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Exercisse 2.2 Analisis riil Bartle
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Exercisse 2.2 Analisis riil Bartle
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Rifda Kharisma Putri
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Exercisse 2.2 2. If
, show that | | || || if and only if .
Proof:
| | || || | | | || || | || |||| || || || |||| |||| ||| | ||| |||| ||| . Since || || , then ||| ||| . So, ||| Given . implies that ab = 0 or ab > 0. Given
→
←
ab = 0 implies a = 0 or b = 0.
| | | | || || || || || for b = 0 then | | | | || || || || || for a = 0 then
ab > 0implies a > 0 and b > 0. Thus, a+b > 0. So that
4. Show that
| | || ||
| | if and only if
Proof:
| | ( ( ) . that satisfy the following inequalities: a. || b. | |
6. Find all
Solution : a.
||
So, the solution set of the inequalities above is SS:=
{ | }.
| | Since , then is unusefull boundary So, So, the SS:= * | +
b.
7. Find all
that satisfy the equation | | | | .
Solution : In this problem, we can separate it into three cases:
ii.) iii.) i.)
– ( ) ii.)For , we get ( ) i.) For x < -1, we get
Since this statement is false, no value of x from case (ii) that satisfies the equality. iii.) For
, we get
From i, ii, iii, we can conclude that the value of x that satisfies the equation are -3 or 4 and it can be denoted by SS:=
*|⋁ +
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