NERACA_MASSA Tricloro Etilen

4.11 Neraca Massa Industri Trichloroethylene

“ BLOCK DIAGRAM “

Diketahui

: Bahan Baku Cl2 = 1,26 ton C2H2 = 0,23 ton (85 % konversi)

1. TETRACHLO TETRACHLOROETHAN ROETHANE E REACTOR

C2H2 = 230 k" Cl2

$

ol Cl2

$

ol C2H2

= 1260 k"

=

=

Cl2

 =! k"

C2H2

=

! k"

C2H2Cl# =  k"

 etrahloroeth ane

1,26ton =

0,01&&55 t'ol

71ton / tmol  0, 23 ton 0,0088 t'ol 26 ton / tmol  =

= 1&,&55 k'ol

= 8,8 k'ol

Reaksi : C2H2 



2Cl2

85 %

   →  

C2H2Cl#

8,8

1&,&55

$



&,#8

1#,*6

&,#8

k'ol

+

1,32

2,&*5

&,#8

k'ol

k'ol

B

26,0# k"k'ol

Berat

&1

3#,3&

16&,86

1*8,#5

1255,5*

k"

Neraca Massa : -o'.onen

/n.ut (k")

ut.ut (k")

C2H2

230

3#,3&

Cl2

1260

1*8,#5

C2H2Cl#

$

1255,5*

 otal

1#*0

1#*0

Cl2

 = 1*8,#5 k"

C 2H2

= 3#,3& k"

 otal

= 232,82 k"

C2H2  = 230 k" Cl2 = 1260 k" 1255,5* k"

 etrahloroeth ane

C 2H2Cl#

 otal = 1#*0 k"

2. STRIPPER H2 =50 -"

C2H2 = 

C2H2 = 3#,3& k" Cl2

= 1*8,#5 k"

+tri.. er

H2 =  Cl2 =   Asumsi penambahan H2O sebanyak : 50 kg

Input = output : $ C2H2 = 3#,3& k" $ Cl2 = 1*8,#5 k" $ H2 = 50 k"

Neraca Massa : -o'.onen

/n.ut (k")

ut.ut (k")

C2H2 Cl2 H2

3#,3& 1*8,#5 50

3#,3& 1*8,#5 50

 otal

282,82

282,82

=

H2 =50 -"

C2H2 = 3#,3& Cl2

C2H2 = 3#,3& k"

k"

= 1*8,#5 k"

 otal =232,82 k"

+tri.. er

H2 = 50 k" Cl2 = 1*8,#5 k"  otal = 2#8,#5 k"

3. TRICHLOROETHYLENE REACTOR C2H2Cl# k" C2H2Cl# = 1255,5* k" k"

 rihloroethle ne eator

C2HCl3 HCl

Reaksi

: C2H2Cl#



&,#8 k'ol

85 %

     →

C2HCl3

 $

=

HCl $

=

k"

=



6,358

6,358

6,358

1,122

6,358

6,358

k'ol + k'ol B

16&,86

131,#0

188,3# k"

835,##

36,#6

k"k'ol Berat

231,81

Neraca Massa : -o'.onen

/n.ut (k")

ut.ut (k")

C2H2Cl#

1255,5*

188,3#

C2HCl3

$

835,##

HCl

$

231,81

 otal

1255,*

1255,*

C2H2Cl# = 188,3# k" C2H2Cl# = 1255,* k" k"

 rihloroethle ne eator

C2HCl3

HCl otal

4. KONDENSER C2HCl3 = 835,## k" C2H2Cl# = 188,3# k" HCl

= 231,81 k"

Cooler 1

= 835,##

= 231,81 k" = 1255,* k"

C2H2Cl#

=

C2HCl3 =  HCl

C2H2Cl#

=

 = 

C2HCl3  =  HCl

=

 Assumsikan Fase uap 60% berubah menjadi fase cair yan ke!uar pada baian ba"ah# $utput : •

a"ah C2H2Cl#

= 60% 4 188,3# k" = 113,00# k"

C2HCl3

= 60 % 4 835,## k" = 501,26# k"

HCl

•

= 60% 4 231,81 k" = 13*,086 k"

&roduk uap C2H2Cl#

= (188,3#  113,00#) k" = &5,336 k"

C2HCl3

= (835,##  501,26#) k" = 33#,1&6 k"

HCl

= (231,81  13*,086) k" = *2,&2# k"

Neraca Massa : -o'.onen

/n.ut (k")

ut.ut (k")

C2H2Cl#

188,3#

188,3#

C2HCl3

835,##

835,##

HCl

231,81

231,81

 otal

1255,5*

1255,5*

C2HCl3 = 835,## k" C2H2Cl# = 188,3# k" HCl  otal

= 231,81 k" = 1255,5* k"

C2H2Cl#

Cooler 1

= &5,336

C2HCl3 = 33#,1&6 k" HCl

= *2,&2#

 otal

C2H2Cl#

 = 113,00# k"

C2HCl3 = 501,26# k" HCl

= 13*,086 k"

 otal

= &53,35# k"

5. BRINE HCl 50 % C2H2Cl# = &5,336 k" C2HCl3 = 33#,1&6 k" HCl

= *2,&2# k"

Brine

k"

= 502,236 k"

k"

C2H2Cl# =  C2HCl3

= 

HCl

= 

 Asumsi : HCl 50 % =

50 100

 x 92,724 kg 

=

46,362 kg 

$utput : C2H2Cl#

∴

= &5,336

k"

C2HCl3

= 33#,1&6 k"

HCl

= *2,&2#  #6,362 k" = #6,362 k"

untuk HCl

= #6,362 k"  #6,362 k" = *2,&2# k"

Neraca Massa : -o'.onen

/n.ut (k")

C2H2Cl#

ut.ut (k")

&5,336

&5,336

C2HCl3

33#,1&6

33#,1&6

HCl

*2,&2#

*2,&2#

total

502,236

502,236

HCl 50 % = #6,362 k"

C2H2Cl# = &5,336 HCl

k" Brine

= *2,&2# k"

C2HCl3 = 33#,1&6 k"  otal = 502,236 k" C2H2Cl# = &5,336 HCl

k"

= #6,362 k"

C2HCl3 = 33#,1&6 k"

 otal = #55,8&# k"

6. HCl STRIPPER Input dari '(! striper merupakan abunan dari ke!uaran coo!er  dan brine  )adi : C2H2Cl# = (&5,336  113,00#) k"

= 188,3# k"

C2HCl3  = (33#,1&6  501,26#) k" = 835,## k" HCl

= (#6,362

 13*,086) k" = 185,##8 k"

C2H2Cl# = 188,3# k" HCl

C2HCl3 = 835,## k" HCl

HCl rele ( #0%)

+tri..e r

= 185,##8 k"

C2H2Cl# =  C2HCl3  =  HCl

=

Recyc!e : HCl #0% =

40 100

 x 185,448 kg 

=

74,18 kg 

$utput : C2H2Cl#

= 188,3# k"

C2HCl3 = 835,## k" HCl

= 185,##8 k"  &#,18 k" = 111,268 k"

HCl = 111,268 k"  &#,18 k" = 185,##8 k"

∴

Neraca Massa :

-o'.onen

/n.ut (k")

ut.ut (k")

C2H2Cl#

188,3#

188,3#

C2HCl3

835,##

835,##

HCl

185,##8

185,##8

 otal

120*,23

120*,23

HCl

C2H2Cl# = 188,3# k" C2HCl3

= 835,## k"

HCl

= 185,##8 k"

 otal

= 120*,23 k"

+tri..er

rele HCl #0 % = &#,18 k"

C2H2Cl# = 188,3# C2HCl3 = 835,##

k" k"

HCl

= 111,268 k"

 otal

= 1135,0#8 k"

7. DESTILASI 1

HCl = 

C2H2Cl# C2HCl3 HCl

= 188,3# k" = 835,## k" = 111,268 k"

Destila si

C2HCl3 =  C2H2Cl# = 

$utput : C2H2Cl# C2HCl3

= 188,3# k" = 835,## k"

HCl = 111,268 k"

Neraca Massa : -o'.onen

/n.ut (k")

ut.ut (k")

C2HCl3

188,3#

188,3#

C2HCl3

835,##

835,##

HCl

111,268

111,268

 otal

1135,0#8

1135,0#8

HCl = 111,268k"

C2H2Cl# = 188,3#

k"

C2HCl3  = 835,##

k"

HCl otal

= 111,268 k"

Destila si

= 1135,0#8 k"

C2H2Cl# = 188,3# k" C2HCl3 = 835,## k"  otal

= 1023,&8 k"

8. DESTILASI II

C2H2Cl# = 188,3# k" C2HCl3 = 835,## k"

Destila si

C2HCl3 = 

C2H2Cl# = 

Input = $utput : C2H2Cl# = 188,3# k" C2HCl3 = 835,## k"

Neraca Massa : -o'.onen

/n.ut (k")

ut.ut (k")

C2H2Cl#

188,3#

188,3#

C2HCl3

835,##

835,##

 otal

1023,&8

1023,&8

 C2H2Cl# = 188,3# k" C2HCl3 = 835,## k"  otal

Destilas i

= 1023,## k" C2H2Cl# = 188,3# k"

C2HCl3 = 835,## k"

NERACA MASSA INDUSTRI TRICHLRETH!LENE