce & t,e i+uct&r is is

Z R= R =1000  Z >= /ω>= / ( 100,000 ) ( 0.002 )= / 200 

Si+ce t,e@ are i+ series( L ' 1("""2"" 1("""2"" &,ms #$ESTI%N 36 N is t,e t&tal resista+ce see+ at t,e l&a e+ 9it, t,e *<a)e s&urce set eual t& Ger& 0replace @ s,&rt circuit Rn=60  +( 50  ∈ ¿ with 200  )

¿ 60 + 40 =100  #$ESTI%N 37 " 9ill e maximum 9,e+ K a+ C are i+ parallel res&+a+ce 0.5 x 10 rads √ (¿¿ −6 )( 5 x 10−3 )=2 x 104 s ω 0=

1

=

1

>C ¿ √ >C

3

f 0=

20 x 10 2 $

=3.18 *=

#$ESTI%N 3 B@ i+specti&+ & t,e circuit 9it, eac, capacita+ce replace 9it, a+ &pe+ circuit 30 30 + 20

=0.6 V


41

#$ESTI%N 3! T,e i+put curre+t curre+t t& a+ ieal &p amp is Ger&( a+ t,e *<a)e et9ee+ t,e t9& i+put termi+als & a+ ieal &p amp must e Ger&. T,ere&re( t,e *<a)e i*ier relati&+ )i*es< V ¿ =(

4 30 + 4

) V out

V out 34 = =8.5 V ¿ 4

#$ESTI%N 4" T,e B&e pl&t ,as sl&pes & "B &r -2" B per ecae( s& t,ere are simple p&les &+l@ at M ' 1" rass a+ 1(""" ras a+ a simple Ger& at M'1"" rass. T,e &+l@ tra+ser u+cti&+ t,at t,a t satis=es t,ese c&+iti&+s is %pti&+ . T,e c&rrect c&rrect a+s9er is . . #$ESTI%N 41 T,e *alue & t,e i+te)ral is is ∞

∫ cos ( 2 t ) δ ( t −1 ) dt =cos ( 2 ) =−0.4161

−∞

#$ESTI%N 42 eer eer t& t,e p,ase-e*iati&+ euati&+ i+ t,e ,a+&&;. T,e c&rrect c&rrect a+s9er is . #$ESTI%N 43 Ce+ter reue+c@ f 0 =5000 +

50 −20 2

=5,250 =

Ba+9it, B: =500−20 = 480∨0,ose ¿ 500 = #$ESTI%N 44 Y ( ( s ) K 50 = 2 = 2 R ( s ) s + 2 s + 150 s + 2  ωn s + ωn2 2

ω n=150∧2  ωn= 2 =

2 2 ωn

=

1 150 √ 150

= 0.082

#$ESTI%N 45 Fr&m t,e J-map( J-map( F is satis=e @ t,e t,ir a+ &urt, c&lum+s & t,e =rst r&9 ´ + A ´ B . T,e c&rrect ´ Thereforee ( F ' A C 0C &r @ t,e sec&+ c&lum+0 A B ¿ 5 Therefor a+s9er is D. #$ESTI%N 46


42

I+exe aressi+) uses t,e c&+te+ts & s&me re)ister 0 i+ t,is pr&lem as a p&i+ter t& t,e e)i++i+) 0&r e+ & a list 0arra@ & *alues i+ mem&r@ ase. + &8set 0 is ae t& t,e *alue & t,e ase p&i+ter t& etermi+e t,e l&cati&+ & a+ &pera+. T,e c&rrect c&rrect a+s9er is C #$ESTI%N 47 F&r F&r c ias ias calcul calculati ati&+s( &+s( all capaci capacit&r t&rs s li;e li;e &pe+ &pe+ circui circuits. ts. T,e T,e*e T,e*e+i+ +i+ eui*ale+t & t,e ase-ias circuit ca+ e represe+te represe+te as s,&9+ el&9 el&9

,ere( B is i+ parallel 9it, 1 a+ 2 9,ic, is eual t& 667 &,ms. R2 1 V BB =V CC =30 V =10 V 3 R1 + R2

()

B@ JK

V BB − 8 B R B −V BD− 8 D R D= 0

8 D Si+ce 8 s= E + 1 8 D V BB = R −V BD− 8 D R D=0 E + 1 B 8 0 = 8 D=

V BB −V BD R D + RB /( E + 1)

=

V BB −V BD R D

=

9.3 0.5

=18.6 "A

#$ESTI%N 4


43

Fr&m t,e )i*e+ arra@( t,is is a &urt, &rer s@stem. T,e e+&mi+at&r & t,e s@stem is & t,e &rm 4 3 2 a0 s + a1 s + a2 s + a 3 s + a4 T,e &ut, arra@ arra@ is &rme &rme @ @ 4 s =a0 a2 a4 3

s = a1 a 3 2

s=

a1 a2− a0 a3 a1

a4

Sustituti+) r&m t,e )i*e+ &ut, arra@ @iels t,e e+&mi+at&r p&l@+&mial s + 7 s + 12 s + ( 10 + 14 K ) s + 42 K 4

3

2

#$ESTI%N 4! ( ; =1 V - ( 4 =0 V therefore-( 4;=1 V Si+ce

( ; > V + ∨1 >−4 ∧( 4 > V +∨0 >−4

T,e H%SFET &perates i+ t,e tri&e tri&e re)i&+ 2 i 4 =0.2 2 ( 1 −(−4 ) ) ( 1 )− (1 ) =0.2 [ 9 ] =1.8 "A

[

]

#$ESTI%N 5" F&r "OtO1 t

∫ ( G G ) ( 1 ) dG = 12 t

x ( t )∗h ( t )=

2

0

T,is is a uaratic. %+l@ t,e =)ure =)ure s,&9+ i+ %pti&+ D is uaratic &r "OtO1 T,e c&rrect c&rrect a+s9er is D


FE CBT Electrical Sample Exam II

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