Descripción: Permite el calculo de area bajo una curva por modelos numericos, dividiendo en subareas de tipo arco de parabola. Yamil Armando Cerquera
MS Word format of Sir Nelson Tubon's ppt. lecture notesFull description
SOALDeskripsi lengkap
Deskripsi lengkap
Permite el calculo de area bajo una curva por modelos numericos, dividiendo en subareas de tipo arco de parabola. Yamil Armando Cerquera
CATFull description
CAT
SAP HANA
SAP HANA
Descripción: Métodos numéricos: Trapecio y Simpson Compuesto, teoría y algoritmos. Los métodos numericos se utilian para encontrar la solución a sistemas de ecuaciones lineales, no lineales y trascendentales, ...
Regla de OSHADescripción completa
Descripción: Regla de OSHA
El caos interno que se genera por la discordinación de la Razón y la Animalidad de la regla anterior encuentran la perfecta coordinación al respetar la dimensión de cada uno de los component…Descripción completa
Como desarrollar los ejercicios.Descripción completa
metode numerikDeskripsi lengkap
UNIVERSIDAD NACIONAL HERMILIO VALDIZAN FACULTAD DE INGENIERIA INDUSTRIAL Y INDUSTRIAL Y SISTEMAS
E.A.P DE INGENIERIA INDUSTRIAL METODOS NUMÉRICOS Tema
:
Docente
:
REGLA DE SIMPSON 1/3 Ing. Marco Villavicenci Villavicencio o
Alumnos : Chávez Villanueva Lincoln Andrés
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ALGORITMO DE TRABAJO Definición del Problema
Recopilación de Datos
Modelo Matemátic Matemático o
Trabajo Manual
Diagrama de Flujo ( programación)
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DEFINICION DEL PROBLEMA
El desarrollo de las integrales siempre es un problema debido a la complejidad de las funciones a integrar es por ello que se realizan software de aplicación en este campo mediante varios métodos , uno de ellos es la Regla de Simpson que es simple de utilizar. En este caso que se tienen una funcione a
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Recopilación de Datos Los datos para evaluar la integrar son los siguiente: A=0 B=1 N=10 H=0.1
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MODELO MATEMATICO *La integral a evaluar con la regla de simpson es:
A) INTEGRAL( X/SQRT(1+X^4),DE 0 A 1 ;N=10 Xi = a + i * h H = (b-a) / N = (1-0) / 10 = 0.1
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CUADRO DE RESULTADOS DE LA INTEGRAL i
Xi
F(xi)
&
&*F(xi)
0
0
0
1
0
1
0.1
0.0999
4
0.3996
2
0.2
0.1998
2
0.3997
3
0.3
0.2987
4
1.1948
4
0.4
0.3949
2
0.7898
5
0.5
0.485
4
1.94
6
0.6
0.5645
2
1.129
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Resultados de la Primera Integral
&*F (xi)=SUMA=13.2188
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DIAGRAMA DE FLUJO INICIO INGRESAR A, B Y N DEFINIR F (X) CONVERSION
no si I < N+1
INTEGRAL=SUMA*H/3
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Codificación en C++ #include #include #include void main(void) {int N,i; double a,b,suma,f,xi,h; cout<<" *********METOD *********METODO O SIMPSO SIMPSON N 1/3********** 1/3************"<>a; cout<<"Ingrese cout<<"I ngrese el Limite Superior de la Integral definida: "; cin>>b; cout<<"Ingrese un Numero par de Iteraciones : ";
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